Which of the following is equivalent to a real number?
A. (-46)^1/2
B. (-10596)^1/8
C. (-4099)^1/5
D. (-5403)^1/6
Answer:
C. (-4099)^1/5
Step-by-step explanation:
[tex]x^{\frac{1}{2} } = \sqrt{x}[/tex]
you can not take roots (real roots) of a negative number if the exponent is
even ... A,B,D have even exponents (in the denominator of the exponent.. in other words the index of the radical is even)...
the only odd index is in "B" (the 5 in the 1/5)
Can someone please help me thank you !!!!!
What is the common difference between successive terms in the sequence?
0.36, 0.26, 0.16, 0.06, –0.04, –0.14,
What is the area of the circle in terms of [tex]\pi[/tex]?
a. 3.4225[tex]\pi[/tex] m²
b. 6.845[tex]\pi[/tex] m²
c. 7.4[tex]\pi[/tex] m²
d. 13.69[tex]\pi[/tex] m²
[tex] \sf \: d \: = 3.7m \\ \sf \: r \: = \frac{3.7}{2} = 1.85 \: m\\ \\ \sf \: c \: = \pi {r}^{2} \\ \\ \sf \: c \: = \pi ({1.85})^{2} \\ \sf c = 1.85 \times 1.85 \times \pi \\ \sf \: c = \boxed {\underline{ \bf a. \: 3.4225\pi \: m ^{2} }}[/tex]
[tex]i^0 +i^1+i^2+i^3+............+i^{2021} = ?[/tex]
Include work.
Answer:
1+i
Step-by-step explanation:
I do believe i to be the imaginary unit.
Let's write out some partial sums from power=0 to power=7 or whatever we need to see a pattern.
i^0=1
i^0+i^1=1+i
i^0+i^1+i^2=1+i+-1=i
i^0+i^1+i^2+i^3=i+i^3=i+-i=0
i^0+i^1+i^2+i^3+i^4=0+i^4=0+1=1
Hmmm.... we might see 1+i, then i, then 0 again.... let's see.
i^0+i^1+i^2+i^3+i^4+i^5=1+i
Coolness so we should see a pattern
Sum from power=0 to power=multiples of 4 will give us 1.
Sum from power=0 to power=remainder of 1 when final power is divided by 4 gives us 1+i.
Sum from power=0 to power=remainder of 2 when final power is divided by 4 gives us i.
Sum from power=0 to power=remainder of 3 when final power is divided by 4 gives us 1
0.
So 2021 divided by 4....
Since 2020 is a multiple of 4, then 2021 has a remainder of 1 when divided by 4.
So the answer is 1+i.
A line has a slope of 7 and passes through the point (-2,-1) What is its equation in point-slope form?
Answer:
y + 1 = 7(x + 2).
Step-by-step explanation:
Point slope form:
y - y1 =m(x - x1).
Here m = 7 and (x1, y1) = (-2, -1)
So the answer is;
y - (-1) = 7(x - (-2))
i need help. i will give brainiest as soon as possible
Answer:
B
Step-by-step explanation:
Let me know if you need an explanation.
Answer:
B
Step-by-step explanation:
4x^3+x^2+5x+2
4x^3 cannot cancel with others= 4x^3
4x^2-3x^2= x^2
5x cannot cancel with others= 5x
-3+5= 2
4x^3+x^2+5x+2
There were 2,300 applicants for enrollment to the freshman class at a small college in the year 2010. The number of applicants has risen linearly by roughly 170 per year. The number of applications f(x) is given by f(x) = 2,300 + 170x, where x is the number of years since 2010. a. Determine if the function g(x) = * = 2,300 is the inverse of f. 170 b. Interpret the meaning of function g in the context of the problem.
a. No
b. The value g(x) represents the number of years since the year 2010 based on the number of applicants to the freshman class, x.
a. Yes
b. The value 8(x) represents the number of applicants to the freshman class based on the number of years since 2010,
a. No
b. The value slx) represents the number of applicants to the freshman class based on the number of years since 2010,
a. Yes
b. The value six) represents the number of years since the year 2010 based on the number of applicants to the freshman class x
Answer:
The inverse function is [tex]g(x) = \frac{x - 2300}{170}[/tex]
The value of g(x) represents the number of applicants to the freshman class based on the number of years since 2010.
Step-by-step explanation:
Number of applicants in x years after 2010:
Is given by the following function:
[tex]f(x) = 2300 + 170x[/tex]
Inverse function:
We exchange the values of y = f(x) and x in the original function, and then find y. So
[tex]x = 2300 + 170y[/tex]
[tex]170y = x - 2300[/tex]
[tex]y = \frac{x - 2300}{170}[/tex]
[tex]g(x) = \frac{x - 2300}{170}[/tex]
The inverse function is [tex]g(x) = \frac{x - 2300}{170}[/tex]
Meaning of g:
f(x): Number of students in x years:
g(x): Inverse of f(x), is the number of years it takes for there to be x applicants, so the answer is:
The value of g(x) represents the number of applicants to the freshman class based on the number of years since 2010.
At the Fidelity Credit Union, a mean of 3.5 customers arrive hourly at the drive-through window. What is the probability that, in any hour, more than 5 customers will arrive? Round your answer to four decimal places.
Answer:
0.1423 = 14.23% probability that, in any hour, more than 5 customers will arrive.
Step-by-step explanation:
We have the mean, which means that the Poisson distribution is used to solve this question.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
A mean of 3.5 customers arrive hourly at the drive-through window.
This means that [tex]\mu = 3.5[/tex]
What is the probability that, in any hour, more than 5 customers will arrive?
This is:
[tex]P(X > 5) = 1 - P(X \leq 5)[/tex]
In which
[tex]P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)[/tex]
Then
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-3.5}*3.5^{0}}{(0)!} = 0.0302[/tex]
[tex]P(X = 1) = \frac{e^{-3.5}*3.5^{1}}{(1)!} = 0.1057[/tex]
[tex]P(X = 2) = \frac{e^{-3.5}*3.5^{2}}{(2)!} = 0.1850[/tex]
[tex]P(X = 3) = \frac{e^{-3.5}*3.5^{3}}{(3)!} = 0.2158[/tex]
[tex]P(X = 4) = \frac{e^{-3.5}*3.5^{4}}{(4)!} = 0.1888[/tex]
[tex]P(X = 5) = \frac{e^{-3.5}*3.5^{5}}{(5)!} = 0.1322[/tex]
Finally
[tex]P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0302 + 0.1057 + 0.1850 + 0.2158 + 0.1888 + 0.1322 = 0.8577[/tex]
[tex]P(X > 5) = 1 - P(X \leq 5) = 1 - 0.8577 = 0.1423[/tex]
0.1423 = 14.23% probability that, in any hour, more than 5 customers will arrive.
(3) If a tire rotates at 400 revolutions per minute when the car is traveling 72km/h, what is the circumference of the tire?
Show all your steps.
Answer:
3 meters.
Step-by-step explanation:
400 rev / minute = 400 × 60 rev / 60 minutes
= 24,000 rev / hour
24,000 × C = 72,000 m : C is the circumference
C = 3 meters
Answer:
3 meters
Step-by-step explanation:
72 km / hour * 1 hour/ 60 min * 1000m/ 1 km
72000 meters /60 minute
1200 meters / minute
velocity = radius * w
Where w is 2*pi * the revolutions per minute
1200 = r * 2 * pi *400
1200 / 800 pi = r
1.5 /pi = r meters
We want to find the circumference
C = 2 * pi *r
C = 2* pi ( 1.5 / pi)
C = 3 meters
3.52 A coin is tossed twice. Let Z denote the number of heads on the first toss and W the total number of heads on the 2 tosses. If the coin is unbalanced and a head has a 40% chance of occurring, find (a) the joint probability distribution of W and Z; (b) the marginal distribution of W; (c) the marginal distribution of Z
Answer:
a) The joint probability distribution
P(0,0) = 0.36, P(1,0) = 0.24, P(2,0) = 0, P(0,1) = 0, P(1,1) = 0.24, P(2,1)= 0.16
b) P( W = 0 ) = 0.36, P(W = 1 ) = 0.48, P(W = 2 ) = 0.16
c) P ( z = 0 ) = 0.6
P ( z = 1 ) = 0.4
Step-by-step explanation:
Number of head on first toss = Z
Total Number of heads on 2 tosses = W
% of head occurring = 40%
% of tail occurring = 60%
P ( head ) = 2/5 , P( tail ) = 3/5
a) Determine the joint probability distribution of W and Z
P( W =0 |Z = 0 ) = 0.6 P( W = 0 | Z = 1 ) = 0
P( W = 1 | Z = 0 ) = 0.4 P( W = 1 | Z = 1 ) = 0.6
P( W = 1 | Z = 0 ) = 0 P( W = 2 | Z = 1 ) = 0.4
The joint probability distribution
P(0,0) = 0.36, P(1,0) = 0.24, P(2,0) = 0, P(0,1) = 0, P(1,1) = 0.24, P(2,1)= 0.16
B) Marginal distribution of W
P( W = 0 ) = 0.36, P(W = 1 ) = 0.48, P(W = 2 ) = 0.16
C) Marginal distribution of Z ( pmf of Z )
P ( z = 0 ) = 0.6
P ( z = 1 ) = 0.4
Part(a): The required joint probability of W and Z is ,
[tex]P(0,0)=0.36,P(1,0)=0.24,P(2,0)=0,P(0,1)=0,P(1,1)=0.24,\\\\P(2,1)=0.16[/tex]
Part(b): The pmf (marginal distribution) of W is,
[tex]P(w=0)=0.36,P(w=1)=0.48,P(w=2)=0.16[/tex]
Part(c): The pmf (marginal distribution) of Z is,
[tex]P(z=0)=0.6,P(z=1)=0.4[/tex]
Part(a):
The joint distribution is,
[tex]P(w=0\z=0)=0.6,P(w=1|z=0)=0.4,P(w=2|z=0)=0[/tex]
Also,
[tex]P(w=0\z=1)=0,P(w=1|z=1)=0.6,P(w=2|z=1)=0.4[/tex]
Therefore,
[tex]P(0,0)=0.36,P(1,0)=0.24,P(2,0)=0,P(0,1)=0,P(1,1)=0.24,\\\\P(2,1)=0.16[/tex]
Learn More: https://brainly.com/question/13127182
A medicine bottle contains 8 grams of medicine. One dose is 400 milligrams. How many milligrams does the bottle contain?
Answer:
8×1000 milligrams
8000 milligrams
Hello, please help ASAP. Thank you!
Answer:
23) No
24) No
25) Yes
Step-by-step explanation:
Question 23)
We want to determine if a zero exists between 1 and 2 for the function:
[tex]f(x)=x^2-4x-5[/tex]
Find the zeros of the function. We can factor:
[tex]\displaystyle 0 = (x-5)(x+1)[/tex]
Zero Product Property:
[tex]x-5=0\text{ or } x+1=0[/tex]
Solve for each case. Hence:
[tex]\displaystyle x = 5\text{ or } x=-1[/tex]
Therefore, our zeros are at x = 5 and x = -1.
In conclusion, a zero does not exist between 1 and 2.
Question 24)
We have the function:
[tex]f(x)=2x^2-7x+3[/tex]
And we want to determine if a zero exists between 1 and 2.
Factor. We want to find two numbers that multiply to (2)(3) = 6 and that add to -7.
-6 and -1 suffice. Hence:
[tex]\displaystyle \begin{aligned} 0 & = 2x^2-7x + 3 \\ & = 2x^2 -6x -x + 3 \\ &= 2x(x-3) - (x-3) \\ &= (2x-1)(x-3) \end{aligned}[/tex]
By the Zero Product Property:
[tex]2x-1=0\text{ or } x-3=0[/tex]
Solve for each case:
[tex]\displaystyle x=\frac{1}{2} \text{ or } x=3[/tex]
Therefore, our zeros are at x = 1/2 and x = 3.
In conclusion, a zero does not exist between 1 and 2.
Question 25)
We have the function:
[tex]f(x)=3x^2-2x-5[/tex]
And we want to determine if a zero exists between -2 and 3.
Factor. Again, we want to find two numbers that multiply to 3(-5) = -15 and that add to -2.
-5 and 3 works perfectly. Hence:
[tex]\displaystyle \begin{aligned} 0&= 3x^2 -2x -5 \\ &= 3x^2 +3x - 5x -5 \\ &= 3x(x+1)-5(x+1) \\ &= (3x-5)(x+1)\end{aligned}[/tex]
By the Zero Product Property:
[tex]\displaystyle 3x-5=0\text{ or } x+1=0[/tex]
Solve for each case:
[tex]\displaystyle x = \frac{5}{3}\text{ or } x=-1[/tex]
In conclusion, there indeed exists a zero between -2 and 3.
(3.5 x 10 ^ -4) ÷ (5 x 10 ^ 5) in standard form PLZZ ANSWER QUICK
Answer:
7x10 ^-10
Step-by-step explanation:
URGENT HELP!!!!
Picture included
Answer:
Length (L) = 72 feet
Step-by-step explanation:
From the question given above, the following data were obtained:
Period (T) = 9.42 s
Pi (π) = 3.14
Length (L) =?
The length of the pendulum can be obtained as follow:
T = 2π √(L/32)
9.42 = (2 × 3.14) √(L/32)
9.42 = 6.28 √(L/32)
Divide both side by 6.28
√(L/32) = 9.42 / 6.28
Take the square of both side
L/32 = (9.42 / 6.28)²
Cross multiply
L = 32 × (9.42 / 6.28)²
L = 72 feet
Thus, the Lenght is 72 feet
The radius of the circle is 1/2 inches. Find the circumference
Answer:
[tex]\pi[/tex]
Step-by-step explanation:
1. [tex]c = 2\pi r[/tex]
2. [tex]c=2\pi \frac{1}{2}[/tex]
3. [tex]c=\pi[/tex]
Which property was used to simplify the expression 4(b+2)=4b+8
Answer: distributive property
Step-by-step explanation: the 4 is multiplied by everting in the parenthesis
Seventeen individuals are scheduled to take a driving test at a particular DMV office on a certain day, nine of whom will be taking the test for the first time. Suppose that six of these individuals are randomly assigned to a particular examiner, and let X be the number among the six who are taking the test for the first time. (a) What kind of a distribution does X have (name and values of al parameters)? 17 hx;6, 9, 17) O h(x; 6,? 17 bx; 6, 9,17) (x; 6, 9, 17) 17 (b) Compute P(X = 4), P(X S 4), and P(X PLX = 4) 0.2851 PX S 4)-13946X RX24) -0.1096 X 4). (Round your answers to four decimal places.) (c) Calculaethe mean value and standard deviation of X. (Round your answers to three decimal places.)
Answer:
a) h(x; 6, 9, 17).
b) P[X=2] = 0.2036
P[X ≤ 2] = 0.2466
P[X ≥ 2] = 0.9570.
c) Mean = 3.176.
Variance = 1.028.
Standard deviation = 1.014.
Step-by-step explanation:
From the given details K=6, n=9, N=-17.
We conclude that it is the hypergeometric distribution:
a) h(x; 6, 9, 17).
b)
[tex]P[X=2]=\frac{(^{g}C_{2})^{17-9}C_{6-2}}{^{17}C_{6}\textrm{}}[/tex]
P[X=2] = 0.2036
P[X ≤ 2] = P(x=0)+ P(x=1) + P(x=2)
P[X ≤ 2] = 0.2466
P[X ≥ 2] = 1-[P(x=0)+P(x=1)]
P[X ≥ 2] = 0.9570.
c)
Mean= [tex]n\frac{K}{N}[/tex]
= 3.176.
Variance = [tex]n\frac{K}{N}( \frac{N-K}{N})(\frac{N-n}{n-1} )[/tex]
= 2.824 x 0.6471 x 0.5625
= 1.028.
Standard deviation = [tex]\sqrt{1.028}[/tex] = 1.014.
If the cost of a 2.5 meter cloth is $30.5. What will be the cost of 22 meters ?
Answer:
268.40
Step-by-step explanation:
We can write a ratio to solve
2.5 meters 22 meters
----------------- = --------------
30.5 dollars x dollars
Using cross products
2.5 * x = 30.5 * 22
2.5x =671
Divide each side by 2.5
2.5x / 2.5 = 671/2.5
x =268.4
On a coordinate plane, a curved line begins at point (negative 2, negative 3), crosses the y-axis at (0, negative .25), and the x-axis at (1, 0).
What is the domain of the function on the graph?
Answer:
Option D
Step-by-step explanation:
correct answer on edge :)
Answer:
D <3
Step-by-step explanation:
A wire 9 meters long is cut into two pieces. One piece is bent into a equilateral triangle for a frame for a stained glass ornament, while the other piece is bent into a circle for a TV antenna. To reduce storage space, where should the wire be cut to minimize the total area of both figures? Give the length of wire used for each: For the equilateral triangle:
The length of wire used for the equilateral triangle is approximately 5.61 meters.
The remaining length of wire used for the circle will be 9 - 5.61 ≈ 3.39 meters.
Here,
To minimize the total area of both figures, we need to find the optimal cut point for the wire.
Let's assume the length of the wire used for the equilateral triangle is x meters, and the remaining length of the wire used for the circle is (9 - x) meters.
For the equilateral triangle:
An equilateral triangle has all three sides equal in length.
Let's call each side of the triangle s meters. Since the total length of the wire is x meters, each side will be x/3 meters.
The formula to find the area of an equilateral triangle with side length s is:
Area = (√(3)/4) * s²
Substitute s = x/3 into the area formula:
Area = (√(3)/4) * (x/3)²
Area = (√(3)/4) * (x²/9)
Now, for the circle:
The circumference (perimeter) of a circle is given by the formula:
Circumference = 2 * π * r
Since the remaining length of wire is (9 - x) meters, the circumference of the circle will be 2π(9 - x) meters.
The formula to find the area of a circle with radius r is:
Area = π * r²
To find the area of the circle, we need to find the radius.
Since the circumference is equal to 2πr, we can set up the equation:
2πr = 2π(9 - x)
Now, solve for r:
r = (9 - x)
Now, substitute r = (9 - x) into the area formula for the circle:
Area = π * (9 - x)²
Now, we want to minimize the total area, which is the sum of the areas of the triangle and the circle:
Total Area = (√(3)/4) * (x²/9) + π * (9 - x)²
To find the optimal value of x that minimizes the total area, we can take the derivative of the total area with respect to x, set it to zero, and solve for x.
d(Total Area)/dx = 0
Now, find the critical points and determine which one yields the minimum area.
Taking the derivative and setting it to zero:
d(Total Area)/dx = (√(3)/4) * (2x/9) - 2π * (9 - x)
Setting it to zero:
(√(3)/4) * (2x/9) - 2π * (9 - x) = 0
Now, solve for x:
(√(3)/4) * (2x/9) = 2π * (9 - x)
x/9 = (8π - 2πx) / (√(3))
Now, isolate x:
x = 9 * (8π - 2πx) / (√(3))
x(√(3)) = 9 * (8π - 2πx)
x(√(3) + 2π) = 9 * 8π
x = (9 * 8π) / (√(3) + 2π)
Now, we can calculate the value of x:
x ≈ 5.61 meters
So, the length of wire used for the equilateral triangle is approximately 5.61 meters.
The remaining length of wire used for the circle will be 9 - 5.61 ≈ 3.39 meters.
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Determine the degree of the polynomial −65b+53x3y
Answer:
im pretty sure the degree is 4.
Step-by-step explanation:
[(2021-Y)-5]*X-X=XX cho biết X,Y,XX là gì?
A life insurance policy cost $8.52 for every $1000 of insurance at this rate what is the cost for 20,000 worth of life insurance
Answer:
$170.40
Step-by-step explanation:
cost of policy=$8.52
Groups of $1000=20,00÷1000
=20
20,000 worth=$8.52×20
$170.40
Simplify this expression 3^-3
ASAPPPP PLSSSS
Step-by-step explanation:
-27 okay 3^-3 its same as 3^3
Answer: A)
[tex]3^{-3}[/tex]
[tex]3^{-3}=\frac{1}{3^3}[/tex]
[tex]=\frac{1}{3^3}[/tex]
[tex]3^3=27[/tex]
[tex]=\frac{1}{27}[/tex]
OAmalOHopeO
How many subsets of at least one element does a set of seven elements have?
[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
For each subset it can either contain or not contain an element. For each element, there are 2 possibilities. Multiplying these together we get 27 or 128 subsets. For generalisation the total number of subsets of a set containing n elements is 2 to the power n.
total subsets
2^n2⁷128-28=7(x-7) what does x equal
Answer:
x=3
Step-by-step explanation:
7(x - 7) = -28
x - 7 = -4
x = 3
Answer:
x = 3
Step-by-step explanation:
Your goal is to isolate the x from the other numbers.
-28 = 7(x - 7)
Distribute the 7 to the (x - 7)
You will end up with:
-28 = 7x - 49
Add 49 to both sides of the equation to further isolate the x
21 = 7x
Finally, divide both sides by 7 so x is by itself
x = 3
Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.
60, 58, 64, 64, 68, 50, 57
On the eighth day, she drinks 82 ounces of water. Select all the true statements about the effect of the eighth day's amount on Joanna's daily amount distribution.
PLZ HELP ME I NEED AN ANSWER ASAP WILL NAME BRAINLIEST
(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
Answer:
The Interquartile range increases when the 8th day is included.
The median is higher when the 8th day is included.
Step-by-step explanation:
i got it right. Hope this helps.
A bus driver makes roughly $3280 every month. How much does he make in one week at this rate.
Answer:
I think around $36
Hope it helps!
Answer:
It depends...
Step-by-step explanation:
It depends how much weeks are in the month if there are three weeks and no extra days then you would have an answer of about 1093 (exact: 1093.33333333). just divide the number of weeks by the number of money.
Using f(x)=2x+7 and g(x)=x-3, find f(g(-2))
