Answer:
the answer to the expression is u=4
Plz help me solve this ASAP and show the work thank you
Answer:
14
Step-by-step explanation:
The diagram is right angle triangle so we can use SOHCAHTOA
So in the diagram we have 62 degree opposite to x and the hypotenuse
Step 1
Sin62=x/16
Step 2
X=16sin62 by cross multiplication
Step 3
X=14.13
X=14
I would raise it to 1grand but I’m very broke
Answer:
ITS A LOL
Step-by-step explanation:
the diagram below shows a square inside a regular hexagon. The apothem of the hexagon is 18.11 units. To the nearest square unit, what is the area of the shaded region.
A. 1027 square units
B. 1087 square units
C. 862 square units
D. 1948 square units
the answer is 862sq units probably
can you explain it please and which method is correct?
Answer:
The second one (answer of 3), but the other ones could've worked, they were just calculated wrong.
Step-by-step explanation:
Here's why each one did or didn't work:
First answer- you had the right idea by cancelling out the two in the denominator, however if you're going to divide 2, you have to divide it from everything in the equation. Meaning you would divide 4 by 2 to get 2, and then add the 1 + 2 to get final answer 3.
Second answer- since you added the numerator separately and then did the basic division, this worked.
Third one- similarly to the first one, you would have to also divide the 2 by 2 to get 1, then adding 1 + 2 to get 3.
The amount of time needed to complete a job, t, varies inversely with the number of workers, w. If
9 workers can complete a job in 56 minutes, how many minutes would it take 14 workers?
Do not include the units in your answer.
Answer:
38
Step-by-step explanation:
If 9 workers can complete a job in 56 minutes, then it takes 36 minutes for 14 workers.
What is Ratio?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given that amount of time needed to complete a job, t, varies inversely with the number of workers, w.
t=k/w
k is a constant
9 workers can complete a job in 56 minutes
t=56 and w=9
56=k/9
Apply cross multiplication
k=9×56
k=504
We need to find how many minutes would it take for 14 workers.
t=504/14
t=36
Hence, it takes 36 minutes for 14 workers.
To learn more on Ratios click:
https://brainly.com/question/1504221
#SPJ2
Angle A and B are supplementary angles. The measure of angle B is twice the measure of angle A minus 24. Find the measure of the angle A and B.
Answer:
A = 58
B = 112
Step-by-step explanation:
A + B = 180 Supplementary angles
B = 2A - 24 Given
Substitute for B in the first equation
A + 2A - 24 = 180
3A - 24 = 180 Add 24 to both sides
3A = 180 + 24 Combine the right
3A = 204 Divide both sides by 3
A = 204/3
A = 68
B = 2A - 24
B = 2*68 - 24
B = 136 - 24
B = 112
How do you work out the volume of a cube
Answer:
V=a cubed
Step-by-step explanation:
Activity 2. pls just give me the formula or answer this, it really help me
Answer:
X= sin (56) . 17) hope this helps
Emilio compro 3 bolitas y pago 180 en total. Carlos compro 4 bolitas y pago 200 en total ¿Quién pago menos por cada una de las bolitas que compro?
Answer:
emilio:
3 bolitas = 180
1 bolita = 60
carlos:
4 bolitas = 200
1 bolita = 50
carlos pago menos.
Convert 10,000 seconds into the number of equivalent hours, minutes, and seconds.
Answer:
She's "Hot"!
Step-by-step explanation:
x^3 - 3mx^2 + 3(2m - 1)+1
Answer:
21e
jjjjjjjoiooooooooooooooooooooimm
at a grocery store, an uncooked beef roast is on sale for $5.99/lb. At the same grocery store, prepared roast beef is available at the deli for $2.99/100g. How much more expensive is the deli roast compared to the uncooked roast?
Answer:
$7.58/lb
Step-by-step explanation:
raw roast: $5.99 per lb
deli roast: $2.99 for 100g
We know the price per lb of the raw roast.
Let's find the price per lb of the deli roast.
1 lb = 454 grams
454 grams / 100 grams = 4.54
1 lb is 4.54 times 100 g
If we multiply the price of 100g of deli roast by 4.54, we get teh price per lb.
$2.99/lb * 4.54 = $13.57/lb
raw roast: $5.99/lb
deli roast: $13.57/lb
difference in price of 1 lb: $13.57 - $5.99 = $7.58
Answer: $7.58/lb
Answer:
.01669 $/g or $7.57 $/lb
Step-by-step explanation:
$2.99/100g = .0299 $/g
1 lb = 453.59237 g.
$5.99/453.59237 g= .0132$/g
Solve simultaneously
4X + 3y= 19
2X +5y= 20
answer
4
2
Step-by-step explanation:
4x+3y=19
4x=19-3y
4x=16
x=16/4
x=4
2x+5y=20
5y=20/2x
5y= 10
y=10/5
y=2
The graph below have the same shape. What is the equation of the graph?
Answer:
C
Step-by-step explanation:
The graph has been translated down 4 units and moved to the right 2 units
so correct answer is C (x-2)^2-4.
Whats the mean, modian, mode, and range, of these five?
6) 35, 74, 76, 93, 84, 22
Mean=
Median=
Mode=
Range=
7) 72, 55, 11, 55, 42, 25, 79, 69
Mean=
Median=
Mode=
Range=
8) 93, 15, 11, 58, 94, 87, 73, 16, 21
Mean=
Median=
Mode=
Range=
9) 17, 45, 12, 74, 89, 57
Mean=
Median=
Mode=
Range=
10) 52, 35, 55, 23, 30
Mean=
Median=
Mode=
Range=
Answer:
Step-by-step explanation:
mean:64
median: (74+76)/2=75
mode: no mode
Range: 71
#2
mean:51
median:(55+55)/2=55
mode:55
Range; 68
Answer:
6)
Mean = 35+ 74+ 76+ 93+ 84+ 22 = 384
mean = total amount/total numbers
384/6 = 64
Median = 76 + 93/2 = 169/2 = 84.5
Mode = there is no mode (there are no numbers repeated)
Range = (biggest - smallest) = 93 - 22 = 71.
7)
Mean = total amount/total numbers
72+ 55 +11+ 55 + 42 + 25 + 79 + 69 = 408/8 = 51
Median = 55 + 42/2 = 97/2 = 48.5
Mode = 55
Range = 79 - 25 = 54
8) Mean = 93 + 15 + 11+ 58+ 94+ 87 + 73+ 16+ 21 = 468/9 = 52
Median = 94
Mode = nothing
Range = 93 - 11 = 82
9)
Mean = 17+45+ 12+ 74+ 89 + 57 = 294/6 = 49
Median = 12 + 74/2 = 43
Mode = nothing
Range = 89 - 12 = 77
10)
Mean = 52+ 35+ 55+ 23+ 30 = 195/5 = 39
Median = 55
Mode = nothing
Range = 55 - 23 = 32
Step-by-step explanation:
I rlly hope this helped i took soooo long(sry for that btw)
Let ℤ be the set of all integers and let, (20) 0 = { ∈ ℤ| = 4, for some integer }, 1 = { ∈ ℤ| = 4 + 1, for some integer }, 2 = { ∈ ℤ| = 4 + 2, for some integer }, 3 = { ∈ ℤ| = 4 + 3, for some integer }. Is {0, 1, 2, 3 } a partition of ℤ? Explain your answer.
Answer:
[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z
Step-by-step explanation:
Given
[tex]$$A _ { 0 } = \{n \in \mathbf { Z } | n = 4 k$$,[/tex] for some integer k[tex]\}[/tex]
[tex]$$A _ { 1 } = \{ n \in \mathbf { Z } | n = 4 k + 1$$,[/tex] for some integer k},
[tex]$$A _ { 2 } = { n \in \mathbf { Z } | n = 4 k + 2$$,[/tex] for some integer k},
and
[tex]$$A _ { 3 } = { n \in \mathbf { Z } | n = 4 k + 3$$,[/tex]for some integer k}.
Required
Is [tex]\{0, 1, 2, 3\}[/tex] a partition of Z
Let
[tex]k = 0[/tex]
So:
[tex]$$A _ { 0 } = 4 k[/tex]
[tex]$$A _ { 0 } = 4 k \to $$A _ { 0 } = 4 * 0 = 0[/tex]
[tex]$$A _ { 1 } = 4 k + 1$$,[/tex]
[tex]A _ { 1 } = 4 *0 + 1$$ \to A_1 = 1[/tex]
[tex]A _ { 2 } = 4 k + 2[/tex]
[tex]A _ { 2} = 4 *0 + 2$$ \to A_2 = 2[/tex]
[tex]A _ { 3 } = 4 k + 3[/tex]
[tex]A _ { 3 } = 4 *0 + 3$$ \to A_3 = 3[/tex]
So, we have:
[tex]\{A_0,A_1,A_2,A_3\} = \{0,1,2,3\}[/tex]
Hence:
[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z
g(x)=x ^2 and f(x)=x-7 so what is g(f(4)
Answer:
I think the answer is 9
=====================================================
Work Shown:
f(x) = x-7
f(4) = 4-7
f(4) = -3
We can see that f(4) and -3 are the same number. Because of this, we can replace f(4) with -3
This will have us go from g( f(4) ) to g( -3 )
Then we plug x = -3 into the g(x) function
g(x) = x^2
g(-3) = (-3)^2
g(-3) = 9 is the final answer
Again, since -3 and f(4) are the same thing, we can replace that '-3' in g(-3) to get
g( -3 ) = 9
g( f(4) ) = 9
-------------------
An alternative route:
g(x) = x^2
g( f(x) ) = ( f(x) )^2 .... replace every x with f(x)
g( f(x) ) = ( x-7 )^2 .... plug in f(x) = x-7 for the right hand side only
g( f(4) ) = ( 4-7 )^2 ... plug in x = 4
g( f(4) ) = (-3)^2
g( f(4) ) = 9
i need the answer asap please help!
In right ΔDEF, DF = 20, m∠ F = 90˚, EF = 17. Which of the following is true? Does option 5 apply
define supplementary angles
A pair of angles is known as supplementary angles when the sum of the angles is 180°
Step-by-step explanation:
Supplementary angles are those angles that measure up to 180 degrees. hope it helps.stay safe healthy and happy....A group of friends wants to go to the amusement park. They have $214.25 to spend on parking and admission. Parking is $6.75, and tickets cost $20.75 per person, including tax. Write and solve an equation which can be used to determine pp, the number of people who can go to the amusement park.
Answer:
10 friends can go to the amusement park
Step-by-step explanation:
214.25 = 6.75 + 20.75x
207.50 = 20.75x
x = 10 friends can go
Determine the degree of the Maclaurin polynomial required for the error in the approximation of the function at the indicatedvalue of x to be less than 0.0001.
Answer:
Fifth degree polynomial
Step-by-step explanation:
Given data:
e^0.3
error = 0.0001
let the function ; f(x) = e^x
note : x = 0.3
The Maclaurin polynomial f(x) = e^x = 1 + x + x^2 / 2! + x^3/3! --- + ∑ x^n/n!
= 1 + 0.3 + (0.3)^2/2! + (0.3)^3 / 3! --- + ∑ (0.3)^n/n!
Attached below is the remaining part of the solution
what is the length of RS? no links.
Answer:
25 units
Step-by-step explanation:
TR = TQ
2x + 10 = 18
2x = 8
x = 4
RS = QS
RS = 9x - 11
RS = 9(4) - 11
RS = 25
1. what are the two pair of alternate exterior angles?
2. angle 1 is 60 find the value of angle 8
Answer:
see explanation
Step-by-step explanation:
∠ 1 and ∠ 8 , ∠ 2 and ∠ 7 are alternate exterior angles
They are on opposite sides of the transversal and outside the parallel lines
Given ∠ 1 = 60° , then
∠ 8 = 60° ( alternate exterior angles are congruent )
Answer:
1. <1 and <8
< 2 and <7
2. 60°
Step-by-step explanation:
1. When two lines are cut by a transversal, the pairs of angles on either side of the transversal and outside the two lines are called the alternate exterior angles.
2. If two parallel lines are cut by a transversal, then the alternate exterior angles formed are congruent.
Congruent angles are angles with the same measurement.
Annapolis Company purchased a $4,000, 6%, 5-year bond at 101 and held it to maturity. The straight line method of amortization is used for both premiums & discounts. What is the net cash received over the life of the bond investment? (all money received minus all money paid, round to nearest whole dollar)
Answer:
The answer is "[tex]\bold{\$1160}[/tex]"
Step-by-step explanation:
Calculating total paid money:
[tex]= \$4000 \times 101\% \\\\= \$4000 \times \frac{101}{100} \\\\=\$40 \times 101\\\\=\$4040[/tex]
[tex]\text{Total received money = Principle on Maturity + Interest for 5 years}[/tex]
[tex]= \$4000 + \$4000\times 6\% \times 5 \\\\= \$4000 + \$4000\times \frac{6}{100} \times 5 \\\\= \$4000 + \$40 \times 6 \times 5 \\\\= \$4000 + \$40 \times 30 \\\\= \$4000 + \$1200 \\\\= \$5200 \\\\[/tex]
Total earnings over the life of the corporate bond
[tex]= \$5200 - \$4040 \\\\=\$1160[/tex]
What is the following sum?
Answer:
[tex]D. 7x^{2}(\sqrt[3]{x^{2}y} )[/tex]
Step-by-step explanation:
is this edge?
If it is, my friend had the same question i think. I didn't tho
Which division problem does the number line below best illustrate?
0 1 2 3 4 5 6 7 8 9 10 11 12 13
O 12-3-4
O 9-3-3
O 12-2-6
o 16-4-4
Answer:
12/3=4 ..............
What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?
Answer:
Range D = {-7, 1, 9, 17}
Step-by-step explanation:
f(x) = 4x + 9
4(-4) + 9 = -7
4(-2) + 9 = 1
4(0) + 9 = 9
4(2) + 9 = 17
An automobile insurance company issues a one-year policy with a deductible of 500. The probability is 0.8 that the insured automobile has no accident and 0.0 that the automobile has more than one accident. If there is an accident, the loss before application of the deductible is exponentially distributed with mean 3000. Calculate the 95th percentile of the insurance company payout on this policy.
Answer:
y₀.₉₅ = 3659
Step-by-step explanation:
P( no accident ) = 0.8
P( one accident ) = 0
deductible = 500
mean = 3000
Determine the 95th percentile of the insurance company payout
Assuming : y =company payout , x =amount of loss incurred due to accident
Then :
P( x < 500 ) = 0.2 ( 1 - e^-500/3000)
= 0.2 ( 1 - e^-1/6 )
95th percentile =
= P( y < y₀.₉₅ ) 0.95
P( y = 0 ) = 0.8 + 0.2 ( 1 - e^-1/6 ) = 0.8307
attached below is the remainder of the solution
A study was conducted by a team of college students for the college research center. From the study, it was reported that most shoppers have a specific spending limit in place while shopping online. The reports indicate that men spend an average of $230 online before they decide to visit a store. If the spending limit is normally distributed and the standard deviation is $19.
(a) Find the probability that a male spent at least $210 online before deciding to visit a store. Ans: ____________
(b) Find the probability that a male spent between $240 and $300 online before deciding to visit a store. Ans: ____________
(c) Find the probability that a male spent exactly $250 online before deciding to visit a store. Ans: (d) Ninety-one percent of the amounts spent online by a male before deciding to visit a store are less than what value? Ans: ____________
Answer:
0.8536
0.29933
Step-by-step explanation:
Given :
Mean amount spent, μ = $230
Standard deviation, σ = $19
1.)
Probability of spending atleast $210
P(x ≥ 210)
The Zscore = (x - μ) / σ = (210 - 230) / 19 = - 1.052
P(Z ≥ -1.052) = 1 - P(Z ≤ - 1.052) = 1 - 0.1464 = 0.8536
2.)
Probability that between $240 and $300 is spent:
P(x < $240) = Zscore = (240 - 230) / 19 = 0.526
P(Z < 0.526) = 0.70056
P(x < 300) = Zscore = (300 - 230) / 19 = 3.684
P(Z < 3.684) = 0.99989
P(Z < 3.684) - P(Z < 0.526)
0.99989-0.70056 = 0.29933