You are going 5 meters per second
To get your answer, divide 50 by 10, you get 5.
A windshield hits a bug with force of 10 N.
What force does the bug hit the windshield?
Explain using Newton's third law.
Please help ASAP !!!!
Which of the following statements is true?
Observations are often used to form questions about the world.
The dependent variable is changed by the experimenter.
The best hypotheses are written as answers to a question.
A hypothesis is created at the end of an experiment.
Answer:
The answer is B.
Explanation:
They are in control of the experiment, they can change it the variables to better help the experiment.
Answer:
b
Explanation: its b
A ball is thrown up into the air with an initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed for the ball to reach its max height.
Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} -g*t[/tex]
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
[tex]y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\[/tex]
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
Which of the following pairs of elements is most likely to form an ionic bond?
A. carbon and chlorine
B. phosphorus and bromine
C. sulfur and oxygen
D. aluminum and nitrogen
Answer: the answer is D. Aluminum and nitrogen
Explanation:
3. Four projectiles, A, B, C, and D, were launched from, and returned to, level ground.
The data table below shows the initial horizontal speed, initial vertical speed, and
time of flight for each projectile.
Data Table
Projectile Initial Horizontal Speed (m/s) Initial Vertical Speed (m/s) Time of Flight (s)
A
40.0
29.4
6.00
B
60.0
19.6
4.00
С
50.0
24.5
5.00
D
80.0
19.6
4.00
Which projectile traveled the greatest horizontal distance? [Neglect friction.]
Answer is D
Taking the test rn and found out the answer
The projectile D traveled the greatest horizontal distance.
What is projectile motion?Projectile motion is a form of motion experienced by an object or particle that is projected near the Earth's surface and moves along a curved path under the action of gravity only.
What is projectile horizontal distance?Horizontal range of a projectile is the horizontal distance travelled by the projectile between launch and the landing points.
The projectile horizontal distance is depend on horizontal speed and time in air.
In all these four projectile, projectile D has maximum horizontal speed and time in air.
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Can frictional forces ever increase an object’s kinetic energy?
Explanation:
friction opposes the relative motion between two bodies,hence it decreases the kinetic energy but, in the view that friction supplies the force that accelerates the object , for example friction helps in walking we can say that friction causes an increase in kinetic energy
Answer:
In most situations, frictional forces tend to reduce the kinetic energy of an object. However, frictional forces can sometimes increase an object's kinetic energy.
A football is thrown at an angle of 30° above the ground and is in the air for a total of 1.93 s
before it is caught (at the same height). If the football traveled a horizontal distance of 43 m
a) with what speed was the football thrown?
b) what max height would the football reach?
1.53 secs :)))))))))))))))
A 3.0\, \text {kg}3.0kg3, point, 0, start text, k, g, end text box is at rest on a table. The static friction coefficient \mu_sμ s mu, start subscript, s, end subscript between the box and table is 0.400.400, point, 40, and the kinetic friction coefficient \mu_kμ k mu, start subscript, k, end subscript is 0.100.100, point, 10. Then, a 10\,\text N10N10, start text, N, end text horizontal force is applied to the box. What is the best estimate of the magnitude of the box’s acceleration?
Answer:
its 0 m/s^2 on khan
Explanation:
usually how i think of it if its below 15 N then its 0
Answer:
5.3m/s^2
Explanation:
:)
A person travels by car from one city to another. He drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas. What is the average speed for the trip?
Answer:
53.53 km/h
Explanation:
Given that the person drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas.
So, the total time to complete the journey is
t=30+12+45+15=102 min
[tex]=\frac{102}{60}=1.7[/tex] hours
As distance=(speed)x(time), so
the distance covered in 30 minutes with a speed of 80 km/h
[tex]d_1=80 \times \frac{30}{60}=40[/tex] km.
The distance covered in 12 minutes with a speed of 105 km/h
[tex]d_2=105 \times \frac{12}{60}=21 km[/tex].
The distance covered in 45 minutes with a speed of 40 km/h
[tex]d_3=40 \times \frac{45}{60}=30 km[/tex].
So, to the total distance covered is
[tex]d=d_1+d_2+d_3[/tex]
[tex]=40+21+30=91 km[/tex]
As the average speed = (Total distance covered)/(Total time taken)
So, the average speed for the whole journey
[tex]=\frac{d}{t}[/tex]
[tex]=\frac{91}{1.7}= 53.53 km/h[/tex].
Hence, the average speed for the trip is 53.53 km/h.
Which Sl units are combined to describe energy?
A. Kilograms and m/s2
B. Kilograms and joules
C. Kilograms and m/s2
D. Kilograms and meters
Answer:
kilograms and m²/s²
Explanation:
The SI units combined to describe energy is kilograms and m²/s² ;
Energy can be derived from;
Potential energy = mgh
Units = kg x m/s² x m
= kg m²/s²
Even if we use kinetic energy, we still get kg m²/s²
Which change will always result in an increase in the gravitational force between two objects?
OO
increasing the masses of the objects and increasing the distance between the objects
decreasing the masses of the objects and decreasing the distance between the objects
increasing the masses of the objects and decreasing the distance between the objects
decreasing the masses of the objects and increasing the distance between the objects
Answer:
increasing the masses of the objects and increasing the distance between the objects
While sitting in class, your body exerts a force of 600 N on your chair. How much work do you do?
Answer:
1000 N
Explanation:
If the mass of the coaster car is 50 Kg and the height of the car at position 4 is meters,
and the car is moving at 2 m/s at position 4, what is the mechanical energy of the
system?
Adhira loves to ride her bike around the neighborhood. She starts riding 1.2 miles at 30° S of E. Then, she rides another 2.0 miles at 20° W of S. Next, she rides 1.6 miles at 30° S of W. And finally, she rides 2.6 miles at 15° W of N. What is her final displacement from her starting point?
Answer:
D = 1.8677 miles , θ = 24.28º at South of West
Explanation:
This is an exercise in adding vectors, the easiest way to solve them is to decompose the vectors and add each component algebraically. Let's use trigonometry
first displacement. d = 1.2 miles to 30º south of East
cos ( 360-30) = cos (-30) = x₁ / d
sin (-30) = y₁ / d
x₁ = d cos (-30)
y₁ = d sin (-30)
x₁ = 1.2 cos (-30) = 1,039 miles
y₁ = 1.2 sin (-30) = -0.6 miles
second shift. d = 2.0 miles to 20º West of South
cos (270-20) = x₂ / d
cos (250) = y₂ / d
x₂ = 2.0 cos 250 = -0.684 miles
y₂ = 2.0 sin250 = -1.879 miles
Third displacement. d = 1.6 miles to 30º South of West
cos (180 + 30) = x₃ / d
sin (210) = y₃ / d
x₃ = 1.6 cos 210 = -1.3856 miles
y₃ = 1.6 sin 210 = -0.8 miles
Fourth displacement. d = 2.6 miles to 15º West of North
cos (90 + 15) = x₄ / d
sin (105) = y₄ / d
x₄ = 2.6 cos 105 = -0.6729 miles
y₄ = 2.6 sin 105 = 2,511 miles
having all the components we add
x-axis (West-East direction)
X = x₁ + x₂ + x₃ + x₄
X = 1.039 -0.684 - 1.3846 - 0.6729
X = -1.7025 miles
Y = y₁ + y₂ + y₃ + y₄
Y = -0.6 -1.879 -0.8 +2.511
Y = -0.768
The modulus of this displacement is we use the Pythagorean theorem
D = √ (X² + Y²)
D = √ (1.7025² + 0.768²)
D = 1.8677 miles
let's use trigonometry to find the direction
tan θ = Y / X
θ = tan⁻¹ Y / x
θ = tan⁻¹ (0.768 / 1.7025)
θ = 24.28º
as the two components are negative this angle is in the third quadrant
therefore in cardinal direction form is
θ = 24.28º at South of West
Which is the balanced equation for Sg + O2 → SO2?
OS: + 016 — 8S02
O S₂ + O₂S₃ + O₂
O S8+ O₂S₂O₂
O Sg + 802 8S02
The balanced equation for S(g) + O₂ → SO₂ is as follows: S₈ + 8O₂ → 8SO₂ (option C).
What is a balanced equation?A balanced equation is a chemical equation in which the number of atoms of each element on both sides of the equation are the same.
This means that the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.
According to this question, sulfur reacts with oxygen gas to produce sulfur dioxide as follows:
S₈ + O₂ → SO₂
The balanced chemical equation is as follows:
S₈ + 8O₂ → 8SO₂
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A man travels 25 kilometers in 15 minutes. A police officer stops him and
writes a ticket for speeding. The posted speed limit is 80 kilometers per
hour. Did the man exceed the posted speed limit?
Answer:
yes
Explanation:
cuz 15x2=30 30x2=60 60=1 hour, and the limited is 80 km per hour
15=25
15x4=60 25x4=100
so yes
he was going 100km per hour
What is the speed of a car that
accelerates at a rate of 10 m/s2 for a
total of 25 seconds?
Answer:
250 m/sExplanation:
The speed of the car can be found by using the formula
v = a × twhere
a is the acceleration
v is the speed
t is the time
From the question we have
v = 10 × 25
We have the final answer as
250 m/sHope this helps you
A marble rolls off a table from a height of 1.5 meters. Approximately how much time was the marble in the air?
O 1.1 seconds
O 0.78 seconds
O 0.55 seconds
O 0.2 seconds
Answer:
t = 0.55 s
Explanation:
Given that,
Height of the marble, h = 1.5 m
We need to find the time for which the marble is in air. Let the time is t. Using second equation of motion to find it as follows :
[tex]h=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 and a = g
[tex]h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\cdot1.5}{9.8}}\\\\t=0.55\ s[/tex]
So, the marble is in air for 0.55 s. Hence, the correct option is (c).
30.) We observe motion by using a *blank* of *blank*.
Answer:
Point of Reference
Explanation:
A student is given an investigation of the human body. The student is to predict how new cells are created. According to cell theory, which prediction is correct?
A.Cells grow and develop, but are never replaced.
B. New cells are created from pre-existing cells in the human body.
C. New cells are created but quickly die during cell growth.
D. Humans are born with all the cells they will ever need.
Answer:
B. New cells are created from pre-existing cells in the human body.
Explanation:
According to the cell theory, the correct assumption from the student's investigation is that "new cells are created from pre-existing cells in the human body".
One of the postulates of the cell theory is that all cells originated from pre-existing cells. Also, a cell is the fundamental unit of life.So, the student is correct to say that new cells are created from pre-existing cells in the human body.
does anyone know how to do this? the scenario is ""dominique reads that race cars have wide tires because the increased area of contact between the tire and the road results in a stronger force of friction. she hypothesizes that the force of kinetic friction on an object is directly proportional to the area of the object in contact with the surface and wants to test this hypothesis. Dominique and Blake take a long wooden plank and cut the plank into pieces that have different lengths but the same width and height. The students also have access to other equipment commonly available in a school physics lab.
Answer:
Stupid
Explanation:
Because there is never a answer when we are trying to find one
Beginning: Identify the above circuits (A and B) as either a series or parallel circuit.
What is the answer to these?
Answer: it told u the answer bc u got it wrong-
what does terminal velocity mean ? please help
[tex] \underline{ \bf{\underline{\large{Terminal \: Velocity}}}}[/tex]
The maximum constant velocity acquired by a body while falling through a viscous medium is called it's terminal velocity. It is usually denoted by [tex] \sf V_T [/tex].It is directly proportional to the square of the radius of the body (a²) & the difference of the densities of the body and the fluid [tex] \sf (\rho - \sigma) [/tex].It is inversely proportional to the viscosity of the medium [tex] \sf (\eta) [/tex].Formula of Terminal Velocity:[tex] \boxed{ \bf{V_T = \dfrac{2}{9} \dfrac{ {a}^{2} }{ \eta} ( \rho - \sigma)g}}[/tex]Which temperature is the hottest? 98 F or 39 C or 303K?
F= 1.8C + 32
C= (F-32)/1.8
Answer:
The hottest temperature is [tex]T_2 = 39^o C[/tex]
Explanation:
From the question we are given
[tex]T_1 = 98 F[/tex]
[tex]T_2 = 39^oC[/tex]
[tex]T_3 = 303 \ K[/tex]
Generally converting [tex]T_3[/tex] to Fahrenheit
[tex]T_3' = (T_3 -273 ) * \frac{9}{5} + 32[/tex]
=> [tex]T_3' = (303 -273 ) * \frac{9}{5} + 32[/tex]
=> [tex]T_3' = 86 F[/tex]
Converting [tex]T_2[/tex] to Fahrenheit
[tex]T_2' = T_2 * \frac{9}{5} + 32[/tex]
=> [tex]T_2' = 39 * \frac{9}{5} + 32[/tex]
=> [tex]T_2' =102.2 F[/tex]
Now comparing the temperature in Fahrenheit we see that [tex]T_2[/tex] is the hottest
What is the acceleration of a 12kg box being pushed with 60N of force?
Pls help, will give brainliest!! An airplane pilot tries to fly directly east with a velocity of 800.0 km/hr. If a
wind comes from the southwest (45 degrees) at 80.0 km/hr., what is the relative velocity of the plane to the earth's surface?
please help me quickly
Answer:
not moving
Explanation:
what inflammatory molecule aids with muscle building and is released when muscles experience microscopic damage?
Answer:
Cytokines
Explanation:
Cytokines are known as inflammatory molecules which are also proteinous and aid signaling of certain processes and conditions in the body.
They are also normally involved in aiding muscle building and are released when muscles experience microscopic damage which may lead to the muscles being sore.
