Answer:
9
Step-by-step explanation:
So it kinda easy but ill Just give u the answer :D
Answer:
9-3÷ 1/3+1= 9
Step-by-step explanation:
I can't do solution sorry.
Can someone help me with this please
Answer:
y=1/2x
Step-by-step explanation:
Answer:
10
9
8
7
6
5
4
3
2
1
0 1 2 3 4 5 6 7 8 9 10
Step-by-step explanation:
So the arrow is pointing at 10 and 5
Answer 10 5
Not 5
its 10 5
So the answer is 10 5
Jonnell has finished 20% of an art project that has taken him a total of 3 hours so far. If he continues to work at the same rate, how many hours will it take for him to complete the entire project?
Answer:
15 hours
Step-by-step explanation:
20%=3 hours
times 5 both sides
100%=15 hours
(2x+y)2-y2 if x=-3 y=4 and z=-5
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
Which of the following is true?
|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5
Answer:
|-4| < |-5|
Step-by-step explanation:
because if modules is given sub sign will be deducate
pasagot po please
answer it please
Answer:
24 I hope help you yieeeeeee
Answer:
ummmmmmmmmmm itsssssssss
Step-by-step explanation:
Answer all of the following questions. 3 Points a question. ALSO NO LINKS!
Is 2 a prime number?
Is 3 a prime number?
Is 11 a prime number?
Is 18 a prime number?
Is 20 a prime number?
Is 27 a prime number?
Answer:
no
yes
yes
no
no
yes
Step-by-step explanation:
a prime number cant be devided by any thing other than itself or one
Answer:
Step-by-step explanation:
Is 2 is 3 is 11 is 18 is 20 is 27
fill in the blank with the letter of the description that best matches the term for the verb porter, match the subject pronoun with the correct form of the verb. i'll mark Brainliest if the answers are correct.
A. portons
B. porte
C. portez
D. portes
E. portent
FILL IN THE BLANK
je ____
tu ____
nous ____
vous ____
ils ____
Step-by-step explanation:
je........porte
tu.......portes
nous.......portons
vous........portez
ils......portent
Can someone help’ it’s due today pls help pls pls
Answer:
MQP = 138
Step-by-step explanation:
Since the angle bisector always divides the angle in half exactly, we know both of the angle measures we have are the same, and set it up like this: 5x + 19 = 2x + 49 (subtract 2x from both sides) 3x + 19 = 49 (subtract 19 on both sides) 3x = 30 (divide by 3) x = 10
Substitute that x value (10) into the original equations in place of x for each angle to get MQN = 69 and NQP = 69
Add the two values to get 138. MQP = 138
Answer:
138
Step-by-step explanation:
QN bisects ∠MQP. ⇒ ∠MQN = ∠NQP
5x + 19 = 2x + 49
Subtract 19 from both sides
5x = 2x + 49 - 19
5x = 2x + 30
Subtract 2x from both sides
5x -2x = 30
3x = 30
x = 30/3
x = 10
∠MQN = 5x + 19
= 5*10 + 19
= 50 +19
= 69
∠MQP = ∠MQN +∠NQP = 69 + 69 = 138
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
Express the tan G as a fraction in simplest terms.
Answer:
[tex]\frac{\sqrt{70} }{5}[/tex]
Quiz 2
You might need: Calculator
Naoya read a book cover to cover in a single session, at a rate of 55 pages per hour. After 4 hours, he had
350 pages left to read.
Let y represent the number of pages left to read after a hours.
Complete the equation for the relationship between the number of pages left and number of hours.
y =
Total pages read after 4h
[tex]\\ \sf\longmapsto 4(55)=220pages[/tex]
Pages left=350
Now
[tex]\\ \sf\longmapsto y=350+220[/tex]
[tex]\\ \sf\longmapsto y=570[/tex]
the common multiple of 4 and 20 is? a.3 b.4 c.8 d.20
Answer:
i belive its A
Step-by-step explanation: hope this helps :)
Answer:
B. 4
Step-by-step explanation:
4 times 5 is 20 and 20 divided by 5 is 4
Use the information given to find the equation of the line using the point-slope formula (y-y_1)=m(x-x_1)). Then convert your answer to slope-intercept form (y=mx+b).
y-intercept of 2 and (4,-1)
If it's possible please a explanation on how you solved it.
Answer:
y=[tex]-\frac{3}{4}[/tex]x+2
Step-by-step explanation:
y=sx+2;
-1=4s+2;
s=-3/4;
y=[tex]-\frac{3}{4}[/tex]x+2
The greatest possible number whose digits are all even numbers from 1 to 9
Answer:
8642Step-by-step explanation:
Our even numbers from 1-9 are:
2,4,6,8The largest possible number using the even numbers once is 8642.
Hoped this helped
what is the answer to this question: 3.75x =60
Answer:
x = 16
Step-by-step explanation:
If 3.75x would equal to 60, then x would equal to 60/3.75, which would be 16
Hope this helps!
Help me this question is so hard i fried up my brain yesterday working on it for so long!!!!
Hello there! (:
The answer is 9.
3^4=3*3*3*3 (81)
3^2=9
81:9=9
So the answer is 9.
Hope it helps! If you have any question or query, feel free to ask! (:
~An excited gal
[tex]SparklingFlower[/tex]
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
BRAINLIEST, 5 STARS, AND A THANKS FOR WHOEVER HELPS!
Which statement about the answer to this problem is most accurate?
5\6−3\8=19\24
The answer 19\24 is reasonable because both fractions are closer to 1\2 than they are to 1, making the difference close to 0.
The answer 19\24 is reasonable because 5\6 and 3\8 are both closer to 1 than to 1\2, making the difference close to 0.
The answer 19\24 is not reasonable because 5\6 is closer to 1 than to 1\2, and 3\8 is close to 1\2, making the difference close to 1\2.
The answer 19\24 is not reasonable because 5\6 is closer to 1\2 than to 1, and 3\8 is closer to 0 than to 1\2, making the difference close to 1\2.
Answer:
The answer 19\24 is not reasonable because 5\6 is closer to 1 than to 1\2, and 3\8 is close to 1\2, making the difference close to 1\2.
Step-by-step explanation:
Answer:
1/2 1 0
Step-by-step explanation:
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
Find the perimeter of a rectangle whose length is 12 longer than its width
with an area of 45 square feet. To earn 5 points write the mathematical
sentence, the value of Length, width and perimeter
Answer:
l = 21
w = 9
P = 60
Step-by-step explanation:
l = 12 + w
A = l*w = 45
substitute l = 12 +w
45 = (12 + w) * w
45 = 12w + w^2
w^2 + 12w - 45 = 0
w^2 + 2*6*w +36 = 45 + 36 (added 36 on both sides 6^2)
(w + 6) ^2 = 45+36 = 81
w + 6 = +-9
As width cannot be negative w = 9
so l = 12 + 9
= 21
Perimeter = P = 2 (l + b)
= 2 ( 21 + 9)
= 2 (30)
= 60
What is 8 times larger than 3
8 x 3 = 24 for should be 24
Only because 8 times larger than three seems like a multiplication problem..
I hope this helps if it is correct!
Answer:
(8+1) x 3 = 27
Step-by-step explanation:
this is correct rather than 8 x 3 = 24 because both sides of 8x3=24 are equal rather than the sum being greater than the statement.
Please I need help ASAP. Can someone help me?
Answer: The second bubble thing is correct you have picked the wrong one.
Can someone help plz
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
the sum of three whole numbers in a row is 57. what are the three numbers?
Answer:
18, 19, 20
Step-by-step explanation:
(n) + (n + 1) + (n + 2) = 57
3n + 3 = 57
3n = 57 - 3 = 54
n = 54/3 = 18
three numbers are 18, 18+1, 18+2
18, 19, 20
Answer:
18,19,20
Step-by-step explanation:
x + (x+1) + (x+2) = 57
x + x + 1 + x + 2 = 57
Combine like terms
3x + 3 = 57
subtract 3 from both sides
3x = 54
divide both sides by 3
x = 18
The answer is 18, 19, 20
Since we know the value of x, we can look at it like this:
x + (x+1) + (x+2) --- > 18 + (18+ 1) + (18+2) --> 18 + 19 + 20
Before deciding whether to fly or drive, the family decided to estimate a budget of $1,400 for airfare. One airline has
several different airfares and charges $25 round-trip for each bag that is checked. Since there are 4 members of the
family and each person would check 1 bag, Luis wrote the equation 4(t + 25) = 1,400 to find the maximum cost
per ticket, t, that will fit their budget.
What is the maximum cost per ticket that will be in their budget?
325
I hope that helps
what is the awnser and solve for C
2c=6–3c
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
[tex]\fbox \colorbox{black}{ \colorbox{white}{C} \: \: \: \: \: \: \: \: \colorbox{white}{ = } \: \: \: \: \: + \colorbox{white}{6/5}}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
Let's find the value of c ~
[tex]2c = 6 - 3c[/tex][tex]2c + 3c = 6[/tex][tex]5c = 6[/tex][tex]c = \dfrac{6}{5} \: \: or \: \: 1.2[/tex]Answer:
c= -6
Step-by-step explanation:
2c -6 = 3c
we move all to the left
2c -6 (3c)= 0
add everything and the variables
-1c - 6 = 0
move all terms containing c to the left everything else to the right
-1c = 6
c=6/-1
c=-6
which rotation about its center will carry a regular hexagon onto itself
PLEASE HELP ME!!! jacky starts biking to meet up with her friend. she knows that if she bikes at a speed of 10 mph, she will be 3 minutes late. jacky also know that if she bikes at a speed of 12 mph, she will be there 2 minutes before they agree to meet. how much time does she have left before the appointed time?
Answer:
27s
Step-by-step explanation:
d = distance to rendezvous point in miles
t = time of arrival at 10mph, i.e. 3 mins later than appointed time
10 mph = 10 miles per hour = ¹/₆ miles per min
12 mph = ¹/₅ miles per min
t = d/(¹/₆)
t = 6d
5 min = ¹/₁₂ hr
t - ¹/₁₂ = d/(¹/₅)
t = 5d + ¹/₁₂
Elimination of t:
6d = 5d + ¹/₁₂
d = ¹/₁₂ mi
t = 6(¹/₁₂)
t = ¹/₂ min
Time left to appointed time = ¹/₂ - ³/₆₀
= ¹⁰/₂₀ - ¹/₂₀
= ⁹/₂₀.min → 27 seconds
Answer:
27 min
Step-by-step explanation:
rsm
