Answer:
200
Step-by-step explanation:
I think sorry if I am wrong
help me please !!!!
Answer:
graph X only
Step-by-step explanation:
because with the rate of change it makes a straight line
How many solutions can be found for the system of linear equations represented on the graph?
A) no solution
B) one solution
C) two solutions
D) infinitely many solutions
Answer:
A) No solution
Step-by-step explanation:
Given the systems of linear equations, y = 2x + 1 and y = 2x - 1:
Both equations in the system have the same slope, m = 2, thus forming parallel lines. Since their lines are parallel from each other, then it means that their lines will never intersect.
Therefore, the given systems of linear equation is an inconsistent system that has no solution.
FInd the value of T - triangle measerments
JK=JH
[tex]\\ \sf\longmapsto 10t=7t+15[/tex]
[tex]\\ \sf\longmapsto 10t-7t=15[/tex]
[tex]\\ \sf\longmapsto 3t=15[/tex]
[tex]\\ \sf\longmapsto t=15/3=5[/tex]
hi please help me with part b and can you see if i did a correctly pls?
a is right its 58
and in my opinion i think b would be 58*5=290 cents, since nickel is worth 5 cents.
but gotta check other people's answers
What is the equation of the line in slope-intercept form?
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Answer:
[tex]y=-\frac{1}{4}x\\[/tex]
Step-by-step explanation:
The slope is calculated by "up ÷ across".
= -1 ÷ 4
= [tex]-\frac{1}{4}[/tex]
The y-intercept is just 0 (because the line meets at the y axis at 0).
So, using [tex]y=mx+b[/tex] (where m = slope and b = y-intercept),
[tex]y=-\frac{1}{4}x+0[/tex]
but the '+0' is unnecessary so we just say [tex]y=-\frac{1}{4}x[/tex]
Please help. ASAP. Work out, giving your answer in its simplest form:
3 1/2 divided by 2 3/5
Answer:
26/35
Step-by-step explanation:
1. First to divide the 3 1/2 by 2 3/5 you have to turn them both into improper fractions
First take 3 1/2. You have to multiply the whole number (3) by the denominator (2) and you would get 6. Then you would add then you add the product (6) to the numerator (1) and get 7.
You keep the denominator the same so the improper fraction is 7/2
Do the same thing to 2 3/5 and the improper fraction is 13/5
2. Now we can divide 13/5 by 7/2 using "keep, change, flip"
Keep: 13/5
Change: division to multiplcation
Flip: 7/2 to make 2/7
Your new equation is 13/5 × 2/7. Multiplcation is easy so you just have to multiply staight across: 13 × 2 and 5 × 7 giving you 26/35
If you divide 35 by 26 you will get 1.34 and a bunch of other numbers but I usually stop at two decimal places
hope this helps :)
I'm timed! can someone please help me solve this problem..
Answer:
C
Step-by-step explanation:
The circumference of a circle is 14.444 miles. What is the circle's diameter?
Answer:
2.29883
formula
[tex]c = 2 \times \pi \times r[/tex]
solving for (r) radius
[tex]r = \frac{c}{2\pi} = \frac{14.44}{2 \times \pi} [/tex]
= 2.29883
How many 2 digit numbers have unit digit 6 but are not perfect squares
9514 1404 393
Answer:
7
Step-by-step explanation:
Of the 9 2-digit numbers ending in 6, only 2 are perfect squares: 16 and 36. The other 7 are not perfect squares.
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
Write a linear inequality for each graph (back page)
Answer:
I can't read that...........
Help with this problem pls!
Answer:
uh.. shii i dont know
Step-by-step explanation:
PRETTY PLS HELP ME JUST 2 MORE QUESTIONS PLS 50 POINTS
Answer:
I think that you should take your time and answer, every one can help you
Step-by-step explanation:
Step-by-step explanation:
ok give question and intro new sis
can someone help
me on one of these please!
3 t-shirts cost £25.95.
How much do 10 t-shirts cost?

Answer:
£86.50
Step-by-step explanation:
To find how much 10 t-shirts cost we have to find how much they cost individually.
3 T- Shirts / 25.95 = 8.65 which means that each T-Shirt Costs 8.65.
8.65 x 10 T-Shirts = £86.50
Today everything at a store is on sale the store offers a 20
% discount the regualr price of a t shirt is 18 what is the discount price
Answer:
$14.40 is the discount price.
Step-by-step explanation:
0.2 x 18 = 3.6
18 - 3.6 = 14.4
Simplify the linear expression.
−2/3a+1/8−1/6a−3/4
Enter your answer as simplified fractions in the boxes.
Answer:
-5/6a - 5/8
Step-by-step explanation:
i took the k12 quiz
What is the period of y=2cos(3x-2(3.14))?
A. 3(3.14)
B. 6(3.14)
C. 3(3.14)-2
D. 3(3.14)/3
Answer:
the correct answer is B
Step-by-step explanation:
I got it correct on 2021 edge
Identify the similar triangles.
ΔHFE=
ΔHFE=
∆HFE is similar to ∆HFG and ∆ HEG (they all are right triangles and have the same, shape.)
The given triangle ΔHFE is similar to triangle GFH and triangle GHE.
What are similar triangles?Similar triangles are two triangles that have the same shape but may differ in size. They have corresponding angles that are congruent and corresponding sides that are proportional.
Here,
Since triangle HFE is similar to triangle GFH,
∠HEF = ∠GHF,
∠FHE = ∠HGF, and ∠HFE = ∠HFG
Similarly
ΔHFE is similar to triangle ΔGHE.
Similar triangles are useful in many areas of mathematics and in the real world, such as in architecture, engineering, and cartography, where they are used to make scale models of buildings and other structures.
Thus, the given triangle ΔHFE is similar to triangle GFH and triangle GHE.
Learn more about similar triangles here:
https://brainly.com/question/12101336
#SPJ2
if 5/6 of the 30 motorcycles were new, how many motorcycles were used
Answer:
5 Motorcycles are used
30÷6= 5
5×5= 25
30-24=5
so the answer is 5
Answer:
5 out of the 30 motorcycles are used
Step-by-step explanation:
First, we should look at what we know. We know that there are 30 motorcycles in total. As a fraction, that'd be 30/30. We also know that of that 30, the equivalent of 5/6 are brand new.
Our next step is to figure out how much 5/6 is out of 30. Since we know that in total there 30/30 motorcycles, we need to convert 5/6 to have a denominator of 30. So what times 6 equals 30.
30 ÷ 6 = ? opposite of 6 x ? = 30
5 divide
So now we now that 6 times 5 equals 30. What we do to the denominator we must do to the numerator.
[tex]\frac{5}{6}[/tex] × [tex]\frac{5}{5}[/tex]
[tex]\frac{25}{30}[/tex]
Now we know that 25 of the 30 motorcycles are new and all we need to do is subtract that 25 from the total 30 to get 5. This tells us that 5 of the total motorcycles are used.
I hope this helped :)
