3. The size of a red blood cell is 0.000007 m and the size of a plant
cell is 0.0000127 m. Compare these two.​

Answers

Answer 1

Given:

Size of a red blood cell = 0.000007 m

Size of a plant cell = 0.0000127 m

To find:

The comparison of these two values.

Solution:

We have,

Size of a red blood cell = 0.000007 m

Size of a plant cell = 0.0000127 m

Clearly, [tex]0.0000127>0.000007[/tex]. Now, the difference between these two values is:

[tex]0.0000127-0.000007=0.0000057[/tex]

Therefore, the size of a plant cell is 0.0000057 m more than the size of a red blood cell.


Related Questions

The volume of a gas with a pressure of 1.2 atm increases from 1.0 L to 4.0 L. What is the final pressure of the gas, assuming constant temperature?
(a) 1.2 atm
(b) 0.30 atm
(c) 3.3 atm
(d) 4.8 atm
(e) 1.0 atm

Answers

Answer:

(b) 0.30 atm

Step-by-step explanation:

Given data

Initial pressure= 1.2atm

Initial volume= 1.0L

Final volume= 4.0L

Final pressure= ???

Let us apply the gas formula to find the Final pressure

P1V1= P2V2

Substitute

1.2*1= x*4

Divide both sides by 4

1.2/4= x

x= 0.3atm

Hence the final pressure is 0.3 atm


rewrite -4<x<-1 using absolute value sign​

Answers

[tex] - | 4 | < x < - |1| [/tex]

dunno if that's the desired form tough, but it states the same definition

The given inequality rewritten using absolute value sign​ as |-4|<x<|-1|.

What are inequalities?

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The given inequality is -4<x<-1.

An absolute value inequality is an expression with absolute functions as well as inequality signs.

Here, using absolute value sign​ we get

|-4|<x<|-1|

Therefore, the given inequality rewritten using absolute value sign​ as |-4|<x<|-1|.

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A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas. During one particular week, the two cars went a combined total of 1825 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of the two cars that week?

Answers

Answer:

1) 35 gallons by the first car 2) 40 gallons by the second car

Step-by-step explanation:

Suppose the first car used x gallons, when the second car used the rest- 75-x

If the first car's efficiency is 35 miles per galon, its milleage is 35*x, the second car's milleage is 15*(75-x). And the summary milleage is equal to 1825.

35x+15(75-x)=1825

35x+1125-15x= 1825

20x=700

x=35- gallons consumed by the first car,

75-35=40- gallons consumed by the second one

multiply 725base 9× 367base 9​

Answers

Answer:

Hello,

Answer 303028

Step-by-step explanation:

Multiplication in base 9

[tex]\begin{array}{cccccc}9^5&9^4&9^3&9^2&9^1&9^0\\--&--&--&--&--&--\\&&&7&2&5\\&&&3&6&7\\--&--&--&--&--&--\\&&5&5&8&8\\&4&7&6&3&\\2&3&7&6&&\\--&--&--&--&--&--\\3&0&3&0&2&8\end{array}[/tex]

Given the function f(x) = 3x - 1, explain how to find the average rate of change between x = 1 and x = 4.

Answers

Step-by-step explanation:

f(1) = 3×1 - 1 = 2

f(4) = 3×4 - 1 = 12-1 = 11

so, the functional value changes 11-2=9 units on an x interval of 4-1=3 units length.

the average change rate is the total change across the x interval relative to the interval length.

that is

9/3 = 3

which is the slope (= the factor of x) in the line equation.

for a line its change rate for any point is the same constant. and that is therefore automatically also the average change rate across an interval of x values.

if the change rate would be different for different parts of the function, it would not be a straight line.

Answer:

3

Step-by-step explanation:

The average rate of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [ a, b ] = [ 1, 4 ] , then

f(b) = f(4) = 3(4) - 1 = 12 - 1 = 11

f(a) = f(1) = 3(1) - 1 = 3 - 1 = 2

average rate of change = [tex]\frac{11-2}{4-1}[/tex] = [tex]\frac{9}{3}[/tex] = 3

(a+b)^3=? hhihiihihihihih

Answers

Answer:

Step-by-step explanation:

A cone and a pyramid have equal heights and volumes. If the base area of the pyramid is 154cm^2, find the radius of the cone

Answers

Answer:

√154/π

Step-by-step explanation:

thể tích nón = thể tích hình chóp

1/3πr².h=1/3S.h

πr²=154(rút gọn h và 1/3)

=> r=√154/π

The radius of the cone is 7 cm if the cone and a pyramid have equal heights and volumes.

What is a cone?

It is defined as a three-dimensional shape in which the base is a circular shape and the diameter of the circle decreases as we move from the circular base to the vertex.

[tex]\rm V=\pi r^2\dfrac{h}{3}[/tex]

We have:

A cone and a pyramid have equal heights and volumes.

154 = πr²

π = 22/7

r = 7 cm

Thus, the radius of the cone is 7 cm if the cone and a pyramid have equal heights and volumes.

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Complete the equation describing how
x and y are related.
5
1 2 3 4
8 13 18
-2
3
23
28
y = 5x + [?]
Enter the answer that belongs in [?].

Answers

Answer:

y=5x+3

Step-by-step explanation:

The equation of line is y=5x+3 since the y intercept is 3

I need help in understanding and solving quadratic equations using the quadratic formula

x^2+8x+1=0​

Answers

Answer:

Exact Form: -4⊥√15

Decimal Form:

0.12701665

7.87298334

Which statements can be used to compare the characteristics of the functions? Select three options.

Answers

Answer:

Step-by-step explanation:

g(x) has the smallest minimum value. All three functions share the same domain and the y-intercept is also the same for all three thus options (C),(D), and (E) is correct.

What is a graph?

A graph is a diametrical representation of any function between the dependent and independent variables.

For example y = x² form a parabola now by looking at only the graph we can predict that it has only a positive value irrespective of the interval of x.

As per the given table,

The minimum value among all functions is -204 which is for g(x).

The domain is the set of x since all function defines the same x thus they have the same domain.

At y-intercept x = 0

Since at x = 0 all function is 3 thus all three will have the same y-intercept.

Hence "The smallest minimal value is for g(x). The y-intercept for all three functions is the same, and all three functions have the same domain".

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It used to take 20 hours to get to Los Angeles, now it takes 12 hours, how much shorter was it?​

Answers

Step-by-step explanation:

It takes 20 Hours to get to Los Angeles

Now it takes 12 hours....

Therefore we subtract 20 from 12

which becomes

20 - 12= 8.

So it's 8 hours shorter

When it was built, the given stadium held 31,080 fans per game. Today, it holds 86,047. How many more fans could attend per year (12 games) compared to the year it was built?

Answers

Answer:

659604 students

Step-by-step explanation:

86047-31080=54967 more students per game

54967 students per game x 12 games = 659,604 students

2x + 5y = 10 into slope- intercept form

Answers

Answer:

y=-2x+10

Step-by-step explanation

Hope this helped

Find area and perimeter of shaded regions below

Answers

Answer:

Step-by-step explanation:

ABCD is a square.

side = 24 cm

Area of square = side  * side = 24 * 24 = 576 cm²

Semicircle:

d = 24 cm

r = 24/2 = 12 cm

Area of semi circle =πr²

                               = 3.14 * 12 * 12

                               = 452.16 cm²

Area of shaded region = area of square - area of semicircle  + area of semicircle

  = 576  - 452.16 + 452.16

  = 576 cm²

Perimeter:

Circumference of semicircle = 2πr

               = 2 * 3.14 * 12

               = 75.36

Perimeter = 2* circumference of semicircle + 24 + 24

                = 2 * 75.36 + 24 + 24

                = 150.72 + 24 + 24

                 = 198.72 cm

Which of the two functions below has the smallest minimum y-value?
f(x) = 4(x - 6)4 + 1
g(x) = 2x3 + 28
O A. g(x)
B. f(x).
C. The extreme minimum y-value for f(x) and g(x) is --
D. There is not enough information to determine

Answers

Answer:

Answer A

Step-by-step explanation:

[tex]\displaystyle \lim_{n \to -\infty} (3x^3+28)=-\infty\\\\minimum\ of \ f(x)=6\\\\Answer\ A[/tex]

log, (x + y)=log, y, log, x .
Solve for question D only

Answers

Answer:

4.

Step-by-step explanation:

Change of base formula is

logb x = loga x / loga b

So logx 25 = log5 25 /log5 x

Now log5 25 = log5 5^2 = 2, so:

logx 25 = 2 / log5 x

So log5 x^2 * logx 25

= log5 x^2 * 2 /log5 x

= 2 log5 x * 2 / log5 x

= 4.

Form a polynomial whose zeros and degree are given.
Zeros: - 2, 2, 6; degree: 3
Type a polynomial with intéger coefficients and a leading coefficient of 1 in the box below.
f(x)=(Simplify your answer.)

Answers

Answer:

[tex]f(x) = (x + 2)(x - 2)(x - 6)[/tex]

[tex]f(x) = ({x}^{2} + 4)(x - 6)[/tex]

[tex]f(x) = {x}^{3} - 6 {x}^{2} + 4x - 24[/tex]

Step-by-step explanation:

Multiply factors.

Order the expressions from least to greatest.

Anwser

4 then 5 then 6

Answers

Answer:

This the right order:

4^2+2^2 = 20

5^2= 25

6^2-6 = 30

Please Help!
Use the function f(x) to answer the questions

f(x) = 5x^2 + 2x - 3

Part A: What are the x-intercepts of the graph of f(x)? Show your work (5 points)

Part B: Is the vertex of the graph of f(x) going to be a maximum or a minimum? What are the coordinates of the vertex? Justify your answers and show

your work (5 points)

Part 2: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph (5 points)

Answers

9514 1404 393

Answer:

  A: -1, 3/5

  B: (-1/5, -3 1/5)

  2: plot the given points and draw a curve through them.

Step-by-step explanation:

Part A

The x-intercepts are most easily found from a graph of the function. I like the Desmos graphing calculator for this purpose. The x-intercepts are -1 and 3/5.

You can also find the x-intercepts by factoring the function.

  f(x) = 5x^2 +5x -3x -3 = 5x(x +1) -3(x +1) = (5x -3)(x +1)

The x-intercepts are the values of x that make the factors zero:

  5x -3 = 0   ⇒   x = 3/5

  x +1 = 0   ⇒   x = -1

__

Part B

The vertex is on the axis of symmetry, which is the vertical line at the value of x halfway between the zeros. (-1 +3/5)/2 = (-2/5)/2 = -1/5

The value of f(x) there is ...

  f(-1/5) = (5(-1/5) +2)(-1/5) -3 = (-1 +2)(-1/5) -3 = -1/5 -3 = -3 1/5

The vertex is (-1/5, -3 1/5).

__

Part 2

The easiest step to take to graph the function is to type it into a graphing calculator (see attached).

If you're graphing this by hand, the three points given in parts A and B will be on the graph. The leading coefficient in the function is 3, so the x^2 parent function is vertically stretched by a factor of 3. This can make it a little more difficult to find points that lie on the graph.

Recognizing that the vertex form equation is ...

  f(x) = 3(x +1/5) -3 1/5

I might choose x-values that are -1/5 ± 1/2 to get y-values that are -3 1/5 + 3/4. And, x = -1/5 ± 1 ⇒ y = -3 1/5 +3.

Which graph represents the solution set for the quadratic inequality x2 + 2x + 1 > 0?

Answers

You need to sole for o and you will get x4 and the graph

howdy!!

yr answer is the third graph!

HURRY WILL GIVE BRANLIEST

Answers

I believe that the answers in order are: Rational, Irrational, Irrational, Irrational. I think these answers are correct, but if not, please let me know. Thanks.

Answer:

I think 0.5 and 0/100 are rational

the others are irrational

Is 3.6 a integer or a whole number?

Answers

36 is a whole number.

Answer:

The number 3.6 is a rational number.

All numbers that can be represented as fractions made of two integers (whole numbers) are considered to be

I’m the triangle shown we can find the angle theta as follows.

Answers

Answer:

sin = opp/hyp

cos = adj/hyp

tan = opp/adj

14% of all Americans live in poverty. If 35 Americans are randomly selected, find the probability that

a. Exactly 3 of them live in poverty.

b. At most 7 of them live in poverty.

c. At least 4 of them live in poverty.

d. Between 1 and 8 (including 1 and 8) of them live in poverty.

Answers

At least 4 of them will live in poverty

Find the other endpoint of the line segment with the given endpoint (-2, -2) and midpoint (3,10)

Answers

9514 1404 393

Answer:

  (8, 22)

Step-by-step explanation:

For endpoints A and B, and midpoint M, the relationship of interest is ...

  B = 2M -A

  B = 2(3, 10) -(-2, -2) = (6+2, 20+2)

  B = (8, 22)

The other end point is (8, 22).

I really need the help please and thank you

Answers

Asnwer: C

-------------------------------------

1km make how many cm​

Answers

Answer:

100000

Step-by-step explanation:

Find Term 20 for the sequence a= 4 6 8 10......​

Answers

term 20 in the sequence of a = 42

4,6,8,10 are in A.P

a=4d=2

[tex]\\ \rm\Rrightarrow a_n=a+(n-1)d[/tex]

[tex]\\ \rm\Rrightarrow a_20=4+(20-1)2[/tex]

[tex]\\ \rm\Rrightarrow a_20=4+19(2)[/tex]

[tex]\\ \rm\Rrightarrow a_20=4+38[/tex]

[tex]\\ \rm\Rrightarrow a_20=42[/tex]

The weight of an object above the surface of the Earth varies inversely with the square of the
distance from the center of the Earth. If a body weighs 50 pounds when it is 3,960 miles from
Earth's center, what would it weigh if it were 4,015 miles from Earth's center?

Answers

Answer:

weight =48.71228786pounds

Step-by-step explanation:

[tex]w = \frac{k}{ {d}^{2} } \\ 50 = \frac{k}{ {3960}^{2} } \\ \\ k = 50 \times {3960}^{2} \\ k = 50 \times 15681600 \\ k = 784080000 \\ \\ w = \frac{784080000}{ {d}^{2} } \\ w = \frac{784080000}{16120225} \\ \\ w = 48.71228786 \\ w = 48.7pounds[/tex]

If a body weighs 50 pounds when it is 3,960 miles from Earth's center, it would weigh approximately 48.547 pounds if it were 4,015 miles from Earth's center, according to the inverse square law formula.

We know the inverse square law formula:

W₁ / W₂ = D²₂ / D²₁

Where W₁ is the weight of the body at the initial distance D₁, and W₂ is the weight at the final distance D₂.

So we have,

W₁ = 50

D₁  = 3,960

D₂  = 4015

We know that the body weighs 50 pounds when it is 3,960 miles from Earth's center,

So we can plug in those values as follows:

50 / W₂ = (4,015)²/ (3,960)²

To solve for W₂, we can cross-multiply and simplify as follows:

W₂ = 50 x (3,960)² / (4,015)²

W₂ = 50 x 15,681,600 / 16,120,225

W₂ = 48.547 pounds (rounded to three decimal places)

Therefore, if the body were 4,015 miles from Earth's center, it would weigh approximately 48.547 pounds.

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Consider the probability that no more than 28 out of 304 students will not graduate on time. Choose the best description of the area under the normal curve that would be used to approximate binomial probability.

a. Area to the right of 27.5
b. Area to the right of 28.5
c. Area to the left of 27.5
d. Area to the left of 28.5
e. Area between 27.5 and 28.5

Answers

Solution :

Here the probability that exactly 28 out of 304 students will not graduate on time. That is

P (x = 28)

By using the normal approximation of binomial probability,

[tex]$P(x=a) = P(a-1/2 \leq x \leq a+1/2)$[/tex]

∴ [tex]$P(x=28) = P(28-1/2 \leq x \leq 28+1/2)$[/tex]

                   [tex]$=P(27.5 \leq x \leq 28.5)$[/tex]

That is the area between 27.5 and 28.5

Therefore, the correct option is (e). Area between 27.5 and 28.5

Other Questions
the slope of line is Please help me my little sister and i dont understand!! Half a league, half a league,Half a league onward,All in the valley of DeathRode the six hundred:'Forward, the Light Brigade!Charge for the guns' he said:Into the valley of DeathRode the six hundred.'Forward, the Light Brigade!'Was there a man dismay'd ?Not tho' the soldier knewSome one had blunder'd:Theirs not to make reply,Theirs not to reason why,Theirs but to do and die,Into the valley of DeathRode the six hundred.Cannon to right of them,Cannon to left of them,Cannon in front of themVolley'd and thunder'd;Storm'd at with shot and shell,Boldly they rode and well,Into the jaws of Death,Into the mouth of HellRode the six hundred.Flash'd all their sabres bare,Flash'd as they turn'd in airSabring the gunners there,Charging an army whileAll the world wonder'd:Plunged in the battery-smokeRight thro' the line they broke;Cossack and RussianReel'd from the sabre-stroke,Shatter'd and sunder'd.Then they rode back, but notNot the six hundred.Cannon to right of them,Cannon to left of them,Cannon behind themVolley'd and thunder'd;Storm'd at with shot and shell,While horse and hero fell,They that had fought so wellCame thro' the jaws of Death,Back from the mouth of Hell,All that was left of them,Left of six hundred.When can their glory fade?O the wild charge they made!All the world wonder'd.Honour the charge they made!Honour the Light Brigade,Noble six hundred! 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