Answer:
Step-by-step explanation:
19.
The numbers are m and n
Sum of m and n = m + n
Sum is multiplied by 91 = 91 x ( m + n )
20.
Let the number be = m
Six subtracted from the number = m - 6
41 times the difference = 41 x ( m - 6)
21.
Let the number be = r
Difference between 83 and 10 = 83 - 10 = 73
[tex]The \ number\ divided \ by\ the \ difference \ = \frac{r}{73}[/tex]
22.
Total of p and 23 = p + 12
[tex]Total \ divided \ by \ 18 = \frac{p + 12 }{18}[/tex]
23.
The product of c and 3 = 3c
Sum of 9 and 12 = 21
Product is more than Sum = 3c + 21
24.
Sum of y and 10 = y + 10
Number x decreased by 5 = x - 5
[tex]Sum \ divided \ by \ difference = \frac{ y + 10 }{x - 5}[/tex]
q= 3ym/2 make m the subject of the formula
Answer:
m = [tex]\frac{2q}{3y}[/tex]
Step-by-step explanation:
Given
q = [tex]\frac{3ym}{2}[/tex] ( multiply both sides by 2 to clear the fraction )
2q = 3ym ( isolate m by dividing both sides by 3y )
[tex]\frac{2q}{3y}[/tex] = m
write your answer as an integer or as a decimal rounded to the nearest tenth
Answer:
Step-by-step explanation:
CE and are the sides making up the sine of an angle.
CE is the side opposite the angle
DE is the side hypotenuse.
<D = 61 degrees
Sin(D) = opposite / hypotenuse
hypotenuse = 8
Sin(61) = 0.8746
CE = ?
sin(61) = CE / 8 multiply both sides by 8
8 sin(61) = CE
CE = 8 * 0.8746
CE = 6.9969
CE = 7.0
That 0 should be included in the answer, but I think it is safe to say that if you enter 7, you will get it right.
Answer:
7.0
Step-by-step explanation:
The sum of a rational and irrational number is
Answer:
It will be irrational
Step-by-step explanation:
irrational+rational=irrational
Plz this is due today help me explain the answer
Answer:
177.3 feet
This is a classic find the vertex of a parabola question.
if this was a calculus class the solution would be to take the derivative and set it equal to zero... -32t+ 105 = 0
BUT i assume that you are not in a calculus class..
so we try plan "B" the highest (or lowest) point of parabola is it's vertex
the vertex formula is [-b/2a,f(-b/2a)]
in your problem a = -16, b=105, c= 5
so the "X" (TIME) is located at -(105)/(2*-16) = 3.28
plug in 3.28 into -16(3.28)^2 + 105(3.28) + 5 = 177.27
and you will get
Step-by-step explanation:
If using the method of completing the square to solve the quadratic equation x 2 − 9 x − 8 = 0 x 2 −9x−8=0, which number would have to be added to "complete the square"?
Answer:
Add 81/4 to both sides.
Step-by-step explanation:
x^2 − 9x − 8 = 0
x^2 - 9x = 8
Take the coefficient of the x term: -9
Divide by 2: -9/2
Square it: 81/4
Add 81/4 to both sides.
Which equation represents a slope of −4 and y-intercept of (0,2)?
y = −4x + 2
y = −2x
y = −2x − 4
y = 4x + 2
Answer:
y=-4x+2
Step-by-step explanation:
Hi there!
We want to find out which equation represents a line with a slope of -4 and a y intercept of (0,2)
The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
We have everything we need to plug into the equation, let's just label the values to avoid confusion
m=-4
b=2 (when you substitute the y intercept as b, b is the value of y in the point)
Now substitute into the equation
y=-4x+2
Hope this helps!
please help me fast!
9514 1404 393
Answer:
B) 40
Step-by-step explanation:
Vertical angle XZU has the same measure as the given angle, 130°. It is equal to the sum of right angle XZV and unknown angle UZV. So, ...
∠UZV +90° = 130°
∠UZV = 40° . . . . . . . . . subtract 90°
a person who take 40 paces to cover 20m finds that a square field has a side that is 520 paces long .calculate the length of the side and the area of the field
The area of the square field is 67600 m² and the side is 260 m long.
What is square?A quadrilateral with all sides equal and all angles are right angles.
Given that, a person takes 40 paces to cover 20 m of a square field according to him the field has a side that is 520 paces long, we need to find the measure of the side and the area,
Since,
40 paces = 20 m
1 pace = 1/2 m
Therefore,
520 paces = 0.5 x 520 m
= 260 m
Therefore, the square field is 260 m long,
Area of the square field = side² = 260²
= 67600 m²
Hence, the area of the square field is 67600 m² and the side is 260 m long.
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Given ADEF: ARST, find the scale factor
Answer:
the scale factor is 3/4
x = 16×3/4 = 12
Step-by-step explanation:
the only side length we have for both triangles is the short left side.
we see that we get ED from SR and need to transform 4 into 3. how do we do that ?
well,
4×f = 3
f = 3/4
that is the scaling factor, as all side lengths in EDF are created by multiplying the corresponding side in SRT by the same scaling factor (3/4).
therefore,
x = EF = ST×f = 16×3/4 = 4×3 = 12
Answer:
The scale factor is 4/3 and x is 12
Step-by-step explanation:
→ Divide RS by DE
4 ÷ 3 = 4/3
→ Divide the answer by 16
16 ÷ 4/3 = 12
Solve the following equation for
b
b. Be sure to take into account whether a letter is capitalized or not.
Answer:
b = h*D +hg^3
Step-by-step explanation:
b/h = D +g^3
Multiply each side by h
h* b/h = h*D +hg^3
b = h*D +hg^3
The formula for finding the area of a square that has a side length, s, is A= 52. If a square has an area of 40 square
units, what is the length of a side?
20
10/
2 /10
Answer:
2√10
Step-by-step explanation:
Given the following data;
Area of square = 40
Mathematically, the area of a square is calculated by using the formula;
Area, A = s²
Where;
s is the length of sides of a square.
Substituting into the formula, we have;
40 = s²
s = √40
s = √4 * √10
s = 2 * √10
s = 2√10
Aku has less than 3 times as many mangoes as Alaba and half as many mangoes as Amina if alaba has x mangoes the interns of x then how many mangoes do aku alaba and Amina have in combined
Answer:
I have no clue my bad bro.
The 3rd and 7th terms of an arithmetic progression are 6and 30 respectively determine the common difference, first term,10th term.
Answer:
d = 6 , a₁ = - 6 and a₁₀ = 48
Step-by-step explanation:
The nth term of an arithmetic progression is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₃ = 6 and a₇ = 30 , then
a₁ + 2d = 6 → (1)
a₁ + 6d = 30 → (2)
Subtract (2) from (1) term by term to eliminate a₁
4d = 24 ( divide both sides by 4 )
d = 6
Substitute d = 6 into (1)
a₁ + 2(6) = 6
a₁ + 12 = 6 ( subtract 12 from both sides )
a₁ = - 6
Then
a₁₀ = - 6 + (9 × 6) = - 6 + 54 = 48
----------------------------------------------------
Answer:
d=6
a=-6
Step-by-step explanation:
use the formula for the nth term which is
Tn=a+(n-1)d..you will have to create two equations then solve them as a simultaneous equation
T3=6 and T7=30
T3=a+(3-1)d
6=a+2d........... first equation
T7=a+(7-1)d
30=a+6d.......... second equation
then solve them as a simultaneous equation
a+2d=6
a+6d=30
-4d/-4=-24/-4
d=6
a+2d=6
a+2(6)=6
a=6-12
a=-6
I hope this helps
The table above shows the percent of the area of a town
devoted to three uses. If the area devoted to business use
is 7,200 acres less than the area devoted to residential
use, what is the area, in acres, devoted to government
use?
A) 1,400
B) 1,800
C) 5,200
D) 44,000
=========================================================
Explanation:
Let
r = area devoted to residential use
This variable is some positive real number, and it represents the area in acres.
Your teacher says that " the area devoted to business use is 7,200 acres less than the area devoted to residential use"
This means the expression r-7200 represents the area for business use
Note the jump from 25% to 65% is 65/25 = 2.6, meaning that we multiply by 2.6 when going from the business area to the residential area.
So we'll multiply by 2.6 to go from r-7200 to r
We'll have this equation
2.6(r-7200) = r
because it's effectively saying
2.6*(business area) = residential area
--------------------------
Let's isolate r
2.6(r-7200) = r
2.6r-2.6*7200 = r
2.6r - 18720 = r
2.6r - r = 18720
1.6r = 18720
r = 18720/(1.6)
r = 11700
We'll use 11700 acres for the residential portion.
And also r-7200 = 11700-7200 = 4500 acres are set aside for the business district.
--------------------------
The largest region (residential) uses 11700 acres of land.
Note the jump from 10% to 65% involves a multiplier of 6.5 because 65/10 = 6.5
So if g is the amount of government land used, then,
6.5g = r
6.5g = 11700
g = 11700/(6.5)
g = 1800
1800 acres of land are for government use
This is why the answer is choice B.
The area, in acres, devoted to government use is 1800.
Option (B) is correct.
To find the area.
What is percentage?Percentage, a relative value indicating hundredth parts of any quantity.
Given that:
Let
r = area devoted to residential use
This variable is some positive real number, and it represents the area in acres.
This means the expression r-7200 represents the area for business use
Note the jump from 25% to 65% is 65/25 = 2.6, meaning that we multiply by 2.6 when going from the business area to the residential area.
To multiply by 2.6 to go from r-7200 to r
The equation is
2.6(r-7200) = r
because it's effectively saying
2.6*(business area) = residential area
--------------------------
Let's isolate r
2.6(r-7200) = r
2.6r-2.6*7200 = r
2.6r - 18720 = r
2.6r - r = 18720
1.6r = 18720
r = 18720/(1.6)
r = 11700
We'll use 11700 acres for the residential portion.
And also r-7200 = 11700-7200 = 4500 acres are set aside for the business district.
The largest region (residential) uses 11700 acres of land.
Note the jump from 10% to 65% involves a multiplier of 6.5 because 65/10 = 6.5
So if g is the amount of government land used, then,
6.5g = r
6.5g = 11700
g = 11700/(6.5)
g = 1800
So, the area, in acres, devoted to government use is 1800.
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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math problems. Chapter 12 part 2 PLEASE SHOW WORK!!!
4a. a_n = 2(1/3 + a_n-1), a_1 = 4
4b. a_n= n/(a_n-1), a_1 = 6
4c. 1/6, 2/3, 8/3, . . .
Problem 4a
The instructions are incomplete. You set up the recursive formula, but didn't ask any question about said formula.
I'll assume that your teacher wants you to list out a few terms. I'll list out the first five terms.
The notation a_1 = 4 is the same as writing [tex]a_1 = 4[/tex] where the '1' is a subscript. It tells us that the first term is 4.
The nth term a_n or [tex]a_n[/tex] is defined as such
[tex]a_n = 2*(1/3 + a_{n-1})\\\\[/tex]
Notice how if we replaced n with 2, then we get
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_2 = 2*(1/3 + a_{2-1})\\\\a_2 = 2*(1/3 + a_1)\\\\[/tex]
So the second term is directly tied to the first term, or it is dependent on it.
We'll replace a_1 with 4 to get the following
[tex]a_2 = 2*(1/3 + a_1)\\\\a_2 = 2*(1/3 + 4)\\\\a_2 = 2*(1/3 + 12/3)\\\\a_2 = 2*(13/3)\\\\a_2 = 26/3\\\\[/tex]
So the second term is 26/3.
As you can guess, the third term is going to be found in a similar fashion
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_3 = 2*(1/3 + a_{3-1})\\\\a_3 = 2*(1/3 + a_2)\\\\a_3 = 2*(1/3 + 26/3)\\\\a_3 = 2*(27/3)\\\\a_3 = 2*(9)\\\\a_3 = 18\\\\[/tex]
So 18 is the third term.
We'll repeat for n = 4 to get the fourth term.
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_4 = 2*(1/3 + a_{4-1})\\\\a_4 = 2*(1/3 + a_3)\\\\a_4 = 2*(1/3 + 18)\\\\a_4 = 2*(1/3 + 54/3)\\\\a_4 = 2*(55/3)\\\\a_4 = 110/3\\\\[/tex]
The fourth term is 110/3.
Lastly, we'll plug in n = 5
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_5 = 2*(1/3 + a_{5-1})\\\\a_5 = 2*(1/3 + a_4)\\\\a_5 = 2*(1/3 + 110/3)\\\\a_5 = 2*(111/3)\\\\a_5 = 2*(37)\\\\a_5 = 74\\\\[/tex]
The fifth term is 74.
Answer: The first five terms are 4, 26/3, 18, 110/3, 74==============================================================
Problem 4b
Again, the instructions are missing. I'll assume the same thing as problem 4a.
[tex]a_1 = 6[/tex] is the first term
Plug n = 2 into the first equation to get
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_2 = \frac{2}{a_{2-1}}\\\\a_2 = \frac{2}{a_{1}}\\\\a_2 = \frac{2}{6}\\\\a_2 = \frac{1}{3}\\\\[/tex]
The second term is 1/3.
Repeat for n = 3
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_3 = \frac{3}{a_{3-1}}\\\\a_3 = \frac{3}{a_{2}}\\\\a_3 = \frac{3}{1/3}\\\\a_3 = 3\div\frac{1}{3}\\\\a_3 = 3\times\frac{3}{1}\\\\a_3 = 9\\\\[/tex]
The third term is 9
Repeat for n = 4.
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_4 = \frac{4}{a_{4-1}}\\\\a_4 = \frac{4}{a_{3}}\\\\a_4 = \frac{4}{9}\\\\[/tex]
The fourth term is 4/9
Repeat for n = 5
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_5 = \frac{5}{a_{5-1}}\\\\a_5 = \frac{5}{a_{4}}\\\\a_5 = 5 \div a_{4}\\\\a_5 = 5 \div \frac{4}{9}\\\\a_5 = 5 \times \frac{9}{4}\\\\a_5 = \frac{5}{1} \times \frac{9}{4}\\\\a_5 = \frac{5*9}{1*4}\\\\a_5 = \frac{45}{4}\\\\[/tex]
Answer: The first five terms are 6, 1/3, 9, 4/9, 45/4==============================================================
Problem 4c
I'm not much help here for this problem. Not only are the instructions missing, but it's not clear how this sequence is set up. If I had to guess, it's somehow recursively defined. How exactly, I'm not sure. I would ask your teacher for any clarification.
6x/x+6
Find all real numbers for which the rational expression is undefined.
Answer:
x=-6
Step-by-step explanation:
For the rational expression, 6x/(x+6) to be undefined, the denominator need to be 0, so x=-6 is the point at which the function is undefined.
The rational expression 6x / (x + 6) is undefined when x equals -6, and it is defined for all other real numbers.
To find the real numbers for which the rational expression 6x / (x + 6) is undefined, we need to identify the values of x that would make the denominator equal to zero. When the denominator is zero, the expression becomes undefined.
In this case, the denominator is (x + 6). Setting the denominator equal to zero, we have:
x + 6 = 0
Solving for x, we subtract 6 from both sides:
x = -6
Therefore, the rational expression 6x / (x + 6) is undefined when x = -6.
When x is equal to -6, the denominator becomes zero, which causes division by zero. Division by zero is undefined in mathematics. Hence, for x = -6, the rational expression is not defined.
For any other real numbers other than x = -6, the expression is defined and can be simplified or evaluated.
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Emma spent 4 and one-half days planting her garden. Her brother spent 2 Over 9 as much time as Emma did. How many days did her brother spend planting his garden?
Answer: 1 day
Step-by-step explanation:
i took the test lol...
2/c = 4/9
(these are fractions btw)
Answer:
2/9
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Geometry work due tonight worth 50 points!!!!
Answer:
75
Step-by-step explanation:
All of the angles within the triangle must add up to 180 degrees. So, angle 2 =50
The angles 4,2,5 also equal 180 because they are on the blue line. Since angle 2=50 and angle 5= 55 angle 4 must be 75 which is needed to add up to 180.
Answer:
Angle 4 is 75°
b represent angle 2
d represent angle 4
70+60+b=180
130+b=180
b=50
55+50+d=180
105+d=180
d=75
prove it using mathematical induction
Answer:
Mathematical induction can be used to prove that an identity is valid for all integers n≥1. Here is a typical example of such an identity: 1+2+3+⋯+n=n(n+1)2. More generally, we can use mathematical induction to prove that a propositional function P(n) is true for all integers n≥1.
Step-by-step explanation:
I'd really appreciate a brainleast please:)
Margaret drives 188 miles
with 8 gallons of gas. Find the unit rate
The unit rate will be "23.5 miles/gallon". In the below segment, a further solution to the given question is provided.
Given values in the question are:
Total distance,
= 188 miles
Total gas used,
= 8
Now,
⇒ The rate of gas consumption will be:
= [tex]\frac{Total \ distance}{Total \ gas \ used}[/tex]
By putting the given values in the above formula, we get
= [tex]\frac{188}{8}[/tex]
= [tex]23.5 \ miles/gallon[/tex]
Thus the above is the appropriate solution.
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The point (7, 8) is the solution of which of the following systems of equations?
1. 8x - y = 48
9x + 10y = 142
2. 9x - y = 55
8x + 10y = 140
3. x-6y=-41
8x + 9y = 127
4. x-7y=-49
10x + 9y = 142
Option 4
Verification:-
[tex]\\ \sf\longmapsto x-7y=-49[/tex]
[tex]\\ \sf\longmapsto 7-7(8)=-49[/tex]
[tex]\\ \sf\longmapsto 7-56=-49[/tex]
[tex]\\ \sf\longmapsto -49=-49[/tex]
And
[tex]\\ \sf\longmapsto 10x+9y=142[/tex]
[tex]\\ \sf\longmapsto 10(7)+9(8)=142[/tex]
[tex]\\ \sf\longmapsto 70+72=142[/tex]
[tex]\\ \sf\longmapsto 142+142[/tex]
Hence verified
Answer:
4.
Step-by-step explanation:
1. 8x - y = 48
9x + 10y = 142
8(7) - 8 = 48
9(7) + 10(8) = 143
No
2. 9x - y = 55
8x + 10y = 140
9(7) - 8 = 55
9(7) - 10(7) = -24
No
3. x-6y=-41
8x + 9y = 127
7 - 6(8) = -41
8(7) + 9(8) = 128
No
4. x-7y=-49
10x + 9y = 142
7 - 7(8) = 49
10(7) + 9(8) = 142
Yes
What ordered pairs are the solutions of the system of equations shown in the graph below?
The solutions are where the two lines cross over each other.
(0,3) and (4,-5)
What is the phase of y= -3cos (3x-pi) +5
Answer:
[tex]- \frac{\pi}{3}[/tex]
Step-by-step explanation:
Given
[tex]y = -3\cos(3x - \pi) + 5[/tex]
Required
The phase
We have:
[tex]y = -3\cos(3x - \pi) + 5[/tex]
Rewrite as:
[tex]y = -3\cos(3(x - \frac{\pi}{3})) + 5[/tex]
A cosine function is represented as:
[tex]y = A\cos(B(x + C)) + D[/tex]
Where:
[tex]C \to[/tex] Phase
By comparison:
[tex]C = - \frac{\pi}{3}[/tex]
Hence, the phase is: [tex]- \frac{\pi}{3}[/tex]
A line contains the points (4, 5) and (3,-9). Write the equation of the line using slope-intercept form. A. y=-2x - 3 B. y = 2x – 15 C. 1 yax +3 2 1 V= -X-7 2
Answer:
Y =-4X +21
Step-by-step explanation:
x1 y1 x2 y2
4 5 3 9
(Y2-Y1) (9)-(5)= 4 ΔY 4
(X2-X1) (3)-(4)= -1 ΔX -1
slope= -4
B= 21
Y =-4X +21
Find the area of the triangle with the given
Answer:
616.2442
area to the nearest whole number=616
Step-by-step explanation:
using formula 1/2absinx
where a =44,b=29 ,x=105
1/2x44x29xsin105
44x29=1276
1276÷2=638
638 x sin 105
the sin of 105 is 0.9659
if u are using a four figure table where u can't find 105 under sin of angle
u simply subtract 105 from 180=75
638 x 0.9659 =616.2442
approx.616
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!
Find the 5th term for the following recursive formulas/sequences. SHOW YOUR WORK!!
c. 1/6, 2/3, 8/3, . . .
Answer:
128/3
Step-by-step explanation:
The sequence follow the rule (1/6)*(4)^(n-1). The 5th term will be (1/6)*(4)^4=128/3
Answer:
128/3
Step-by-step explanation:
1/6, 2/3, 8/3, . . .
1/6, 4/6, 16/6
We are multiplying by 4 each time
1/6 *4 = 4/6
4/6 * 4 = 16/6
This is a geometric sequence with the common ratio of 4
an = a1 (r)^(n-1)
an = 1/6 (4) ^(n-1)
Let n = 5
a5 = 1/6 (4)^(5-1)
a5 = 1/6 (4)^4
a5 = 1/6 * 256
a5 =128/3
find three numbers in dip, such that their sum is 60 and the last one is three times the first
30,20 and 10
30 + 20 + 1/3×30 = 60
50 + 10 = 60
60 = 60
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If the statement is true, type true in the space provided. If it is false, replace the underlined
word(s) with the word(s) that will make the statement true.
* The associative (associative is underlined) property is used on the following expression: 2 + 3 = 3 + 2.
144 is the same as 379 less than c
How can this be wrote in a equation
Answer:
144 = c - 379
Step-by-step explanation:
"144 is the same as 379 less than c"
144 = c - 379
Answer and Step-by-step explanation:
This can be written in an equation like this:
144 = c - 379
The question is saying that 144 is the same answer as the result of 379 less than c (or c minus 379). This is why we equal 144 to the result of c minus 379.
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