Step-by-step explanation:
ok for a. the both are 126
and for b. the both are 30
for c. i believe its true
How high up the wall can a 12-foot ladder reach if its base is 4 feet from the wall? Round your answer to the nearest tenth of a foot if necessary.
Answer: 24 ft I think
Step-by-step explanation:
FastForward has net income of $19,090 and assets at the beginning of the year of $209,000. Its assets at the end of the year total $264,000. Compute its return on assets.
Given:
Net income = $19,090
Assets at the beginning of the year = $209,000.
Assets at the end of the year total = $264,000.
To find:
The return on assets.
Solution:
Formula used:
[tex]\text{Return of assets}=\dfrac{\text{Net income}}{\text{Average of assets at the beginning and at the end}}[/tex]
Using the above formula, we get
[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{20900+264000}{2}}[/tex]
[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{473000}{2}}[/tex]
[tex]\text{Return of assets}=\dfrac{19090}{236500}[/tex]
[tex]\text{Return of assets}\approx 0.0807[/tex]
The percentage form of 0.0807 is 8.07%.
Therefore, the return on assets is 8.07%.
2.6.5 A plant physiologist grew birch seedlings in the green-house and measured the ATP content of their roots. (See Example 1.1.3.) The results (nmol ATP/mg tissue) were as follows for four seedlings that had been handled identically.39 1.45 1.19 1.05 1.07 Calculate the mean and the S
Answer:
[tex](a)\ \bar x = 1.19[/tex]
[tex](b)\ \sigma_x = 0.18[/tex]
Step-by-step explanation:
Given
[tex]n = 4[/tex]
[tex]x: 1.45\ 1.19\ 1.05\ 1.07[/tex]
Solving (a): The mean
This is calculated as:
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
[tex]\bar x = \frac{1.45 + 1.19 + 1.05 + 1.07}{4}[/tex]
[tex]\bar x = \frac{4.76}{4}[/tex]
[tex]\bar x = 1.19[/tex]
Solving (b): The standard deviation
This is calculated as:
[tex]\sigma_x = \sqrt{\frac{\sum(x - \bar x)^2}{n - 1}}[/tex]
So, we have:
[tex]\sigma_x = \sqrt{\frac{(1.45 -1.19)^2 + (1.19 -1.19)^2 + (1.05 -1.19)^2 + (1.07 -1.19)^2}{4 - 1}}[/tex]
[tex]\sigma_x = \sqrt{\frac{(0.1016}{3}}[/tex]
[tex]\sigma_x = \sqrt{0.033867}[/tex]
[tex]\sigma_x = 0.18[/tex]
I NEED HELP!!!!
If, XYZ~EDF the measure of angle F is
Answer:
63°
Step-by-step explanation:
∠F is equal to ∠Z
Learning Task No. 1 Randy, Manny and Jan put 3 As, 4 Bs and 5 Cs in the box. They will take turns in getting a letter from the box. They are trying to test the probability of getting their favourite letter.
Randy - A
Manny-B
Jan-C
1. What is the probability of getting each boy's favourite letter? a. Randy b. Manny c. Jan
2. If you are next to Jan to pick up a letter and your favourite letter is A , What is the probability of getting your favourite letter?
3. Who is most unlikely to get his favourite letter.
Answer:
1. A = 3/12
B= 4/12
C = 5/12
2......
3. Randy
Step-by-step explanation:
3+4+5 = 12
therefore there are 12 letters in the box
we can say that there are 3/12 A's in the box and do the same for the remaining letters
question two does not make sense
3. the person who has the lowest fraction in value which is A
If $3000 is invested at 3% interest, find the value of the investment at the end of 7 years if the interest is compounded as follows. (Round your answers to the nearest cent.)
(i) annually
(ii) semiannually
(iii) monthly
(iv) weekly
(v) daily
(vi) continuously
Answer:
annualy=$3689.62
semiannually=$3695.27
monthly=$3700.06
weekly=$3700.81
daily=$3701.00
Continuously=$3701.03
Step-by-step explanation:
Given:
P=3000
r=3%
t=7 years
Formula used:
Where,
A represents Accumulated amount
P represents (or) invested amount
r represents interest rate
t represents time in years
n represents accumulated or compounded number of times per year
Solution:
(i)annually
n=1 time per year
[tex]A=3000[1+\frac{0.03}{1} ]^1^(^7^)\\ =3000(1.03)^7\\ =3689.621596\\[/tex]
On approximating the values,
A=$3689.62
(ii)semiannually
n=2 times per year
[tex]A=3000[1+\frac{0.03}{2}^{2(4)} ]\\ =3000[1+0.815]^14\\ =3695.267192[/tex]
On approximating the values,
A=$3695.27
(iii)monthly
n=12 times per year
[tex]A=3000[1+\frac{0.03}{12}^{12(7)} \\ =3000[1+0.0025]^84\\ =3700.0644[/tex]
On approximating,
A=$3700.06
(iv) weekly
n=52 times per year
[tex]A=3000[1+\frac{0.03}{52}]^3^6 \\ =3000(1.23360336)\\ =3700.81003[/tex]
On approximating,
A=$3700.81
(v) daily
n=365 time per year
[tex]A=3000[1+\frac{0.03}{365}]^{365(7)} \\ =3000[1.000082192]^{2555}\\ =3701.002234[/tex]
On approximating the values,
A=$3701.00
(vi) Continuously
[tex]A=Pe^r^t\\ =3000e^{\frac{0.03}{1}(7) }\\ =3000e^{0.21} \\ =3000(1.23367806)\\ =3701.03418\\[/tex]
On approximating the value,
A=$3701.03
Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated samplingg distribution.
The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.5 years and a standard deviation of 2.1 years. Random samples of size 17 are drawn from the population and the mean of each sample is determined.
a. 1.33 years, 2.1 years
b. 5.5 years, 0.12 years
c. 5.5 years, 0.51 years
d. 1.33 years, 0.51 years
Answer:
c. 5.5 years, 0.51 years
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Mean of 5.5 years and a standard deviation of 2.1 years.
This means that, for the population, [tex]\mu = 5.5, \sigma = 2.1[/tex]
Random samples of size 17.
This means that [tex]n = 17[/tex]
Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution.
The mean is the same as the mean for the population, that is, 5.5 years.
The standard deviation is:
[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{17}} = 0.51[/tex]
This means that the correct answer is given by option c.
Which equation could represent each grapes polynomial function?
9514 1404 393
Answer:
top graph: y = x(x +3)(x -2)bottom graph: y = x⁴ -5x² +4Step-by-step explanation:
Each x-intercept at x=a corresponds to a polynomial factor of (x -a).
__
The top graph has x-intercepts of -3, 0, +2, so the factors of this cubic are ...
y = (x +3)(x -0)(x -2)
y = x(x +3)(x -2) . . . . . . . matches upper right tile
__
The bottom graph has x-intercepts of -2, -1, 1, 2, so the factors of this quartic are ...
y = (x +2)(x +1)(x -1)(x -2) = (x² -4)(x² -1)
y = x⁴ -5x² +4 . . . . . . . matches lower left tile
Work out the area of the shape,show working out
help me and I think I did the sides wrong
If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2
Hey there!
We are given two functions - one is Exponential while the another one is Linear.
[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]
1. Operation of Function
(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]
2. Substitution
Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]
3. Evaluate/Simplify
Cancel out the brackets and combine like terms.[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]
4. Final Answer
(f+g)(x) = 4^x+5x-2which represents the value of point D on the number line?
Answer:
The answer would be D, -(-4)
Step-by-step explanation:
This is because two negatives equal a positive.
Answer:
D shawtay
Step-by-step explanation:
the answers d cus negatives cancel eachother out
what is the value of digit 6 in9.78265.
Answer: uhh I think 60?
Step-by-step explanation:
the answer is 6p because after any value place is zero hoped I helped
The following data were collected from a simple random sample from an infinite population.
13 15 14 16 12
The point estimate of the population standard deviation is _____.
a. 1.581
b. 2.500
c. 2.000
d. 1.414
Answer:
1.581
Step-by-step explanation:
Given the data:
13 15 14 16 12
The point estimate of the standard deviation will be :
√Σ(x - mean)²/n-1
Mean = Σx / n = 70 / 5 = 14
√[(13 - 14)² + (15 - 14)² + (14 - 14)² + (16 - 14)² + (12 - 14)² / (5 - 1)]
The point estimate of standard deviation is :
1.581
The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4959 miles, with a standard deviation of 448 miles. If he is correct, what is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles
Answer:
0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean number of miles between services is 4959 miles, with a standard deviation of 448 miles
This means that [tex]\mu = 4959, \sigma = 448[/tex]
Sample of 43:
This means that [tex]n = 43, s = \frac{448}{\sqrt{43}}[/tex]
What is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles?
p-value of Z when X = 4959 + 111 = 5070 subtracted by the p-value of Z when X = 4959 - 111 = 4848, that is, probability the sample mean is between these two values.
X = 5070
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{5070 - 4959}{\frac{448}{\sqrt{43}}}[/tex]
[tex]Z = 1.62[/tex]
[tex]Z = 1.62[/tex] has a p-value of 0.9474
X = 4848
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{4848 - 4959}{\frac{448}{\sqrt{43}}}[/tex]
[tex]Z = -1.62[/tex]
[tex]Z = -1.62[/tex] has a p-value of 0.0526
0.9474 - 0.0526 = 0.8948
0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles
HELP PLEASE!!! So for this problem is got 0.48 however I just wanted to confirm that my answer is correct. Can someone please help me if the answer is wrong and how to solve it. Thank your for your time
Answer:
ur answer is correct
A =xy
A = 1.6×0.3 = 0.48
Domain and range
O Function
O Not a function
Answer:
Radiation 1- Function
Radiation 2- Not a function
Radiation 3- function
Radiation 4- function
Answer:
1 - Function
2 - Not a function
3 - function
4 - function
Step-by-step explanation:
If you spin two times, what is the probability of landing on
green both times? (leave answer in fraction form in lowest
terms)
Red
Green
Yellow
Red
1/9
1/30
1/6
1/360
Find the length of an arc of a circle with a 8-cm radius associated with a central angle of 240 degrees. Give your answer in exact and approximate form to the nearest hundredth.
Answer:
l = 1920 cm
Step-by-step explanation:
Given that,
The radius of circle, r = 8 cm
The central angle is 240 degrees
We need to find the length of the arc. We know that,
[tex]l=r\theta[/tex]
Where
l is the length of the arc
So,
[tex]l=8\times 240[/tex]
[tex]\implies l=1920\ cm[/tex]
so, the length of the arc is equal to 1920 cm.
Please help, I’m running out of time. Please.
Answer:
which standard questions is it
At a bake sale, pies cost $8 each. One customer buys $64 worth of pies.
The customer bought 8 pies.
To find the total amount of pies the customer bought, simply divide 64 by 8 to recieve your answer of 8 pies.
I hope this is correct and helps!
To find the quotient of 8 divided by one-third, multiply 8 by
O One-eighth
O One-third
O 3
O 8
Answer:
3
Step-by-step explanation:
Skip,Flip,Multiply Method
[tex] \frac{8}{ \frac{1}{3} } = \frac{8}{1} \times 3 = 24[/tex]
Answer:
3
Step-by-step explanation:
y.y3 write without exponts
Answer:
Y x Y x Y x Y
Step-by-step explanation:
The exponent tells how many times that number is multiplied.
So, x^3 is the same as multiplying x 3 times.
Find, correct to the nearest degree, the three angles of the triangle with the given ven
A(1, 0, -1), B(4, -3,0), C(1, 2, 3)
o
CAB =
O
LABC =
O
LBCA =
9514 1404 393
Answer:
∠CAB = 86°
∠ABC = 43°
∠BCA = 51°
Step-by-step explanation:
This can be done a couple of different ways (as with most math problems). We can use the distance formula to find the side lengths, then the law of cosines to find the angles. Or, we could use the dot product. In the end, the math is about the same.
The lengths of the sides are given by the distance formula.
AB² = (4-1)² +(-3-0)² +(0-(-1)) = 16 +9 +1 = 26
BC² = (1-4)² +(2-(-3))³ +(3-0)² = 9 +25 +9 = 43
CA² = (1-1)² +(0-2)² +(-1-3)² = 4 +16 = 20
From the law of cosines, ...
∠A = arccos((AB² +CA² -BC²)/(2·AB·CA)) = arccos((26 +20 -43)/(2√(26·20)))
∠A = arccos(3/(4√130)) ≈ 86°
∠B = arccos((AB² +BC² -AC²)/(2·AB·BC)) = arccos((26 +43 -20)/(2√(26·43)))
∠B = arccos(49/(2√1118)) ≈ 43°
∠C = arccos((BC² +CA² -AB²)/(2·BC·CA)) = arccos((43 +20 -26)/(2√(43·20)))
∠C = arccos(37/(4√215)) ≈ 51°
The three angles are ...
∠CAB = 86°
∠ABC = 43°
∠BCA = 51°
_____
Additional comment
This sort of repetitive arithmetic is nicely done by a spreadsheet.
A loan of £1000 has a compound interest rate of 2.7% charged monthly. Express the original loan as a percentage of the total amount awed after 2 months if no payment are made
Answer:
£1054.729
Step-by-step explanation:
To find compound interest you need to use the equation 1000(1.027)^x.
To find the interest rate (1.027):
100 + 2.7 = 102.7
102.7 / 100 = 1.027
The value of x is the amount of months if no payment is made in this situation, so 2 would be the x value for this problem.
Hope this helps!
A driver must decide whether to buy a new car for $24,000 or lease the same car over a four-year period. Under the terms of the lease, she can make a down payment
of $3000 and have monthly payments of $150. At the end of the four years, the leased car has a residual value (the amount she pays if she chooses to buy the car at
the end of the lease period) of $11,000. Assume she can sell the new car at the end of the four years at the same residual value. Is it less expensive to buy or
to lease?
Answer:
3000 is the answer this question.
When Claire chooses a piece of fruit from a fruit bowl, there is a 22% chance that it will be a plum, an 18%
chance that it will be an orange, and a 60% chance that it will be an apple. Which type of fruit is she least likely
to choose?
Answer:
Orange
Step-by-step explanation:
As the chance of choosing orange is 18% which is the least.
The Sureset Concrete Company produces concrete. Two ingredients in concrete are sand (costs $6 per ton) and gravel (costs $8 per ton). Sand and gravel together must make up exactly 75% of the weight of the concrete. Also, no more than 40% of the concrete can be sand and at least 30% of the concrete be gravel. Each day 2000 tons of concrete are produced. To minimize costs, how many tons of gravel and sand should be purchased each day
Answer:
The Sureset Concrete Company
The tons of gravel and sand that should be purchased each day are:
Sand = 800 tons
Gravel = 700 tons
Step-by-step explanation:
Two ingredients for producing concrete = sand and gravel
Cost of sand per ton = $6
Cost of gravel per ton = $8
Sand and gravel = 75% of the concrete
Therefore 25% (100 - 75%) will be made up of cement and water
Tons of concrete produced each day = 2,000
Sand and gravel = 1,500 (2,000 * 75%)
Sand <= 40% of 2,000 = 800 tons
Gravel => 30% of 2,000 = 700 (1,500 - 800) tons
To minimize costs, 800 tons of gravel and 700 tons of sand should be purchased each day.
Total cost incurred daily for both sand and gravel = $10,400 (800 * $6 + 700 * $8)
Please help me figure out if this truth table is equivalent or not. People who show their work and give a proper answer shall receive brainliest
Answer:
The statements are logically equivalent.
The 6th column is:
F T F F
The 7th column is:
F T F F
Step-by-step explanation:
The 6th column is just the opposite of the 5th column
The 7th column is T only if both the 1st and 4th are T
every student from different schools planted as many plants of their number if they planted 4225 plants how many students were there
Answer:
65 students.
Step-by-step explanation:
Given that :
Every student planted as many plant as their number ;
Then let the number of student = x
Then the number of plant planted by each student will also = x
The total number of plants planted by all the students = 4225
The Number of students can be obtained thus ;
Total number of plants = Number of plants * number of plants per student
4225 = x * x
4225 = x²
√4225 = x
65 = x
Hence, there are 65 students
The sum of the first ten terms of an arithmetic progression consisting of
positive integer terms is equal to the sum of the 20th, 21st and 22nd term.
If the first term is less than 20, find how many terms are required to give
a sum of 960.
Answer: [tex]n=13[/tex]
Step-by-step explanation:
Given
Sum of the first 10 terms is equal to sum of 20, 21, and 22 term
[tex]\Rightarrow \dfrac{10}{2}[2a+(10-1)d]=[a+19d]+[a+20d]+[a+21d]\\\\\Rightarrow 5[2a+9d]=3a+60d\\\Rightarrow 10a+45d=3a+60d\\\Rightarrow 7a=15d[/tex]
No of terms to give a sum of 960
[tex]\Rightarrow 960=\dfrac{n}{2}[2a+(n-1)d]\\\\\Rightarrow 1920=n[2a+(n-1)\cdot \dfrac{7}{15}a]\\\\\Rightarrow 28,800=n[30a+7a(n-1)]\\\\\Rightarrow a=\dfrac{28,800}{n[30+7n-7]}\\\\\Rightarrow a=\dfrac{28,800}{n[23+7n]}[/tex]
Value of first term is less than 20
[tex]\therefore \dfrac{28,800}{n[23+7n]}<20\\\\\Rightarrow 28,800<20n[23+7n]\\\Rightarrow 0<460n+140n^2-28,800\\\Rightarrow 140n^2+460n-28,800>0\\\\\Rightarrow n>12.79\\\\\text{For integer value }\\\Rightarrow n=13[/tex]
Answer:
15
Step-by-step explanation:
In the previous answer halfway through they used the equation: 960 = (n÷2)×(2a+(n-1)×(7a÷15))
Using this equation we can substitute an number to replace n, the higher the number is the smaller a would be.
When we substitute 15 into a, then it leaves us with the answer to be a = 15 which is a positive integer and also is smaller than 20, this then let’s us know that 15 is how many terms can be summed up to make 960.
To double check this answer you can find that d = 7 by changing the a into 15 in the formula 7a/15 (found in the previous answer.
Then in the expression: (n÷2)×(2a+(n-1)×d)
substitute:
n = 14 (must be an even number for the equation to work)
a = 15
d = 7
This will give you an answer of 847, but this is only 14 terms as we changed n into 14. To add the final term you need to complete the following equation: 847+(a+(n-1)×d)
substituting:
n = 15
a = 15
d = 7
This will give you the answer of 960, again proving that it takes 15 terms to sum together to make the number 960.
I hope this has helped you.
P.S. Everything in the previous solution was right apart from the start of the last section and the answer
