[15-(|-6+2|+ squareroot9)]^2
can anyone explain the steps for how to solve it too? i’m confused :(

Answer:

d= 3h-6

Step-by-step explanation:

h= d/3+2

h-2= d/3

d= 3(h-2)= 3h-6

Answer:

d = 3h - 6

Step-by-step explanation:

[tex]h = \frac{d}{3} + 2[/tex]

subtract 2 on all sides :

[tex](h) - 2 = (\frac{d}{3} + 2) - 2 \\ \\ h - 2 = \frac{d}{3} [/tex]

multiply 3 on all sides:

[tex](h - 2) \times 3= \frac{d}{3} \times 3 \\ \\ 3(h - 2) = d[/tex]

open bracket:

[tex]d = 3h - 6[/tex]

Answer:

9 miles

Step-by-step explanation:

I have to ask here too: are you sure you have this description right ? because cm and miles are usually not used in combination.

but fine.

1 cm <-> 4.5 miles

2 cm <-> ? miles

remember questions like "if 1 apple costs $1.10, how much are 2 apples or 5 or 10 apples ?"

you remember what you had to do ?

pretty common sense : you multiplied the price by the same number that you multiplied the unit count number with. so, in my example, by 2, by 5 and by 10. and you got $2.20, $5.50 and $11.00 as prices.

so, what do you think we need to do to calculate the miles that are residents by 2 cm on the map ?

right ! we need to multiply by 2 - because 2×1 = 2.

so, 4.5 × 2 = 9 miles

yes, if 1 cm on the map stands for 4.5 actual miles, then 2 cm stand for 2×4.5 = 9 actual miles.

Answer:

Hence, total surface area of the pyramid is 360 cm².

Step-by-step explanation:

We first calculate slant height L of the pyramid with base s=10 cm and height 12 cm:

L²=H²+(s/2)²=122+(10/2)²=122+5²

=144+25=169⇒

L=(169)^1/2=13

The perimeter of the base is P=4s, since it is a square, therefore, 

P=4×10=40 cm

The general formula for the lateral surface area of a regular pyramid is LSA=1/2Pl where P represents the perimeter of the base and l is the slant height.

Since the perimeter of the pyramid is P=40 cm and the slant height is l=13 cm, therefore, the lateral surface area is:

LSA=1/2Pl=1/2×40×13=260 cm²

Now, the area of the base B=s² with s=10 cm is:

B=s²=10²=100 cm²

The general formula for the total surface area of a regular pyramid is TSA=1/2Pl+B where P represents the perimeter of the base, l is the slant height and B is the area of the base.

Since LSA=1/2Pl=260 cm² and area of the base is B=100 cm², therefore, the total surface area is:

TSA=1/2Pl+B=260+100=360 cm²

Hence, total surface area of the pyramid is 360 cm².

Answer:

Yes, the table represents a function.

Step-by-step explanation:

A function doesn't have multiple x values (inputs).

If the table were to have more than one 5 (or more than one 4 etc.) in the input column then it would not be a function.

Answer:

please give me brilliant answer

Boundless Algebra

Quadratic Functions and Factoring

Graphs of Quadratic Functions

Parts of a Parabola

The graph of a quadratic function is a parabola, and its parts provide valuable information about the function.

LEARNING OBJECTIVES

Describe the parts and features of parabolas

KEY TAKEAWAYS

Key Points

The graph of a quadratic function is a U-shaped curve called a parabola.

The sign on the coefficient aa of the quadratic function affects whether the graph opens up or down. If a<0a<0, the graph makes a frown (opens down) and if a>0a>0 then the graph makes a smile (opens up).

The extreme point ( maximum or minimum ) of a parabola is called the vertex, and the axis of symmetry is a vertical line that passes through the vertex.

The x-intercepts are the points at which the parabola crosses the x-axis. If they exist, the x-intercepts represent the zeros, or roots, of the quadratic function.

Key Terms

vertex: The point at which a parabola changes direction, corresponding to the minimum or maximum value of the quadratic function.

axis of symmetry: A vertical line drawn through the vertex of a parabola around which the parabola is symmetric.

zeros: In a given function, the values of xx at which y=0y=0, also called roots.

Recall that a quadratic function has the form

f(x)=ax2+bx+cf(x)=ax2+bx+c.

where aa, bb, and cc are constants, and a≠0a≠0.

The graph of a quadratic function is a U-shaped curve called a parabola.  This shape is shown below.



Parabola : The graph of a quadratic function is a parabola.

In graphs of quadratic functions, the sign on the coefficient aa affects whether the graph opens up or down. If a<0a<0, the graph makes a frown (opens down) and if a>0a>0 then the graph makes a smile (opens up). This is shown below.



Direction of Parabolas: The sign on the coefficient aa determines the direction of the parabola.

Features of Parabolas

Parabolas have several recognizable features that characterize their shape and placement on the Cartesian plane.

Vertex

One important feature of the parabola is that it has an extreme point, called the vertex. If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function. If the parabola opens down, the vertex represents the highest point on the graph, or the maximum value. In either case, the vertex is a turning point on the graph.

Axis of Symmetry

Parabolas also have an axis of symmetry, which is parallel to the y-axis. The axis of symmetry is a vertical line drawn through the vertex.

yy-intercept

The y-intercept is the point at which the parabola crosses the y-axis. There cannot be more than one such point, for the graph of a quadratic function. If there were, the curve would not be a function, as there would be two yy values for one xx value, at zero.

xx-intercepts

The x-intercepts are the points at which the parabola crosses the x-axis. If they exist, the x-intercepts represent the zeros, or roots, of the quadratic function, the values of xx at which y=0y=0. There may be zero, one, or two xx-intercepts. The number of xx-intercepts varies depending upon the location of the graph (see the diagram below).



Possible xx-intercepts: A parabola can have no x-intercepts, one x-intercept, or two x-intercepts

Recall that if the quadratic function is set equal to zero, then the result is a quadratic equation. The solutions to the equation are called the roots of the function. These are the same roots that are observable as the xx-intercepts of the parabola.

Notice that, for parabolas with two xx-intercepts, the vertex always falls between the roots. Due to the fact that parabolas are symmetric, the 

Answer:

-1, 0, 1, 2, 3

Step-by-step explanation:

Los números son mayores a medida que se mueven hacia la izquierda de la recta numérica, por lo que retrocederá desde -2

Answer:

Step-by-step explanation:

Answer:

7.3

Step-by-step explanation:

The length of AB is found using the distance formula

We need to know the coordinates of A and B

A = (-5,-4) and B = (-3,3)

The distance is

d = sqrt ( (y2-y1)^2 + (x2-x1)^2)

   = sqrt( (3 - -4)^2 +(-3 - -5)^2)

   = sqrt( (3+4)^2 +(-3+5)^2)

   = sqrt(7^2+2^2)

   = sqrt(49+4)

  = sqrt(53)

  =7.280109889

To the nearest hundredth

 =7.3

Answer:

x = 3

13 miles between Madison and Jamie's house.

Step-by-step explanation:

If we add the distance between Anoa's and Madison's house with the distance between Jamie's and Madison's house, then we get the total distance between Anoa's and Jamie's house.

(3x + 2) + (3x + 4) = 9x - 3

Let's add up the terms first

3x + 2 + 3x + 4 = 9x - 3

6x + 6 = 9x - 3

Let's move the variables to the right side by subtract 6x from both sides

6x + 6 = 9x - 3

-6x         -6x

6 = 3x - 3

Add 3 to both sides

6 = 3x - 3

+3        +3

9 = 3x

Isolate the variable, x, by dividing both sides by the coefficient, 3.

9/3 = 3x/3

x = 3

Now we need to find the distance between Madison's and Jamie's house.

3x + 4

Plug in 3 in place of the x

3(3) + 4

9 + 4 = 13

Answer:

Step-by-step explanation:

If we add the distance between Anoa's and Madison's house with the distance between Jamie's and Madison's house,then we get the total distance between anoa's and Jamie's house.

Answer: 2 pens and 4 pencils.

Step-by-step explanation:

If you buy 2 pens it is equal to $2.

If you buy 4 pencils it is also equal to $2.

2+2=4

and 2 pens and 4 pencils is equal to 6 in total.

Answer

[tex]2[/tex] pens and [tex]4[/tex] pencils were bought for [tex]\$4[/tex] such that [tex]6[/tex] pens and pencils are bought for [tex]\$4[/tex] and each pen costs [tex]\$1[/tex] and each pencil costs [tex]\$0.50[/tex].

The equation whose variables' highest power is one is known as linear equation.

To find the unknown quantities, always assume it to be a variable and then form the equation based on the conditions given in the question.

Let the number of pens bought be [tex]x[/tex].

and the number of pencils bought be [tex]y[/tex].

The total number of pens and pencils [tex]=6[/tex].

So, the first equation is,

[tex]x+y=6[/tex]

[tex]x=6-y[/tex] ... (i)

And the costs per pen and pencil is [tex]\$1[/tex] and [tex]\$0.50[/tex] respectively.

So, the second equation is,

[tex]x+0.5y=4[/tex] ... (ii)

Now, solve the pair of linear equations.

Put the value of [tex]x[/tex] in the equation (ii),

[tex]6-y+0.5y=4\\-0.5y=-2\\y=4[/tex]

So,

[tex]x=6-4\\x=2[/tex]

Thus, [tex]2[/tex] pens and [tex]4[/tex] pencils were bought for [tex]\$4[/tex].

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Answer:

x = 4

y = 36

Step-by-step explanation:

use substitution

y=3x+24

y=9x

therefore . 9x=3x+24

x = 4

sub 4 in for x and solve for y

y = 9(4) = 36

Step-by-step explanation:

(X)^2 - (6)^2

= (x-6)(X+6)

Answer:

[tex](x - 6) \times (x + 6)[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 36[/tex]

write in exponential form.

[tex] {x}^{2} - {6}^{2} [/tex]

factor:

[tex](x - 6) \times (x + 6)[/tex]

A set S has four members if there are six subsets of it, each with two members.

The combination formula, which is given by: can be used to determine the total amount of subsets with two members each.

[tex]^nC_k= \dfrac{n!}{(k!(n-k)!)}[/tex]

There are 6 subsets in this situation, each with 2 members.

So, [tex]^nC_2[/tex] = 6

Simplifying the equation:

n! / (2!(n-2)!) = 6

n(n-1) / (2 x 1) = 6

n(n-1) / 2 = 6

n(n-1) = 12

Expanding the equation:

[tex]n^2 - n = 12[/tex]

[tex]n^2 - n - 12 = 0[/tex]

Factoring the quadratic equation:

(n - 4)(n + 3) = 0

When all factors are set to zero and n is calculated:

n - 4 = 0    or    n + 3 = 0

n = 4        or    n = -3

Since n must be a positive integer.

So, n = 4 is the valid solution.

Thus, set S consists of 4 members.

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Answer:

[tex] \frac{dy}{dx} = - \frac{ {x}^{3} }{ {y}^{3} } [/tex]

Step-by-step explanation:

Differentiate both sides of the equation (consider y as a function of x).

[tex] \frac{d}{dx} ( {x}^{4} + {y}^{4} (x)) = \frac{d}{dx} (16)[/tex]

the derivative of a sum/difference is the sum/difference of derivatives.

[tex]( \frac{d}{dx} ( {x}^{4} + {y}^{4} (x))[/tex]

[tex] = ( \frac{d}{dx} ( {x}^{4} ) + \frac{d}{dx} ( {y}^{4} (x)))[/tex]

the function of y^4(x) is the composition of f(g(x)) of the two functions.

the chain rule:

[tex] \frac{d}{dx} (f(g(x))) = \frac{d}{du} (f(u)) \frac{d}{dx} (g(x))[/tex]

[tex] = ( \frac{d}{du} ( {u}^{4} ) \frac{d}{dx} (y(x))) + \frac{d}{dx} ( {x}^{4} )[/tex]

apply the power rule:

[tex](4 {u}^{3} ) \frac{d}{dx} (y(x)) + \frac{d}{dx} ( {x}^{4} )[/tex]

return to the old variable:

[tex]4(y(x) {)}^{3} \frac{d}{dx} (y(x)) + \frac{d}{dx} ( {x}^{4} )[/tex]

apply the power rule once again:

[tex]4 {y}^{3} (x) \frac{d}{dx} (y(x)) + (4 {x}^{3} )[/tex]

simplify:

[tex]4 {x}^{3} + 4 {y}^{3} (x) \frac{d}{dx} (y(x))[/tex]

[tex] = 4( {x}^{3} + {y}^{3} (x) \frac{d}{dx} (y(x)))[/tex]

[tex] = \frac{d}{dx} ( {x}^{4} + {y}^{4} ))[/tex]

[tex] = 4( {x}^{3} + {y}^{3} (x) \frac{d}{dx}(y(x))) [/tex]

differentiate the equation:

[tex]( \frac{d}{dx} (16)) = (0)[/tex]

[tex] = \frac{d}{dx} (16) = 0[/tex]

derivative:

[tex]4 {x}^{3} + 4 {y}^{3} \frac{dy}{dx} = 0[/tex]

[tex] \frac{dy}{dx} = - \frac{ {x}^{3} }{ {y}^{3} } [/tex]

The financial statement performed by Snell Corporation shows how the revenue recognition provides financial statement users(i.e. the client that uses Snell Co. service in May, June, and July) with relevant information regarding the services associated with revenue from customer contracts.

In the given case, the Snell Co. service charge was hiked in May since the entire service income must be accounted for in May. The amount owed from a client is seen as a current asset on the balance sheet, and once the amount is received from a client, it is removed off from the current asset. Thus it is added to the zero dollars ($0) company's cash balance. In this case, the cash collected in June and July is not recorded as revenue.

We can conclude that the monthly revenue recorded from Snell Co. performance and services for the client in May, June, and July for this service is as follows:

Months                               Revenue

May                                     $1000

June                                       0

July                                         0

Learn more about revenue here:

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Revenue is only earned after the required obligation (goods delivered or service rendered) has been fulfilled. From the question, we noted that Snell Co. performs and completes services for a client in May hence the revenue was earned in May irrespective of when money was received for the service rendered.

As such revenue earned in;

May is $1,000

June is $0

July is $0

for the service rendered

Answer:

D.

Step-by-step explanation:

Mean : 7 + 5 + 6 + 4 + 7 + 8 + 12 = 12 + 10 + 7 + 20 = 30 + 19 = 49. 49/7= 7

Mode : 7.

Median 4 , 4, 6, 7, 7, 8, 12.    7 is the middle number

Answer:

1 as

3/5 × 2/2 = 6/10

Step-by-step explanation:

Hope it helps

Answer:

10cm

Step-by-step explanation:

78,5=pi.r^2

Answer5:

Step-by-step explanation:

Answer:

(x+y+5)(x-y+1)

Step-by-step explanation:

factor by grouping

x^2+6x+5-4y-y^2

x^2+6x+9 - (y^2+4t+4) + 5-9+4

(x+3)^2 - (y+2)^2

(x+3+(y+2))(x+3-(y+2))

(x+y+5)(x-y+1)

109 pumpkins

Step-by-step explanation:

I don't think this is right but

Answer:

range is the y part and domain is the x so the range is the y coordinates

-6,-3,-2,-2,1,4

Step-by-step explanation:

Answer: 7-9

Step-by-step explanation: normal job hours

Like an 8, a 9-5 is what most people have so over 40 hours is overtime

Answer:

f(2) = 11

Step-by-step explanation:

Plug 2 in for x

3(2) + 5

6 + 5

= 11