Physics College

A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What is the 3250 kg car’s initial velocity calculated to the nearest tenth? Record your answer in the boxes below. Be sure to use the correct place value.

Answers

Answer 1

Answer:

2.1 m/s

Explanation:

According to law of conservation of momentum;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the common velocity

Given

m1 = 2150kg

m2 = 3250kg

u1 = 10.0m/s

u2 = ?

v = 5.22m/s

Substitute and get u2

2150(10) + 3250u2 = (2150+3250)5.22

21,500 + 3250u2 = 5400(5.22)

3250u2 = 28,188 - 21500

3250u2 = 6688

u2 = 6688/3250

u2 = 2.1 m/s

Hence the 3250 kg car’s initial velocity has an initial velocity of  2.1 m/s

Related Questions

A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?

Answers

Answer:

50 km/h

Explanation:

200 km = 4 hours

200/4=50

50km/h

what is mean by combination reaction ?​​

Answers

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

A 96 kg man lying on a surface of negligible friction shoves a 75 g stone away from himself, giving it a speed of 7.2 m/s. What speed does the man acquire as a result?

Answers

Answer:

7.21m/s

Explanation:

Using the law of conservation of momentum expressed as;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the mass of the man and the stone respectively

u1 and u2 are their respective initial velocities

v is their final common velocity

Given

m1 = 96kg

m2 = 75g = 0.075kg

u1 = ?

u2 = 0m/s (initial speed of the stone)

v = 7.2m/s

Substitute into the firmula and get u1

96u1 + 0.075(0) = (96 + 0.075)(7.2)

96u1 = 96.075(7.2)

u1 = 691.74/96

u1 = 7.21m/s

Hence the man acquired a speed of 7.21m/s

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