Answer:
A. width = 13.5 ft; area = 182.3 ft2
Step-by-step explanation:
Suppose you have 54 feet of fencing to enclose a rectangular dog pen. The function A = 27x – x2, where x = width, gives you the. Answer: The width of the dog pen is 13.5 ft and the area is 182.3 square feet.
A shipping container is in the shape of a right rectangular prism with a length of 2.5 feet, a width of 13 feet, and a height of 11 feet. The container is completely filled with contents that weigh, on average, 0.55 pounds per cubic foot. What is the weight of the contents in the container, to the nearest pound?
Answer:
Volume = 2.5 x 13 x 11
Volume = 357.5
357.5 x 0.55 = 196.625, which can be rounded up to 197.
So, the correct answer is 197 pounds.
Let me know if this helps!
Find x (Round to the nearest tenth). PLS HURRY
Answer:
x = 28.4°
Step-by-step explanation:
The cos(x) = 15/17 ≈ 0.88
The acos(0.88) = 28.4°
Find the area of the shaded region.
8 in
24 in
Answer:
96 in^2
Step-by-step explanation:
area of rectangle: 24*8=192
Area of triangle: (1/2)*base*height
= .5 * 8 * 24
=192/2
=96
area of shaded=rectangle - triangle
= 192-96
which is also just 192/2
so it is 96
Select the point that is a solution to the system of inequalities.
y< x2 + 6
y> x2 - 4
The only point that is a solution to the system of inequalities is (C) (2, 6).
How to determine inequalities?To solve this problem, substitute each of the points into the inequalities.
For point (A), y < (4)² + 6 and y > (4)² − 4.
This simplifies to y < 22 and y > 12.
However, 2 is not greater than 12, so (A) is not a solution.
For point (B), y < (0)² + 6 and y > (0)² − 4.
This simplifies to y < 6 and y > −4.
However, 8 is not less than 6, so (B) is not a solution.
For point (C), y < (2)² + 6 and y > (2)² − 4.
This simplifies to y < 10 and y > 0.
6 is less than 10 and greater than 0, so (C) is a solution.
For point (D), y < (−2)² + 6 and y > (−2)² − 4.
This simplifies to y<2 and y>−8.
-4 is not greater than -8, so (D) is not a solution.
Therefore, the only point that is a solution to the system of inequalities is (C).
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Identify the function given y= -9/4
Answer:
the function is a y-intercept
Step-by-step explanation:
y=mx+b is the slope intercept formula, m being the slope and b being the y-intercept, meaning y=b, so b=-9/4.
Because it says y=-9/4, we can assume that m, or the slope equals 0.
so when you plug it in, you get
y=0x-9/4
y=-9/4
An angle measures 75.2° more than the measure of its complementary angle. What is the measure of each angle?
Answer:
x = complement
x + 5.2 = first angle (5.2 more than complement)
measure of two complementary angles add up to 90.
x + x+ 5.2 = 90
2x = 84.8
x = 42.4
other angle = x + 5.2 = 42.4 + 5.2 = 47.6
hope it's help you.....!!!!!
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Step-by-step explanation:
Hope it will help you .
.
.
.
The scores of players on a golf team are shown in the table. The team’s combined score was 0. What was Travis’s score?
Answer:here’s the table
Step-by-step explanation:
Celina -3
Jannie 3
Sami 1
Ted 4
Travis ??
Answer:
Step-by-step explanation:
-5
ate
at?
20) A triangular garden has sides that
1
5
6- 7
feet.
6
What is the perimeter of the garden?
Answer:
Since all the three sides of the triangle are of equal length, we can find the perimeter by multiplying the length of each side by 3. 20 + 20 + 20 = 3 × 20 = 60 cm.
Can someone please answer B (PICTURE)
Answer:
The question is asking for the perimeter. There are three ways to answer this depending on the assumptions though so I'll let you choose.
Assumptions are basically the different scenarios
1st scenario being the trim covers the carpet and the tile, they'd need 48m of trim (12+12+4+8+8+4)
2nd scenario in which the trim covers the carpet but not the tiled area, they'd need 44m of trim (12+12+4+8)
3rd scenario where the trim only covers the the tiled area, 4m of trim
(just 4 since the tile only touches 4m of the wall)
Hope this helps!
Step-by-step explanation:
trim is just the perimeter since it covers the base of the wall
What are the solutions to the quadratic equation (5y + 6)2 = 24?
y = StartFraction negative 6 + 2 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction negative 6 minus 2 StartRoot 6 EndRoot Over 5 EndFraction
y = StartFraction negative 6 + 2 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction 6 minus 2 StartRoot 6 EndRoot Over 5 EndFraction
y = StartFraction negative 4 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction negative 8 StartRoot 6 EndRoot Over 5 EndFraction
y = StartFraction 4 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction 8 StartRoot 6 EndRoot Over 5 EndFraction
there are two solutions:
a) y = [tex]\frac{-6+2\sqrt{6} }{5}[/tex]
b) [tex]y = \frac{-6-2\sqrt{6} }{5}[/tex]
Answer:
it's A
Step-by-step explanation:
Trust me I got the question right on the quiz
Find AC (Round to the nearest tenth) PLS HURRY
Answer:
Does the answer help you?
what is the simplification of 9^8 / 9^7?
Answer:
9
Step-by-step explanation:
We know that a^b / a^c = a^(b-c)
9^8 / 9^7
9^(8-7)
9^1
9
What error did Leah make?
Answer:
the lines arent parallel, so you cant use corresponding angles theorem
The error is corresponding property does not apply.
What are parallel lines?Parallel lines are those lines that are equidistant from each other and never meet, no matter how much they may be extended in either directions. For example, the opposite sides of a rectangle represent parallel lines.
We know that when two lines are parallel they the following property:
Alternate interior angleCorresponding angleco- interior angles.As, there is no parallel lines line.
So, the measurement if <1 = 88 can't be true because corresponding doesn't apply.
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A boat travels 12 km upstream and 40 km downstream in 8 hours. It can go 16 km upstream and 32 km downstream in the same time. Find the speed of the boat in still water and the speed of the stream.
the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h
Let's define the variables:
B = speed of the boat in still water.
S = speed of the stream.
When the boat travels downstream, the total speed of the boat will be equal to the sum of the speed of the stream and the speed of the boat in still water:
speed = B + S
When the boat goes downstream, the speed will be:
speed = B - S
Now, also remember the relation:
speed*time = distance.
The given information is:
In 8 hours the boat can:
go 12 km upstream and 40km downstream.
We now need to define another variable, T, as the time that the boat travels upstream.
Then we can write this as:
12km = (B - S)*T
If the boat travels T hours upstream, and travels for a total of 8 hours, then the amount of time that travels downstream is 8h - T, then we can write:
40km = (S + B)*(8h - T)
Similarly, when we have:
"it can go 16 km upstream and 32 km downstream in the same time."
we can define a new variable T', and write:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
Then we have a system of 4 equations:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
40km = (S + B)*(8h - T)
12km = (B - S)*T
And we need to solve this for S and B.
To do it, we need to isolate one of the variables in one of the equations.
Let's isolate T in the last equation:
T = 12km/(B - S)
now we can replace that in the third equation to get:
40km = (S + B)*(8h - 12km/(B - S))
So now we have 3 equations:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
40km = (S + B)*(8h - 12km/(S - B))
Now we need to do the same thing, this time let's isolate T' in the first equation and replace it in the second one:
T' = 16km/(B - S)
Replacing it in the second equation we get:
32km = (S + B)*(8h - T')
32km = (S + B)*(8h - 16km/(B - S))
So now we have two equations:
40km = (S + B)*(8h - 12km/(B - S))
32km = (S + B)*(8h - 16km/(B - S))
Let's simplify these:
40km = 8h*(S + B) - 12km*(S + B)/(B - S)
32km = 8h*(S + B) - 16km*(S+ B)/(B - S)
Now we can multiply both equations by (B - S) to get:
40km*(S - B) = 8h*(S + B)*(B - S) - 12km*(S + B)
32km*(S - B) = 8h*(S + B)*(B - S) - 16km*(S+ B)
Let's keep simplifying this:
40km*(B - S) + 12km*(S + B) = 8h*(S + B)*(B - S)
32km*(B - S) + 16km*(S+ B) = 8h*(S + B)*(B - S)
Now we get:
52km*B - 28km*S = 8h*(S^2 + B^2)
48km*B - 16km*S = 8h*(S^2 + B^2)
Notice that the right side of these equations is the same thing, then we can write:
52km*B - 28km*S = 48km*B - 16km*S
(52km - 48km)*B = (28km - 18km)*S
4km*B = 10km*S
B = (10/4)*S
B = (5/2)*S
Now we can replace this in one of our two equations, let's use the first one:
48km*B - 16km*S = 8h*(S^2 + B^2)
48km*(5/2)*S - 16km*S = 8h*( S^2 + ( (5/2)*S)^2)
Now we can solve this for S
104km*S = 8h*( S^2 + 25/4*S^2)
104km*S = 8h*(29/4*S^2) = 48h*S^2
104km*S = 48h*S^2
dividing at both sides by S we get:
104km = 48h*S
104km/48h = S = 2.167 km/h
And using B = (5/2)*S
We can find the speed of the boat:
B = (5/2)*2.167 km/h = 5.418 km/h
Then:
the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h
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Land surveyors outlined a park as shown. What is the area of the park?
Answer:
70.875
Step-by-step explanation:
Area of park=Area of rectangle+Area of triangle
Area of park=13.5*4.8+(0.5)*(13.5)*0.9=70.875
Easton is going to invest $340 and leave it in an account for 8 years. Assuming the interest is compounded quarterly, what interest rate, to the nearest tenth of a percent, would be required in order for Easton to end up with $420?
Answer:
100.7%
Step-by-step explanation:
Since the interest is compounded quarterly, and there are 4 quarters per year, that would leave us with 32 quarters total where interest is acquired. Now, we need to find the interest rate, that would be required in order to end up with 420 dollars after 32 quarters.
We can setup a formula using our period of time and the money he invested into the bank:
[tex]340(x)^{32}=420[/tex]
We can divide 340 from both sides, and simplify the right side to 21 divided by 17:
[tex]x^{32}=\frac{21}{17}[/tex]
Taking the 32th root of 21/17 is equal to 1.00662, which is equal to 100.0662%. To the nearest tenth of a percent, this is equal to 100.7%.
I NEEEDDDD HELPPPP ITS URGENTTTTT!!!!!! I’ll mark you brainliest
Answer:
(x+2)^2 + (y-15)^-1 = 64
Step-by-step explanation:
plz mark brainlist
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112 A. Median: 102, Q1: 87, Q3: 113, IR: 28, outliers: none B. Median: 102, Q1: 87, Q3: 115, IR: 28, outliers: 68 C. Median: 102, Q1: 87, Q2: 115, IR: 28, outliers: none D. Median: 102, Q1: 87, Q3: 115, IR: 27, outliers: none
Answer:
Q1 = 87 ;
Q2 = 102 ;
Q3 = 115 ;
IQR = 28
OUTLIER = None
Step-by-step explanation:
Given the data:
111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112
Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152
Sample size, n = 15
The first quartile, Q1 = 1/4(n+1)th term
Q1 = 1/4(15+1)th term
Q1 = 1/4(16) = 4th term
Q1 = 87
The Median , Q2 = 1/2(n+1)th term
Q2 = 1/2(15+1)th term
Q2 = 1/2(16) = 8th term
Q2 = 102
The third quartile, Q3 = 3/4(n+1)th term
Q3 = 1/4(15+1)th term
Q3 = 3/4(16) = 12th term
Q3 = 115
The interquartile range, IQR = Q3 - Q1
IQR = (115 - 87) = 28
Q1 = 87 ;
Q2 = 102 ;
Q3 = 115 ;
IQR = 28
OUTLIER = None
Which of the following is equivalent to the expression below?
Answer:
4
Step-by-step explanation:
ln(e)=1 since ln= log_e
log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4
Answer:
D
Step-by-step explanation:
ln(e^4)
The 4 comes down in front of the natural log (ln). You get 4 ln(e)
The natural log of e (ln e ) is 1.
So the answer is 4 * 1 = 4
That may not be clear to you. We could try it another way.
e = 2.718281828
ln (2.718281828) = 1
ln(2.718281828)^4 = 4. The calculator gags until you get it right. You need the y^x key (or the x^y key of ^) It does come back with 4.
You have to monkey around with the calculator to get this to happen.
4. What is the domain?
What is the sum of the interior angles of a regular polygon with 13 sides?
giving 20 points!!
Answer:
1980
Step-by-step explanation:
13 sides
Number of sides n=13
The sum of interior angles of polygon =(2n−4)×90o
=(2×13−4)×90o
=(26−4)×90o
=22×90o
We get,
=1980
what is the length of the third side triangle?
Answer:
x = 8cm
Step-by-step explanation:
17² = 15² + x²
289 = 225 + x²
- x² = 225 - 289
x² = 64
x = √64
x = 8
Good Luck! :)[tex]{ \boxed{ \sf \color{blue}{answer}}}[/tex]
x = 8 cm
Step-by-step explanation:
17² = 15² + x²
289 = 225 + x²
x² = 225 - 289
x² = 64
x = √64
x = 8
___________________Teorema pythagoras
[tex]3x + 9 = 12[/tex]
Solve for x
Answer:
x=1
Step-by-step explanation:
3x+9 = 12
Subtract 9 from each side
3x+9-9=12-9
3x = 3
Divide by 3
3x/3 = 3/3
x=1
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]x = 1[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Calculating the answer...}}\\\\3x + 9 = 12\\-------------\\\rightarrow 3x + 9 - 9 = 12 - 9\\\\\rightarrow 3x = 3\\\\\rightarrow \frac{3x=3}{3}\\\\\rightarrow \boxed{x=1}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Will Mark Brainlest helppp plss
Answer:
you can ask from it will be easy for you actually I don't know answern
PLEASE HELP
What is the area of a triangle having a base of 6m and a height of 27m?
I really just need a answer so please don't joke around and do not send me a website just please with me the correct answer
Answer:
1/2b*h
1/2 6*27
162/2
81 is the answer
A piece of land is 20cm by 5cm. A portion of the land by size 10cm by 2cm was used to cultivate tomatoes. what is the area of the land?
Answer:
80cm^2
Step-by-step explanation:
20*5=100
10*2=20
100-20=80
Please hurry I will mark you brainliest
Given angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
Answer:
y = 3
Step-by-step explanation:
*As seen in the photo, the fact that EF = GF and the bisector being there makes EH = HG.
5y + 10 = 28 - y
*Add y to both sides.
6y + 10 = 28
*Subtract 10 from both sides.
6y = 18
*Divide both sides by 6.
y = 3
In triangle EFG, with angle bisector FH and equal lengths for EF and GF, the value of y is 3.
Use the concept of a triangle defined as:
A triangle is a 3-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.
Given that,
Angle EFG has an angle bisector FH.
EF = GF (the lengths of the corresponding sides of triangle EFG are equal).
EH = 5y + 10 (length of segment EH).
HG = 28 - y (length of segment HG).
To find the value of y,
Start by applying the angle bisector theorem in triangle EFG.
According to the theorem,
The ratio of the lengths of the segments formed by the angle bisector to the corresponding sides should be equal.
Since EF = GF,
Set up the following equation:
EH / HG = EF / FG
Substituting the given values, we have:
[tex]\dfrac{(5y + 10)}{ (28 - y)} = \dfrac{1} { 1}[/tex]
Cross-multiplying, we get:
5y + 10 = 28 - y
Combining like terms, we have:
6y = 18
Dividing both sides by 6, we find:
y = 3
Therefore, the value of y is 3.
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can a right triangle be obtuse?
I need help finding y
to solve for y, we must multiply by t on both side to get ride of the t in the denominator. By doing this, we will get:
[tex] {t}^{3} [/tex]
on the right side.
Subtracting 3, and we have successfully isolated y.
It would be impossible to get a quantitative value for y if we don't know the value of t.
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