5. A child rides a pony on a circular track with a radius of 5 m Find the distance traveled and the placement
after the child has gone halfway around the track (8) Does the distance traveled increase, decrease, or stay the
same when the child completes one circuit of the track? Does the displacement increase, decrease, or stay the
same? Explain. (C) Find the distance and displacement ter a complete circuit of the track

Answers

Answer 1

The answer are :

A. Distance = 15.71 m , The displacement = 10 m

B. distance traveled will increase, displacement will decrease

C. The distance = 31.42 m , Displacement = 0

Difference between Distance and Displacement

Distance is a scalar quantity, while displacement is a vector quantity. Displacement is the distance travelled in a specific direction.

Given that a child rides a pony on a circular track with a radius of 5 m, after the child has gone halfway around the track

(A)

The distance traveled will be = 2[tex]\pi[/tex]r / 2

The distance = πr

The distance = 22/7 x 5

The distance = 15.71 m

The displacement = 2r

The displacement = 2 x 5

The displacement = 10 m

(B) The distance traveled will increase as the child completes one circle of the track but the displacement will decrease because the displacement in one cycle of a circular motion is zero since it is a vector quantity.

(C) The distance after a complete circuit of the track = 2πr

The distance = 2 × 22/7 × 5

The distance = 31.42 m

The displacement after a complete circuit of the track will be zero.

That is;

Displacement = 0

Therefore, the distance traveled and the displacement after the child has gone halfway around the track are 15.7 m and 10 m respectively. While the distance and displacement after a complete circle of the track are 31.42 m and 0 respectively.

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Related Questions

the hydrometer with the density of liquid to be 800 kg metre per square is the volume of the submerged part of the hydrometer is 5 into 10 to the power minus 5 calculate the mass of the hydrometer​

Answers

Answer:

Mass = 0.04 Kg

Explanation:

Given the following data;

Density = 800 kg/m³

Volume = 5 * 10^{-5} m³

To find the mass of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

[tex] Density = \frac {mass}{volume} [/tex]

Making mass the subject of formula, we have;

[tex] Mass = density * volume [/tex]

Substituting the values into the formula, we have;

[tex] Mass = 800 * 5 * 10^{-5} [/tex]

Mass = 0.04 Kg

Describe the laws of liquid pressure and explain the term fluid. (Please try to give the correct answer 'coz it's urgent!)​

Answers

Answer:

The laws of liquid pressure are: ... The liquid pressure at a point inside the liquid is same in all directions. The liquid pressure at a point inside the liquid is directly proportional to the depth of that point from the free surface of liquid. The pressure of liquid at same depth is different for different liquids

Answer:

The laws of liquid pressure:

The pressure that is inside the liquid rises with the intensity from the surface of a liquid.

The term fluid:

Fluid is basically liquid and a substance that is known to have no certain shape. The opposite of the term fluid would be solid.

a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what will be the effort distance ?​

Answers

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load  distance=10 cm

We have to find the effort distance.

We know that

[tex]load\times load\;distance=Effort\times effort\;distance[/tex]

Using the formula

[tex]800\times 10=200\times effort\;distance[/tex]

Effort distance=[tex]\frac{800\times 10}{200}[/tex]

Effort distance=[tex]\frac{8000}{200}[/tex]

Effort distance=40 cm

Hence,  the effort distance will be 40 cm.

define mass defect and binding energy​

Answers

Answer:

About Transcript. Nuclear binding energy is the energy required to split an atom's nucleus into protons and neutrons. Mass defect is the difference between the predicted mass and the actual mass of an atom's nucleus. The binding energy of a system can appear as extra mass, which accounts for this difference.

Explanation:

PLZ MARK AS THE BRAINLIEST

I NEED IT URGENTLY

HAVE A GOOD DAY

MAY GOD BLESS U

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The hair dryer has a plastic case so there is no need for an earth wire connection in the plug ,explain why the hair dryer is still safe to use.

Answers

Answer:

plastics are unable to conduct electricity and heat due to there being no free flowing electrons, meaning they are safe to use.

Explanation:

A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then curves upwards by 1.0 mm above the ground such that the person is consequently launched into the air. Ignoring friction, how fast is the person moving upon leaving the waterslide

Answers

Answer:

change waterslide according to question. and you are good to go. check photo for solve

The person moving with speed upon leaving the waterslide is equal to 0.313 m/s while ignoring the friction.

What is the law of conservation of energy?

If there is a loss of energy in any part of the system, there must be the same amount of a gain of energy in some other part of the isolated system.

Kinetic energy + Potential energy = constant

Therefore, the initial kinetic and potential energy of the person must be equal to the final kinetic and potential energy.

mgh₁ + mv₁²/2 = mgh₂ + mv₂²/2

gh₁ + v₁²/2 = gh₂ + v₂²/2

2gh₁ + v₁² = 2gh₂ + v₂²

2g(h₁ - h₂) = v₂² -  v₁²

[tex]v_2=\sqrt{2g(h_2-h_1) + v^2_1}[/tex]                                               .................(1)

Given, the mass of the person, m = 63 Kg

The initial speed of the person as at rest, v₁ = 0

Consider that the speed of the person while leaving the waterslide is v₂

The initial height of the person above the ground, h₁ = 6.0 mm

The height of the person leaving the waterslide, h₂= 1.0 mm

Substitute, the value of m, v₁, h₁ and h₂ in equation (1):

[tex]v_2 = \sqrt{2(9.8m/s^2)(6mm-1mm) + (0)^2}[/tex]

[tex]v_2 =\sqrt{2(9.8)\times 5 \times 10^{-3}} \;m/s[/tex]

[tex]v_2 =\sqrt{0.098}\; m/s[/tex]

v₂ = 0.313 m/s

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A car is traveling at 36km/h when it accelerates and after 2 seconds the car reaches a speed of 54km/h. Calculate the speed of the car in 2s?

Answers

Answer:18km





Answer:18km

54-36=18

Define the term ‘matter’ in physics.

Answers

Answer:

Matter is any substance that has mass and takes up space by having volume

Define measurement and write its importance.​

Answers

Answer:

Measurement is the way humans define certain amounts of matter, and is expressed in various types of units respective to the type of matter or object being defined.

Explanation:

Measurement is extremely important because it helps one another understand how much of something is needed to accomplish something. If no method existed to define the specific amount needed, we would simply mess delicate operations up and machines, even simple recipes, would fail.

28 Why is soft iron used for the core of an electromagnet?

А Soft iron easily becomes a permanent magnet.
B Soft iron is a good electrical conductor.
с Soft iron is a poor thermal conductor.
D Soft iron loses its magnetism when the current in the coil is switched off.​

Answers

Answer:

An electromagnet is a form of magnet that is made by the passage of electric current through a coil of wire. The core of an electromagnet increases the strength of the produced magnetic field

Soft iron is used as the core of an electromagnet because soft iron is a magnetic material and therefore it is permeable to and becomes magnetized by the magnetic field coming from the flowing current, thereby allowing more flux to pass through the core of the electromagnet, producing a magnetic field strength that is several times that of an air core electromagnet as the relative permeability (to magnetic flux, compared to vacuum) of soft iron is about 64 × 10³

However, once the current is switched, the soft iron does not remain its magnetic, and therefore, the electromagnet becomes demagnetized, thereby being able to maintain its electromagnetic characteristics (being made magnetic by the flow of electric current)

Explanation:

If the force on a spring is 2 N and it stretched 0.5 m, what is the spring constant?
O A. 2 N/m
OB. 0.2 N/m
OC. 0.4 N/m
OD. 4 N/m

Answers

It solved by the Hooke's law states F=kx

answer is

0.4n/m

How does the temperature of a planet determine the states of matter you would observe on that planet?

Answers

Explanation:

the temperature will determine the kinetic energy or degree of freedom of the molecules of matter.

if the temperature is high, the kinetic energy of the molecules increase which may cause a change of state into a gas which has molecules of high kinetic energy. this shows that temperature is a measure of the kinetic energy of the molecules.

Mass of the sun is 2x10³⁰ kg and that of the earth is 6/10²⁴ kg and the distance between them is 1.5 x 10¹¹m. What is the gravitational force produced between them? ​

Answers

Answer:

The gravitational force is 3.56 × 10^22 N

Explanation:

[tex]{ \bf{force = \frac{GM_{s} m _{e}}{ {r}^{2} } }}[/tex]

[tex]{ \sf{force = \frac{6.67 \times {10}^{ - 11} \times (2 \times {10}^{30} ) \times (6\times {10}^{24}) }{(1.5 \times {10}^{11}) {}^{2} } }} \\ \\ { \sf{force = 3.56 \times {10}^{22} \: newtons}}[/tex]

An observer measures a 100 Hz Doppler shift as an ambulance goes by. At rest, the frequency of the ambulance's siren is 2,000 Hz. What is the speed of the ambulance?

Answers

The change in the frequency of the sound, due to the relative motion of the source of sound and the observer, is determined by the Doppler's Effect.

The speed of the ambulance (source) is "6517 m/s"

The equation of Doppler's Effect is given as follows:

[tex]f_o = \frac{v+v_o}{v+v_s}f_s[/tex]

where,

[tex]f_o\\[/tex] = frequency of sound measure by observer  = 100 Hz

v = speed of sound = 343 m/s

[tex]v_o[/tex] = speed of observer = 0 m/s

[tex]v_s[/tex] = speed of ambulance (source) = ?

[tex]f_s[/tex] = actual frequency = 2000 Hz

Therefore, using the values, we get:

[tex]100\ Hz = \frac{343\ m/s + 0\ m/s}{343\ m/s + v_s}(2000\ Hz)\\\\(100\ Hz)(343\ m/s + v_s) = (343\ m/s)(2000\ Hz)\\\\v_s = \frac{686000\ Hz.m/s - 34300\ Hz.m/s}{100\ Hz}[/tex]

v_s = 6517 m/s

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a car moves at a speed of 40km/h. it is stopped by applying brake which produce a uniform acceleration of-0.5m/s^2. how much distance will it move before coming to stop ? plz its urgent

Answers

Answer:

Explanation:

I answered this in question #24313516

A rabbit runs a distance of 60 meters in 20s. What is the average speed?

Answers

Answer:

3 m/s

Explanation:

Given,

Total distance = 60 m

Total time = 20 s

We know that,

Average speed = Total distance/Total time

=> Average speed = 60 m/20 s

=> Average speed = 3 m/1 s

=> Average speed = 3 m/s

Distance=60mTime=20s

Average speed=Total distance/Total time

[tex]\\ \sf\longmapsto Average\:Speed=\dfrac{60}{20}[/tex]

[tex]\\ \sf\longmapsto Average\:Speed=3m/s[/tex]

Kgms-1-= Ns ...solution






Answers

Answer:

units of impact or impulse or momnetum are same

These are

Kg m s-1 or N s

If we aim a radio telescope at a distant spiral arm of the Milky Way Galaxy, we will probably observe a 21-cm line. If we point a large optical telescope at this same region, we will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal. Why not

Answers

Answer:

Because of the interstellar dust and interior location of the solar system.

Explanation:

We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.

Un muelle se alarga 20 cm cuando ejercemos sobre él una fuerza de 24 N. Calcula:El valor de la constante elástica del muelle

Answers

Answer:

120 Nm-1

Explanation:

Según la ley de Hooke;

F = Ke

F = fuerza sobre el resorte

K = constante de fuerza

e = extensión

Por eso;

K = F / e

K = 24N / 20 × 10 ^ -2m

K = 120 Nm-1

Which class of lever has all advantages of lever

Answers

Answer:

Helo ....

so this answer would be First class levers

becoz...

First-class levers have a considerable practical advantage over the other types of levers. They convert a downward moving force into a lifting force

is it possible to mark it brainliest <3

How many atoms are in the compound NaNO3?

Answers

Explanation:

3 atoms are in the compound

A converging lens of focal length 20cm, forms a real image twice the size of the object. Calculate:
i) the power of the lens;
ii) the position of the image.

Answers

Answer:

Solition given:

focal length(f)=20cm

size of image(v)=2x

size of object(u)=x

we have

power of lens= reciprocal to focal length=1/20=0.05/cm

ii.

the position of the image is beyond C.

Explanation:

See the attachment !!!!!!!

What is the purpose of the lab the importance of the topic and the question you are trying to answer?

Answers

perpose of lab is to store apparatus and do some experiment

Helps someone to know the exert lengh of something


Can someone help me please this test is very important

Answers

Answer:

Friction is caused in roller coasters by the rubbing of the car wheels on the track and by the rubbing of air (and sometimes water!) against the cars.

Explanation:

In which instrument of the following the water works as a bulb

Answers

Answer:

hydrometer

Explanation:

A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water.

A bullet with a mass mb=13.5 g is fired into a block of wood at velocity vb=245 m/s. The block is attached to a spring that has a spring constant k of 205 N/m. The block and bullet continue to move, compressing the spring by 35.0 cm before the whole system momentarily comes to a stop. Assuming that the surface on which the block is resting is frictionless, determine the mass mw of the wooden block.

Answers

Momentum is conserved, so the sum of the momenta of the bullet and block before collision is equal to the momentum of the combined bullet-block system,

[tex]m_bv_b+m_wv_w = (m_b+m_w)v[/tex]

where v is the speed of the bullet-block system. The block starts at rest so it has no initial momentum, and solving for v gives

[tex]v = \dfrac{m_b}{m_b+m_w} v_b[/tex]

The total work W performed by the spring on the bullet-block system as it is compressed a distance x is

[tex]W = -\dfrac12kx^2[/tex]

where k is the spring constant, and the work done is negative because the restoring force of the spring opposes the bullet-block as it compresses the spring.

By the work-energy theorem, the total work done is equal to the change in the bullet-block's kinetic energy ∆K, so we have

[tex]W_{\rm total} = W = \Delta K[/tex]

The bullet-block starts moving with velocity v found earlier and comes to a stop as the spring slows it down, so we have

[tex]-\dfrac12kx^2 = -\dfrac12(m_b+m_w)v^2 \implies kx^2 = \dfrac{{m_b}^2}{m_b+m_w}{v_b}^2[/tex]

Solve for [tex]m_w[/tex]:

[tex]m_w=\dfrac1k\left(\dfrac{m_bv_b}x\right)^2-m_b[/tex]

[tex]m_w=\dfrac1{205\frac{\rm N}{\rm m}}\left(\dfrac{(0.0135\,\mathrm{kg})\left(245\frac{\rm m}{\rm s}\right)}{0.350\,\rm m}\right)^2-0.0135\,\mathrm{kg}\approx \boxed{0.422\,\mathrm{kg}}[/tex]

What do you mean by unit?​

Answers

Unit is the quantity of a constant magnitude which is used to measure the magnitudes of other quantities of the same nature.

Answer:

The standard known quantity which is used to measure a physical quantities is known as unit.

State newton's universal law of gravitation

Answers

Every particle of mass is attracted to every other particle of mass.  The magnitude of the force between two objects is proportional to the product of their masses, and inversely proportional to the square of the distance between them.  The direction of the force is along the line between their centers.

(NOTE:  Newton's 3rd law of motion tells us that gravitational forces always come in pairs.  Between two objects, there are two forces ... one in each direction.  Their strengths are equal ... Your weight on Earth is exactly equal to the Earth's weight on YOU.)

7. A thin wire was wound 30 times closely over a boiling tube. The total length of the windings as measured was found to be 6.3mm. Determine the diameter of the wire .​

Answers

Answer:

Diameter of wire = 0.00021 meters

Explanation:

Given the following data;

Number of windings = 30

Length of windings = 6.3 mm to meters = 0.0063 meters

To find the diameter of the wire, we would use this mathematical expression;

Length of windings = number of windings * diameter of wire

Substituting the values into the expression, we have;

0.0063 = 30 * diameter of wire

Diameter of wire = 0.0063/30

Diameter of wire = 0.00021 meters

How do longshore currents shape the land?

Answers

Longshore drift has a very powerful influence on the shape and composition of the coastline. It changes the slopes of beaches and creates long, narrow shoals of land called spits, that extend out from shore. Longshore drift may also create or destroy entire “barrier islands” along a shoreline.

Answer:

Longshore drift has a very powerful influence on the shape and composition of the coastline. It changes the slopes of beaches and creates long, narrow shoals of land called spits, that extend out from shore. Longshore drift may also create or destroy entire “barrier islands” along a shoreline.

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