World Languages High School

3-the-lamps are connected in parallel. The first lamp has a current of 2. A.


The second lamp has a voltage equal to 10V and a resistance equal to 6 Ohm. The


third-lamp has a current equal to 4A Find in this scheme the total voltage, the current


for all·lamps, the total resistance.

Answers

Answer 1

Total Voltage: 10V

Total Current: Approximately 7.67A

Total Resistance: 2 Ohm

How to solve for the volgtage and resistance

The total voltage in the circuit is equal to the voltage across any of the lamps. In this case, the second lamp has a voltage of 10V, so the total voltage in the circuit is 10V.

Current for all lamps (I):

Since the lamps are connected in parallel, the total current flowing through the circuit is the sum of the individual currents through each lamp.

The first lamp has a current of 2A, the second lamp's current is not given, and the third lamp has a current of 4A. To find the total current, we need to calculate the current through the second lamp.

Since the second lamp has a resistance of 6 Ohm and a voltage of 10V, we can use Ohm's Law (V = I * R) to find the current through the second lamp:

10V = I * 6 Ohm

I = 10V / 6 Ohm

I ≈ 1.67A

Now we can calculate the total current:

Total Current (I) = 2A (first lamp) + 1.67A (second lamp) + 4A (third lamp)

Total Current ≈ 7.67A

Total Resistance (R):

In a parallel circuit, the total resistance is calculated using the reciprocal of the sum of the reciprocals of the individual resistances.

The second lamp has a resistance of 6 Ohm, so the total resistance is:

1 / Total Resistance = (1 / 6 Ohm) + (1 / 6 Ohm) + (1 / 6 Ohm)

1 / Total Resistance = 3 / 6 Ohm

1 / Total Resistance = 1 / 2 Ohm

Total Resistance = 2 Ohm

To summarize:

Read moer on total resistance. here https://brainly.com/question/28135236

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