Answer:
answer E
Explanation:
cuz its 45 is divisible by 3 and 5 but not 10
need help on these 2 an explanation of what formula’s to use would also be appreciated
Answer:
17. .343 seconds: 18.a .357: 18.b 64.5N
Explanation:
17. Since there is no friction, we can apply Newton's equation:
[tex]f=ma[/tex][tex]85N=5kg*a[/tex][tex]17 m/s^2=a[/tex]We can then use the kinematic equation:
[tex]d=v_{i} *t+\frac{1}{2} at^2[/tex][tex]25N=U_{k} *70N[/tex][tex]1m=0+\frac{1}{2}*17m/s^2*t^2[/tex]Solve for t:
[tex]{\frac{1}{8.5}s^2} =t^2[/tex][tex]\sqrt{\frac{1}{8.5} }=t=.343 seconds[/tex]18.a We can use the friction formula:
[tex]F_{k} =U_{k} *F_{N}[/tex][tex]25N=U_{k} *70N[/tex]Solving for kinetic friction of block mass 7kg:
[tex].357=U_{k}[/tex]18.b We should add all forces that will counteract the rightward acceleration.
[tex]F_{a} =F_{x} -F_{N}[/tex][tex]Fr_{7kg} =25N : Fr_{2.5kg} =15.75N[/tex]Use Newton's equation:
[tex]F=ma[/tex][tex]F_{a} =9.5kg*2.5m/s^2[/tex][tex]F_{a} =23.75N[/tex]Solve for [tex]F_{x}[/tex]
[tex]F_{a} +F_{fr} =F_{x}[/tex]
[tex]23.75N+40.75N=F_{x} =64.5N[/tex]
4.Two carts, A and B, sit in front of you. They look identical, and you are told that they are made of the same material. Cart A is at rest on an air track and cart B is given a constant velocity directed to the right toward Cart A on the air track. Cart B collides with cart A elastically. After the elastic collision, both carts move to the right, the velocity of cart B being smaller than what it was before the collision. What can you conclude based on only what you have observed
Answer:
Cart B loses some of its initial kinetic energy and cart A gains kinetic energy.
Explanation:
Since both cart A and cart B have identical masses, and cart B moves with a smaller velocity after the collision than it was moving with before the collision, and also, the collision is elastic. It implies that the initial kinetic energy of cart B equals the final kinetic energy of cart A and cart B after the collision.
Since the initial kinetic energy of cart B is shared between cart A and cart B and cart B moves with lesser velocity after the collision, it implies that cart B has a smaller kinetic energy than its initial kinetic energy before the collision.
And also, since cart A is initially at rest and moves to the right after the collision, it gains kinetic energy.
Thus, cart A has a higher final kinetic energy after the collision. Also, cart A has a smaller kinetic energy after the collision than the initial kinetic energy of cart B, since it is the difference between cart B's initial and final kinetic energies.
So, from our observation, we conclude that cart B loses some of its kinetic energy and cart A gains kinetic energy.
Find the magnetic force experienced by a proton moving with the speed of 4x10^5 m/s in the magnetic field B of magnetic 7x10^-5 T.
A- Fmagnetic = 24.8x10^-19 N
B- Fmagnetic = 34.8x10^-19 N
C- Fmagnetic = 44.8x10^-19 N
D- Fmagnetic = 54.8x10^-19 N
Answer:
F = q v B where B is the component of the field perpendicular to v.
F = 1.6E-19 * 4E5 * 7E-5 = 4.48* 10^-18 N = 44.8 * E-19 N
A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1.0 m from it. Find the position of image and the magnification.
Answer:
The image is formed at 0.44 m in front of the mirror
magnification (M) = 0.44
Explanation:
Applying, mirror formular
1/f = (1/u)+(1/v).................... Equation 1
Where f = Focal length of the convex mirror, u = object distance, v = image distance.
Using the real is positive convection,
From the question,
Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m
Substitute these values into equation 1
-1/0.8 = (1/v)+(1/1)
Solve for v
1/v = 1.25+1
1/v = 2.25
v = 1/2.25
v = 0.44 m
Hence the image is formed at 0.44 m in front of the mirror
Magnification (M) = v/u
m = 0.44/1
m = 0.44
how does washing your clothes affect the weather?
Answer:
carbon dioxide is produced each year per household from washing and drying a load of washing every two days. These carbon dioxide negatively impact the environment and provoke climate change. Also, when washing clothes, around 90% of the energy goes into heating up the water
A bullet from a gun at 30° to the horizontal remains in flight for 25s before touching the ground.Calculate the velocity of the projection.
Answer: The velocity of the bullet will be more than half of its earlier velocity
Explanation: I did it on a test and it was right because i calculated 30 degrees within 25 seconds and it was half times the velocity
i hope this helps sorry if i got it wrong
A blackbody radiator was expected to give off energy of increasing frequency
as its temperature increased. Which of the following ideas provided an
important step toward understanding why this was not observed?
A. Light is quantized and must be absorbed as a unit.
B. Electrons can act as both waves and particles.
C. Matter is quantized and cannot be broken down.
D. Large objects can be viewed as acting as waves.
Answer:
B.
Explanation:
Makes more sense to me
What's Alpha beta gamma emission??
The diagram shows the electric field lines surrounding two positive point charges. If the charge on the right were replaced with a negative charge, which of these would need to change to make a correct representation of the electric fields? (Choose all that apply)
A. Field Lines would full in between the two charges (instead of leaving a blank area at point D
B. The field lines around both charges would change direction.
C. The field lines would get closer together
D. The arrows on the field lines surrounding the negative charge would need to point toward instead of away from the charge.
Answer:
Explanation:
The wording on some of these choices is very strange; I'm not sure exactly what they are stating. First of all, A. is definitely a choice because if both the charges were opposite, they would be attracted to one another as opposed to be repelled away from one another, as they are when they are both positive. What happens is that the charges go OUT from the positive charge and INTO the negative; so as far as the field lines around both charges would change direction...no; only the direction of the field lines would change on the positive charge (which is the one on the left). In that space where D is filled in by the field lines going OUT of the positive charge and INTO the negative one, the lines there are naturally closer together, and that is the point where the charge is the greatest. So if that is what is meant by the field lines getting closer together, then yes, they do. As far as choice D. again the field lines on the negative charge don't change, only the ones on the positive charge change.
The arrows on the field lines surrounding the negative charge would need to point toward instead of away from the charge.
These pattern of lines, sometimes referred to as electric field lines, point in the direction that a positive test charge would accelerate if placed upon the line. As such, the lines are directed away from positively charged source charges and toward negatively charged source charges.
What is negative charge ?“ When an object has more electrons than protons then the object is said to be negatively charged.”
What is positive charge ?“When an object has more protons than electrons, the object is said to be positively charged.”
Know more about field lines here
https://brainly.com/question/23722531
#SPJ2
If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?
Answer:
[tex]g=25.92\ m/s^2[/tex]
Explanation:
Given that,
The mass of the Jupiter,[tex]M=1.9\times 10^{27}\ kg[/tex]
The radius of Jupiter,[tex]r=69,911\ km=69911\times 10^3 km[/tex]
We need to find the acceleration due to gravity on Jupiter. The formula is
[tex]g=G\dfrac{M}{r^2}[/tex]
Put all the values,
[tex]g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2[/tex]
So, the value of acceleration due to gravity on the Jupiter is [tex]25.92\ m/s^2[/tex].
Solve this question for 5 points
Answer:
M_b = 2M_a
Explanation:
From gravity equation, we know that;
g = GM/R²
Where;
g is acceleration due to gravity
G is the gravitational constant
M is mass
Thus, making mass(M) the subject, we have;
M = gR²/G
Since we want to find the mass of B so that value of g on B is half that of its value on A.
Thus;
> g_b = ½g_a
> g_b/g_a = ½
Also, we are told that;
> R_a = ½R_b
> R_b/R_a = 2
If M_a = g_a•R_a²/G
And M_b = g_b•R_b²/G
Thus;
M_b/M_a = (g_b•R_b²/G)/(g_a•R_a²/G)
G will cancel out to give;
M_b/M_a = (g_b•R_b²)/(g_a•R_a²)
Rearranging for ease of simplification, we have;
M_b/M_a = (g_b/g_a) × (R_b/R_a)²
Plugging in the relevant ratios gives;
M_b/M_a = ½ × 2²
M_b/M_a = 2
M_b = 2M_a
please tell its urgent
Answer:
1) 4,422 meters.
2) 14.01 meters.
Explanation:
A round in a circular track means a complete rotation around its perimeter.
So, if the circular track is 44 meters long, 100.5 rounds around it means that the object did travel the 44 meters 100.5 times.
a) The total distance traveled by the object is:
44m*100.5 = 4,422 meters.
b) The displacement is defined as the distance between the final position and the initial position.
Notice that if you do a complete round, you end in the same position that you started.
So if you do 100 rounds, you end in the same position that you started.
If you do 100.5 rounds, we can think this as:
100 rounds + 0.5 round
So you pass for the starting point 100 times, and then you do half a round, this means that you end in the exact opposite part of the circle of the one where you started.
Then the displacement, the distance between the final position and the initial position, is equal to the diameter of the circle.
We know that the perimeter of the circle is 44m
And remember that the perimeter of a circle of diameter D is:
P = 3.14*D
Then the diameter if this circle is given by:
44m = 3.14*D
44m/3.14 = D = 14.01m
The displacement is 14.01m
Mike lives in the northern United States minnesota and nick lives in the southern United States Louisiana. When they both feel insulted by the same individual, nick will be more
Complete question is;
Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana). When they both feel insulted by the same individual, Nick will be more likely to have a(n) ________ cortisol response and show ________ levels of physical aggression.
Answer:
- A hyper cortisol response
- higher levels of physical aggression
Explanation:
In study of hormones in the human body, it has been discovered that cortisol is a stress inducing hormone. Now, if they are in the summer when it is hot, it has been proven that's when the cortisol hormone circulates in a very large manner in the blood. This leads to frustration and as well possibly physical aggression.
Nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.
What is cortisol?Cortisol has been identified as a stress-inducing hormone in studies of hormones in the human body.
Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana).
When they both feel insulted by the same individual, Nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.
Cushing syndrome is a condition characterized by elevated cortisol levels. This disorder is caused by your body producing too much cortisol.
Similar symptoms can occur after large doses of corticosteroids, thus this should be cleared out before testing for crushing syndrome.
Cortisol has been identified as a stress-inducing hormone in studies of hormones in the human body. Now, if they are in the summer when it is hot.
It has been proved that the cortisol hormone circulates in the blood in a very significant amount. This causes irritation and, in some cases, physical aggressiveness.
Hence nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.
To learn more about cortisol refer to the link
https://brainly.com/question/7519944
Explain the term balance point as applies to the Wheatstone Bridge.
Answer:
Explanation: The Wheatstone bridge is the interconnection of four resistances forming a bridge. ... To find the value of unknown resistance the deflection on galvanometer made to zero by adjusting the variable resistor. This point is known as balance point of Wheatstone bridge
A wire, 20m long, is heated from a temperature of 5°C to 55°C. If the change in length is 0.020m, calculate the linear expansivity of the wire.
Answer:
0.01998⁰C;¹
Explanation:
you can see all steps in photo
Can someone please help me with this physics question? I'm desperate!
A track team is practicing for a 4 x 100 m relay race. The first runner, Linda, is running at a constant speed of 8.6 m/s. The next runner, Jenny, will be starting from rest at the 80 m mark. She has an acceleration of 1.0m/s^2. Ideally the two runners meet at the 100m mark to hand over the baton. At this point, Jenny is still accelerating.
a) How long does it take Jenny to run from the 80-m mark to the 100-m mark?
b)At what distance behind Jenny should Linda be when Jenny starts running? (Assume for simplicity that there is no distance between the two runners when the switch happens.)
c)What’s Jenny’s speed at the 100m mark?
Answer:
a) 2·√10 seconds
b) Linda should be approximately 30.6 meters
c) Jenny's speed at the 100-m mark is approximately 6.325 m/s
Explanation:
The speed with which Linda is running = 8.6 m/s
The point Jenny starts = The 80-m mark
The acceleration of Jenny = 1.0 m/s²
a) The time it takes Jenny to run from the 80-m mark to the 100-m mark, t, is given as follows
Δs = u·t + (1/2)·a·t²
Δs = Distance = 100-m - 80-m = 20-m
u = The initial velocity of Jenny = 0
a = Jenny's acceleration = 1.0 m/s²
∴ 20 = 0×t + (1/2) × 1 × t² = t²/2
20 = t²/2
t = √(20 × 2) = 2·√10
The time it takes Jenny to run from the 80-m mark to the 100-m mark = 2·√10 seconds
b) The distance Linda runs in t = 2·√10 seconds, d = v × t
Given that Linda's velocity, v = 8.6 m/s, we have;
d = 8.0 × 2·√10 = 16·√10
The distance Linda runs in t = 2·√10 seconds = 16·√10 meters ≈ 50.6 meters
Therefore, Linda should be approximately (50.6 - 20) meters = 30.6 meters behind Jenny when Jenny starts running
c) Jenny's speed at the 100 m mark is given as follows;
v = u + a·t
t = 2·√10 seconds, a = 1.0 m/s², u = 0
∴ v = 0×t + 1.0×2·√10 = 2·√10 ≈ 6.325
Jenny's speed at the 100-m mark ≈ 6.325 m/s
newtons second law lab report link
Answer:
ghittu iihg उह्स उउह्स उग्य्किव जिक्ह्ब
An upright image which reduced in size 10 times occurred in a mirror. If the radius of
curvature of the mirror is 2 m, bow far is the object from the mirror?
Answer:
-10/9 m
Explanation:
Radius of curvature, R=2 m
Focal length of mirror, f=R/2=2/2=1 m
Let height of object=h
Height of image, h'=h-10h=-9h
We have to find the distance of object from the mirror.
Magnification, m= [tex]\frac{h'}{h}=-\frac{v}{u}[/tex]
[tex]m=\frac{-9h}{h}=-9[/tex]
Image is upright and small in size it means the mirror is convex.
Focal length of convex mirror is negative.
f=-1m
[tex]-9=-\frac{v}{u}[/tex]
[tex]v=9u[/tex]
Now, mirror formula
[tex]\frac{1}{v}+\frac{1}{u}=-\frac{1}{f}[/tex]
[tex]\frac{1}{9u}+\frac{1}{u}=\frac{1}{1}[/tex]
[tex]\frac{1+9}{9u}=-1[/tex]
[tex]10=-9u[/tex]
[tex]u=-\frac{10}{9} m[/tex]
Hence, the distance of object from the mirror is -10/9 m
Cuando una persona sube y baja una escalera, Cuanto vale su desplazamiento y cual es la medida de su trayectoria.
Answer:
Primero, definimos el desplazamiento como la distancia entre la posición final y la posición inicial.
Así, si comenzamos abajo, luego subimos la escalera, y luego bajamos, la posición final y la posición inicial serán la misma
por lo que el desplazamiento es igual a cero.
La medida recorrida es el espacio total recorrido.
Es decir, si entre el principio y el final de la escalera hay una distancia D.
La persona que sube y baja, recorre esta distancia dos veces.
Entonces cuando una persona sube y baja la escalera, la medida de su trayectoria será 2*D.
The Indianapolis speedway consists of a 2.5 mile track having four turns, each 0.25 mile long and banked at 9 12'
Answer: Your question is missing below is the question
Question : What is the no-friction needed speed (in m/s ) for these turns?
answer:
20.1 m/s
Explanation:
2.5 mile track
number of turns = 4
length of each turn = 0.25 mile
banked at 9 12'
Determine the no-friction needed speed
First step : calculate the value of R
2πR / 4 = πR / 2
note : πR / 2 = 0.25 mile
∴ R = ( 0.25 * 2 ) / π
= 0.159 mile ≈ 256 m
Finally no-friction needed speed
tan θ = v^2 / gR
∴ v^2 = gR * tan θ
v = √9.81 * 256 * tan(9.2°) = 20.1 m/s
Which group of people was most directly affected by the twenty sixth amendment
A pendulum, like a bobblehead, moves back and forth through a resting position. At what point on its path is the net force acting on the pendulum zero?
Group of answer choices
When the pendulum is displaced as far to the left as it can be.
When the pendulum is displaced as far to the right as it can be.
When the pendulum is at its resting position.
Never…there is always a net force acting on a pendulum
Answer:
[tex]\\ \longrightarrow\:\bf \purple{\dfrac{1}{v} = \dfrac{1}{ - 100} + \:\dfrac{1}{20} }[/tex]
radiation is the main way of transferring heat in a vacuum b solid c gas d liquid
Answer:
gas
................
Explanation:
hope it helps u
why does the green colour of iron (ii) chloride change to yellow when chlorine gas is bubbled into it
Answer:
FeCl2 has a high melting point.
Explanation:
Iron is seen to get oxidized by addition of chlorine 3 as the product is rust colored and on dissolving in water has a yellow orange color. This is characterized by the aquatic iron and is due to the monohydroxyThree capacitors 2uf, 5uf and 7uf are connected in series what is their equivalent capacitance
Answer:
C eq = .96uF
Explanation:
A mother is pulling a sled at constant velocity by means of a rope at 37°. The tension on the rope is 120 N. Mass of children plus sled is 55 kg. The mother has a mass of 61 kg.
a) Draw FBD for the sled with the kids as one object
b) Draw FBD for the mother
c) Find the normal force on the sled and on the mother
d) Find the kinetic friction acting on the sled and the static friction acting on the mother
e) Find the coefficient of kinetic friction for the sled
Answer:
Please find the complete solution in the attached file.
Explanation:
a.
[2]
A train covers 450 km in 5 hr. between Station A and Station B.
What is the average speed of train in km/h and m/s.
Answer:
90 km/h
50 m/s
Explanation:
Distance = 450 km
Time = 5hrs
Speed = Distance/Time
450/5 = 90 km/h
1 km = 1,000 m
1 hr = 60m = 60 x 60 = 3,600 sec
but since it's 5hrs = 60 x 300m = 18,000
90 x 1,000 = 90,000/18,000 = 50 m/s
A basketball is shot by a player at a height of 2.0 m. The initial angle
was 53° above horizontal. At the highest point the ball was travelling 6
m/s. If he scored (the ball went through the rim that is 3.00 m above the
ground), what was the player’s horizontal distance from the basket?
Answer:
The answer is "8.28 m".
Explanation:
[tex]\to u \cos 53^{\circ}=6 \ \text{therefore the horizontal velocity is constant alaways}\\\\\therefore[/tex]
[tex]u= \frac{6 \times 5}{3}= \frac{30}{3}= 10\ \frac{m}{s}\\\\[/tex]
In the projectfile when vertical displacement is 1 then 5 m comes at farther sides
Using
[tex]S=ut-\frac{1}{2} gt^2\\\\1=u\sin 53^{\circ}\times t-5t^2\\\\1=8t-5t^2\\\\5t^2-8t+1=0\\\\ t=\frac{8\pm \sqrt{64-20}}{10} \\\\=\frac{8\pm 2\sqrt{11}}{10} \\\\t_2=\frac{8+2\sqrt{11}}{10} \\\\[/tex]
[tex]Distance=u \cos 53^{\circ}\times t_2\\\\[/tex]
[tex]=6 \times \frac{8\pm 2\sqrt{11}}{10} \\\\=\frac{24\pm 6\sqrt{11}}{5} \\\\= 8.28 \ m[/tex]
2. A cinder block is sitting on a platform 20 m high. It weighs 16kg. The block has
_ joules of potential energy.
Answer:
3136 Joules
Explanation:
Applying,
P.E = mgh.............. Equation 1
Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.
From the question,
Given: m = 16 kg, h = 20 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
P.E = 16(20)(9.8)
P.E = 3136 Joules
Hence the potential energy of the cinder block is 3136 Joules
When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy
is absorbed by the ethyl alcohol? (Assume the density of ethyl alcohol to be 0.790 g/mL.)
Answer:
Q = 194.34 J
Explanation:
Given that,
100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.
We need to find the amount of thermal energy absorbed by the ethyl alcohol.
The density of ethyl alcohol is 0.790 g/mL.
The formula for heat absorbed is given by :
[tex]Q=mc\Delta T\\\\As, d=\dfrac{m}{V}\\\\So,\\Q=dVc\Delta T\\\\Q=0.79\times 100\times 2.46\\\\Q=194.34\ J[/tex]
So, 194.34 J of thermal energy is absorbed by the ethyl alcohol.
