4. Given the following pattern of shapes, choose the mathematical expression showing th
changes for each iteration if b is the number of boxes in the previous iteration
a) b + 1
b) b + 2
c) 6-1
d) 6-2​

Answer:

b y=2.4x -1.8

Step-by-step explanation:

the equation y=2.4x -1.8 represents 2.4 from it

Answer:

31 Feets

Step-by-step explanation:

Given the expression for the height of a baseball:

Height(t) = -16t^2 +64t +3

Height in Feets ; time (t) in seconds

Height of baseball after 3.5 seconds :

Height(3.5) = -16(3.5)^2 + 64(3.5) + 3

Height = - 16(12.25) + 64(3.5) + 3

Height = - 196 + 224 + 3

Height = 31 Feets

Height after 3.5 seconds = 31 feets

Divide total feet by feet in a mile:

63,756/5280 = 12.075 miles

Divide 70 minutes by 60 minutes per hour:

70/60 = 1.166666 hours( round to 1.17)

Miles per hour = total miles/ total hours:

12.075/1.17 = 10.32 miles per hour

Answer:

There is no solution

Step-by-step explanation:

they all subtract eachother out

Step-by-step explanation:

Since it's a direct variation

y = kx

where k is the constant of proportionality

To find the value of y when x = –0.5 we must first find the relationship between the variables

When

x = 3

y = 2

2 = 3k

Divide both sides by 3

[tex]k = \frac{3}{2} [/tex]

So the formula for the variation is

When x = - 0.5 or - 1/2

[tex]y = \frac{3}{2} ( - \frac{1}{2} )[/tex]

We have the final answer as

Hope this helps you

Answer:

tan(<G) = [tex] \frac{HI}{GI} [/tex]

Step-by-step explanation:

Given:

Right triangle ∆GHI,

Required:

Equivalent of tan(<G)

SOLUTION:

Recall the acronym for trigonometric ratios of angles in a right triangle: SOHCAHTOA.

Thus, the TOA in the acronym above stands for:

Tan(θ) = side opposite to θ ÷ side adjacent to θ

Where,

θ is the angle of interest = <G

Opposite side = HI

Adjacent side = GI

The equivalent of tan(<G) = [tex] \frac{HI}{GI} [/tex]

Answer:

1. Please refer to attached diagram.

2. 135

3. 135

Step-by-step explanation:

Given that

80%examines passed in English, n(E) = 80%

70%In mathematics, n(M) = 70%

and 60% in both subjects, n(E [tex]\cap[/tex] M)  = 60%

45 examines failed in both subject.

1. Venn Diagram is attached in the answer area.

One circle represents the pass examines in Maths and

Other circle represents the pass examines in English.

Rectangle represents the total number of examines that appeared for the exam.

Rectangle minus the area of union of circles represent the number of students who failed in both subjects.

2. To find the number of examines who passed in only one subject.

i.e. n(E) - n(E [tex]\cap[/tex] M) + n(M) - n(E [tex]\cap[/tex] M) = (80 - 60 + 70 - 60)% = 30%

Let us find the number of students who passed in atleast one subject:

[tex]n(E\cup M) = n(E) +n(M)-n(E \cap M)\\\Rightarrow n(E\cup M) = (80 +70-60)\% = \bold{90\%}[/tex]

So, number of students who failed in both subjects = 100 - 90% = 10% of total students = 45

So, total number of students appeared = 450

So, number of examines who passed in only one subject = 450 [tex]\times[/tex] 30% = 135

3. Number of students who failed in mathematics.

100% - Passed in Mathematics = 100% - 70% = 30% of 450 = 135

Answer:

B) $73

Step-by-step explanation:

add all of your values and divide by the amount of values

52+55+55+55+59+64+66+68+72+73+73+73+73+75+81+81+83+84+84+86+87=

1,499

1,499 divided by 21 = 71.3809523...

which rounds to 73

HOPE THIS HELPS!!! :)

The median is of $48 in the stem leaf plot and option B is correct.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

The median of a data-set is the value that separates the bottom 50% from the upper 50% of values.

The graph has 16 values, already ordered.

It is an even number, hence the median is the mean of the 8th and the 9th values, which considering the key are both 48,

Hence, the median is of $48 and option B is correct.

To learn more on Statistics click:

https://brainly.com/question/30218856

#SPJ3

Stem-and-Leaf Plot shows the amount of money each student spends

on travel per day in dollars. What is the median for the data in this graph?

Stem Leaf

A) $35

B) $48

C) $53

D) $54

Answer:

Lets start with the top row.

First, add the two values.

5+14=19

Now, divide each value by the total.

5/19=0.26315789473

Round the decimal to the nearest hundredth.

5/19=0.26

14/19=0.73684210526

Round it to the nearest hundredth.

14/19=0.74

Now, The second row.

Add the two values.

16+7=23

Divide the first value by the total.

16/23=0.69565217391

Round it to the nearest hundredth.

16/23=0.70

Divide the second value by the total.

7/23=0.30434782608

Round to the nearest hundredth.

7/23=0.30

Done!

Answer:

Row 1: 0.26 0.74

Row 2: 0.70 0.30

Step-by-step explanation:

Khan

Answer:

a⁴b⁴ - c⁴

Step-by-step explanation:

The difference of squares formula states that (a - b)(a + b) = a² - b². In this case, a = a²b² and b = c² so a² - b² = (a²b²)² - (c²)² = a⁴b⁴ - c⁴.

Answer:

a^4b^4 - c^4.

Step-by-step explanation:

(a²b²-c²)(a²b²+c²)

Difference of 2 squares:

= (a²b²)^2 - (c²)^2

= a^4b^4 - c^4.

Answer:

x = ±4

Step-by-step explanation:

4x^2 = 64

Divide each by 4

4x^2 /4= 64/4

x^2 = 16

Take the square root of each side

sqrt(x^2) = ±sqrt(16)

x = ±4

Answer:

[tex]\boxed{\boxed{x=\pm 4}}[/tex]

Step-by-step explanation:

[tex]4x^2 = 64[/tex]

Divide both sides by 4.

[tex](4x^2)/4 = 64/4[/tex]

Simplify.

[tex]x^2 =16[/tex]

Take the square root on both sides.

[tex]\sqrt{x^2 } =\pm \sqrt{16}[/tex]

Simplify.

[tex]x=\pm 4[/tex]

Answer:

9). h² - 7h + 11

10). 2a² + 14a + 16

11). 3

12). 2h + 4x - 3

Step-by-step explanation:

9). If j(x) = x² + x - 1

  j(h - 4) = (h - 4)² +(h - 4) - 1

             = h² - 8h + 16 + h - 4 - 1

             = h² - 7h + 11

10). If f(x) = 2x² + 2x - 8

     f(a + 3) = 2(a + 3)² + 2(a + 3) - 8

                 = 2(a² + 6a + 9) + 2a + 6 - 8

                 = 2a² + 12a + 18 + 2a - 2

                 = 2a² + 14a + 16

11). If f(x) = 3x - 1

   [tex]\frac{f(x+h)-f(x)}{h}=\frac{3(x+h)-1-(3x-1)}{h}[/tex]

                     [tex]=\frac{3x+3h-1-3x+1}{h}[/tex]

                     = 3

12). If, f(t) = 2t² - 3t + 7

     [tex]\frac{f(x+h)-f(x)}{h}=\frac{2(x+h)^{2}-3(x+h)+7-(2x^2-3x+7)}{h}[/tex]

                        [tex]=\frac{2(x^2+h^2+2hx)-3x-3h+7-2x^2+3x-7}{h}[/tex]

                        [tex]=\frac{2x^2+2h^2+4hx-3x-3h+7-2x^2+3x-7}{h}[/tex]

                        [tex]=\frac{2h^2+4hx-3h}{h}[/tex]

                        = 2h + 4x - 3

Answer:

A & C

Step-by-step explanation:

-9 is a whole number is rational

Answer:

A 0.6 0.9 1.2 1.5 1.8

B 3/8 5/8 7/8 9/8 11/8

C -7 -5 -3 -2 -1

D 1, 1 1/3, 1 2/3, 2, 2 1/3

E 0.61 0.72 0.83 0.94 1.05

Step-by-step explanation:

Answer:

A.  x  x   1.2  1.5  1.8

B.  3/8   x   x  x  1 2/8

C.  x  x  -3  -2  -1

D.   0  x  x  x  5 1/3

E.   x  x   0.83  0.94  1.05

Step-by-step explanation:

hope it helped

Answer:

A. 2 4/5

Step-by-step explanation:

To find how many hours she worked for $210, you must get the amount of money she gets in 1 hour.

Because she charges $43 dollars every hour, and fines a fee of $30 flat, we must add both of the amount to get how many she earns in 1 hour.

So:

$45 + $30= $75

She earn $75 in 1 hour.

Next, divide $210 dollars that she earned for working for hour(s) to the amount of money she earned in 1 hour to find how many hours she worked.

So:

$210 ÷ $75= 2.8 hours

The answer is 2.8 hours

Because the given answers is in fraction, we must change the decimal into a fraction.

To change a decimal into a fraction, you must place the decimal over its place value.

Because 8 in the decimal 2.8 is in the tenths place, you must place it over 10

So:

2.8 into a decimal is 2 8/10

Simplify (only simplify if possible):

Divide 8 and 10 to their GCF which is 2.

So:

8 ÷ 2= 4

10 ÷ 2= 5

So the fraction and the answer is now:

2 4/5

I hope this helps! I'm sorry if it's wrong and too complicated.

Answer:

Solution :  (− 3, 5, 6)

Step-by-step explanation:

We have the following system of equations that we have to solve for,

[tex]\begin{bmatrix}x+3y-z=6\\ 4x-2y+2z=-10\\ 6x+z=-12\end{bmatrix}[/tex]

To solve this problem we can start by writing the matrix with their respective coefficients --- (1)

[tex]\begin{bmatrix}1&3&-1&|&6\\ 4&-2&2&|&-10\\ 6&0&1&|&-12\end{bmatrix}[/tex]

Now we can reduce this to row echelon form, receiving our solution --- (2)

[tex]\begin{pmatrix}1&3&-1&6\\ 4&-2&2&-10\\ 6&0&1&-12\end{pmatrix}[/tex] Swap row 1 and 3,

[tex]\begin{pmatrix}6&0&1&-12\\ 4&-2&2&-10\\ 1&3&-1&6\end{pmatrix}[/tex] Cancel leading coefficient in row 3,

[tex]\begin{pmatrix}6&0&1&-12\\ 0&-2&\frac{4}{3}&-2\\ 0&3&-\frac{7}{6}&8\end{pmatrix}[/tex] Swap row 2 and 3

[tex]\begin{pmatrix}6&0&1&-12\\ 0&3&-\frac{7}{6}&8\\ 0&-2&\frac{4}{3}&-2\end{pmatrix}[/tex] Cancel leading coefficient in row 3

[tex]\begin{pmatrix}6&0&1&-12\\ 0&3&-\frac{7}{6}&8\\ 0&0&\frac{5}{9}&\frac{10}{3}\end{pmatrix}[/tex]

At this point you can see that we have to cancel the leading coefficient in each row, to row echelon form. Continuing this pattern we have the following matrix,

[tex]\begin{bmatrix}1&0&0&|&-3\\ 0&1&0&|&5\\ 0&0&1&|&6\end{bmatrix}[/tex]

As you can see, x = - 3, y = 5, and z = 6, giving us a solution of (− 3, 5, 6). This is the fourth option.

Answer:

You just answered my question so you can ask yours, what a sped. Now i'm doing the same thing.

Step-by-step explanation:

Answer:

The correct option are;

1) D. A quadratic equation of this form can always be solved using the square root property

2) B. Isolate the quantity being squared

3) C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X so divide both sides by 2 before applying the square root property

Step-by-step explanation:

Where the quadratic equation is of the form x² = b, the square root property method can be used to solve the equation. Due to the nature of square roots, putting a plus-minus before the square root of the constant on the right hand side of the equation after taking the square roots of both sides of the equation, two answers are produced.

It is however to first isolate the term with the squared variable, after which the square root of both sides of the equation is taken.

Hi there! :)

Answer:

[tex]\huge\boxed{V = 359.01 mm^{3} }[/tex]

Use the formula V = 1/3(bh) to solve for the volume of the cone where b = πr² where π ≈ 3.14:

Find the area of the base:

b = π(7)²

b = 49π

b = 153.86 mm²

Find the volume:

V = 1/3(153.86 · 7)

V = 1/3(1077.02)

V = 359.006 ≈ 359.01 mm³.

Answer: 1880 pounds

Step-by-step explanation: when you take the average adult weight, around 160 lbs. you multiply that by eight. you get 1280. then you estimate that each of the children weigh around 100 lbs, then you add 600 to 1280 and get 1,880 lbs

Answer:

1) Please find attached the box and whiskers chart created with Excel

2) The conclusions are;

a) The measure of central tendency (the mean and the median) are approximately equal,

b) The standard deviation for the first five data points is 14.17 while the standard deviation for the whole ten data points is 23.99 as such the data values appeared more clustered at the center and show wider spread towards right ends of the chart

Due to the lack of correlation between the standard deviation and the five data values, the data is not uniformly distributed

Step-by-step explanation:

The given data is as follows;

1,    2,    3,    4,   5,    6,    7,    8,    9,    10

15, 18,   22,  32, 50, 50,  55, 56,  81,    81

The first quartile Q₁ = 22

The second quartile, Q₂ (Median) = 50

The third quartile, Q₃ = 56

The interquartile range IQR = 56 - 22 = 34

The minimum value = 15

The maximum value = 81

The mean = 46

The standard deviation = 23.99

Therefore, the measure of central tendency (the mean and the median) are approximately equal,

The data values appeared more clustered at the center and show wider spread towards the left and right ends of the chart

The standard deviation for the first five data points is 14.17 while the standard deviation for the last five data points is

Due to the lack of correlation between the standard deviation and the five data values, the data is not uniformly distributed.

Answer:

Area of quadrilateral ABCD = 29.79 units² (Approx)

Step-by-step explanation:

Area of triangle ABD

s = (3.48+8.66+8.6) / 2

s = 10.37

Area of triangle ABD = √10.37(10.37-8.66)(10.37-8.6)(10.37-3.48)

Area of triangle ABD = √212.4616

Area of triangle ABD = 14.5760625 unit²

Area of triangle ACD

s = (3.54+8.84+8.6) / 2

s = 10.49

Area of triangle ACD = √10.49(10.49-8.6)(10.49-8.84)(10.49-3.54)

Area of triangle ACD = √227.3558

Area of triangle ACD = 15.0783222 unit²

Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle ACD

Area of quadrilateral ABCD = 14.5760625 unit² + 15.0783222 unit²

Area of quadrilateral ABCD = 29.6542units²

Area of quadrilateral ABCD = 29.79 units² (Approx)

Mistake found

3x-2(2x-4)=2

3x - 4x - 8 = 2 instead of 3x - 4x + 8 = 2

Correct answer

x= -13 y= -30

Answer:

See below.

Step-by-step explanation:

So we have the system of equations:

[tex]3x-2y=21 \text{ and } y=2x-4[/tex]

The student took the following steps:

[tex]3x-2(2x-4)=21\\3x-4x-8=21\\-x-8=21\\-x=29\\x=-29\\y=2(-29)-4=-58-4=-62[/tex]

The student's mistake is in step 2. He/she distributed incorrectly. You are supposed to distribute the -2 to both terms, so it should be -4x plus 8, since -2 times -4 is positive 8. Fixing that mistake, we will have:

[tex]3x-2(2x-4)=21\\3x-4x+8=21 \\-x+8=21\\-x=13\\x=-13\\y=2(-13)-4=-26-4=-30[/tex]

Thus, the final answers should be (-13, -30).

Answer:

[tex](x + 6)^2 = 49[/tex]

[tex]x = 1[/tex]    or [tex]x = -13[/tex]

Step-by-step explanation:

Given

[tex]12x = 13 - x^2[/tex]

Using Completing the Square

[tex]12x = 13 - x^2[/tex] ---- Add [tex]x^2[/tex] to both sides

[tex]x^2 + 12x = 13 - x^2 + x^2[/tex]

[tex]x^2 + 12x = 13[/tex]

Divide the coefficient of x by 2; then add the square to both sides

[tex]x^2 + 12x + 6^2 = 13 + 6^2[/tex]

[tex]x^2 + 12x + 36 = 13 + 36[/tex]

[tex]x^2 + 12x + 36 = 49[/tex]

Factorize

[tex]x^2 + 6x + 6x + 36 = 49[/tex]

[tex]x(x + 6) + 6(x + 6) = 49[/tex]

[tex](x + 6)(x + 6) = 49[/tex]

[tex](x + 6)^2 = 49[/tex]

Hence, the equation is [tex](x + 6)^2 = 49[/tex]

Solving further

Take square root of both sides

[tex](x + 6) = \sqrt{49}[/tex]

[tex]x + 6 = \±7[/tex]

[tex]x = \±7- 6[/tex]

This implies that

[tex]x = 7 - 6[/tex]     or [tex]x = -7 -6[/tex]

[tex]x = 1[/tex]    or [tex]x = -13[/tex]

HEnce, the solutions are [tex]x = 1[/tex]    or [tex]x = -13[/tex]

Answer:

(x+6)^2=49 and  x=−6±7

Step-by-step explanation:

Answer:

30x+160

simple all you had to do is 10*3x and 8x2=16 and 10*16 and you will get 30x+160

Step-by-step explanation:

Answer:

30x + 80x^2

Step-by-step explanation:

10 (3x + 8x^2)

10 * 3x + 10 * 8x^2

30x + 80x^2

Answer:

2

Step-by-step explanation:

3x^2

The coefficient is 3

The variable is x

The exponent is 2

Answer:

Step-by-step explanation:

[tex] \mathsf{3(2 \frac{1}{2} - 1) + \frac{3}{10} }[/tex]

Convert mixed number to improper fraction

[tex] \mathrm{3( \frac{5}{2} - 1) + \frac{3}{10} }[/tex]

Calculate the difference

⇒[tex] \mathrm{3( \frac{5 \times 1}{2 \times 1} - \frac{1 \times 2}{1 \times 2} }) + \frac{3}{10} [/tex]

⇒[tex] \mathrm{ 3 \times( \frac{5}{2} - \frac{2}{2}) } + \frac{3}{10} [/tex]

⇒[tex] \mathrm{3 \times ( \frac{5 - 2}{2} ) + \frac{3}{10} }[/tex]

⇒[tex] \mathrm{3 \times \frac{3}{2} + \frac{3}{10} }[/tex]

Calculate the product

⇒[tex] \mathrm{ \frac{3 \times 3}{1 \times 2} + \frac{3}{10} }[/tex]

⇒[tex] \mathrm{ \frac{9}{2} + \frac{3}{10}} [/tex]

Add the fractions

⇒[tex] \mathsf{ \frac{9 \times 5}{2 \times 5} + \frac{3 \times 1}{10 \times 1} }[/tex]

⇒[tex] \mathrm{ \frac{45}{10} + \frac{3}{10} }[/tex]

⇒[tex] \mathrm{ \frac{45 + 3}{10 } }[/tex]

⇒[tex] \mathrm{ \frac{48}{10} }[/tex]

Reduce the numerator and denominator by 2

⇒[tex] \mathrm{ \frac{24}{5} }[/tex]

Further more explanation:

Addition and Subtraction of like fractions

While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

For example :

Add : [tex] \mathsf{ \frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} } = \frac{4}{5} [/tex]

Subtract : [tex] \mathsf{ \frac{5}{7} - \frac{4}{7} = \frac{5 - 4}{7} = \frac{3}{7} }[/tex]

So, sum of like fractions : [tex] \mathsf{ = \frac{sum \: of \: their \: number}{common \: denominator} }[/tex]

Difference of like fractions : [tex] \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }[/tex]

Addition and subtraction of unlike fractions

While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.

For example:

[tex] \mathsf{add \: \frac{1}{2} \: and \: \frac{1}{3} }[/tex]

L.C.M of 2 and 3 = 6

So, ⇒[tex] \mathsf{ \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} }[/tex]

⇒[tex] \mathsf{ \frac{3}{6} + \frac{2}{6} }[/tex]

⇒[tex] \frac{5}{6} [/tex]

Multiplication of fractions

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:

[tex] \mathsf{4 \times \frac{3}{2} = \frac{4 \times 3}{2} = \frac{12}{2} = 6}[/tex]

Multiplication for [tex] \mathsf{ \frac{6}{5} \: and \: \frac{25}{3} }[/tex] is done by the similar process

[tex] \mathsf{ = \frac{6}{5} \times \frac{25}{3} = 2 \times 5 \times 10}[/tex]

Hope I helped!

Best regards!

[tex](3x^2 - 4x + 1) + (-x^2 + x - 9)=\\3x^2-4x+1-x^2+x-9=\\2x^2-3x-8[/tex]

Answer:

c=13.42

Step-by-step explanation:

[tex]A^2+B^2=C^2\\6^2+14^2=C^2\\C^2=144+36\\C^2=180\\\sqrt{c^2}=\sqrt{180} \\c=13.42[/tex]

Answer:

Step-by-step explanation:

m