A 5.0-g object carries a net charge of 3.8 micro-Coulomb. It acquires a speed v when accelerated from rest through a potential difference V. A 2.0-g object acquires twice the speed under the same circumstances. What is its charge?

Answers

Answer 1

Answer:

The value is  [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

Explanation:

From the question we are told that

     The mass of the object is  [tex]m_1 = 5.0 \ g = 0.005 \ kg[/tex]

     The net charge is  [tex]q = 3.8 \mu C= 3.8 *10^{-6} \ C[/tex]

     The mass of the second object is   [tex]m_1 = 2.0 \ g = 0.002 \ kg[/tex]

Generally for the first object the potential energy gained at the end of its acceleration is equal to its  kinetic energy

i.e

            [tex]\frac{ 1}{ 2} * m_1 * v^2_1 = q_1 * \Delta V \ \ --- (1)[/tex]

Here [tex]v_1[/tex] is the velocity of the first object

        [tex]\Delta V[/tex] is the potential difference through which it is accelerated  

Generally for the second object the potential energy gained at the end of its acceleration is equal to its  kinetic energy

i.e

            [tex]\frac{ 1}{ 2} * m_2 * v^2_2 = q_2 * \Delta V[/tex]

Here [tex]v_2[/tex] is the velocity of the second object and from the question it is

        [tex]v_2 = 2 v_1[/tex]

        [tex]\Delta V[/tex] is the potential difference through which it is accelerated        

So

          [tex]\frac{ 1}{ 2} * m_2 * (2v)^2_1 = q_2 * \Delta V[/tex]

=>        [tex]m_2 * 2v^2_1 = q_2 * \Delta V \ \ ---(2)[/tex]

Generally dividing equation 2 by equation 1

            [tex]\frac{2m_2 v^2_1 }{ \frac{1}{2} * m_1 * v_1^2} = \frac{q_2 \Delta V }{ q_1 * \Delta V}[/tex]

=>         [tex]q_2 = \frac{4m_2 * q_1 }{m_1}[/tex]

=>         [tex]q_2 = \frac{4* 0.002 * 3.8 *10^{-6} }{0.005}[/tex]

=>         [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

=>         [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

           


Related Questions

A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kinetic frictional force is equal to 70 N. Calculate the acceleration of the piano for an applied force of 100 N.

Answers

Answer:

a = 0.1 m/s²

Explanation:

If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:

       [tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]

By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:

       [tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]

Solving for a:

        [tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]

it is easier to climb up a slanted slope than a vertical slope

Answers

Answer:

Yes, it is easier to climb a slanted slope than a vertical or more steep slope.

Explanation:

On a vertical slope, you are climbing higher instead of farther so on each step gravity weighs you down much more than on a gentle slope

Yes it is easier to clime a gentle slope than a vertical or more steep slope. This is because gravity is always pulling objects down so when you climb upward gravity weighs you down, you have to use effort to move yourself in the opposite direction that gravity is pulling you that is why it is harder to climb up a slope. When you climb a gentle slope you still are using energy but it takes longer to reach the same height on a gentle slope versus a vertical slope. On a vertical slope you are climbing higher instead of farther so on each step gravity weighs you down much more than on a gentle slope. When climbing a gentle slope you don't rise as rapidly so gravity doesn't take as much of a toll on you and you have a chance to recover.

A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force

Answers

Answer:

F = 6[N].

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

[tex]P=m*v\\or\\P=F*t[/tex]

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 10 [kg]

v = velocity [m/s]

F = force [N]

t = time = 5 [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 10 [kg]

v₁ = velocity of the object before the impulse = 1 [m/s]

v₂ = velocity of the object after the impulse = 4 [m/s]

[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]

which property of an object is not changed by a force​

Answers

Cannot changed by force hope this help

calculate the net force

250N left force and right force is 150N​

Answers

Answer

100N on the left force

Explanation:

You have to subtract 250 - 100 and the reamaining would be 100 and that 100 would go to the left force since it was the higher number

A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?

Answers

Answer:

50 km/h

Explanation:

200 km = 4 hours

200/4=50

50km/h

WILL MARK BRAINLIEST JUST PLEASE HELP

Answers

Answer:

40N in either direction is the answer

The Third choice 40n in either direction will be your answer. Hope this helped. Have a great day!

TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”

Answers

True as the independent variable is over the dependent variable and controls it as the dependent relies on the independent.

In an open circuit like the picture

A. the light bulb will produce light
B. a resistor controls the flow of current
C. the light bulb will be off
D. current will flow

Answers

C. The light bulb will be off
This is due to the reason that the wire doesn’t go back to the battery :)

In an open circuit like the picture the light bulb will be off. So, option (C) is correct.

What is electric circuit?

Electric circuit is a way for current to flow through electricity. An electric circuit consists of a source of energy for the charged particles that make up the current, like a battery or generator; sources of current-using equipment, like lamps, electric motors, or computers; and the connecting wires or transmission lines.

Ohm's law and Kirchhoff's rules are two of the fundamental mathematical laws that define how electric circuits function.

In the given diagram, the circuit is open. So, no current passes through it and the light bulb will be off. Hence, option (C) is correct.

Learn more about electric circuit here:

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what two charactoristic are needed to describe a force

Answers

Answer:

An applied force, A resistive force

Explanation:

An applied force is an interaction of one object on another that causes the second object to change its velocity.

A resistive force passively resists motion and works in a direction opposite to that motion.

A 96 kg man lying on a surface of negligible friction shoves a 75 g stone away from himself, giving it a speed of 7.2 m/s. What speed does the man acquire as a result?

Answers

Answer:

7.21m/s

Explanation:

Using the law of conservation of momentum expressed as;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the mass of the man and the stone respectively

u1 and u2 are their respective initial velocities

v is their final common velocity

Given

m1 = 96kg

m2 = 75g = 0.075kg

u1 = ?

u2 = 0m/s (initial speed of the stone)

v = 7.2m/s

Substitute into the firmula and get u1

96u1 + 0.075(0) = (96 + 0.075)(7.2)

96u1 = 96.075(7.2)

u1 = 691.74/96

u1 = 7.21m/s

Hence the man acquired a speed of 7.21m/s

what is mean by combination reaction ?​​

Answers

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

Which of the following is the cause of an acceleration?

Answers

[tex]{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}[/tex]

[tex]\longrightarrow[/tex] The rate of change of velocity per unit time is called acceleration.

[tex]\longrightarrow[/tex] Its SI unit is m/s².

[tex]\huge\boxed{\fcolorbox{blue}{red}{Thank you}} [/tex]

we have that from the Question"Which of the following is the cause of an acceleration?" it can be said that  

Acceleration cause bodies to move at an increasing rate after which a velocity or speed is maintained Force is a main cause of Acceleration andacceleration is seen at a change in velocity

From the Question we are told

Which of the following is the cause of an acceleration?

Generally the equation for acceleration is mathematically given as

[tex]a=\frac{F}{m}\\\\or\\\\a=\frac{u-v}{dt}\\\\[/tex]

Therefore

Acceleration cause bodies to move at an increasing rate after with a velocity or speed is maintained Force is a main cause of Acceleration andacceleration is seen at a change in velocity

So in the selection of the option consider these points of acceleration

Acceleration cause bodies to move at an increasing rate after which a velocity or speed is maintained Force is a main cause of Acceleration andacceleration is seen at a change in velocity

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