Answer:
1 (2) f(x) = 1 (3) 1< f(x) < 2 (4) f(x) greater than or equal to 2
Step-by-step explanation:
We know AM ≥ GM
(cos2x+sec2x )/2 ≥ √(cos2x sec2x)
(cos2x+sec2x ) ≥ 2√(cos2x (1/cos2x)
f(x) ≥ 2
Hence option (4) is the answer.
In this exercise, do not attempt formal mathematical derivations, which would actually involve some subtle issues when we go beyond discrete random variables. Rather, use your understanding of the concepts involved. For each one of the statements below, indicate whether it is true or false.
(a) The law of iterated expectations tells us that E [E[X|Y]] = E[X]. Suppose that we want apply this law in a conditional universe, given another random variable Z, in order to evaluate E [X2]. Then: EE[X|Y, 2]|2] = E[X2] y E[E[X|Y]|2] =E[X2] V EE[X|Y,Z]] =E[X2]
(b) Determine whether each of the following statements about the quantity E[g(X,Y)|Y,Z) is true or false. The quantity E[9(X,Y)|Y, 2) is: • a random variable y a number y a function of (X,Y) y a function of (Y,Z) | a function of Z only
Solution :
From the given equation :
E[ E (X|Y) ] = E (X)
a). Then,
E[ E [ X|Y,Z] | Z] = E [ X|Z ]
---- True
E [ E [ X|Y ] | Z ] = E [ X|Z ]
---- False
E [E [X | Y,Z ]] = E [X|Y ]
---- False
b). Th quantity E [ g (X,Y) | Y,Z ] is ,
A random variable ----- TrueA number ----- FalseA function of (X,Y) ----- FalseA function of (Y,Z) ----- TrueA function of Z only ------- FalseThe low of iteration tell the following statement are true E[ E [ X|Y,Z] | Z] = E [ X|Z ] . A random variable y . A function of (Y,Z)
From the given equation the law of iterated expectations
[tex]E[ E (X|Y) ] = E (X)[/tex]
Therefore We have to find a)
What is the definition of iteration?Iteration is the repetition of a process in order to generate a sequence of outcomes.
So by using the low of iteration we can say that,
E[ E [ X|Y,Z] | Z] = E [ X|Z ] ---- True
E [ E [ X|Y ] | Z ] = E [ X|Z ] ---- False
E [E [X | Y,Z ]] = E [X|Y ] ---- False
b). Th quantity E [ g (X,Y) | Y,Z ] is ,
For a random variable y this is ----- True
For a number ----- False
For a function of (X,Y) ----- False
For a function of (Y,Z) ----- True
For function of Z only ------- False
Therefore,The low of iteration tell the following statement are true E[ E [ X|Y,Z] | Z] = E [ X|Z ] . A random variable y . A function of (Y,Z)
To learn more about the iteration visit:
https://brainly.com/question/14284157
8/9 - 1/3
Very easy question for 10 pts
Answer:
answer is 5/9
Step-by-step explanation:
Answer:
The answer is 5/9 or 0.555 (the 5 is repeated)
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31. Otherwise you pay me $21.
Find the expected value of the proposition. Round your answer to two decimal places. Losses must be expressed as negative values.
Answer:
The expected value of the proposition is of -0.29.
Step-by-step explanation:
For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Suppose a basketball player has made 231 out of 361 free throws.
This means that [tex]p = \frac{231}{361} = 0.6399[/tex]
Probability of the player making the next 2 free throws:
This is P(X = 2) when n = 2. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095[/tex]
Find the expected value of the proposition:
0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.
1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So
[tex]E = -31*0.4095 + 21*0.5905 = -0.29[/tex]
The expected value of the proposition is of -0.29.
PLEASE BE RIGHT AND SOLVE
Answer:
Option B: Rotation
Step-by-step explanation:
The shape appears to have the same size, but it has been moved in a way that is not reflection. Through the process of elimination, the answer is rotation.
Solve this:
A woman was 39years old when she gave birth to a pair of twins.12 years ago,she was twice as old as the sum of the ages of the twins put together.Find their present ages.
Answer:
woman =39years
twins 0year each since 12 years ago they were not yet born
PLEASE HELP!!! Which number is a solution of the inequality x less-than negative 4? Use the number line to help answer the question. A number line going from negative 9 to positive 1.
Answer:
is it going to be 10.5
Step-by-step explanation:
I do not have any explanation
Answer: 0 (zero)
Step-by-step explanation:
Start Learning & start growing! edge2023
*DROPS THE MIC*
on a piece of paper, graph y=x^2+x-6 and identify the y-intercept. Then determine which answer choice matches the graph and y-intercept that you drew.
Answer:
c
Step-by-step explanation:
C is the correct answer
r=4+7x-sx
I need help so any one can help with this
what is the difference between the products of the digits in 425 and the sum of the digits in the numeral 92784
Answer: 10
Step-by-step explanation:
4 x 2 x 5 = 40
9 + 2 + 7 + 8 + 4 = 30
40 - 30 = 10
= 10
What is the distance between -10.2 and 5.7?
Answer:
15.9
Step-by-step explanation:
The distance between -10.2 and 5.7 is 15.9 after plotting the points on a number line.
What is a number line?It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.
It is given that:
Two numbers on a number line:
-10.2 and 5.7
As we know, a number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.
Indicating the above numbers on a number line:
= 5.7 -(-10.5)
The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
= 5.7 + 10.5
= 15.9
Thus, the distance between -10.2 and 5.7 is 15.9 after plotting the points on a number line.
Learn more about the number line here:
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What is the value of M
Answer:....... no clue ut pls mark me brainiest
Step-by-step explanation:
Square Footage Frequency
0-499 5
500-999 17
1000-1499 36
1500-1999 115
2000-2499 125
2500-2999 81
3000-3499 47
3500-3999 45
4000-4499 22
4500-4999 7
The accompanying frequency distribution represents the square footage of a random sample of 500 houses that are owner occupied year round. Approximate the mean and standard deviation square footage.
Answer:
2424.5
904.16
Step-by-step explanation:
the mean = ∑frequency /n
∑f = 5+17+36+115+125+81+47+45+22+7 = 500
∑xf = 1212250
∑x²f = 3347037625
sample mean = 1212250/500
= 2424.5
variance = 1/500-1[3347037625 - 1212250²]
= 815710.02
standard deviation is = √variance
standard deviation = √815710.02
= 904.16
please simplify this one. I need answers fast as possible.
This is the answer.
Hope it helps!!
Answer:
[tex]120.\sqrt{2}.\sqrt[3]{3}[/tex]
Step-by-step explanation:
[tex]\sqrt{32} = \sqrt{16.2} =\sqrt{4^{2}.2} = 4\sqrt{2}[/tex]
[tex]\sqrt[3]{81} =\sqrt[3]{27.3} =\sqrt[3]{3^{3}.3 }=3\sqrt[3]{3}[/tex]
∴[tex]5\sqrt{32}.2\sqrt[3]{81} =5. [4\sqrt{2}].2.[3\sqrt[3]{3} ][/tex]
[tex]=120.\sqrt{2}.\sqrt[3]{3}[/tex]
Gsggagsgsvhdgdvdvdvdvdg help me fast I’ll give you brainliste
The answer is D
Hope that was fast enough
What conclusion can be made based on this multiplication problem?
8 × 6 = 48
Eight is 6 times greater than 48.
Eight is 8 times greater than 48.
Forty-eight is 6 times greater than 8.
Forty-eight is 8 times greater than 8.
In this diagram, ABAC – AEDF. If the
area of ABAC = 6 in?, what is the
area of AEDF?
Answer:
2.7 in²
Step-by-step explanation:
similar triangles have the same angles, and all side lengths (or other distances) of one triangle have the same scaling factor to the side lengths of the other triangle.
so, we know the relation between the 2 baselines is 2/3, as this is the factor to turn the baseline of the large triangle into the baseline of the smaller triangle.
in other words
EF = BC × 2/3
2 = 3 × 2/3
correct
how do we calculate the area of a triangle ?
Area = baseline × height / 2
from BAC we know
Area = 6
baseline = 3
height = ?
6 = 3 × height / 2
12 = 3 × height
height = 4
aha !
now, EDF has a height too that we need to calculate is Area. and this height has the same scaling factor compared to the larger triangle as the side lengths : 2/3
so, for EDF we know
Area = ?
baseline = 2
height = 4 × 2/3 = 8/3
therefore, the area is
Area = (2 × 8/3) / 2 = (16/3) / 2 = 8/3 = 2.66666... ≈ 2.7
the shirt answer would be :
we know from the 2 baselines that the scaling factor for each distance is 2/3.
for the area we need to multiply 2 distances, so that means we have to multiply both by 2/3. and so on the formula for the area we have to use 2/3 × 2/3.
2/3 × 2/3 = 4/9
=>
Area small = Area large × 4/9 = 6 × 4/9 = 24/9 = 8/3 ≈ 2.7
The following data was collected to explore how the average number of hours a student studies per night and the student's GPA affect their ACT score. The dependent variable is the ACT score, the first independent variable (x1)is the number of hours spent studying, and the second independent variable (x2) is the student's GPA
Effects on ACT Scores
Study Hours GPA ACT Score
5 4 27
5 2 18
5 3 18
1 3 20
2 4 21
Step 1 of 2: Find the p-value for the regression equation that fits the given data. Round your answer to four decimal places.
Step 2 of 2: Determine if a statistically significant linear relationship exists between the independent and dependent variables at the 0.01 level of significance. If the relationship is statistically significant, identify the multiple regression equation that best fits the data, rounding the answers to three decimal places. Otherwise, indicate that there is not enough evidence to show that the relationship is statistically significant.
Answer:
Pvalue = 0.1505
y = 0.550x1 + 3.600x2 + 7.300
Step-by-step explanation:
Given the data :
Study Hours GPA ACT Score
5 4 27
5 2 18
5 3 18
1 3 20
2 4 21
Using technology, the Pvalue obtained using the Fratio :
F = MSregression / MSresidual = 30.228571/ 8.190476 = 3.69
The Pvalue for the regression equation is:
Using the Pvalue from Fratio calculator :
F(1, 3), 3.69 = 0.1505
Using the Pvalue approach :
At α = 0.01
Pvalue > α ; Hence, we fail to reject H0 and conclude that ; There is not enough evidence to show that the relationship is statistically significant.
The regression equation :
y = A1x1 + A2x2 +... AnXn
y = 0.550x1 + 3.600x2 + 7.300
x1 and x2 are the predictor variables ;
y = predicted variable
Hello!
i need help with question 67 & 68
Answer:
67. A
68. D
Step-by-step explanation:
I don't remember exactly the explanation, but I recommend you try to learn more about number lines sometime when you aren't under stress from schoolwork, because they're pretty simple questions to answer once you get a better understanding of them!
help me pleaseeeeeeeeeeeeeeeeee………….
Answer:
d
Step-by-step explanation:
because u did the math for you
If there is a 90% chance of rain tomorrow and a 70% chance of wind and rain,
what is the probability that it is windy, given that it is rainy? Round your
answer to the nearest percent.
Answer:
78%
Step-by-step explanation:
the chance of rain
P(R) = 0.9
the chance of wind and rain
P(R∩ W) = 0.7
The probabilities of windy weather is
P(W) = [tex]\frac{P(RW)}{P(R)} =\frac{0.7}{0.9} =0.78[/tex]
The correct answer is B) 78%
rewrite the polynomial in the form ax^2 + bx + c then identify the values of a, b, and c
x^2/8 - 8
Answer:
[tex]x^{2} -16[/tex]
a = 1
b=0
c= -16
i assume the next question is to factor that...
(x-4)(x+4)
Step-by-step explanation:
Each student at some college has a mathematics requirement M (to take at least one mathematics course) and a science requirement S (to take at least one science course). A poll of 150 sophomore students shows that: 60 completed M, 45 completed S, and 25 completed both M and S
Find the number of students who have completed
(a) At least one of the two requirements
(b) Exactly one of the two requirements
(c) Neither requirement.
all students = 150
M = 60
S = 45
M and S = 25
(a) At least one of the two requirements:
M or S = M + S - (M and S) = 60 + 45 - 25 = 80
(b) Exactly one of the two requirements:
(M or S) - (M and S) = 80 - 25 = 55
(c) Neither requirement:
(all students) - (M or S) = 150 - 80 = 70
Which expression is equivalent to 3 square root of x^5*y
Answer:
√3 x^5y
First, let's do √3
√3=1.7
1.7 • x^5 • y
if you want
1.7 • X^4• x• y.
There are tons of equivalent's!
How to solve it and explain it
Answer:
28.27 in²
Step-by-step explanation:
The equation for the area of a circle is A = π[tex]r^{2}[/tex]. However, we got the diameter.
diameter = 2(radius), so:
A = [tex]\frac{1}{4}[/tex]πd².
A = 1/4 * π * 6² ≈ 28.27433
How to find the surface area of a cuboid
Find the scale ratio for the map described below.
1cm (map) 50km (actual)
The scale ratio is 1 to .....?
Answer:
50,000 : 0.01
multiply by 100...
5000000 : 1
1:5,000,000
Step-by-step explanation:
What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the first quarter? Do not round intermediate calculations. Enter negative values as negative numbers, if any.
Answer:
(-0.1059 ; - 0.0337)
Step-by-step explanation:
The data table is attached in the picture below:
These is a matched pair design ; which requires taking the difference of the two values for each sample :
The mean and standard deviation of the difference will be used to construct the confidence interval :
The mean of difference, dbar = Σx/n = - 0.0698
The standard deviation of difference, Sd ;
Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054
n = sample size = 25
The confidence interval :
dbar ± [TCritical * Sd/√n]
Tcritical at 90% ; df = n -1 = 25 -1
Tcritical(90% , 24) = 1.1711
C.I = - 0.0698 ± (1.711 * 0.1054/√25)
C.I = - 0.0698 ± 0.0361
C.I = (-0.1059 ; - 0.0337)
In 1980, the median age of the U.S. population was 30.0; in 2000, the median age was 35.3. Consider 1980 as the starting point (time zero) for this problem. Create an explicit exponential formula for the median age of the U.S. population t years after 1980, assuming the median age has exponential growth.
Answer: [tex]30e^{0.00813x}[/tex]
Step-by-step explanation:
Given
Median age in 1980 is [tex]30[/tex]
It is [tex]35.3[/tex] in year 2000
Suppose the median age follows the function [tex]ae^{bx}[/tex]. Consider 1980 as starting year. Write the equation for year 1980
[tex]\Rightarrow 30=ae^{b(0)}\\\Rightarrow 30=a[/tex]
For year 2000
[tex]\Rightarrow 35.3=30e^{20b}\\\\\Rightarrow \dfrac{30e^{20b}}{30}=\dfrac{35.3}{30}\\\\\Rightarrow e^{20b}=1.17666\\\\\Rightarrow b=0.00813[/tex]
After t years of 1980
[tex]\Rightarrow 30e^{0.00813x}[/tex]
I really need help on this
a) B
b) D
Hope this helps you
A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selects 10 at random for testing and rejects the entire shipment if 1 or more are found defective. What is the probability this shipment passes inspection?
Answer:
0.3968 = 39.68% probability this shipment passes inspection.
Step-by-step explanation:
The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
50 parts means that [tex]N = 50[/tex]
4 defective means that [tex]k = 4[/tex]
10 are chosen, which means that [tex]n = 10[/tex]
What is the probability this shipment passes inspection?
Probability that none is defective, so:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968[/tex]
0.3968 = 39.68% probability this shipment passes inspection.
