Engineering College

4.
error occurs when the measurement we think we see is not the
measurement being indicated by the instrument.
A. Positioning
B. Operator bias
C. Instrument
D. Observational

Answers

Answer 1

Answer: observational error

Explanation:

Answer 2

An Error occurs when the measurement is actually done by the Observational approach. Thus, the correct option is D.

What is an ideal method of measurement?

The ideal methods of measurement are subdivided into two methods: They are as follows:

Direct measurement method.Indirect measurement method.

The Direct measurement method involves the utilization of instruments such as micrometers, vernier calipers, coordinate measuring machines, etc. In this method, the unknown quantity is directly compared with the standard quantity.

In the Indirect measurement method, the physical parameter of the quantity is measured with the help of the direct method.

Positioning of the required quantity, operator-biased measurement, and the utilization of instruments for estimating the measurement of any unknown value are generally favored in order to eliminate the chances of errors.

Therefore, an Error occurs when the measurement is actually done by the Observational approach. Thus, the correct option is D.

To learn more about Errors in Measurement, refer to the link:

https://brainly.com/question/475573

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Related Questions

Determine the size of memory needed for CD recording of a piece of music, which lasts for 26 minutes, is done with a 20-bit Analog-to-Digital Converter (ADC) in stereo (2 channels), at the rate of 44.1 kSa/s, with the compression factor 6 (allow 10% error margin).

Answers

Answer: the size of memory needed for the CD recording is 28.7 MB

Explanation:

so in the case of stereo, the bitrate is;

⇒ 26 × 60 × 44.1 × 10³ × 2

=   137592 × 10³  

for 10 bit

⇒ 137592 × 10³ × 10

= 1375920 × 10³ bits

now divide by 8 (convert to bytes)

⇒ (1375920 × 10³) / 8

= 171,990,000 BYTE

divide by 1000 (convert to kilobytes)

= 171,990,000 / 1000

= 171,990 KILOBYTES

now Given that, the compression ratio is 6      

so  

171,990 / 6

= 28665 KB

we know that. 1 MB = 1000 KB

x MB = 28665 KB

x MB = 28665 / 1000

⇒ 28.665 MB ≈ 28.7 MB

Therefore the size of memory needed for the CD recording is 28.7 MB

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