Answer:
a
Explanation:
What is always true of a salt
(a) shows both acidic and basic properties
(b) creates a neutral pH in solution
(c) is an ionic compound formed from an acid-base reaction
(d) can react with acid but not with a base
This week's imide synthesis involves two reactions. In the first reaction (24A), a(n) ________ bond is formed between the two reactants. Hint: What type of functional group is formed
Answer:
C - N Bond formation.
Explanation:
Imide synthesis is a chemical reaction in organic chemistry which consists of two acyl groups which bond to nitrogen atom. The compound structure is related to acid anhydrides. Imides are monoacyl which are used as valuable intermediates in organic synthesis.
write the formula two atom of iron and three atoms of oxygen
Answer:
Fe2O3 is the formula this is your correct answer
4. How many electrons are in the electron shell closest to the nucleus?
Answer:
2
Explanation:
there are 2 electrons close to the nucleus
Answer:
2
Explanation:
2*n^2, where n is the electron shell.
If we plug 1 in, we will get 2*1, which is 2.
what is interpolation?
Explanation:<3 sorry.
How many moles of AICI3 are produced?
Answer:
please correct it, the question is incomplete
What is the total number of atoms in one formula unit of MgSO4.7H2O?
Answer:
11.
O4 means 4 atoms of oxygen. H2O
has one atom of oxygen, so seven "units" of
H2O has 7.
An 11.5 mL portion of 0.162 M H3PO4 (aq) is to be titrated with 0.229 M NaOH (aq). What volume (in mL) of NaOH will it take to reach the equivalence point
Answer:
8.14 mL of NaOH are required to reach the equivalence point.
Explanation:
Formula for titration is
mmoles of base = mmoles of acid.
Equality is fullfilled at the equivalence point.
M of acid . volume of acid = M of base . volume of base
Let's replace with data given:
11.5 mL . 0.162M = 0.229 M . volume of base
Volume of base = (11.5 mL . 0.162M ) / 0.229M
Volume of base = 8.14 mL
8.14 mL of NaOH are required to reach the equivalence point.
Nitrogen gas and chlorine gas will react to form nitrogen monochloride gas. 5 moles of nitrogen and 10 moles of chlorine are mixed in a previously evacuated 2 L flask at 500 K. After equilibrium has been established, there are 3 moles of NCl (g) present. What is the equilibrium constant (Kc) for this reaction at 500 K
Answer:
0.30
Explanation:
Step 1: Calculate the known initial and equilibrium molar concentrations
[N₂]i = 5 mol/2 L = 2.5 M
[Cl₂]i = 10 mol/2 L = 5 M
[NCl]e = 3 mol/2 L = 1.5 M
Step 2: Make an ICE chart
N₂(g) + Cl₂(g) ⇄ 2 NCl(g)
I 2.5 5 0
C -x -x +2x
E 2.5-x 5-x 2x
Step 3: Find the value of x
We know that [NCl]e = 2x = 1.5 ⇒ x = 0.75 M
Step 4: Calculate the concentrations at equilibrium
[N₂]e = 2.5-x = 2.5-0.75 = 1.75 M
[Cl₂]e = 5-x = 5-0.75 = 4.25 M
[NCl]e = 1.5 M
Step 5: Calculate the equilibrium constant (Kc)
Kc = [NCl]² / [N₂] × [Cl₂]
Kc = 1.5² / 1.75 × 4.25 = 0.30
Make tag question.
neither of them plays cricket,......?
Answer:
neither of them plays cricket,does anyone?
Explanation:
I know you will think I its weird but it is the rule of grammar and 100% correct!
Answer:
neither of them plays cricket, do you?
Explanation:
A certain liquid has a normal freezing point of and a freezing point depression constant . Calculate the freezing point of a solution made of of alanine () dissolved in of .
The question is incomplete, the complete question is;
A certain liquid X has a normal freezing point of 5.40 °C and a freezing point depression constant K=3.05 ?kg mol solution made of 46.1g of alanine (C3H,NO2) dissolved in 750. g of i. Round your answer to 3 significant digits.
Answer:
3.3 °C
Explanation:
If ∆T= K m I
Where;
∆T = freezing point depression
K = freezing point constant
m= morality of solution
i= Van't Hoff factor
Number of moles of solute = 46.1 g/89.09 g/mol = 0.52 moles
Molality of solution = 0.52 moles /750 ×10-3Kg
= 0.69 m
∆T= 3.05 × 0.69 × 1
∆T= 2.10 °C
Freezing point of solution the solution = freezing point of pure solvent - freezing point depression
= 5.40°C - 2.10 °C
= 3.3 °C
how many grams of NaOH will make 1M of its aqueous solution in 1000cm3
Answer: The mass of NaOH is 40 g
Explanation:
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex] .....(1)
Given values:
Molarity of NaOH = 1 M
Molar mass of NaOH = 40 g/mol
Volume of the solution = [tex]1000cm^3=1000 mL[/tex] (Conversion factor: [tex]1cm^3=1mL[/tex])
Putting values in equation 1, we get:
[tex]1=\frac{\text{Mass of NaOH}\times 1000}{40\times 1000}\\\\\text{Mass of NaOH}=\frac{1\times 40\times 1000}{1000}=40g[/tex]
Hence, the mass of NaOH is 40 g
When the nuclide polonium-218 undergoes alpha decay:
a. The name of the product nuclide is _____.
b. The symbol for the product nuclide is _____.
Write a balanced nuclear equation for the following: The nuclide polonium-218 undergoes alpha emission.
Answer:
a): The name of the product nuclide is lead-214
b): The symbol of the product nuclide is Pb-218
Explanation:
There are three types of decay processes:
Alpha decayBeta decayGamma decayAlpha decay is the decay process that happens when a heavy nucleus decays into a light nucleus with the release of an alpha particle. This alpha particle carries a charge of +2 units and has a mass of 4 units. It is also known as the helium nucleus. The general equation for this decay process is:
[tex]_Z^A\textrm{X} → _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha[/tex]
The nuclear equation for the alpha decay of Po-218 follows:
[tex]_{84}^{218}\textrm{Po}\rightarrow _{82}^{214}\textrm{Pb}+_2^4\alpha[/tex]
Hence, the name of the product nuclide is lead-214 and the symbol is Pb-218.
Determine the empirical formula of a compound having the following percent composition by mass: K: 24.74%; Mn: 34.76%; O: 40.50%
Answer: The empirical formula of the compound is [tex]KMnO_4[/tex]
Explanation:
The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Let the mass of the compound be 100 g
Given values:
% of K = 24.7%
% of Mn = 34.76%
% of O = 40.50%
Mass of K = 24.7 g
Mass of Mn = 34.76 g
Mass of O = 40.50 g
To calculate the empirical formula of a compound, few steps need to be followed:
Step 1: Calculating the number of moles of each elementWe know:
Molar mass of K = 39.10 g/mol
Molar mass of Mn = 54.94 g/mol
Molar mass of O = 16 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol[/tex]
[tex]\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol[/tex]
[tex]\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol[/tex]
Step 2: Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.632 moles[tex]\text{Mole fraction of K}=\frac{0.632}{0.632}=1[/tex]
[tex]\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1[/tex]
[tex]\text{Mole fraction of O}=\frac{2.53}{0.632}=4[/tex]
Step 3: Writing the mole fraction as the subscripts of each of the elementThe empirical formula of the compound becomes [tex]K_1Mn_1O_4=KMnO_4[/tex]
Hence, the empirical formula of the compound is [tex]KMnO_4[/tex]
The empirical formula of the compound is KMnO₄
Data obtained from the question Potassium (K) = 24.74%Manganese (Mn) = 34.76%Oxygen (O) = 40.50%Empirical formula =? How to determine the empirical formulaDivide by their molar mass
K = 24.74 / 39 = 0.634
Mn = 34.76 / 55 = 0.632
O = 40.50 / 16 = 2.531
Divide by the smallest
K = 0.634 / 0.632 = 1
Mn = 0.632 / 0.632 = 1
O = 2.531 / 0.632 = 4
Therefore, the empirical formula of the compound is KMnO₄
Learn more about empirical formula:
https://brainly.com/question/24297883
What is the unite of Kc ?
Answer:
There is no unit for Kc
Explanation:
How many grams of potassium chloride will be needed to produce
829 grams of zinc chloride?
Answer:
[tex]2KCl + Zn {}^{2 + } → 2K {}^{ + } + ZnCl _{2} \\ molecular \: mass \: of \: zinc \: chloride = 65 + (35.5 \times 2) = 136 \: g \\ molecular \: mass \: of \: potassium \: chloride = 39 + 35.5 = 74.5 \: g
What is the pressure, in atm, exerted by 41.6 g oxygen in a 22.0L container at 30.0C ?
Answer:
1.47 atm
Explanation:
Step 1: Calculate the moles corresponding to 41.6 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
41.6 g × 1 mol/32.00 g = 1.30 mol
Step 2: Convert 30.0 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 30.0 + 273.15 = 303.2 K
Step 3: Calculate the pressure exerted by the oxygen
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 1.30 mol × (0.0821 atm.L/mol.L) × 303.2 K / 22.0 L = 1.47 atm
A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could use to make a buffered solution.
a. HCI/NaOH
b. HCOOH/ NaHCOO
c. HNO2/H2SO3
d. NaNO3/ HNO3
Answer:
b. HCOOH/ NaHCOO.
Explanation:
A buffer system may be formed in one of two forms:
A weak acid with its conjugate base.A weak base with its conjugate acid.Chose the pairs below that you could use to make a buffered solution.
a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.
b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.
c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.
d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.
Which statement best describes the intermolecular forces between H2
molecules and NH3 molecules in the liquid phase?
A. Dipole-dipole forces are the strongest force between H2
molecules, and Van der Waals forces are the strongest force
between NH3 molecules.
B. Van der Waals forces are the strongest force between H2
molecules, and hydrogen bonding is the strongest force between
the NH3 molecules.
C. Hydrogen bonding is the strongest force between H, molecules
and between NH3 molecules.
D. Van der Waals forces are the strongest force between H2
molecules and between NH3 molecules.
Answer:
D. Van der Waals forces are the strongest force between H2
molecules and between NH3 molecules.
Explanation:
Van der Waal’s forces are the forces which arises due to disturbance in the electron density of the molecule.
These are usually found in non polar molecules. Hence N2 is said to exhibit this force.
Out of these Van der Waals is the weakest force.
Consider the reaction of NO and CO to form N2 and CO2, according to the balanced equation: 2 NO (g) + 2 CO (g) → N2 (g) + 2 CO2 (g) Identify the excess reactant, the limiting reactant, and the product(s) using the molecular art. (Black spheres are carbon, blue spheres are nitrogen, and red spheres are oxygen.)
The image is not given in the question, it is attached below:
Answer: The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.
Explanation:
In the given image:
Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms
The combination of 1 black and 2 red spheres will represent carbon dioxide [tex](CO_2)[/tex] compound
The combination of 2 blue spheres will represent nitrogen molecule [tex](N_2)[/tex]
The combination of 1 blue and 1 red sphere will represent nitrogen monoxide [tex](NO)[/tex] compound
The combination of 1 black and 1 red sphere will represent nitrogen monoxide [tex](NO)[/tex] compound
Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.
Excess reagent is defined as the reagent which is left behind after the completion of the reaction.
We are given:
Given moles of NO = 6 moles
Given moles of CO = 4 moles
For the given chemical equation:
[tex]2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)[/tex]
By stoichiometry of the reaction:
If 2 moles of CO reacts with 2 moles of NO
So, 4 moles of CO will react with = [tex]\frac{2}{2}\times 4=4mol[/tex] of NO
As the given amount of NO is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Thus, CO is considered a limiting reagent because it limits the formation of the product.
Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.
They allow atoms to _______ and form ____________ or ____________ substance.
Answer:
They allow atoms to combine and form new substance.
ASAP!!!!! The data table below shows a person’s heart rate measured in beats per minute (bpm) at five different times in the beginning of a day. What causes the change in heart rate over time?
1. tired
2. increased activity
3. passing of time
4. forgetting to eat
Note: Please show all work and calculation setups to get full credit. T. he following may be used on this assignment: specific heat of (water=4.184 J/g oC; ice=2.03 J/g oC; steam=1.99 184 J/g oC); heat of fusion of water=80. cal/g; heat of vaporization=540 cal/g; 1cal=4.184J.
Calculate the energy required (in J) to convert 25 g of ice at -15 oC to water at 75 oC.
Answer:
1.7 × 10⁴ J
Explanation:
Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C
We will use the following expression.
Q₁ = c(ice) × m × ΔT
Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J
Step 2: Calculate the heat required to melt 25 g of ice
We will use the following expression.
Q₂ = C(fusion) × m
Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C
We will use the following expression.
Q₃ = c(water) × m × ΔT
Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J
Step 4: Calculate the total heat required
Q = Q₁ + Q₂ + Q₃
Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J
For a gas of N identical molecules of molecular volume Vm in total volume V at temperature T, the number of ways of locating the N molecules in the volume is
Answer:
[tex]\left(\frac{V_m}{V}\right)^N[/tex]
Explanation:
Given :
Number of identical volumes = N
The molecular volume = [tex]V_m[/tex]
The total volume = V
Temperature = T
Therefore, the number of the ways for locating one molecule within the volume V is : [tex]\frac{V_m}{V}[/tex]
There are N molecules.
So, the total umber of ways of locating N molecules is [tex]\left(\frac{V_m}{V}\right)^N[/tex]
Your Turn!
How many electrons are required to complete
the octet around nitrogen, when it forms N2
?
A. 2
B. 3
C. 1
D. 4
E. 6
Answer:
because.......
...........
.........
Give two ways to make salt conduct.
Answer:
I think u willl get the answer fast in......
Answer:
this is because when a salt dissolves, its dissociated ions can move freely in solution, allowing a charge to flow. The resulting solution will conduct electricity because it contains ions.
Explanation:
Please Help !! This is an Earth science lab question.
Explain why erosion occurs on the outside of a meander and deposition on the inside of a meander.
Answer:
The sideways movement occurs because the maximum velocity of the stream shifts toward the outside of the bend, causing erosion of the outer bank. At the same time the reduced current at the inside of the meander results in the deposition of coarse sediment, especially sand
What makes up the central nervous system?
a.
motor neurons.
b.
interneurons.
c.
brain and spinal cord.
d.
liver and pancreas.
Answer:
c.
brain and spinal cord.
Explanation:
Calculate the amount of energy produced by the conversion of 50.0 kg of mass into energy. Use 3.00 x 108 m/s for the speed of light. Round to 3 significant digits.
Which setup will solve this problem?
Answer:
tanong mo sa teacher mo ok
Answer:
E = (50.0 kg)(3.00 x 108 m/s)2
Explanation:
if you start with .235 g nickel, tell me how much of the compound product will be produced.
Please show work
Answer:
Explanation:
There are many compounds that are produced from Nickel.
Molar mass of Ni = 58.7g
So for 0.235g Ni, there are 0.004M.
By conservation of mass, the compound produced will contain 0.04M of Ni.
Molar mass of nickel=58g/mol
Given mass=0.235g[tex]\\ \sf\longmapsto No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}[/tex]
[tex]\\ \sf\longmapsto \dfrac{0.235}{58}[/tex]
[tex]\\ \sf\longmapsto 0.004mol[/tex]
Using law of conservation of mass the compound will contain 0.04moles of Ni
