15
Select the correct answer.
If A and B are dependent events, which of these conditions must be true?
O A.
P(A and B) = P(A) + P(B)
OB.
P(A and B)
P(A)
P(B)
Oc.
P(B|A) = P(B)
D.
P(AB) = P(A)
O E
P(BA) + P(B)
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Answer:

8 hours

Step-by-step explanation:

simple, divide 536 miles by 804 miles and multiply the fraction with 12 hours

fraction = 0.6666666 or 536/804 OR two thirds or 2/3

multiply 2/3 by 12 hours

it would take approximately 8 hours to arrive at 536 miles

Answer:

ED = 31

DT = 20

Step-by-step explanation:

m< ESD = 90-52=38°

the distance ED = 40×tan 38° = 31.25 = 31

ET = 40 x tan (90-38) = 40×tan 52°

= 51.19= 51

the distance DT = 51-31 = 20

Answer:

$5900

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Simple Interest Rate Formula: A = P(1 + rt)

Step-by-step explanation:

Step 1: Define

Identify variables

P = 5000

r = 3% = 0.03

t = 6

Step 2: Find Interest

Answer:

C. [tex]\frac{}{AB}[/tex]

Step-by-step explanation:

You can solve this in two ways, firstly by eliminating all the wrong answers, and secondly by just knowing that the horizontal line in [tex]_[/tex][tex]\frac{}{AB}[/tex] means that we are talking about a line.

This is how we solve this question by using the eliminating process.

(A. ∠C) is not the right answer because the ∠ sign lets us know that this answer represents an angle, not a line

(B. B) is not the right answer because it represent a point, not a line (in math we use a singular capital letter to represent points)

(D. ΔABC) is not the right answer because the Δ sign lets us know that the answer represents a triangle, not a line.

Therefore, the only option left is C. [tex]\frac{}{AB}[/tex]

Answer:

Timmy's tubes = 11.25$

Fred's floats = 11.375$

Step-by-step explanation:

For Timmy's tubes

We use unitary method to solve

For 2 1/2 hours, it charges $18.75

So, for 1 1/2 hours it charges $11.25

Similarly for Fred's floats

Base fee = $2

Fee per hour = $6.25

So, for 1 1/2 hour fee = 2 + 6.25 + 3.125 = $11.375

So, Terry should choose Timmy's tubes

well, let's see, what do we know about Timmy's Tubes, is a direct variation equation, since he's charging depending on the hours it's rented, thus

[tex]\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\stackrel{\textit{\underline{c}ost varying with \underline{h}ours}}{c = kh}\qquad \textit{we know that } \begin{cases} c=18.75\to \frac{75}{4}\\ h=1\frac{1}{2}\to ~\hfill \frac{5}{2} \end{cases} \\\\\\ \stackrel{cost}{\cfrac{75}{4}}=\stackrel{hours}{\cfrac{5}{2}h}\implies 2\cdot 75=4\cdot 5h\implies 150=20h\implies \cfrac{150}{20}=h\implies \cfrac{15}{2}=h \\\\\\ therefore\qquad c=\cfrac{15}{2}h\impliedby \textit{Timmy's rate}[/tex]

now, Fred charges $2 flat right off, plus $6.25 for every added hour, so Fred's equation will more or less be

1 hour 2 + 6.25(1)

2 hours 2 + 6.25(2)

3 hours 2 + 6.25(3)

1)

how much will Timmy charge for 1 1/2 hour?

[tex]c = \cfrac{15}{2}\cdot \stackrel{h}{1\frac{1}{2}}\implies c = \cfrac{15}{2}\cdot \stackrel{h}{\cfrac{3}{2}}\implies c = \cfrac{15}{4}[/tex]   or just 3.75

how much will Fred charge for the same time?

[tex]c=2+6.25\left( \frac{3}{2} \right)\implies c=9.375[/tex]

2)

using only $12 for each, who is the better bargain?

[tex]\stackrel{\textit{Timmy's}}{c = \cfrac{15}{2}h}\implies 12=\cfrac{15h}{2}\implies 24=15h\implies \cfrac{24}{15}=h\implies \boxed{1.6=h} \\\\\\ \stackrel{\textit{Fred's}}{c = 2 + 6.25h}\implies 12=2+6.25h\implies 10=6.25h \\\\\\ \cfrac{10}{6.25}=h\implies \boxed{ 1.6=h}[/tex]

well, let's notice, Terri is going to get the same amount of hours with either, so, it really doesn't matter, both will only give 1.6 hours, or 1 hour and 36 minutes.

Answer:

The amount of money one may spend in a month may be greater than that of ones monthly payment especially when the payment is at a lower rate.

Answer:

x=28

y=v7vub8b9nf7v6v

Answer:

T = k * (A/W)

Step-by-step explanation:

Answer:

the last one is correct.............

Answer:

Step-by-step explanation:

a)

The mean for ground floor is 20.67

The mean for balcony is 15.8

b)

the difference between the means is ground floor - balcony

20.67 - 15.8 = 4.87

You can talk about it yourself for part c

Answer: 135 minutes or 2 hours and 15 minutes  

Step-by-step explanation:

4/18 = 30/ x

Solve for duh 'x'

9514 1404 393

Answer:

  160 cm³

Step-by-step explanation:

The ratio of the linear dimensions is the square root of the ratio of areas:

  scale factor B/A= √(64/144) = 8/12 = 2/3

The ratio of volumes is the cube of the scale factor:

  (volume B)/(volume A) = (2/3)³ = 8/27

Then the volume of pyramid B is ...

  volume B = (volume A) × (volume B)/(volume A)

  = (540 cm³) × (8/27) = 160 cm³ . . . . volume of pyramid B

_____

Equivalently, the ratio of volumes is the 3/2 power of the ratio of areas.

 Vb = Va(64/144)^(3/2) = (540 cm³)(4/9)^(3/2) = (540)(8/27) cm³ = 160 cm³

Answer:

-5 is the answer

Step-by-step explanation:

Answer:

-5 corresponds to the coldest temperature here.

Step-by-step explanation:

-5 is to the left of -1 on a number line and is therefore smaller than -1.

Answer:

if you assume one box as 1 m^2

then area of the shape is 54 m^2

but i am not sure if this is correct answer

Answer:

60m^2 is the answer im pretty sure

Step-by-step explanation:

yeah man thats it

Answer:

The relationship between the above two triangles is SAS and they are congruent

9514 1404 393

Answer:

  x = 142

Step-by-step explanation:

You want to find x such that ...

  [tex]\sqrt{x+2} -15=-3\qquad\text{given}\\\\\sqrt{x+2} =12\qquad\text{add 15}\\\\x+2=144\qquad\text{square both sides}\\\\\boxed{x=142}\qquad\text{subtract 2 to get x by itself}[/tex]

Answer:

a

Step-by-step explanation:

Answer:

A plane figure with 4 sides is called a quadrilateral.

Step-by-step explanation:

A plane figure bounded by more than four straight lines is generally referred to as a polygon. A polygon is a closed two-dimensional shape formed by connecting multiple line segments. The line segments, also known as sides, should intersect only at their endpoints, forming vertices of the polygon.

Polygons can have various numbers of sides, and their names are typically based on the number of sides they possess. Some common examples include triangles (3 sides), quadrilaterals (4 sides), pentagons (5 sides), hexagons (6 sides), and so on.

However, when the statement specifies that the plane figure is bounded by "more than four" straight lines, it suggests that the figure in question is a polygon with more than four sides. The exact name or classification of the polygon would depend on the specific number of sides it possesses.

To know more about plane figure . here

https://brainly.com/question/29797834

#SPJ2

Answer:

w ≈ 21.053 inches

l ≈ 28.353 inches

Step-by-step explanation:

Answer:

The smaller number is 4√2 and the larger number is (4√2 + 1).

Step-by-step explanation:

Let the two numbers be x and y, where y is the larger of the two numbers.

Since y is the larger number, it is one more than the smaller number. So:

[tex]y=x+1[/tex]

When negative two times the smaller is added to the square of the larger, the result is 33. In other words:

[tex]-2x+y^2=33[/tex]

Substitute:

[tex]-2x+(x+1)^2=33[/tex]

Solve for x. Square:

[tex]-2x+(x^2+2x+1)=33[/tex]

Simplify:

[tex]x^2+1=33[/tex]

Subtract one from both sides:

[tex]x^2=32[/tex]

And take the square root of both sides:

[tex]x=\pm\sqrt{32}=\pm 4\sqrt{2}[/tex]

Since y is positive, we can ignore the negative case. So, the smaller number is:

[tex]x=4\sqrt{2}\approx5.66[/tex]

And the larger number is:

[tex]y = 4\sqrt{2} + 1 \approx6.66[/tex]

Answer:

.101501615

.84982392

.901244701

Step-by-step explanation:

For this question use a binomial distribtuion

a.

12C3*.44³*(1-.44)⁹= .101501615

b.

to find at least 4 find the probability of less than 4 and take its compliment

12C0*(1-.44)¹²+12C1*.44*(1-.44)¹¹+12C2*.44²*(1-.44)¹⁰+12C3*.44³*(1-.44)⁹= .15017608

1-.15017608=.84982392

c.

To find less than eight's probability find the proability of at least 8 and take its compliment

12C8*.44⁸(1-.44)⁴+12C9*.44⁹(1-.44)³+12C10*.44¹⁰(1-.44)²+12C11*.44¹¹*(1-.44)+12C12*.44¹²= .098755299

1-.098755299= .901244701

Answer: domain: ARN

Range: y less than or equal to 0

Step-by-step explanation:

The arrows indicate that the lines continue forever, so the domain is all real numbers.

The lines only travel under the x-axis, so the range is y less than or equal to zero.

Answer:

?????????????????????????

Answer:

well,

it's more than (20ft)²

bc 20*20 =400

21² = 21 * 21 = 441

getting closer...

22² = 22 * 22 = 484

[tex] \sqrt{484} = {22}^{2} [/tex]

yet, we arrived, short trip tough, pls leave the bus in an orderly manner

Answer:

m<F = 95°

Step-by-step explanation:

We'll begin by calculating the value of x. This can be obtained as follow:

m<C = 50

m<A = (10x – 5)

m<B = m<G = (2x + 15)

m<C + m<A + m<B = 180 (Sum of angles in a triangle)

50 + (10x – 5) + (2x + 15) = 180

50 + 10x – 5 + 2x + 15 = 180

50 – 5 + 15 + 10x + 2x = 180

60 + 12x = 180

Collect like terms

12x = 180 – 60

12x = 120

Divide both side by 12

x = 120 / 12

x = 10

Finally, we shall determine the value of m<F. This can be obtained as follow:

m<F = m<A

But

m<A = 10x – 5

x = 10

Therefore,

m<F = 10x – 5

m<F = 10(10) – 5

m<F = 100 – 5

m<F = 95°

Answer:

this is a linear equation. whatever value you set for x, you substitute and make a table that would probably look like this.

      x      |     y

-------------|-----------

5            | 17/3       <------- what would y be if x is 5?

3             | 5                     lets substitute x with 5

               |                          y=1/3*5+4

               |                         y=5/3+4

               |                        y=17/3

Answer:

[tex]2x^2y\sqrt[3]{7xy^2}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt[3]{56x^7y^5}[/tex]

Required

Solve

Expand

[tex]\sqrt[3]{8*7*x^6*x*y^3*y^2}[/tex]

Rewrite as:

[tex]\sqrt[3]{8*x^6*y^3*7*x*y^2}[/tex]

Split

[tex]\sqrt[3]{8*x^6*y^3} *\sqrt[3]{7*x*y^2}[/tex]

Express 8 as 2^3

[tex]\sqrt[3]{2^3*x^6*y^3} *\sqrt[3]{7*x*y^2}[/tex]

Apply law of indices

[tex]2^{(3/3)}*x^{(6/3)}*y^{(3/3)} *\sqrt[3]{7*x*y^2}[/tex]

[tex]2*x^2*y *\sqrt[3]{7*x*y^2}[/tex]

[tex]2x^2y *\sqrt[3]{7xy^2}[/tex]

[tex]2x^2y\sqrt[3]{7xy^2}[/tex]