Answer:
The p-value of the test is 0.0066 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean salary differs from $39,385
Step-by-step explanation:
The average salary for public school teachers for a specific year was reported to be $39,385. Test if the mean salary differs from $39,385
At the null hypothesis, we test if the mean is of $39,385, that is:
[tex]H_0: \mu = 39385[/tex]
At the alternative hypothesis, we test if the mean differs from this, that is:
[tex]H_1: \mu \neq 39385[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
39385 is tested at the null hypothesis:
This means that [tex]\mu = 39385[/tex]
A random sample of 50 public school teachers in a particular state had a mean of $41,680, and the population standard deviation is $5975.
This means that [tex]n = 50, X = 41680, \sigma = 5975[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{41680 - 39385}{\frac{5975}{\sqrt{50}}}[/tex]
[tex]z = 2.72[/tex]
P-value of the test and decision:
The p-value of the test is the probability that the sample mean differs from 39385 by at least 2295, which is P(|Z| > 2.72), which is 2 multiplied by the p-value of Z = -2.72.
Looking at the z-table, Z = -2.72 has a p-value of 0.0033
2*0.0033 = 0.0066
The p-value of the test is 0.0066 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean salary differs from $39,385
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!
The zeros of the polynomial 3x^4 - 5x^3 - 62x^2 - 92x - 24 are x = {-2, -1/3, 6}. Determine the intervals where the value of f(x) is a negative value. Check all that apply.
a. -∞ < x < -2
b. -2 < x < -1/3
c. -1/3 < x < 6
d. 6 < x < ∞
Answer:
c. -1/3 < x < 6Step-by-step explanation:
There are 3 zero's but we see the polynomial is of degree 4.
It means it has 2 same zero's. We can verify it is -2. Since -2 is doubled, it reflects the local minimum and it is on the x-axis.
In reality we need to consider the other two zero's.
It is obvious the negative interval is between -1/3 and 6 since the polynomial is of even degree and has positive leading coefficient.
Correct choice is c.
The graph is attached to confirm the theory.
If K = (AB)/(A+B) , then B = ?
(a) (A)/(1−A)
(b) (AK)/(A−K)
(c) (AK)/(K−A)
(d) (A+K)/(A)
(e) (A−K)/(AK)
Lets do
[tex]\\ \sf\longmapsto K=\dfrac{AB}{A+B}[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{K}=\dfrac{A+B}{AB}[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{K}=\dfrac{1}{A}+\dfrac{1}{B}[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{B}=\dfrac{1}{K}-\dfrac{1}{A}[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{B}=\dfrac{K-A}{AK}[/tex]
[tex]\\ \sf\longmapsto B=\dfrac{AK}{K-A}[/tex]
Does the point (7,34) satisfy the equation y = 2x + 8
Answer:
no
Step-by-step explanation:
Substitute the point into the equation and see if it is true
34 = 2(7) +8
34 = 14+8
34 = 22
Since this is not true, the point does not satisfy the equation
Answer:
No
Step-by-step explanation:
because 7 is X and 34 is Y
So its 2 *7 +8=22
so no
Find the quotient of 68.4 ÷ 18 = ________. Use an area model to help you solve. (this is on flvs by the way) answers:
3.3
3.5
3.8
3.9
Answer:
C
Step-by-step explanation:
3.8 is the answer
68.4÷18=3.8
Please help with this
Answer:
2. Not Divisible
3. Divisible
4. Divisible
5. Divisible
6. Not Divisible
7. Divisible
Step-by-step explanation:
Question 2. Is 629,257 divisible by 5?
- Numbers that are divisible by 5 should end with either 5 or 0.
- The ending term of [629,257] is 7, which is neither 5 nor 0. Therefore, it is not divisible.
Question 3. Is 3,791,916 divisible by 2?
- Numbers that are divisible by 2 should end with an even number or 0, which include 0, 2, 4, 6, 8.
- The ending term of [3,791,916] is 6, which is an even number. Therefore, it is divisible.
Question 4. Is 63,726,125 divisible by 5?
- Numbers that are divisible by 5 should end with either 5 or 0.
- The ending term of [63,726,125] is 5. Therefore, it is divisible.
Question 5. Is 486,342 divisible by 3?
- In numbers that are divisible by 3, the sum of all digits is a multiple of 3.
- The sum of all digits of [486,342] is [4 + 8 + 6 + 3 + 4 + 2 = 27].
- 27 / 3 = 9
- Since the sum of all digits is divisible by 3, then 486,342 is divisible by 3.
Question 6. Is 474,493 divisible by 10?
- Numbers that are divisible by 10 should end with 0.
- The ending term of [474,493] is 3, which is not 0. Therefore, it is not divisible.
Question 7. Is 53,017,587 divisible by 9?
- In numbers that are divisible by 9, the sum of all digits is a multiple of 9.
- The sum of all digits of [53,017,587] is [5 + 3 + 0 + 1 + 7 + 5 + 8 + 7 = 36].
- 36 / 9 = 4
- Since the sum of all digits is divisible by 9, then 53,017,587 is divisible by 9.
Find the product and simplify your answer 6w(5w^2-5w+5)
2065 Q.No. 2 a A firm produced 100 calculator sets during its first year. The total number of calculator sets produced at the end of five years is 4,500. Assume that the production increases uniformly each year. Estimate the increase in production each year. [3] Ans: 400
Answer:
400
Step-by-step explanation:
First, the firm produces 100 sets its first year. This means that our equation starts at 100. Next, the total number of calculator sets in 5 years is 4500. With y₁ representing the amount of calculator sets produced during year 1, y₂ representing the amount of sets during year 2, and so on, we can say that
y₁+y₂+y₃+y₄+y₅ = 4500
100 + y₂+y₃+y₄+y₅ = 4500
Next, we are given that the production increases uniformly by an amount each year. Representing that amount as a, we can say that
y₁+a = y₂
y₂+a = y₃
y₁+a+a = y₃
y₁+ 2 * a = y₃
and so on, so we have
100 + y₂+y₃+y₄+y₅ = 4500
100 + (100+a) + (100+2a) + (100+3a) + (100+4a) = 4500
500 + 10a = 4500
subtract 500 from both sides to isolate the a and its coefficient
4000 = 10a
divide both sides by 15 to isolate a
a = 400
An analyst has developed the following probability distribution for the rate of return for a common stock.
Scenario Probability Rate of Return
10 0.34 -19%
20 0.48 8%
30 0.18 26%
a. Calculate the expected rate of return. Round your answer to 2 decimal places.
b. Calculate the variance and the standard deviation of this probability distribution. Use the percentage values for your calculations (for example 10% not 0.10). Round intermediate calculations to 4 decimal places.
Answer:
a) 2.06
b) variance = 270.90 , std = 275.14
Step-by-step explanation:
a) Determine Expected rate of return
attached below is the calculated table for the solution provided
∴ Expected rate of return = ∑ Xp(x) = -6.46 + 3.84 + 4.68 = 2.06
b) Determine the variance and standard deviation
Variance ( Vx ) = E(x)^2 - [ Expected rate of return ]^2
= 275.14 - ( 2.06 )^2 ≈ 270.90
standard deviation = √ variance = √270.90 = 16.459
note : E(x)^2 = ∑ x^2 p(x) = 275.14
express 24.123eight to base ten
To convert [tex]24.123[/tex] in base 8, also notated with [tex]24.123_8[/tex] into base 10 simply multiply each digit with 8 to the power of its position relative to the decimal point.
So,
[tex]24.123_8=2\cdot8^1+4\cdot8^0+1\cdot8^{-1}+2\cdot8^{-2}+3\cdot8^{-3}=20.162109375_{10}[/tex]
Hope this helps :)
An empty freight train traveled 60 miles from an auto assembly plant to an oil refinery. There, its tank cars were filled with petroleum products, and it returned on the same route to the plant. The total travel time for the train was 4 1 2 hours. If the train traveled 20 mph slower with the tank cars full, how fast did the train travel in each direction
Answer:
On the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.
Step-by-step explanation:
Since an empty freight train traveled 60 miles from an auto assembly plant to an oil refinery, and there, its tank cars were filled with petroleum products, and it returned on the same route to the plant, and the total travel time for the train was 4.5 hours, if the train traveled 20 mph slower with the tank cars full, to determine how fast did the train travel in each direction the following calculation must be performed:
60/20 = 3
60/40 = 1.5
60/20 = 3
3 + 1.5 = 4.5
Therefore, on the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.
Which number shows four hundredths
.004 .04 .400 4.00
Answer:
hello the answer is .04/0.04
Answer:
.04 is four hundredths
Step-by-step explanation:
I hope this helps
In how many different ways can the letter of word
CORPORATION" be
arranged. So that the vowel always
come together"
Answer:
= 6 ways = Required number of ways = (120×6)=720
what principle will amount to Rs. 4000 in 20 yrs at 2.5%?
Answer:
3200Step-by-step explanation:
Consider principle =Rs.P, Time (T)=4 years
Consider principle =Rs.P, Time (T)=4 yearsRate =6
Consider principle =Rs.P, Time (T)=4 yearsRate =6 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200
if logx27 + logy4 =5
and logx27 - logy4 =1
find x and y
Answer:
Hello,
I have reply too quick in comments (sorry)
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\[/tex]
Simplify the following by removing parentheses and combining terms
- (2x + 8) + 3(2x + 8) - 2x
Answer:
2x+16
Step-by-step explanation:
PEMDAS
A number plus 16 times its reciprocal equals 8. Find all possible values for the number.
Answer:
4
Step-by-step explanation:
[tex]n+16\frac{1}{n} = 8\\\\n^2+16=8n\\n^2 -8n+16=0\\[/tex]Factorizing we get the answer 4
This table shows how many male and female students attended two different
movies.
What is the probability that a randomly chosen person from this group is male
and attended an action movie?
Round your answer to two decimal places.
Action
Drama
Total
Mala
105
124
229
Female
99
151
250
Total
204
275
479
A. 0.11
B. 0.43
Ο Ο Ο Ο
C. 0.22
D. 0.52
Answer:
Male & action movie among a group of total 479
Step-by-step explanation:
We only choose male from action movie category so:
p = 105/ 479 = 0.22
The probability that a randomly chosen person from this group is male and attended an action movie will be 0.22. Then the correct option is C.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
This table shows how many male and female students attended two different movies.
Action Drama Total
Mala 105 124 229
Female 99 151 250
Total 204 275 479
Then the probability that a randomly chosen person from this group is male and attended an action movie will be
Favorable event = 105
Total event = 479
Then the probability will be
P = 105 / 479
P = 0.219
P ≈ 0.22
Then the correct option is C.
More about the probability link is given below.
https://brainly.com/question/795909
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Suppose the following data represent the ratings (on a scale from 1 to 5) for a certain smart phone game, with 1 representing a poor rating. The discrete probability distribution for the random variable x is given below:
Star Frequency
1 2140
2 2853
3 4734
4 4880
5 10,715
Required:
Construct a discrete probability distribution for the random variable X
Answer:
[tex]\begin{array}{cc}{Status} & {Probability} & {1} & {0.0845} & {2} & {0.1127} & {3} & {0.1870} & {4} & {0.1927}& {5} & {0.4231} \ \end{array}[/tex]
Step-by-step explanation:
Given
The above table
Required
The discrete probability distribution
The probability of each is calculated as:
[tex]Pr = \frac{Frequency}{Total}[/tex]
Where:
[tex]Total = 2140+ 2853 + 4734 + 4880 + 10715[/tex]
[tex]Total = 25322[/tex]
So, we have:
[tex]P(1) = \frac{2140}{25322} = 0.0845[/tex]
[tex]P(2) = \frac{2853}{25322} = 0.1127[/tex]
[tex]P(3) = \frac{4734}{25322} = 0.1870[/tex]
[tex]P(4) = \frac{4880}{25322} = 0.1927[/tex]
[tex]P(5) = \frac{10715}{25322} = 0.4231[/tex]
So, the discrete probability distribution is:
[tex]\begin{array}{cc}{Status} & {Probability} & {1} & {0.0845} & {2} & {0.1127} & {3} & {0.1870} & {4} & {0.1927}& {5} & {0.4231} \ \end{array}[/tex]
In Example 9.2 (p. 214), if you instead carried the suitcase by the handle so that the suitcase was hanging directly at your side, how much work would you do on the suitcase as you carried it forward at a constant walking speed
9514 1404 393
Answer:
none
Step-by-step explanation:
No work is required to maintain an object at a constant speed with no change in direction. Work is only done when an object is accelerated, or moved some distance in the direction of the net force applied.
you would do no work
Please help——- Geometry problem
Thank you.
Answer:
b
Step-by-step explanation:
sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{s\sqrt{3} }{2s}[/tex] ( cancel s on numerator/ denominator ), then
sinA = [tex]\frac{\sqrt{3} }{2}[/tex] → b
Find the volume of the figure round your answer to the nearest tenth if necessary
Answer:
56.5
I think this is right
Four fifths of Ali's elephants have long tusks. If Ali has 10 elephants, how many elephants have short tusks?
Cuatro quintas partes de los elefantes de Ali tienen colmillos largos. Si Ali tiene 10 elefantes, ¿cuántos elefantes tienen colmillos cortos?
Answer:
2 elephants have short tusks.
Step-by-step explanation:
Long tusks: 4/5
Short tusks: 1/5
1/5 = x/10
x = 2
If a tank holds 6000 gallons of water, which drains from the bottom of the tank in 50 minutes, then Toricelli's Law gives the volume V of water remaining in the tank after t minutes as
V=5000 (1-1/50*t)^2 0⤠t ⤠50.
1. Find the rate at which water is draining from the tank after the following amount of time. (Remember that the rate must be negative because the amount of water in the tank is decreasing.)
a. 5 min
b. 10 min
c. 20 min
d. 50 min
2. At what time is the water flowing out the fastest?
3. At what time is the water flowing out the slowest?
Answer: hello from the question the volume of tank = 6000 gallons while the value in the Torricelli's equation = 5000 hence I resolved your question using the Torricelli's law equation
answer:
1) a) -180 gallons/minute ,
b) -160 gallons/minute
c) -120 gallons/minute
d) 0
2) The water is flowing out fastest when t = 5 min
3) The water is flowing out slowest after t = 20 mins
Step-by-step explanation:
Volume of tank = 5000 gallons
Time to drain = 50 minutes
Volume of water remaining after t minutes by Torricelli's law
V = 5000 ( 1 - [tex]\frac{1}{50}t[/tex] )^2 ----- ( 1 )
1) Determine the rate at which water is draining from the tank
First step : differentiate equation 1 using the chain rule to determine the rate at which water is draining from the tank
V' = [tex]-10000[ ( 1 - \frac{1}{50}t ) (\frac{1}{50}) ][/tex]
a) After t = 5minutes
V' = - 10000[ ( 1 - 0.1 ) * ( 0.02 ) ]
= -180 gallons/minute
b) After t = 10 minutes
V' = - 10000[ ( 1 - 0.2 ) * ( 0.02 ) ]
= - 160 gallons/minute
c) After t = 20 minutes
V' = - 10000 [ ( 1 - 0.4 ) * ( 0.02 ) ]
= -120 gallons/minute
d) After t = 50 minutes
V' = - 10000 [ ( 1 - 1 ) * ( 0.02 ) ]
= 0 gallons/minute
2) The water is flowing out fastest when t = 5 min
3) The water is flowing out slowest after t = 20 mins because no water flows out after 50 minutes
Please help no links.Mr. Longley is buying a $15 box of trail mix at Whole Foods, where tax is 6%. If Mr. Longley has
a coupon for 10% off the price of any item, how much does he end up paying?
I
Answer:
$14.40
Step-by-step explanation:
my way of doing things:
15/100=0.15=1%of total amount
0.15 x 6=0.9= the 6% which is the tax
0.15 x 10 = 1.5=the coupon
Take the coupon amount $1.50 minus the tax amount $0.90 =$0.60. Because the coupon amount is greater than the tax the 60 cents gets taken away from the original 15 dollars leaving Mr. Longely only having to pay $14.40.
When a number is tripled, its value increases by 10. What is the original value?
[tex]3x=x+10[/tex]
We tripple something and get 10 more than something.
Put the x-es on the left and non x-es to the right,
[tex]2x=10[/tex]
Divide both sides by 2,
[tex]x=5[/tex]
Et Viòla.
Hope this helps :)
When a number is tripled, its value increases by 10 then the original number is 5.
Let's call the original number "x". According to the problem, when this number is tripled, its value increases by 10. Mathematically, we can represent this as an equation:
3x = x + 10
Now, we can solve for "x" step by step:
1. Subtract "x" from both sides of the equation:
3x - x = 10
2. Simplify the left side:
2x = 10
3. Divide both sides by 2 to solve for "x":
x = 10 / 2
x = 5
So, the original number "x" is 5.
In other words, if you take a number, triple it (multiply by 3), and then increase the result by 10, you would end up with the value 5. This can be verified by checking:
3 * 5 = 15
15 + 10 = 25
The equation 3x = x + 10 represents the relationship between the original number and its tripled value with an increase of 10. Solving this equation helps us find the original value that satisfies the given condition.
To know more about Equation here
https://brainly.com/question/17387622
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Answer is D , others say it’s 64 but I got it wrong
Answer:
Oh no I am sorry! If you want answers to be done the real way let me know
Answer:I'm so sorry for you but congrats you did get the answer right it's just the test I guess
Step-by-step explanation:
If my savings of $x grows 10 percent each year, how much will i have in 2 years?
Answer:
20 percent
Step-by-step explanation:
Each year is 10 percent so 10x2 or 10+10 will equal 20
How many numbers multiple of 3 are in the range [2,2000]?
Answer:
There are 666 numbers multiple of 3 in the interval.
Step-by-step explanation:
Multiples of 3:
A number is a multiple of 3 if the sum of it's digits is a multiple of 3.
Range [2,2000]:
First multiple of 3 in the interval: 3
Last: 1998
How many:
[tex]1 + \frac{1998 - 3}{3} = 1 + 665 = 666[/tex]
There are 666 numbers multiple of 3 in the interval.
trigonometric identities
Without knowing what Juan's exact steps were, it's hard to say what he did wrong. The least you could say is that his solution is simply not correct.
4 sin²(θ) - 1 = 0
==> sin²(θ) = 1/4
==> sin(θ) = ±1/√2
==> θ = π/4, 3π/4, 5π/4, 7π/4
Write the degree of [tex] {x}^{2} + 2x + 3 {x}^{5} + 4 {x}^{3} + 9[/tex].
Answer:-
5
Explanation:-The highest degree included in the polynomial is known as degree of polynomial
[tex]\sf \checkmark[/tex] Polynomial with degree 1=monomial
[tex]\sf \checkmark[/tex] Polynomial with degree 2 =binomial
[tex]\sf \checkmark[/tex] Polynomial with degree 3=Trinomial
