4. State one use of the following gases: a) Argon - b) Helium -​

Answers

Answer 1

Step-by-step explanation:

HELIUM: To fill air balloon

ARGON: Used for filling incandescent metal filament electric bulbs


Related Questions

state the dimensions of the matrix. identify the indicated element​

Answers

Answer:

D; 2 * 3; -4

Step-by-step explanation:

The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column

In a row, we have 2 elements, in a column , we have 3 elements

So the matrix is of 2 * 3 dimension

a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4

Given m||n, find the value of x.
+
mm
(6x+4)
(4x-14)
Answer:
Submit Answer
attempt out of 2

Answers

Answer:

x = 19

Step-by-step explanation:

6x+4 + 4x - 14 = 180

10x    - 10 = 180

10 X = 190

x = 19

x=19 would be your final answer

Question 6 of 10
How much would $500 invested at 6% interest compounded monthly be
worth after 5 years? Round your answer to the nearest cen
(0) - P(144
A $674,43
B. $886,41
C, 5669.11
D. $512,68

Answers

9514 1404 393

Answer:

  A.  $674.43

Step-by-step explanation:

The account balance is given by ...

  A = P(1 +r/12)^(12t) . . . . . principal P invested at annual rate r for t years

  A = $500(1 +0.06/12)^(12·5) = $500(1.005^60)

  A ≈ $674.43

What is the perimeter of the rectangular narrow on the aircraft carrier HMS Queen Elizabeth

Answers

Answer:

dddjshsbs zhzusushwbsgzyzhsbssbs s hsbd d dhd ssbshebebs shyshs s sbshss s s

Step-by-step explanation:

shshshsnsnsjzj shsjs s sjsn s s snsnsbzbznnz ssjs s snsnsmkzkxnz

There is meters on the end right over here in the picture I marked could you tell me what the number is there so I could do the problem (comment on this answer and I will reply back) or you could also do it your self I wrote down how to do it on the picture. Let me know if it helps!

Determine whether the equation represents direct, inverse, joint, or combined variation.
y = 4x^3z^3

Answers

Answer: The retort to the peculiar proposed interrogate is definitively identified as ‘Joint Variation’, interchangeably acknowledged as ‘Combined Variation’.

Step-by-Step Explanation:

Given the mathematical statement,
Y = 4x^3z^3

Such coherently demonstrates the principle of a foreign variable, ‘y’, which whom varies directly as the product of at least two distinct or distinguishable quantities occur.

The mentioned is the precise definition of Joint Variation, where ‘y’ is jointly proportional to the product of the minimum agglomerate of two quantities, whilst a presence of a nonzero constant, k.


*I hope this helps.

what is 3^-8 x 3^-4 x 3^-2

Answers

Answer:

Value of given expression is 3⁻¹⁴

Step-by-step explanation:

Given expression:

3⁻⁸ x 3⁻⁴ x 3⁻²

Find:

Value of given expression

Computation:

⇒ 3⁻⁸ x 3⁻⁴ x 3⁻²

⇒ 3[⁻⁸⁻⁴⁻²]

⇒ 3⁻¹⁴

Value of given expression is 3⁻¹⁴

Can someone help me with this math homework please!

Answers

Answer:

Below

Step-by-step explanation:

From the graph the first local minimum is -16.18

The local maximum is 3.75

The second local minimum is -3.

Answer:

Over the interval (-3,0), the local minimum is -16.18Over the interval  [0,3], the local maximum is -3.75Over the interval [0,3], the minimum is -3

----------------------

Hope it helps..

Have a great day!!

can someone help me with the question?​

Answers

Corndogs broo likeee everyone knows this

Is this true or false

Answers

Answer:

I say it's TRUE

Step-by-step explanation:

I hope this help you

I assume that it’s true

simplify: 5 (6 - ab) + 2 (-7 + 3ab)

Answers

Answer:

30-5ab-14+6ab

16-ab ans

Answer:

[tex] \boxed{ab + 16} [/tex]

Step-by-step explanation:

5 (6 – ab) + 2 (-7 + 3ab)

[distribution property]

(6)(5) – (ab)(5) + (-7)(2) + (3ab)(2)

30 – 5ab – 14 + 6ab

[group like terms]

(6ab – 5ab) + (30 – 14)

ab + 16

1. What is the sum of 3/4 and 4/5?

Answers

3/4 + 4/5 =
15/20 + 16/20 = 31/20
= 1 and 11/20

please me in the math
Find the H.C.F
[tex] {x}^{2} - 4 \\ {x}^{3} + 8 \\ {x}^{2} + 5x + 6[/tex]
​it so simple

Answers

Step-by-step explanation:

Solution

First equation x ² - 4

= (x+2) (x-2)

Second equation = x ³ +8 + = x³+2^3

= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)

3 Third equation = x ² + 5x + 6

= x² + 6x= x +6 = x(x+6)-1(x+6)

(x-1) (x+6)

H.C. F= x-2

Find the measure of the missing angle using the triangle angle sum theorm.

Answers

Answer:

65°

Step-by-step explanation:

The sum of angles in a triangle =180

53°+62°+?°=180°

115°+?°=180°

?°=180°-115°

Rate the answer If you love everything I did n explanation

Answer:

65 degrees

Step-by-step explanation:

Angles in a triangle add up to 180, so 180 - 53 - 62 = 65.

Help please…

If (tan^30-1/tan0-1)-sec^20+1=0, find cot0

Answers

Answer:

dl5fgtrrfhrruf ofender fkufgj jjgglr

a line has slope 3 and y-intercept 4

Answers

Answer:

y = 3x+4

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 3x+4

Explain this to me I don't understand

Answers

Answer:

26.124

Step-by-step explanation:

SOH CAH TOA

tan 43 = about 0.933

than times it by 28 and get

26.124

Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 ​ p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus, 5 p=p=p, equals

Answers

Given:

The given equation is:

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

To find:

The value of p.

Solution:

We have,

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

Multiply both sides by 3.

[tex]3(16-3p)=3\left(\dfrac{2}{3}p+5\right)[/tex]

[tex]48-9p=2p+15[/tex]

Isolating the variable terms, we get

[tex]48-15=2p+9p[/tex]

[tex]33=11p[/tex]

Divide both sides by 11, we get

[tex]\dfrac{33}{11}=p[/tex]

[tex]3=p[/tex]

Therefore, the required solution is [tex]p=3[/tex].

Answer:

p=3

Step-by-step explanation:

i got it right on khan

Given that $x < 5$, rewrite $5x - |x - 5|$ without using absolute value signs. WILL GIVE BRAINLIEST

Answers

Answer:

6x-5 if x<5

Step-by-step explanation:

If x<5, then x-5<0.

If x-5 is negative, then |x-5)=-(x-5) or -x+5.

5x - |x - 5|

5x-(-x+5) provided x<5

5x+x-5 by distributive property

6x-5 combined liked terms

Complete table of values

Answers

Step-by-step explanation:

here's the answer to your question

expand this question (x+5)(x-3)

Answers

X•x + x•-3 + 5•x +5•-3
X^2+-3x+5x+-15
X^2+2x-15

tanA × cosecA = secA​

Answers

Step-by-step explanation:

L.H.S

tanA * cosecA

=sinA/cosA * 1/sinA

now cancel sinA and sinA

then,

1/cosA

= secA

= RHS

hence proved

The cost price of a box and a pen is Rs 120. The box is sold at 10% profita the pen is sold at 10% loss. If the selling price of the box is Rs 52 more than of the pen, calculate the profit or loss percent in the whole.​

Answers

Answer:

3.803% Profit

Step-by-step explanation:

First let us calculate total sales, then calculate the total cost, and then divide the two.

Sale: 120*1.1=132 and 52*.9=46.8

Cost: 120 and 52

Profit equation:

[tex]\frac{Net sales-COGS}{Net Sales} =Profit[/tex]

[tex]\frac{(132+46.8)-(120+52)}{(132+46.8)}[/tex]

Simplify:

[tex]\frac{6.8}{178.8} =.03803[/tex] or 3.803% Profit

Line r is parallel to line c.​

Answers

Answer:

I think ∆5 is the correct Ans

Answer:
Angle 5

Explanation:
It is given that there are parallel lines, so by opposite interior angles by the line intersecting the parallel lines angle 5 is congruent to angle 3.

Can someone help me with this math homework please!

Answers

9514 1404 393

Answer:

7/3-3y = 7/3x - 3

Step-by-step explanation:

1) The slope is given by the formula ...

  m = (y2 -y1)/(x2 -x1)

  m = (4 -(-3))/(3 -0) = 7/3

__

2) The y-intercept is the point where x=0:

  (x, y) = (0, -3) . . . . . y = -3

__

3) Then the slope-intercept equation is ...

  y = mx + b . . . . . . . line with slope m and y-intercept b

  y = 7/3x -3

Suppose f(x)=x^3 what is the graph of f(x+3)

Answers

Answer:

[tex]f(x + 3) = {(x + 3)}^{3} [/tex]

Shifted left with x-intercept at (-3,0) and the y-intercept at (0,27)

A cash register at a store contains $277 bills. There are six more $5 bills than $10 bills. The number of $1bills is two more than 24 times the number of $10 bills. How many bills of each kind are there

Answers

Answer: See explanation

Step-by-step explanation:

Your question isn't well written, the store contains $227 and not $277.

let c be the number of $1 bills

let f be the number of $5 bills

let t be the number of $10 bills.

Therefore, the equation will be:

1c + 5f + 10t = 227

Since there are six more $5 bills than $10 bills, therefore,

f = t+6

Also, the number of $1 bills is two more than 24 times the number of $10 bills and this will be:

c = 24t + 2

Now, we substitute the equation for f and c into the main equation and this will be:

1c + 5f + 10t = 277

1(24t + 2) + 5(t + 6) + 10t = 227

24t + 2 + 5t + 30 + 10t = 227

39t + 32 = 227

39t = 227 - 32

39t = 195

t = 195/39

t = 5

Therefore, there are 5 $10 bills

Since c = 24t + 2

c = 24(5) + 2

c = 120 + 2

c = 122

Therefore, there are 122 $1 bills

Since f = t+6

f = 5+6

f = 11

Therefore, there are 11 $5 bills.

Please solve this problem 9p-10=6+p?

Answers

Answer:

p=2

Step-by-step explanation:

9p-10=6+p

Subtract p from each side

9p-p-10=6+p-p

8p -10 =6

Add 10 to each side

8p -10+10 =6+10

8p =16

Divide each side by 8

8p/8 = 16/8

p =2

Answer:

p = 2

Step-by-step explanation:

1. 9p - 10 = 6 + p

2. 8p - 10 = 6

3. 8p = 16

4. p = 2

Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

Answers

Answer:

[tex]{ \tt{ {x}^{2} + {y}^{2} - 6x - 2y + 4 = 0 }} [/tex]

Center:

[tex]{ \tt{(3, \: 1)}}[/tex]

Radius:

[tex]{ \tt{radius = \sqrt{ {g}^{2} + {f}^{2} - c } }} \\ = \sqrt{36 + 4 - 4} \\ = 6 \: units[/tex]

If triangle LMQ is similar to triangle LNP, calculate the length of segment LP.

Answers

Answer:

LP = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{LM}{LN}[/tex] = [tex]\frac{LQ}{LP}[/tex] , substitute values

[tex]\frac{4}{10}[/tex] = [tex]\frac{LQ}{LQ+QP}[/tex]

[tex]\frac{2}{5}[/tex] = [tex]\frac{LQ}{LQ+9 }[/tex] ( cross- multiply )

5LQ = 2(LQ + 9) = 2LQ + 18 ( subtract 2LQ from both sides )

3LQ = 18 ( divide both sides by 3 )

LQ = 6

Then

LP = LQ + QP = 6 + 9 = 15

A block is being dragged along a horizontal surface by a constant horizontal force of size 45 N. It covers 8 m in the first 2 s and 8.5 m in the next 1 s. Find the mass of the block.

Answer: 15kg

Can anyone please explain this sum with proper working? ​

Answers

Answer:

Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a

F

=m

a

. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form

(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S

1

=v

1

⋅t

1

+a

2

t

1

2

, where S_1=8m, t_1=2s S

1

=8m,t

1

=2s , other quantities we don't know. The similar equation we can write for next time interval

(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S

2

=v

2

⋅t

2

+a

2

t

2

2

. where S_2=8.5m, t_2=1s S

2

=8.5m,t

2

=1s

Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.

(3) v_2=v_1+a\cdot t_1v

2

=v

1

+a⋅t

1

Substitute (3) to (2) we get

(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S

2

=(v

1

+a⋅t

1

)⋅t

2

+a

2

t

2

2

=v

1

⋅t

2

+a⋅t

1

⋅t

2

+a

2

t

2

2

From equation (1) and (4) we can exclude unknown quantity v_1v

1

, then remain only one unknown aa. For determine aa we dived (1) by t_1t

1

, (4) by t_2t

2

to find the average speed at time intervals and subtract (1) from (4).

(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-

t

2

S

2

t

1

S

1

=v

1

+a⋅t

1

+a

2

t

2

−(v

1

+a

2

t

1

)=a

2

t

1

+t

2

− For acceleration we get

(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(

t

2

S

2

t

1

S

1

)/(t

1

+t

2

)=2⋅

3s

(8.5m/s−4m/s)

=3ms

−2

For mass from second Newton's law we get

(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=

a

F

=

3ms

−2

45N

=15kg

Answer: The mass of the block is 15 kg

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