100 POINTS PLEASE HELP You push on a box with 50N to the right, your friend decides to be difficult and pushes against you with 15N. There is also friction between the box and ground that is making your job harder. The friction is 6N in total and the box has a mass of 8kg 1. Draw a free body diagram and put in the essay box using the insert media button 2. Find acceleration of the box 3. bonus - what is the coefficient of friction between the box and the ground
Answers
Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:
1. See attachment to this answer
2. a = 3.63 m/[tex]s^{2}[/tex]
3. μ = 0.36
Friction is an oppositional force between the surfaces of two bodies in contact, and tries to limit the motion of one body over the other. It is dependent on the nature of the surfaces in contact.
From the given question;
1. The free body diagram for this question is herewith attached to this answer.
Given that: [tex]F_{1}[/tex] = 50 N, [tex]F_{2}[/tex] = 15 N, [tex]F_{3}[/tex] = 6 N, and m = 8 kg.
2. The acceleration of the body can be determined by:
F = ma
where F is the total force acting on the body, m is the mass of the body and a is its acceleration.
So that;
a = [tex]\frac{F}{m}[/tex]
The total force on the body is;
F = [tex]F_{1}[/tex] - ([tex]F_{2}[/tex] + [tex]F_{3}[/tex])
= 50 - (15 + 6)
= 50 - 21
F = 29 N
Then;
a = [tex]\frac{29}{8}[/tex]
= 3.625
a = 3.63 m/[tex]s^{2}[/tex]
The acceleration of the body is 3.63 m/[tex]s^{2}[/tex].
3. The coefficient of limiting friction (μ) between the surfaces is:
μ = [tex]\frac{Force}{Reaction}[/tex]
Force = 29 N
Reaction = mg
= 8 x 10
= 80 N
μ = [tex]\frac{29}{80}[/tex]
= 0.3625
μ = 0.36
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Answer:
Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:
1. See attachment to this answer
2. a = 3.63 m/
3. μ = 0.36
Explanation:
Related Questions
1
2) Mighty Mouse can lift seven mammoths with a total mass of 525 kg. Using the acceleration of
gravity, find the total WEIGHT that Mighty Mouse is lifting. (answer: 5250 N)
Answers
Answer:
5250N
Explanation:
Weight= Mass × acceleration due to gravity
= 525kg × 10m/s^2
= 5250N
For a horizontally projectile object if the initial velocity doubled, the Vertical displacement (angle y) will be :
Answers
Answer:
Unchanged
Explanation:
horizontal projection always has initial vertical velocity equal to zero.
gravity works pretty much the same at any point on earth and will accelerate any falling object at the same rate traveling the same vertical distance in the same time. Neglecting air resistance of course.
By the way, Δy is read "delta y" not "angle y" which would be "∠ y"
delta represents a change in something, in this case the y coordinate.
A driver entering the outskirts of a city takes her foot off the accelerator so that the car slows down from 90 km/h to 50 km/h in 10.0s. Find the car’s average acceleration
Answers
Answer:
Explanation:
a = (vf - vi) / t
a = (50 - 90) / 10.0
a = -4 km/h/s(1000 m/km / 3600 s/h)
a = - 1.11 m/s²
Option B.
Consider a setup in which two springs are attached to a mass in parallel.
Convince yourself that in this setup, the compression of each spring must be the same. Using
this fact, derive the effective spring constant for springs in parallel
This is asking, "ll1 replace the two springs by a single imaginary spring, what would its spring
constant be such that the force stays the same?" Your answer should only depend on k, and k
Answers
Answer:
it would be...
Explanation:
ou are pulling a 35 kg object with 18.4 N force which is oriented at 10 degree with ground. What is acceleration?
Answers
Answer:
Acceleration= 0.52 m/s²
Market researchers were interested in the relationship between the number of pieces in a brick-building set and the
cost of the set. Information was collected from a survey and was used to obtain the regression equation ý =
0.08x + 1.20, where x represents the number of pieces in a set and ŷ is the predicted price in dollars) of a set.
What is the predicted price of a set that has 500 pieces?
$40
$41.20
$600
$6,235
Answers
Then do 40 + 1.2 = 41.20
Answer B
In a car crash, how are force, mass, acceleration, and velocity related?
Answers
Answer:
the answer is simple but click on the brainiest and thank me.
Explanation:
F=force, m=mass, a=acceleration, v=velocity
v=displcement/time
a= v/t
F= m×a
F= m× (v/t)
What on earth is equal to 9.8m/s/s
Answers
Answer:
Acceleration due to gravity
an electric field is 16 n/c northwest. that makes it a
a) magnitude
b)direction
c)vector
d)scalar
Answers
16 n/c to the northwest lies an electric field. hence it qualifies as a direction. Thus, the correct response is (b). It is assumed that the field's direction corresponds to the direction in which a positive test charge should experience force.
With a positive point charge, the electric field radiates outward, whereas with a point charge that's negative, it radiates in.
How big and which way is the electric field pointing?
A positive point charge is pointed directly away by the electric field, while a negative point charge is pointed directly inside the opposite direction. When you go away again from point charge, the power of the electrical field diminishes as 1 / r 2 1/r21, slash, r, square.
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Answer:
c)vector
Explanation:
I got it right :)
A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.
What is the acceleration of the SRB and main engine during the first 2.0 minutes of flight?
A. 52 m/s2
B. 13 m/s2
C. 9.8 m/s2
D. 11 m/s2
Answers
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
A rocket ship has several engines and thrusters. We can divide its initial movement into 2 parts:
From t = 0 min to t = 2.0 min, the SRB and the main engines act together and the speed goes from 0 m/s (rest) to 1341 m/s.From t = 2.0 min to t = 8.5 min, the main engines alone accelerate the ship form 1341 m/s to 7600 m/s.We want to know the acceleration in the first part (first 2.0 minutes). We need to consider that:
The speed increases from 0 m/s to 1341 m/s.The time elpased is 2.0 min.1 min = 60 s.The acceleration of the ship during the first 2.0 minutes is:
[tex]a = \frac{\Delta v }{t} ) \frac{(1341m/s-0m/s)}{2.0min} \times \frac{1min}{60s} = 11 m/s^{2}[/tex]
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
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Which language style would be most appropriate for the given situation?
dinner at a neighbor's birthday party
o informal language
o formal language
o technical language
Pls help
Answers
Answer:
informal language
Explanation:
you do not need to be formal! you are not at a business conference. technical is not needed either since you are not discussing the intricacies of your job or some computer language.
How can you use the Pythagorean theorem to add two vectors that are not perpendicular?
Answers
Colette launches an air rocket in the upward, positive direction. It launches with an initial velocity of 25.5 m/s. It accelerates in the downward, negative direction at a rate of 9.81 m/s2. After 3.5 seconds, what is the magnitude of the rocket's displacement?
Answers
Answer:
Give me some hint please
Pushing a chair is a law of______?
A. Law of friction
B. Law of interaction
C. Law of acceleration
D. Law of universal gravitation
please help..
Answers
Answer:
A.Law of friction
Explanation:
because friction is the move chair floor
50 Points Help Asap !!
Briefly describe V-T graph For every point please if its increasing if its flat or if its positive or negative help fast
Answers
#A
It's flat as no change can be seen on the graph of A part#B
Its increasing as the line goes up in B part.#C.
It's flat as no change can be seen on the graph of C part#D
It's decreasing as the graph goes down in D part.#E
It's decreasing as the graph goes down in E part#F
It's decreasing as the graph goes down in F part.#G
It's increasing as the graph goes up in G part.Question 2 of 5 Which two statements are true for both compounds and mixtures? A. They can be separated into two or more elements. B. Their particles all have the same chemical formula. C. Their particles are held together by chemical bonds. D. They are made up of more than one type of atom.
Answers
Answer:
D and A
I'm not sure about A lol
need some help plsss!
Answers
Answer:
1and4attract and1and 2repel
Why does air pressure decrease with increasing altitude? (Select all that apply.)
Colder air is less dense.
The weight of the air below is smaller.
Less air above pushes down.
Hot air rises.
The weight of the air above is smaller.
There is more air below to push up more strongly
Answers
The air pressure decrease with increasing altitude as less air above pushes down and the weight of the air above is smaller.
When the temperature cools, molecules often slow down and they do not move and bump into each other.When altitude increases, the amount of gas molecules in the air also decrease.
The air becomes less dense than air nearer to sea level.
When the atmospheric pressure is high at lower altitudes, the density being higher.
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what is the approximate distance from the surface of the earth center 2900km 700km 50000km 6400km
Answers
Answer:
6400km is the closest
Explanation:
Why are electromagnetic waves used to transmit signals?
Answers
Because everybody who is trying to receive signals is using an electromagnetic wave receiver. If you used anything else to transmit your signals, the person looking for your signals would never know when they show up.
Which force, in real life, will have the least effect on a bowling ball rolling down a lane toward bowling pins?
A) magnetism
B) air resistance
C) gravity
D) friction
Answers
Answer:
Its Friction
Explanation:
the pins are not floating and they are not a magnet and not involved with air
The force, in real life, that will have the least effect on a bowling ball rolling down a lane toward bowling pins is magnetism. The correct option is A.
What is magnetism?Magnetism is basically the force which indeed magnets exert when they attract or even repel one another. The movement of electric charges resulting in magnetism.
Every substance is composed of tiny units referred to as atoms. Each atom contains electrons, which are charged particles.
To increase stability, the pins themselves have a low center of gravity. Because they are spherical in shape, they can roll and strike other pins in a variety of directions.
The force acting on the bowling ball is friction and air resistance. The friction force is equal to the friction coefficient multiplied by the normal force, and thus mass times acceleration.
Thus, the correct option is A.
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ILS) Retake question
If you saw these 2 structures in a cell, you would definitely be looking at an animal
cell.
Answers
Answer:
lysosome,flagellum are the 2 structures in a cell
Vesta is a minor planet (asteroid) that takes 3.63 years to orbit the Sun.
Calculate the average sun -Vesta distance
Answers
Using Kepler's third law, the average sun -Vesta distance is 2.36 AU.
According to Kepler's laws, the square of the period of revolution of planets are proportional to the cube of their average distances from the sun. Hence, we can write; [tex]T^{2} =r^{3}[/tex]
Where;
T = period of the planet
r = average distance of the planet
When;
T = 3.63 years
r = [tex]\sqrt[3]{T^2}[/tex]
r = [tex]\sqrt[3]{(3.63)^2}[/tex]
r = 2.36 AU
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WILL DO BRAINLIEST A jar contains seven pink, 6 orange, and four blue marbles. If you pick one without looking, what is the probability that the marble you pick will be orange?
6/10
6/17
11/17
7/11
Answers
Answer:
Choice 2: 6/17
Explanation:
4+7=11. 6+11= 17. so it's 6/17
Which of Newton’s Laws of motion help explain the following scenario?
A paddle wheel boat pushes on the water and the water pushes back causing the boat to move
Answers
Answer:
Newton #3
Explanation:
For every action there is an equal and opposite reaction.
Which scientist is credited with having the greatest contribution to early microscopy and was the first to observe and describe single-celled organisms?
Answers
Answer:
Antonie van Leeuwenhoek
Explanation:
An object moves 45m due East and then 15m due West, the total distance is
Answers
Answer:30m east
Explanation: 45m-15m=30m, which cancels out the one to the west. All that is left is 30m east.
Is this a test/quiz btw?
During a ball in the cup lab students notice that a ball rolling horizontally on the table pass through two photogates .30 meters apart in 0.133 seconds. They measure the height of the table to be 0.85 meters. Determine the distance away from the tables edge the students must place a cup to catch the ball to complete the activity?
Answers
Answer:
2 meters
Explanation:
Before the collision, the toy train is travelling at 0.5 m/s. The train and the stationary
truck both have a mass of 75 g.
Calculate the momentum of the toy train before the collision?
Answers
Answer:
Explanation:
p = mv = 0.075(0.5) = 0.0375 kg•m/s
A 15 g bullet is fired at 630 m/s into a 4.9 kg block that sits at the edge of a 75-cm-high table. The bullet embeds itself in the block and carries it off the table.
How far from the point directly below the table's edge does the block land?
Answers
The horizontal distance traveled below the table's edge is 29.4 cm.
The given parameters;
mass of the bullet, = 15 g = 0.015 kgspeed of the bullet, = 630 m/smass of the block, = 4.9 kgThe final velocity of the bullet-block system is calculated as follows;
[tex]m_1 u_1 + m_2u_1 = v(m_1 + m_2)\\\\0.015(630) + 4.9(0) = v(0.015 + 4.9)\\\\9.45 = 4.915 v\\\\v = \frac{9.45}{4.915} \\\\v = 1.923 \ m/s[/tex]
The time for the bullet-block system to reach the ground from the table is calculated as follows;
[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\2h = gt^2\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.75}{9.8} }\\\\t = 0.153 \ s[/tex]
The horizontal distance traveled below the table's edge is calculated as follows;
[tex]X = vt\\\\X = 1.923 \times 0.153\\\\X = 0.294 \ m\\\\X = 29.4 \ cm[/tex]
Thus, the horizontal distance traveled below the table's edge is 29.4 cm.
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