90
1
39
is the
In the following decay equation,
90
Sy →
38
et
90
39
-1
A. alpha particle
B. parent element
C. daughter element
D. beta particle

Answers

Answer 1

Answer:

D. beta particle

Explanation:

Number of protons increases from 38 to 39 indicating beta decay (only one proton up from parent isotope to daughter isotope) Also atomic mass (on top of an isotope), 90 stays the same as beta particle is very small.


Related Questions

Help naming this plzzzzzzzzzzzzz

Answers

Answer:

A. 3-chloro-1-methylcyclobutane.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer that the name of this compound is A. 3-chloro-1-methylcyclobutane because of the fact that the parent chain is a cyclobutane which starts by the methyl radical as it has the priority over the chlorine radical which is actually named first at the third carbon (clockwise).

Therefore the name is given in A, accordingly to the IUPAC rules of nomenclature.

Regards!

A gaseous mixture containing 7.00 moles of nitrogen, 2.50 moles of oxygen, and 0.500 mole of helium exerts a total pressure of 0.900 atm. What is the partial pressure of the nitrogen?

Answers

Answer:

Partial Pressure = 0.630atm

Explanation:

The total pressure of a mixture of gases is equal to the partial pressure of those gases. The partial pressure of a gas is defined as:

Partial pressure = Mole Fraction * Total pressure

The mole fraction of a gas is the ratio between the moles of the gas and the total moles.

To solve this question we need to find the mole fraction of nitrogen to find its partial pressure:

Mole Fraction nitrogen:

7.00 moles Nitrogen / (7.00moles N2 + 2.50moles O2 + 0.500moles He) = 0.700 = Mole fraction.

Partial Pressure = 0.700* 0.900atm

Partial Pressure = 0.630atm

Calculate the concentration of ammonium nitrate in a solution prepared by dissolving 3.20 g of the salt in enough water to make 100. mL of solution, then diluting 2.00 mL of this solution to a volume of 25.00 mL.

Answers

Answer:

.032 M .

Explanation:

Molecular weight of ammonium nitrate is 80  .

3.2 g = 3.2 / 80 moles

= .04 moles

volume = 100 mL = 0.1 L

Molarity of 100 mL solution = .04 moles / 0.1 L

= 0.4 M solution.

Now 2 mL solution of 0.4 M is diluted to a volume of 25 mL .

Using the formula S₁ V₁ = S₂V₂

0.4 M x 2 mL = S₂ x 25 mL

S₂ = .4 x 2 / 25

= .032 M

Hence required concentration is .032 M .

Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is ________ M.
A) 0.0735
B) 0.0762
C) 0.0980
D) 0.0709
E) 0.00253

Answers

Answer: The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.

Explanation:

Given: Concentration of hydrogen fluoride = 0.126 M

Concentration of fluoride ions = 0.1 M

Volume of HCl = 9.0 mL

Concentration of HCl = 0.01 M

Volume of HCl = 25.0 mL

Moles of [tex]F^{-}[/tex] ions are calculated as follows.

[tex]Moles of F^{-} = molarity \times volume\\= 0.1 M \times 0.025 L\\= 0.0025 mol[/tex]

Moles of HF are as follows.

[tex]Moles of HF = Molarity \times Volume\\= 0.126 M \times 0.025 L\\= 0.00315 mol[/tex]

Moles of HCl are as follows.

[tex]Moles of HCl = Molarity \times volume\\= 0.01 M \times 0.009 L\\= 0.00009 mol[/tex]

Now, reaction equation with initial and final moles will be as follows.

                        [tex]H^{+} + F^{-} \rightarrow HF[/tex]

Initial:      0.00009  0.0025    0.00315

Equilibrium:      (0.0025 - 0.00009)    (0.00315 + 0.00009)

                                = 0.00241                    = 0.00324

Total volume = (9.00 mL + 25.0 mL) = 34.0 mL = 0.034 L

Hence, concentration of fluoride ions is calculated as follows.

[tex]Concentration = \frac{moles}{volume}\\= \frac{0.00241 mol}{0.034 L}\\= 0.0709 M[/tex]

Thus, we can conclude that concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.

Curium – 245 is an alpha emitter. Write the equation for the nuclear reaction and identify the product nucleus.

Answers

Answer:

Please find the complete solution in the attached file.

Explanation:

Is sucrose classified as aldose or ketose?

Answers

Answer:

Because sucrose is a complex disaccharide, it is not classified as either an aldose or a ketone. Instead, it is a compound that contains both. glucose is aldose sugar and fructose is a ketose sugar.

An example of a molecular compound that obeys the octet rule in which all atoms have a zero formal charge is:

Answers

Answer:

[tex]NCl_3[/tex]

Explanation:

An octet rule is a thumb rule in the chemical sciences in which there is a natural tendency for an atom to prefer eight electrons in the valence shell of the atom. When there are less than eight electrons in the atom, they react with other atoms and form more stable compounds.

In the context, nitrogen trichloride, [tex]NCl_3[/tex], is an example of molecular compound which obeys the octet rule having a zero formal charges on each atom of the compound.

difference between hygroscopic and deliquescent substance with of each​

Answers

Answer:

The water soluble substance which absorb moisture from the air and then dissolve on the absorbed moisture to change into liquid taste are called deliquescent substances whereas the substances which absorb moisture from air but do not change their state are called hygroscopic substances.

Answer:

Hygroscopic substances absorb moisture from the air but do not dissolve in it, whereas substance that undergo deliquescence dissolves in the water vapour that is absorbed from the air, forming a liquid solution

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Answers

Answer:

please translate in english

Identify the most and the least acidic compound in each of the following sets. Leave the remaining answer in each set blank. a) difluoroacetic acid: _______ fluoroacetic acid: _______ trifluoroacetic acid: _______ b) 2-chlorobutanoic acid: _______ 4-chlorobutanoic acid: _______ 3-chlorobutanoic acid: _______ c) cyclohexanol: _______ phenol: _______ benzoic acid:

Answers

Explanation:

The given set of options are:

a) difluoroacetic acid: _______ fluoroacetic acid: _______ trifluoroacetic acid: _______

b) 2-chlorobutanoic acid: _______ 4-chlorobutanoic acid: _______ 3-chlorobutanoic acid: _______

c)cyclohexanol: _______ phenol: _______ benzoic acid:

A strong acid is one whose conjugate base is stabilized either by resonance or -I effect.

a) If -I groups are present on the carboxylic acid group then they stabilize the carboxylate anion (the conjugate base of the carboxylic acid) and give more strength to the carboxylic acid group. More the number of -I groups then more will be the strength of the carboxylic acid.

Among the given options,

Trifluoroacetic acid has three fluorine atoms in its structure thus it is a strong acid.

Fluoroacetic acid has only one fluorine atom in its structure. Hence it is the weak acid among the given options.

b) The -I groups should be nearer to the carboxylic acid group then it attains more stability.

If the distance of the -I group increases from the -COOH group then, the strength of the carboxylic acid group decreases.

So, the strongest acid is 2-chlorobutanoic acid.

The weak acid among them is 4-chlorobutanoic acid.

c) Among the given options benzoic acid is the strongest acid because due to resonance benzoate anion is stabilized more.

Here resonance exists in both phenyl group and [tex]-COO^-[/tex] group.

The weak acid is cyclohexanol.

Because cyclohexanolate anion is not stabilized by resonance.

Determine the type of alcohol corresponding to each given description or name. 1-pentanol 3-ethyl-3-pentanol 2-hexanol An alcohol with two other carbons attached to the carbon with the hydroxyl group_____.An alcohol with one other carbon attached to the carbon with the hydroxyl group____.An alcohol with three other carbons attached to the carbon with the hydroxyl group____.

Answers

Answer:

1). 1-pentanol - Primary

2). 3-ethyl-3-pentanol - Tertiary

3). 2-hexanol - Secondary

4). Alcohol with two other carbons attached to the carbon with the hydroxyl group - Secondary

5). Alcohol with one other carbon attached to the carbon with the hydroxyl group - Primary

6). Alcohol with three other carbons attached to the carbon with the hydroxyl group - Tertiary

Explanation:

The distinct types of alcohol have been matched with the categories above as per their descriptions provided. In chemistry, alcohols have been categorized into three different categories namely primary, secondary, and tertiary.

In the primary type, those alcohols are involved in which there is an association of hydroxyl group to a primary atom of carbon along with a minimum of two atoms of hydrogen. Example; ethanol.

In the secondary type, the alcohols have an association of carbon atoms to hydroxyl with a single atom of hydrogen and has a formula of '-CHROH.' Example: 2 - propanol.

In the tertiary alcohols, here the association is between the hydroxyl group with the carbon atom that is saturated and possessing 3 atoms of carbon associated with it. It has a formula of '-CR2OH.' Example:  3-ethyl-3-pentanol, -tert -butyl alcohol, etc.

One of the fastest ways to dissolve a solid in a liquid requires adding energy and exposing as much surface area of the solid as possible. Which of the following would be the quickest way to dissolve the largest possible amount of gelatin powder in a quart of water?
(1) Use cold water and stir it as the gelatin powder is added.
(2) Use hot water and stir it as the gelatin powder is added.
(3) Place the gelatin powder in a chilled container and pour lukewarm water over it.
(4) Place the gelatin powder in water that contains ice cubes.
(5) Place the gelatin powder and water at room temperature in a closed container and shake it.

Please help me.​

Answers

Place the gelatin powder in a chilled container and pour lukewarm water over it

Answer:

2

Explanation:

I think because the hot water would enable it to dissolve much faster as compared to cold water.its like when adding sugar to a cup of tea it would dissolve much faster in hot tea rather than cold tea

what happens to water molecules when water vapor change to ice

Answers

Answer:

When the water vapor is cooled by the ice, the water molecules slow down more than in the cup without the ice. This allows their attractions to bring more molecules together to become liquid water.

Question 2 10
10 Points
Which of the following chemical equations depicts a balanced chemical equation?
O A. AgNO, Kcro > KNO, Agro,
OB. AgNO3 + Kycro, » 2K NO; + Agro,
C.3AgNO3 + 2K,Cro--> 3KNO3 + 249900,
D. 2AgNO, K Cro-> 2KNO; 1Cro,
Resol Selection

Answers

Answer:

2AgNO, K Cro-> 2KNO; 1Cro,

The number of moles of H in 5 moles of glucose (C6H1206) is

Answers

Answer:

60 mols hydrogen

Explanation:

1 mol of glucose contains 12 mols of Hydrogen

5 mols of glucose contains 12 * 5 = 60 moles of hydrogen.

Calcium carbonate reacts with stomach acid (HCI) according to the following equation:
Caco, (s) + 2 HCl(aq) - CaCl, (aq) + CO2(g) + H20 (1)
Tums, an antacid, contains CaCo3. If Tums is added to 25.7 mL of a 0.738 M HCl solution, how many grams of Co, are produced?

Answers

Answer:

0.418 g of CO₂ will be produced

Explanation:

Equation of the reaction is given below:

CaCO₃ (s) + 2HCl (aq) ----> CaCl₂(aq) + CO₂ (g) + H₂O (l)

From the equation of reaction , 1 mole of CaCO₃ reacts with 2 molemolesmof HCl to produce 1 mole of CO₂

Number of moles of HCl in 25.7 ml of a 0.738 M solution of HCl is obtained using the formula below:

Number of moles = molarity × volume (Litres)

Number of moles of HCl = 0.738 M × 25.7 mL × 1 L/1000 mL = 0.0190 moles

Since the antacid, Tums will be excess, the limiting reactant is HCl

2 moles of HCl produces 1 mole of CO₂

0.0190 moles of HCl will produce 0.0190 moles ÷ 2 = 0.0095 molesof CO₂

Mass of 0.0095 moles of CO₂ = Numbe of moles × molar mass of CO₂

Molar mass of CO₂ = 44.0 g/mol

Mass of CO₂ produced = 0.00950 moles × 44.0 g/mol = 0.418 g of CO₂

Therefore, 0.418 g of CO₂ will be produced if Tums is added to 25.7 mL of a 0.738 M HCl solution

which of these is not a gas? A. hydrogen B. gravity C. Oxygen D. heluim

Answers

Answer:

B. Gravity

Explanation:

Gravity is a force, not a gas :)

Answer:

B: Gravity

Explanation:

gravity pulls on the gad

Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a Choose... that contains Choose... carbons. The keto- part of the name indicates that fructose contains Choose... functional group. Fructose can combine with glucose to form sucrose. Therefore, sucrose is a Choose... .

Answers

Answer:

carbohydrate, 6, a carbonyl, disaccharide

Explanation:

Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a carbohydrate that contains 6 carbons. There are more isomers that are ketohexoses.

The keto- part of the name indicates that fructose contains a carbonyl functional group. In ketones, the carbonyl is in an inner carbon.

Fructose can combine with glucose to form sucrose. Therefore, sucrose is a disaccharide. Disaccharides are formed by the bonding of 2 monosaccharides.

A ligand is a molecule or ion that acts as a

Answers

Answer:

Lewis base/electron pair donors

Explanation:

Ligands are ions or neutral molecules which bond together with a central ion. They act as election pair donors, also known as Lewis bases, while the central ion they are connected to acts as the acceptor.

Therefore, a ligand is a molecule or ion that acts as a Lewis base/electron pair donors

BaCl2+Al(NO3)3=Ba(NO2)3+AlCl3

How many moles of barium nitrate are produced if 4.25 moles of aluminum nitrate are used in the reaction?

Answers

Answer:

6.75 moles of Ba(NO₃)₂.

Explanation:

The balanced equation for the reaction is given below:

3BaCl₂ + 2Al(NO₃)₃ —> 3Ba(NO₃)₂ + 2AlCl₃

From the balanced equation above,

2 moles of Al(NO₃)₃ reacted to produce 3 moles of Ba(NO₃)₂

Finally, we shall determine the number of mole of Ba(NO₃)₂ produced by the reaction of 4.25 moles of Al(NO₃)₃. This can be obtained as illustrated below:

From the balanced equation above,

2 moles of Al(NO₃)₃ reacted to produce 3 moles of Ba(NO₃)₂.

Therefore, 4.25 moles of Al(NO₃)₃ will react to produce = (4.50 × 3)/2 = 6.75 moles of Ba(NO₃)₂.

Thus, 6.75 moles of Ba(NO₃)₂ were obtained from the reaction.

The smallest atoms can themselves exhibit quantum-mechanical behavior. Calculate the de Broglie wavelength (in picometers) of a hydrogen atom traveling at 490 m/s. Express your answer using three significant figures.

Answers

Answer:

810 pm

Explanation:

Step 1: Given and required data

Velocity of the atom (v): 490 m/sMass of a hydrogen atom (m): 1.67 × 10⁻²⁷ kgPlanck's constant (h): 6.63 × 10⁻³⁴ J.s

Step 2: Calculate the de Broglie wavelength of the hydrogen atom

We will use de Broglie's equation.

λ = h / m × v

λ = 6.63 × 10⁻³⁴ J.s / 1.67 × 10⁻²⁷ kg × 490 m/s = 8.10 × 10⁻¹⁰ m

Step 3: Convert 8.10 × 10⁻¹⁰ m to picometers

We will use the conversion factor 1 m = 10¹² pm.

8.10 × 10⁻¹⁰ m × 10¹² pm/1 m = 810 pm

Which has the greater amount of energy, the mixture of hydrogen and oxygen or the water?
Suggest a reason for your answer.

Answers

Answer:

water

Explanation:

because its molecular formula is H2O which clarify that, their is the two hydrogen element used in water meanwhile,

mixture of hydrogen and oxygen contain just one hydrogen element and only one oxygen element.

What is the specific heat of a substance if 373 J is required to raise the temperature of a 312 g sample by 15°C?

Answers

Answer:

0.080 J/g °C

General Formulas and Concepts:

Thermodynamics

Specific Heat Formula: q = mcΔT

q is heat (in J)m is mass (in g)c is specific heat (in J/g °C)ΔT is change in temperature (in °C)

Explanation:

Step 1: Define

[Given] q = 373 J

[Given] m = 312 g

[Given] ΔT = 15 °C

[Solve] c

Step 2: Find Specific Heat

Substitute in variables [Specific Heat Formula]:                                        373 J = (312 g)c(15 °C)Multiply:                                                                                                        373 J = (4680 g °C)cIsolate c:                                                                                                        c = 0.079701 J/g °C

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

0.079701 J/g °C ≈ 0.080 J/g °C

Topic: AP Chemistry

Unit: Thermodynamics

When you burn a birthday candle, you may wonder whether the fire you see is matter. The
flame consists of hot, glowing gases, such as oxygen, carbon dioxide, water vapor, and
parts of the candle that have been vaporized. The heat and light given off are forms of
energy. The smoke contains ash and unburned particles.
a. From the above description of a candle flame, list at least three things that are matter and
three things that are not mattel. (6 points)
Matter
Not Matter

Answers

Answer:

matter

1. Candle. not matter

1. light

2. Unburned Particles

2. heat

3. Ash

3. energy

Explanation:

1.The candle is experiencing a solid phase into a gas phase because the heat given off causes smoke.

2. Chemical Potential Energy to Heat EnergyThe candle has Chemical Potential Energy then when it gets lit by the flame heat energy is released.

What is it?? plzzzz help

Answers

The answer is D.

A symmetrical molecule cancels out the effects of polar bonds.
it’s D took the test

Part A
If the theoretical yield of a reaction is 23.5 g and the actual yield is 14.8 g, what is the percent yield?

Answers

Answer:

[tex]\boxed {\boxed {\sf 63.0 \%}}[/tex]

Explanation:

The percent yield is the ratio of the actual yield to the theoretical yield.

[tex]percent \ yield = \frac{actual \ yield}{theoretical \ yield} * 100[/tex]

The actual yield is the amount obtained from performing a chemical reaction. For this problem, it is 14.8 grams. The theoretical yield is the potential amount from performing a chemical reaction at maximum performance. For this problem, it is 23.5 grams.

We can substitute the known values into the formula.

[tex]percent \ yield= \frac{ 14.8 \ g}{23.5 \ g}*100[/tex]

Divide.

[tex]percent \ yield = 0.629787234043*100[/tex]

Multiply.

[tex]percent \ yield = 62.9787234043[/tex]

The original measurements for the theoretical and actual yields have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place.

The 7 to the right, in the hundredths place, tells us to round the 9 up to a 0. Since we rounded up to 0, we have to move to the next place to the left and round the 2 up to a 3.

[tex]percent \ yield \approx 63.0[/tex]

The percent yield is approximately 63.0 percent.

complete the following steps.
Remember to follow lower numbered rules first.
K2S(aq) + CO(NO3)2(aq) COS (?) + KNO3 (?)
a. Write a balanced chemical equation. (1 pt)
b. If a reaction occurs, write the balanced
chemical equation with the proper states of matter
(i.e. solid, liquid, aqueous) filled in. If no reaction
occurs, write “No reaction.” (1 pt)
c. If a reaction occurs, write the net ionic equatibn
for the reaction. If no reaction occurs, write “no
reaction.” (1 pt)

Answers

Answer:

See explanation

Explanation:

a) The balanced reaction equation is;

K2S + CO(NO3)2 ------> COS + 2 KNO3

b) When we include the states of matter, we have;

K2S(aq) + CO(NO3)2(aq) ----> COS(s) + 2 KNO3(aq)

c) The complete ionic equation is;

2K^+(aq) + S^2-(aq) + Co^2+(aq) + 2NO3^-(aq) ----> CoS(s) + 2K^+(aq) + 2NO3^-(aq)

Net ionic equation;

Co^2+(aq) + S^2-(aq) ----> CoS(s)

Explain the term global warming​

Answers

Answer: A gradual increase in the overall temperature of the earth's atmosphere generally attributed to the greenhouse effect caused by increased levels of carbon dioxide, chlorofluorocarbons, and other pollutants.

Explanation:

What is the difference between acids and strong acids?
a. Strong acids produce all of their H30+ ions
b. Strong acids release all of their H30+ ions
c. Strong acids produce all of their OH- ions
d.Strong acids release all of their OH ions

Answers

Answer:

A and b are the both the answers

Combustion of 5.024 mg of coniine yields 13.90 mg CO2 and 6.048 mg of H2O. What is the empirical formula for coniine, listing the elements in the order C, H, N?

Answers

Answer:

C8H17N

Explanation:

Number of moles of c

13.90 × 10^-3/44 g/mol × 1 = 0.000316 moles

Mass of C= 0.000316 moles × 12 = 0.00379 g

Number of moles of H

6.048 × 10^-3/18 × 2 = 0.000672 moles

Mass of H

0.000672 moles × 1 = 0.000672 g

Mass of N

0.005024 - [0.00379 g + 0.000672 g]

= 0.000562 g

Number of moles of N

0.000562 g/14 = 0.00004 moles

Divide through by the lowest ratio;

C= 0.000316/0.00004, H= 0.000672 /0.00004, N= 0.00004/0.00004

C= 8, H = 17, N = 1

Hence the empirical formula is;

C8H17N

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