5. If W(-10, 4), X(-3,-1), and Y(-5, 11) classify AWXY by its sides. Show all work to justify your
answer.​

Answer:

{(2,3), (-5,2), (1,8), (6,3), (-6, 2)

Step-by-step explanation:

The domain is the input and the range is the output

We need inputs of -6 -5 1 2 6

and outputs of 2 3 and 8

Answer:

D ). (-7,-4)

Step-by-step explanation:

To locate the position or the location of the centre of the circle we have to bear in mind that the center of the circle is the midpoint of the diameter line.

Formula for midpoint of a line is given below

Midpoint= (X1+x2)/2 ,(y1+y2)/2

Where X1= -2,y1= -3

X2= -12, y2= -5

The midpoint= (-2+(-12))/2,(-3+(-5))/2

Midpoint= (-2-12)/2,(-3-5)/2

Midpoint= (-14)/2,(-8)/2

Midpoint=( -7,-4)

The center of the circle is located at the point (-7,-4)

Answer:

x = 10

Step-by-step explanation:

2x/3 + 1 = 7x/15 + 3

(times everything in the equation by 3 to get rid of the first fraction)

2x + 3 = 21x/15 + 9

(times everything in the equation by 15 to get rid of the second fraction)

30x+ 45 = 21x + 135

(subtract 21x from 30x; subtract 45 from 135)

9x = 90

(divide 90 by 9)

x = 10

2x/3 + 1 = 7x/15 + 3

(find the LCM of 3 and 15 = 15)

(multiply everything in the equation by 15, then simplify)

10x + 15 = 7x + 45

(subtract 7x from 10x; subtract 15 from 45)

3x = 30

(divide 30 by 3)

x = 10

Answer:

A) distribution of x2 = ( 0.4167 0.25 0.3333 )

B) steady state distribution = [tex]\pi a \frac{4}{9} , \pi b \frac{2}{9} , \pi c \frac{3}{9}[/tex]

Step-by-step explanation:

Hello attached is the detailed solution for problems A and B

A) distribution states for A ,B, C:

Po = ( 1/3, 1/3, 1/3 )  we have to find the distribution of x2 as attached below

after solving the distribution

x 2 = ( 0.4167, 0.25, 0.3333 )

B ) finding the steady state distribution solving

[tex]\pi p = \pi[/tex]

below is the detailed solution and answers

Answer:

The expectation is  [tex]E(1 )= -\$ 1[/tex]

Step-by-step explanation:

From the question we are told that  

     The first offer is  [tex]x_1 = \$ 8000[/tex]

     The second offer is  [tex]x_2 = \$ 4000[/tex]

      The third offer is  [tex]\$ 1600[/tex]

      The number of tickets is  [tex]n = 5000[/tex]

      The  price of each ticket is  [tex]p= \$ 5[/tex]

Generally expectation is mathematically represented as

             [tex]E(x)=\sum x * P(X = x )[/tex]

     [tex]P(X = x_1 ) = \frac{1}{5000}[/tex]    given that they just offer one

    [tex]P(X = x_1 ) = 0.0002[/tex]    

 Now  

     [tex]P(X = x_2 ) = \frac{1}{5000}[/tex]    given that they just offer one

     [tex]P(X = x_2 ) = 0.0002[/tex]    

 Now  

      [tex]P(X = x_3 ) = \frac{5}{5000}[/tex]    given that they offer five

       [tex]P(X = x_3 ) = 0.001[/tex]

Hence the  expectation is evaluated as

       [tex]E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001[/tex]

      [tex]E(x)=\$ 4[/tex]

Now given that the price for a ticket is  [tex]\$ 5[/tex]

The actual expectation when price of ticket has been removed is

      [tex]E(1 )= 4- 5[/tex]

      [tex]E(1 )= -\$ 1[/tex]

Answer:

  1/8, 3/8

Step-by-step explanation:

Let x and y represent the two fractions. Then we are given ...

  x + y = 1/2

  x + 5y = 2

Subtracting the first equation from the second, we get ...

  (x +5y) -(x +y) = (2) -(1/2)

  4y = 3/2 . . . . . simplify

  y = 3/8 . . . . . . divide by 4

  x = 1/2 -3/8 = 1/8

The two numbers are 1/8 and 3/8.

Answer:

5 11/20

Step-by-step explanation:

1 3/4 + 3 4/5

Get a common denominator of 20

1 3/4 * 5/5   + 3  4/5 *4/4

1 15/20    + 3  16/20

4 31/20

Rewriting

4 + 20/20 + 11/ 20

4+1 + 11/20

5 11/20

Answer:

132 kilo meters

Step-by-step explanation:

Pro por tions:

9 lite rs ⇒ 99 km

12 lite rs  ⇒  P km

P = 99*12/9

P = 132 km

Answer:

132

Step-by-step explanation:

give person above brainliest :))

Answer:

0.5

1 divide by 2 = 0.5

Answer:

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 38

d = 32 - 38 = - 6 or 20 - 26 = - 6

Substitute the values into the above formula

A(n) = 38 + (n - 1)-6

= 38 - 6n + 6

We have the final answer as

Hope this helps you

Answer:

a

Step-by-step explanation:

you're welcome!

Answer: 0.98

Step-by-step explanation:

given data:

probability they won a game = 58% = 0.58

since outcome of games are independent, and percentage would remain same as 2014.

probablility that Dodgers wins atleast 1 of their next 7 games

= 1 - p

= 1 - ( 0.58 )^ 7

= 1 - 0.02208

= 0.98

probabikotun that Dodgers would win one of their next seven games is 0.98

Answer:

The corresponding graph is Graph A.

Step-by-step explanation:

Part 1: Rewriting the inequality and solving for d

To start, the inequality will need simplified.

[tex]9-4d\geq -3\\\\-4d\geq -12\\\\\frac{-4d}{-4} \geq \frac{-12}{-4} \\\\d \leq 3[/tex]

Because simplifying the inequality involved dividing by a negative number, the sign must be flipped.

Part 2: Determining the graph for the inequality

Now, refer to the rules for graphing inequalities.

Therefore, because [tex]d \leq 3[/tex], the graph will start at 3 as a closed dot. Then, it will go left because values must be equal to 3 or less than 3.

Therefore, the graph that represents this is Graph A.

Answer:

Graph A

I hope this helps!

Answer:

Z=9

Step-by-step explanation:

Insert A into A+Z=14

5+z=14

Subtract 5 on both sides, to find Z.

-5     -5

z=9

Answer:

y = x-4

Step-by-step explanation:

The y intercept is -4

We have 2 points so we can find the slope

( 0,-4) and(4,0)

m = ( y2-y1)/(x2-x1)

    = ( 0- -4)/ (4-0)

    = 4/4

   =1

The slope intercept form is

y = mx+b

y = 1x-4

y = x-4

Answer:

7+sqrt(37)

Step-by-step explanation:

7+sqrt(6*(3+4)-2+9-3*2^2)=7+sqrt(6*7+7-3*4)=7+sqrt(42+7-12)=7+sqrt(37)

Answer:

-36

Step-by-step explanation:

3*12=36

she is going down (negative) so, it is -36

not sure if this is what you are asking for, if not try this

0-12-12-12=-36

Answer:

1)

[tex] \sqrt{( \sqrt{} 3 {}^{2} } + 1 {}^{2} )[/tex]

[tex] \sqrt{4} = 2[/tex]

then the angle,

[tex] \tan( \alpha ) = - 1 \div \sqrt{3} = 330[/tex]

in radians,

[tex]11\pi \div 6[/tex]

hope this helps for the next questions

Answer:

Step-by-step explanation:

(5+(-4))/2 = 1/2 or 0.5

(-7 + 6)/2 = -1/2 or -0.5

the solution is D

(0.5, -0.5)

Answer:

8-2x

Step-by-step explanation:

2 distributed over the entire expression equals 8-2x

Answer:

the answer is b

Step-by-step explanation:

Answer:

Option C. x + 12 ≤ 2(x – 3)

Step-by-step explanation:

From the question, we obtained the following information:

x + 12 ≤ 5 – y .......(1)

5 – y ≤ 2(x – 3) ....... (2)

To know which option is correct, do the following:

From equation 2,

5 – y ≤ 2(x – 3)

Thus, we can say

5 – y = 2(x – 3)

Now, we shall substitute the value of 5 – y into equation 1 as shown below:

x + 12 ≤ 5 – y

5 – y = 2(x – 3)

x + 12 ≤ 2(x – 3)

From the above illustration, we can see that if x + 12 ≤ 5 – y and 5 – y ≤ 2(x – 3), then x + 12 ≤ 2(x – 3) must be true.

Option C gives the correct answer.

Answer:

30,455

Step-by-step explanation:

Exponential decay

y = a(1 - b)^x

y = final amount

a = initial amount

b = rate of decay

x = time

We are looking for the rate of decay, b.

900 = 450000(1 - b)^30

1 = 500(1 - b)^30

(1 - b)^30 = 0.002

1 - b = 0.002^(1/30)

1 - b = 0.81289

b = 0.1871

The equation for our case is

y = 450000(1 - 0.1871)^x

We are looking for the amount in 13 hours, so x = 13.

y = 450000(1 - 0.1871)^13

y = 30,455

Answer:

6(x-3)

Step-by-step explanation:

the common number for 6 and 18 is 6 so if you extract that from the expression then it turns to 6(x-3) which cannot be factored further

Answer:

Option B:  6(x - 3)

Step-by-step explanation:

Answer:

a.    [tex]\mathbf{36 \sqrt{5}}[/tex]

b.   [tex]\mathbf{ \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}[/tex]

Step-by-step explanation:

Evaluate integral _C x ds  where C is

a. the straight line segment x = t, y = t/2, from (0, 0) to (12, 6)

i . e

[tex]\int \limits _c \ x \ ds[/tex]

where;

x = t   , y = t/2

the derivative of x with respect to t is:

[tex]\dfrac{dx}{dt}= 1[/tex]

the derivative of y with respect to t is:

[tex]\dfrac{dy}{dt}= \dfrac{1}{2}[/tex]

and t varies from 0 to 12.

we all know that:

[tex]ds=\sqrt{ (\dfrac{dx}{dt})^2 + ( \dfrac{dy}{dt} )^2}} \ \ dt[/tex]

∴

[tex]\int \limits _c \ x \ ds = \int \limits ^{12}_{t=0} \ t \ \sqrt{1+(\dfrac{1}{2})^2} \ dt[/tex]

[tex]= \int \limits ^{12}_{0} \ \dfrac{\sqrt{5}}{2}(\dfrac{t^2}{2}) \ dt[/tex]

[tex]= \dfrac{\sqrt{5}}{2} \ \ [\dfrac{t^2}{2}]^{12}_0[/tex]

[tex]= \dfrac{\sqrt{5}}{4}\times 144[/tex]

= [tex]\mathbf{36 \sqrt{5}}[/tex]

b. the parabolic curve x = t, y = 3t^2, from (0, 0) to (2, 12)

Given that:

x = t  ; y = 3t²

the derivative of  x with respect to t is:

[tex]\dfrac{dx}{dt}= 1[/tex]

the derivative of y with respect to t is:

[tex]\dfrac{dy}{dt} = 6t[/tex]

[tex]ds = \sqrt{1+36 \ t^2} \ dt[/tex]

Hence; the  integral _C x ds is:

[tex]\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt[/tex]

Let consider u to be equal to  1 + 36t²

1 + 36t² = u

Then, the differential of t with respect to u is :

76 tdt = du

[tex]tdt = \dfrac{du}{76}[/tex]

The upper limit of the integral is = 1 + 36× 2² = 1 + 36×4= 145

Thus;

[tex]\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt[/tex]

[tex]\mathtt{= \int \limits ^{145}_{0} \sqrt{u} \ \dfrac{1}{72} \ du}[/tex]

[tex]= \dfrac{1}{72} \times \dfrac{2}{3} \begin {pmatrix} u^{3/2} \end {pmatrix} ^{145}_{1}[/tex]

[tex]\mathtt{= \dfrac{2}{216} [ 145 \sqrt{145} - 1]}[/tex]

[tex]\mathbf{= \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}[/tex]

Answer:

The error is the use of wrong trigonometric ratio formula.

Sine was used instead of tangent.

It should be: [tex] tan(A) = \frac{36}{84} [/tex]

Step-by-step explanation:

Side length, 36, is opposite to <A. Side length, 84, is the adjacent side. Therefore, the right trigonometric ratio formula to use is:

[tex] tan(A) = \frac{opposite}{adjacent} [/tex]

[tex] tan(A) = \frac{36}{84} [/tex]

[tex] A = tan^{-1}(\frac{36}{84}) [/tex]

m<A ≈ 23°

The error made was the use of wrong trigonometric ratio formula.

Answer:

Step-by-step explanation:

Given that:

population mean [tex]\mu[/tex] = 47600

population standard deviation [tex]\sigma[/tex] = 2000

sample size n = 49

Sample mean [tex]\over\ x[/tex] = 48000

Level of significance = 0.05

The null and the alternative hypothesis can be computed as follows;

[tex]H_0 : \mu = 47600 \\ \\ H_1 : \mu \neq 47600[/tex]

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics can be calculated by using the formula:

[tex]z= \dfrac{\overline X - \mu }{\dfrac{\sigma}{ \sqrt{n}}}[/tex]

[tex]z= \dfrac{ 48000-47600 }{\dfrac{2000}{ \sqrt{49}}}[/tex]

[tex]z= \dfrac{400 }{\dfrac{2000}{ 7}}[/tex]

[tex]z= 1.4[/tex]

Conclusion:

Since 1.4 is lesser  than 1.96 , we fail to reject the null hypothesis and  that there is insufficient information to conclude that the   mean gross income is not equal to $47600

The P-value is being calculate as follows:

P -value = 2P(Z>1.4)

P -value =  2 (1 - P(Z< 1.4)

P-value = 2 ( 1 - 0.91924)

P -value = 2 (0.08076 )

P -value = 0.16152

Answer:

It’s symmetric property

Answer:

Symmetry

Step-by-step explanation:

The guy above me

Answer:

25(4 + 3)

Step-by-step explanation:

100 = 2^2 + 5^2

75 = 3 * 5^2

GCF = 5^2 = 25

100 + 75 =

= 25 * 4 + 25 * 3

= 25(4 + 3)

Answer:

25= q+20

25 - 20 =q

5 = q

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------

[tex]25 = q + 20[/tex]

Swap sides so that all variable terms are on the left hand side.

[tex]q + 20 = 25[/tex]

Subtract 20 from both sides.

[tex]q = 25 - 20[/tex]

Answer:

The answer is: Leo's phone had the greater initial trade-in value. Tonya's phone decreases at an average rate slower than the trade in value of Leo's phone.

Step-by-step explanation:

I got it right. Hope this helps.

The initial trade-in value of Tonia's phone is greater when compared with Leo's    

There is a decrease in the trade-in value of Leo's phone at an average slower rate

[tex]f(x) = 490\times 0.88[/tex]

[tex](x)[/tex] ⇒ [tex]g(x)[/tex]

[tex]0[/tex] ⇒ [tex]480[/tex]

[tex]2[/tex] ⇒ [tex]360[/tex]

[tex]4[/tex] ⇒ [tex]470[/tex]

Now we will solve with the greater initial value

The initial value is when x = 0. So, we have

[tex]f(x) = 490 \times o.88^x\\\ f(o) = 490 \times 0.88 ^0\\f(0 =490 \times 1 \\f(o) = 490[/tex]

From leos table

[tex]g(0) = 480\\f(0) > g(o)\\i.e \\490 > 480[/tex]

So Tonia had a greater initial value

Solving (b): The phone with a lesser rate

y [tex]y = a b ^ x[/tex]

An exponential function is:

where [tex]b \rightarrow rate[/tex]

For Tonia

[tex]b = o.88[/tex]

For Leo we have

[tex](x_{1} , y_{1} )= (0,480)\\(x_{1}, y_{1} ) = (2, 360)[/tex]

So the equation becomes

[tex]y = ab ^x \\480 = ab ^0 \\and \\360 = ab ^2[/tex]

On solving

[tex]480 = a \times 1\\a = 480[/tex]

[tex]360 = ab ^ 2[/tex]

so it becomes

[tex]480 = 360 \times b ^2 \\[/tex]

On dividing both sides by [tex]480[/tex]  we get

[tex]b ^ 2 = 0.87[/tex]

[tex]b ^ 2 = 0.75[/tex]

On taking square root we get

[tex]b = 0.87[/tex]

In comparison, we get Leo's rate is slower.

Learn more about Equation here:

https://brainly.com/question/14686792

# SPJ2

Complete Question

Find the indicated area under the curve of the standard normal​ distribution, then convert it to a percentage and fill in the blank.

About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

Answer:

About 97.219% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

Step-by-step explanation:

From the question given we can see that they both are the same so 1  will just solve one

   Now the area under this given range can be represented mathematically as

  [tex]P ( -2.2 < z < 2.2) = P(z < 2.2 ) - P(z < -2.2 )[/tex]

Now  from the z-table  

        [tex]p(z < 2.2 ) = 0.9861[/tex]

and

        [tex]p(z < - 2.2 ) = 0.013903[/tex]

So

     [tex]P ( -2.2 < z < 2.2) = 0.9861 - 0.013903[/tex]

     [tex]P ( -2.2 < z < 2.2) = 0.97219[/tex]

So converting to percentage  

     [tex]P ( -2.2 < z < 2.2) = 0.97219 * 100[/tex]

    [tex]P ( -2.2 < z < 2.2) = 97.219 \%[/tex]