The temperature of two main-sequence stars is the same. Star B is two times further away than star A if star A is four times more brilliant.
What's the connection between temperature and luminosity for main sequence stars?The temperature and brightness of a main-sequence star depend on its mass. Bigger is always hotter and brighter. A star with ten times the mass of the sun contains nuclear energy. The brightness is 3000 times that of the sun.
Does a star's luminosity have to be the same for stars with the same temperature?Even stars with the same temperature inevitably have different luminosities. As an illustration, consider stars A and E, which have the same temperature but differ in luminosity.
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Elcft parallelepiped is in an electric field which to the left of the dashed line; has the value Eleft =< -55.37,0,0 > N/C,and Eright =< 55.37,0,0 > N/C to the right of the dashed line_ The top and bottom of the parellelepiped are rectangles Iying in the = plane, and measure /1 by l2, as shown: The left and right faces are rectangles inclined by an angle 0 = 83.489 from the € axis, and measure lz by l3. The values Of L1,l2, and l3 are 23.82 cm, 11.27 cm, and 32.48 cm, respectively. What charge is contained inside the parallelepiped?
There is a net flux going into the surface, the parallelepiped must have a net charge (negative charge). Additionally, without an external field, all lines would point at the slab.
Six parallelograms come together to form a three-dimensional shape called a parallelepiped (the term rhomboid is also sometimes used with this meaning). It is comparable to a parallelogram in the same way that a cube is comparable to a square. There are three similar descriptions of a parallelepiped. A prism with a parallelogram-shaped base, a hexahedron with three pairs of parallel faces, and a polyhedron with six faces, each of which is a parallelogram.
There are pairs of parallel and congruent faces. The parallelepiped has twelve (12) edges and eight (8) vertices. The edges of the parallelepiped can be split into three (3) sets of four (4) edges each, where the edges in each set are all parallel and the same length. The parallelepiped is also a zonohedron.
A parallelepiped is a three-dimensional object having six faces and a parallelogram-like design. It has 8 vertices, 6 faces, and 12 edges. The parallelepiped is also known by the names rhombic, cuboid, and cube.
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what is the force on the electron, magnitude, and direction? (i.e. when it is in the plane of the page as stated above.) justify your answer.
Faraday's left hand rule gives us the direction of the force on the particles, then [tex]F^{\prime}=B q v\\[/tex] gives the size of the force.
What is direction?
Direction is characterized as the course that anything follows, the route that must be taken to go to a particular location, the direction in which something is beginning to take shape, or the direction you are facing. When you turn right instead of left, that is an illustration of direction.
If we use Faraday's left hand rule on each particle, we can determine the effect of the magnetic field on the particle. The diagram shows the direction of the fields and the "current" so we can apply the rule.
For the electron, the magnetic field will exert a force directed into the plane of the paper (or if travelling on the earth, this will be towards the earth).
For the proton, the magnetic field will exert a force out of the paper (or if travelling on the earth, this will be away from the earth).
The force on a particle of charge q moving in a magnetic field, B with a velocity v is given by:
[tex]F=B q v[/tex]
Both proton and electron have a charge of [tex]1.6 \times 10^{-19} C\\[/tex]
For the electron
[tex]$$F=\left(190 \times 10^{-3}\right) \cdot\left(1.6 \times 10^{-19}\right) \cdot 575000=1.748 \times 10^{-14} N$$[/tex]
For the proton
[tex]$$F=\left(54.2 \times 10^{-6}\right) \cdot\left(1.6 \times 10^{-19}\right) \cdot 130000=1.127 \times 10^{-18} N$$[/tex]
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The smoke from the Old Man’s furnace travels up from the basement at a velocity of |.5 meters per second. Ralphie is sitting in the kitchen above and can smell the smoke within 6 seconds. What is the approximate distance that the smoke travels up from the furnace?
The approximate distance that the smoke travels up from the furnace is 9metres.
What is distance?Distance is described as a numerical or occasionally qualitative measurement of how far apart objects or points are. In the field of physics or everyday usage, distance is usually referred to a physical length or an estimation based on other criteria.
Parameters given:
Velocity = 1.5
time = 6 seconds
We know that distance = speed x time
Hence, distance = 1.5 x 6 seconds
distance = 9 meters.
Distance is a scalar quantity that refers to how much ground an object has covered in the course of its motion while we can describe displacement as a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
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umama wants to enable user experience virtualization (ue-v) by configuring group policy settings. two important settings that she needs to configure are the setting storage location and settings template catalog location. which of the following is true of this scenario?
Correct. When new user profiles are created, the default profile is utilised. Umama wants to configure Group Policy settings to enable User Experience Virtualization (UE-V).
UEV policy settings: What are they?You can enable or disable User Experience Virtualization using this Group Policy setting (UE-V). Only versions of UE-V 2.x and earlier are affected by this setting. Use the Enable UE-V setting in Wind ows 10, version 1607, for UE-V. The location of the settings template catalogue and the location of the settings storage location are two crucial settings that she must set up.
Microsoft User Experience Virtualization: What is it?A programme called Micro soft UE-V (User Experience Virtualization) enables users to switch between Wind ows devices while keeping their current operating system (OS) and application settings.
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the following items describe observational characteristics that could indicate that an object is either a white dwarf or a neutron star. match each characteristic to the correct object.
When a white dwarf acquires enough mass for its carbon interior to start fusing, a white dwarf supernova results.
The white dwarf entirely explodes as the star's fusion starts nearly immediately throughout the entire star. When iron is produced during fusion in a star's core, a "massive stellar supernova" results. If a white dwarf in a near binary system acquires enough mass to surpass the "white dwarf limit (1.4 solar masses)," it will erupt as a supernova. The absence of hydrogen characteristics in type I supernovae's spectra at maximum luminosity is a crucial identifying trait. The remnant core of a low-mass star known as a white dwarf is protected from the force of gravity by electron degeneracy pressure. The mass of the Sun is often condensed into a body no bigger than Earth in a white dwarf.
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a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b
Maximum torque developed is (BIL²/4[tex]\pi[/tex]n).
Torque is a measure of force that can cause an object to rotate about an axis.
A force causes an object to accelerate in linear kinematics. Similarly, torque causes angular acceleration. Torque can therefore be defined as the rotational equivalent of a linear force. The line about which the object rotates is called the axis of rotation. In physics, torque is simply the tendency of a force to rotate or twist.For any structure such as a solenoid, toroid, and circular arc, the magnetic field at a certain point of the structure is always proportional to the number of turns of the coil.
As we know magnetic field is (BIL²/4[tex]\pi[/tex]n)
2[tex]\pi[/tex]rn = L
r = (L/2[tex]\pi[/tex]n)
A = [tex]\pi[/tex]r²
A = (L²/4[tex]\pi[/tex]n²)
M = niA
M = (iL²/4n[tex]\pi[/tex])
Then Torque is Z = MBSin90°
The question is incomplete, the complete question is "a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b, the maximum possible torque developed is?"
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if the short-term passive test indicates a radon level reading of 18 pci/l, which of the following statements is the most correct?
Radon is a radioactive gas which has no smell, colour or taste.
What is radon?When you breathe in radon gas, it decomposes into solid radioactive particles that can become trapped in your lungs. These particles release small energy bursts as they degrade further. Over the course of ones lifetime, this can cause lung tissue to deteriorate and result in lung cancer.
Lung cancer has radon as one of its main causes. Depending on the average radon level across the nation and the prevalence of smoking, radon is thought to be responsible for anywhere from 3% to 14% of all lung cancers. Smokers are more likely to develop lung cancer due to the interaction between radon and smoking cigarettes.
There are tried-and-true, long-lasting, and reasonably priced ways to keep radon out of new construction and reduce it in existing structures.
With a small passive detector, it is simple to measure the amount of radon indoors.
The amount of radon in the air is measured in “picocuries per liter of air,” or “pCi/L
Note that your information is incomplete and a overview was given.
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Part B
The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified equation for y in this case. Explain how you have been able to simplify it from this general displacement equation:
The general vertical displacement equation for object moving upwards is written as h = v₀t - ¹/₂gt².
What is the vertical displacement of an object?The vertical displacement of an object is the height travelled by the object.
The general kinematic equations of motion for vertical displacement is written as follows;
y = y₀ + v₀t + ¹/₂at²
where;
y₀ is initial vertical position of the objectv₀ is the initial vertical velocity of the objecta is the acceleration of the objectt is the time of motionIf the object is moving upwards, the new kinematic equation becomes;
h = 0 + v₀t - ¹/₂gt²
h = v₀t - ¹/₂gt²
where;
h is the vertical displacement of the objectv₀ is the initial vertical velocity of the objectg is the acceleration due to gravityt is the time of motion of the objectFor the simplified equation above, the acceleration of the object changes to acceleration due to gravity since the object is moving against gravity in the negative direction.
Thus, the general kinematic equations of motion for vertical displacement is written in terms of acceleration due to gravity in negative direction since it is moving upwards.
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A student releases the 4kg bob of a 0.47m long
pendulum from the position shown.
What is the period of the harmonic motion?
S
What is the frequency of the harmonic motion?
Hz
How many cycles would the pendulum make in
45s?
6
(You may answer with a decimal)
6°
Projectile launch is a kinematics application to the movement of objects near the earth's surface.
How to find Projectile launch?Since the acceleration is constant, the time it takes for the body to go up is equal to the time it takes to go down; thus, the time it takes to go up is half of the total time.
tu = ttotal/2
tu = 4.70 / 2
tu = 2.35 s
The height the ball reach
The point of maximum height where the vertical velocity is zero
vy = voy - gt
0 = voy - gt
voy = gt
= 9.8 x 2.35
= 23 m / s
By using the equation.
v²y = v²oy - 2gy
0 = v²oy - 2gy
y = v²oy/2g
y = 23²/2 x 9.8
y = 27 m
To find the initial velocity,
Initial vertical velocity = 23 m / s
vx = x/t
The throw range is 44m in time of 4.60 s
vₓ = 44 / 4.60
v₀ = [tex]\sqrt{v^{2}ox + v^{2}oy }[/tex]
v₀ = [tex]\sqrt{9.56^{2}+23^{2} }[/tex]
v₀ = 24.9 m / s
The launch angle is:
Let's use trigonometry
tan θ = voy/vox
θ = tan⁻¹ voy/vox
θ = tan⁻¹ 23/9.56
θ = 67.4°
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Which statement best explains the purpose of making the loop of wire turn between the permanent magnets in an electric generator?
OA. The magnetic fields of the magnets cause electric charges in the
moving wire to flow.
B. The poles of the magnets reverse while the loop of wire is in
motion.
OC. The electric charges in the loop are repelled if the loop of wire
stops turning.
D. The electric current in the loop causes a magnetic field to form
around the moving wire.
Answer: C
Explanation:
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A 50 gg mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cmcm-long, massless, rigid rod. The other end of the rod is attached to a frictionless pivot at the origin.
What is the gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis? Give your answer using unit vectors.
The gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis is (0.1838 Nm)k
What is torque?Torque is the turning effect of a force which causes rotation. It is given by τ = F × d where
F = force and d = perpendicular distance of force from point of action.What is the gravitational torque about the pivot when the mass is 60° above the +x-axis?Since a 50 g mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cm-long, massless, rigid rod.
The gravitational torque is given by τ = F × d where
F = component of weight perpendicular to rod = -(mgcosФ)j where m = mass, g = acceleration due to gravityФ = angle between rod and x axis and d = length of rodSo, τ = F × d
= -(mgcosФ)j × di
= mgdcosФ(-j × i)
= -mgdcosФ(j × i)
= -mgdcosФ(-k)
= (mgdcosФ)k
Given that
m = 50 g = 0.05 kgg = 9.8 m/s²,d = 75 cm = 0.75 m and Ф = 60°Substituting the values of the variables into the equation, we have
τ = (mgdcosФ)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.3675 kgm²/s² × 0.5)k
= (0.18375 kgm²/s²)k
= (0.18375 Nm)k
≅ (0.1838 Nm)k
So, the torque is (0.1838 Nm)k
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A rod has a length 2.0000m at 20.0C. The length of the rod increases to 2.0005
5.00 × 10-3/K is the coefficient of thermal expansion of the material from which the rod is made as it increases its length to 2.0005m
What is the purpose of the thermal expansion coefficient?The coefficient of thermal expansion explains how an object's size varies when temperature changes. In particular, it measures the fractional size change per degree change in temperature at constant pressure, where lower coefficients denote a reduced propensity for size change.
What does thermal expansion mean?The propensity of matter to alter shape, volume, and area in reaction to a change in temperature is known as thermal expansion. The average molecular kinetic energy of a substance has a monotonic relationship with temperature.
How is thermal expansion calculated?Use the equation for linear thermal expansion ΔL=αLΔT Δ L = α L Δ T to calculate the change in length, ΔL .
How to solve?Get your rod hot enough to achieve, say, 1% linear thermal expansion.
The rod's dimension has increased to 1.01 units.
The rod is 1.030301 times its original size, or 1.013 larger than it was before heating.
This equals 1.03 when rounded to three major figures. In other words, its volume is 3% higher than that of the cold specimen.
The linear expansion is tripled, or 3%, by the volumetric expansion.
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Complete question:
A rod has a length 2.0000 m at 20.0°C. The length of the rod increases to 2.0005 m when the temperature increases to 40.0°C. What is the coefficient of thermal expansion of the material from which the rod is made?
A pulley system is used to lift up a 90N boulder. What is the mechanical advantage if you only need to use 15N of force to lift the boulder?
By simply creating more loops or pulleys, the pulley system's mechanical advantage can be accomplished.
Equation:
It is known that a pulley system can lift a crate with 90 newtons of force. Finding the pulley system's mechanical advantage is important if the input force is 15 newtons.
The force makes the distance longer as though it were working. Mechanical advantage is not greatly affected by the number of pulleys. This is only based on the amount of weight that needs to be lifted.
Therefore,
F1/F2 = 90/15
F1/F2 = 6
Given that the crate's weight is 90 N and the input force is 15 N, this makes sense.
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find the finel angular velocity (w) when the intial angular velocity(w) is 5rad/s the Angular acceleration is 2rad/s² and the time of motion is 5sec
Answer:
15 rad/s
Explanation:
Given:
α = 2 rad/s²
ω₀ = 5 rad/s
t = 5 s
Find: ω
ω = αt + ω₀
ω = (2 rad/s²) (5 s) + (5 rad/s)
ω = 15 rad/s
A 20 g ball of clay traveling east at 2.5 m/s collides with a 25 g ball of clay traveling north at 2.0 m/s .
What is the speed of the resulting 45 g ball of clay?
What is the direction of the resulting ball of clay?
The final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰.
The given parameters;
mass of the first clay ball, m₁ = 20 g = 0.02 kg
initial velocity of the first clay ball, u₁ = 3 m/s
mass of the second clay ball, m₂ = 30 g = 0.03 kg
initial velocity of the second ball, u₂ = 2 m/s
The initial momentum of the fist ball is calculated as follows;
P₁ = m₁u₁
P₁ = (0.02)(3)
P₁ = 0.06 kg.m/s
The initial momentum of the second ball is calculated as follows
P₂ = m₂u₂
P₂ = (0.03)(2)
P₂ = 0.06 kg.m/s
The resultant initial momentum of the two balls is calculated as follows;
Apply the principle of conservation of momentum, to determine the final velocity of the two balls;
The direction of the two ball's velocity is calculated as follows;
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Suppose a rocket is fired vertically upward from the surface of the earth with one-half of the esacpe speed. How far from the center of the earth will it reach vefore it begins to fall back?
(let g = 9.8 m/s^2 and Re = 6370 km)
A. 1.3 * 104 km
B. 8.5 * 103 km
C. 9.6 * 103 km
D. 2.6 * 104 km
E. 1.9 * 104 km
The correct answer: B.
I do not understand why I am not getting the correct answer.
The distance before it falls back to the earth is 8.5 * 103 km. Option B
What is the escape velocity?We know that the escape velocity has to do with the velocity that has to be supplied to a material so that the material can be able to escape from the earth's gravitational pull. Let us recall that the whole earth is a large gravitational field. If we throw an object up then the object would have to certainly fall doen to the ground under the influence of gravity.
It is therefore clear that gravity is the force that draws any object that goes upwards down back to the ground. Given that we have been told here that the speed is one-half of the escape speed, then then the magnitude of the speed is 5590.3 m/s.
Given that;
v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Then;
u^2 = 2gh
h = u^2/2g
h = ( 5590.3)^2/2 * 9.8
= 8.5 * 103 km
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Calculate the power of an electric bulb which consumes 2400 J in a minute
power of the bulb = 40 watt
Briefing
Power: In physics, the term "power" refers to the rate at which a task is completed, or how much energy is used during the allotted time.
What is energy now?
In physics, energy refers to the ability to do a task. It may exist in different forms, including potential, kinetic, thermal, electrical, chemical, radioactive, and others.
Consequently, in light of the posed query:
2400 J of energy
60 seconds in a minute is time.
As a result, we know that Power = Energy/Time.
p = E/t p = (2400-/60) joules/sec
p=40 W
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apply the loop rule to loop 2 (the smaller loop on the right). sum the voltage changes across each circuit element around this loop going in the direction of the arrow. remember that the current meter is ideal.express the voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.
The voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.ΣΔV = 0 = I3 ⋅ R3 - I2 ⋅ R2.
When applying Kirchhoff's second rule the loop rule we need to identify closed loops and decide whether to loop clockwise or counterclockwise. For example, in Figure 3 the loop was traversed in the same direction as the current.
Loop 1 is the full loop and Loop 2 is the small loop on the right. To apply the loop rule, add all those voltage changes. Kirchhoff's Second Law, also known as Kirchhoff's Voltage Law states that the sum of all voltages around the closed loop of any circuit must be zero. This is a result of charge conservation and energy conservation.
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in the figure, light is incident at angle on a boundary between two transparent materials. some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air.
(a) θ5 in the air is 56.9° and (b) θ4 in the bottom material 35.30°. Normally, a light beam that strikes an angle on a prism's refracting face emerges from the opposite face.
How to calculate?(a) Approximating n=1 for air, we have
n1. sinθ1 = (1)sinθ5 ⇒56.9°=θ5
and with the more accurate value for n air in Table below, we obtain 56.80.(b) Equation n1 sinθ c =n2 sin 90° leads to,
n1 sinθ 1=n2 sinθ2 =n3 sinθ 3 =n4 sinθ 4
so that. θ4 =sin −1( n1/n4.sinθ 1 )=35.30° .
What does angle of incidence mean?The angle of incidence is formed by a line drawn perpendicular to the reflecting barrier and the wave's direction of motion.
Is the incidence angle of refraction?Refraction Depending on the Refractive Indices in the Two Media and the Angle of Incidence. Snell's law states that the angle of incidence, I and the proportion of the refractive indices of the two media that make up the interface determine the angle of refraction, r.
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A steam power plant operates on the simple ideal Rankine cycle between the pressure limits of 10 kPa and 10 MPa, with a turbine inlet temperature of 600 degree C. The rate of heat transfer in the boiler is 800 kJ/s. Disregarding the pump work, the power output of this plant is: A. 284 kW B. 800 kW C. 508 kW D. 243 kW E. 335 kW
Option E; The pump work, the power output of this plant is 335KW
Pressure. at turbine. inlet P1 = 10 Mpa.
Enthalpy at turbine inlet = h1=3625.84 KJ/kg.
Entropy at turbine inlet S1 =6.90 KJ/kg-K.
It is given that process performed acceording to ideal rankine cycle which is "Reversible adiabatic expansion' in case of turbine wor., Since it is reversible adiabatic expansion, entropy at turbine inlet and entropy at turbine outlet is constant. So quality at turbine outlet is evaluated by using this relation. S1 = S2.
Pressure at turbine outlet = 10 Kpa.
Enthalphy of steam = hg =2675.1 KJ/kg.
Enthaphy of liquid=hf =417.51 KJ/kg
Entropy of steam = Sg =7.3589 KJ/kg-K.
Entropy of liquid =Sf =1.302 KJ/kg-K.
We know S1 = S2 =6.090=1.302+x(7.3589 - 1.302).
Quality at turbine exit x =0.79.
Enthalphy at exit = h2 = 417.51+ 0.79*(2675.1 - 417.51) =2201 KJ/kg-K.
heat transfered= mass*(enthlphy at exit of condenser - enthalphy at turbine inlet), Since pump work negleted
At exit of condenser, steam gets converted into water at 10 Kpa pressure whose enthalphy is hf =417.51 KJ/kg.
800 = m(3625.84 - 417.51).
mass flow rate of steam = 0.24 Kg/sec.
Turbine work the power output of this plant is = m(h1 - h2) =0.24(3625.84 - 2201) = 335 KW.
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You drop a 2.00 kg book to a friend who stands on the ground at distance D = 10.0 m below. If your friend's outstretched hands are at distance d = 1.50 m above the ground (Fig. 8-28), (a) how much work Wg does the gravitational force do on the book as it drops to her hands? (b) What is the change ΔU in the gravitational potential energy of the book–Earth system during the drop? If the gravitational potential energy U of that system is taken to be zero at ground level, what is U(c) when the book is released and (d) when it reaches her hands? Now take U to be 100 J at ground level and again find (e) Wg, (f) ΔU, (g) U at the release point, and (h) U at her hands.
The aswers are as follows:
a) 167J, b) -167J, c) 196J, d)29J, e)167J, f)-167J g)296J, and h) 129J
If your friend's outstretched hands are at distance d = 1.50 m above the ground, (a) work Wg does the gravitational force do on the book as it drops to her hands 167J, b) -167J, c) 196J, d)29J, e)167J, f)-167J g)296J, and h) 129J
a) Work = mg(Ac)
= 2 × 9.8 × (10 - 1.5) = 167j
b) ΔU = Ubc - Uab = Mg(bc) - Mg(ab)
= mg(bc - ab)
= 2 × 9.8 (1.5 - 10) = -167j
c) Potential energy at reach point v = mg(AB) = 2 × 9.8 × 10 = 196J
d) Potential energy at reach point U = mg (bc) = 2 × 9.8 × 1.5 = 29.4j
e) Total work wg = mg (ac) = 2 × 9.8 × 3.5 = 167j
f) ΔU = -wg = - 167j
g) ui = mg × AB + 100 = 196 + 100 = 296j
h) uf = mg × bc + 100 = 29.4 + 100 = 129j
Given the possibility of motion, gravitational forces can sort phases of various densities. Although high temperatures are not anticipated for the early Earth, widespread melting is one possibility. Sorting in response to the outgassing of deeply buried ices is a more feasible scenario. Such processes would have altered the moment of inertia, necessitating an adjustment to the angular velocity. Friction opposes gravitational settling and prevents it from being conservative, which makes quantification dubious. The ensuing phase separation and angular momentum alterations would not need to be as extensive as commonly believed if an iron protocore existed.
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when an object of unknown mass is attached to an ideal spring with force constant 130 n/m, it is found to vibrate with a frequency of 7.25 hz.
When a massless item is fastened to an ideal spring with a force constant of 130 n/m, it is discovered that it vibrates at a frequency of 7.25 hz. The motion lasts 0.138 seconds.
What does a spring's force constant mean?In accordance with Hooke's law, the force necessary to compress or enlarge a spring is directionally related to or proportionate to the length it is stretched to. K is used to indicate the force constant.
What exactly is a vibration's frequency?The rate of vibrations and oscillations is called frequency, and it is expressed in hertz (Hz) units. To distinguish and ascertain vibrational patterns, frequencies are used. Therefore, a faster-vibrating atom would be seen as having a greater frequency than a slower-vibrating one.
Briefing:T= 1/f = 1/7.25 Hz = 0.138s
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The given question is incomplete. The complete question is:
When an object of unknown mass is attached to an ideal spring with force constant 130 n/m, it is found to vibrate with a frequency of 7.25 hz. What is the period of the motion?
sand dunes form when ? ? sand build up in one place
Sand dunes form when the mound grows in circumference and height due to subsequent sand build up in one place by wind.
What is sand dunes?A sand dune is a mass of loose sand grains that have accumulated due to wind movement. The mound will eventually get so massive that it will collapse under its own weight to form a sand dune as it increases in height and circumference as a result of additional sand deposits. A set of sand dunes is referred to as a sand dune complex or sand dune system by geologists.
On the other hand, depending on the quantity of vegetation present, vast clusters of sand dunes are referred to as sand seas or sand dune fields. Ergs are another name for sand seas.
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Your question is incomplete, but most probably the question was:
sand dunes form when _______ sand build up in one place by wind.
Can someone help me and tell me as soon as possible
Answer:
copy and complete this diagram so that the system is in equilibrium
aphasia
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience:
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience: aphasia.
Aphasia is the inability to understand or form language due to damage to certain areas of the brain The main causes are stroke and head trauma. Although the prevalence is difficult to determine, aphasia due to stroke is estimated at 0.1-0.4% in the Global North. Aphasia can also be the result of a brain tumor, brain infection, or neurodegenerative disease (such as dementia).
To be diagnosed with aphasia, communication after an acquired brain injury Speech or language must be significantly impaired in one (or more) of the four aspects of Alternatively, in the case of progressive aphasia, it must have decreased significantly over a short period of time. The four dimensions of communication are auditory comprehension, verbal expression, reading and writing, and functional communication.
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A taxi company is trying to decide whether to purchase brand A or brand B tires for its fleet of taxis. To estimate the difference in the two brands, an experiment is conducted using 12 of each brand. The tires are run until they wear out. The results are Brand A: \overline{x}_1 = 36. 300 x
1
=36.300 kilometers, s_1s 1
= 5000 kilometers. Brand B: \overline{x}_2 = 38. 100 x
2
=38.100 kilometers, s_2 = 6100s 2
=6100 kilometers. Compute a 95% confidence interval for \mu A − \mu BμA−μB assuming the populations to be approximately normally distributed. You may not assume that the variances are equal.
A 95% confidence interval for μA-μB is 0.025
If we want to make a 95% confidence interval estimate for an unknown population mean. This means that there is a 95% probability that the confidence interval will have the true population mean.
Thus, P( [sample mean] - margin of error < μ < [sample mean] + margin of error) = 0.95.
We have,
n1 = 12
s1 = 5000
mean x1 = 36300
n2= 12
s2 =6100
mean x2 =38100
We have to find 95%confidence interval for μA- μB
from 95% = 100 (1-α%)
1-α = 0.95
α = 1-0.95 =0.05
α/2 = 0.025
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Two blocks, with masses indicated in the figure above, are at rest on a horizontal surface and connected by a string of negligible mass and a compressed spring. There is negligible friction between the blocks and the surface. The string is cut, and the spring pushes the blocks away from each other. Which of the following statements are true about the motion of the blocks immediately after the string is cut? select two answers.
1. The velocity of the center of mass of the two-block system is zero.
2. The magnitude of the acceleration of the left block is greater than that of the right block.
The center of mass, or balancing point, of a distribution of mass in space is the only location where the total of the weighted relative positions of the distributed mass equals zero. In order to accelerate linearly without also accelerating angularly, a force might be applied at this moment. Using the center of mass as a reference point simplifies calculations in mechanics quite a bit. To imagine how an object would move, one can imagine a hypothetical location where the object's total mass is concentrated. To apply Newton's equations of motion to a particular object, the center of mass is the particle equivalent of that thing.
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An ice skater with rotational inertia I0I0 is spinning with angular speed ω0ω0. She pulls her arms in, thereby increasing her angular speed to 4ω04ω0. Her rotational inertia is then:
a. I0I0
b. I02I02
c. 2I02I0
d. I04I04
e. 4I0
The new rotational inertia or final moment of inertia of the girl is I₀ / 4.
option D is the correct answer.
What is rotational inertia?
Rotational inertia is a property of any object which can be rotated.
Rotational inertia or moment of inertia of an object is a measure of the resistance of an object to changes in its angular velocity.
Based on the law of conservation of angular momentum, the formula for her new rotational inertia is given as;
I₀ω₀ = I₁ω₁
where;
I₀ is the initial moment of inertiaI₁ is the final moment of inertiaω₀ is the initial angular velocity of the objectω₁ is the final angular velocity of the objectThe given parameters include,
initial angular velocity = ω₀
final angular velocity = 4ω₀
initial moment of inertia = I₀
The final moment of inertia of the girl is calculated as
I₁ = ( I₀ω₀ ) / (ω₁)
I₁ = ( I₀ω₀ ) / (4ω₀)
I₁ = I₀ / 4
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With respect to stellar spectra, select all of the correct statements from the following list.
Doppler shifts in spectral lines give clues to the motions of stars.
The Lyman and Paschen series of the hydrogen spectrum are not visible.
Stellar spectra are absorption spectra.
Spectra can reveal the chemical composition of stars.
With respect to stellar spectra Doppler shifts in spectral lines give clues to the motions of stars.
What do spectral lines tell us?The spectral lines of an element can be used by astronomers to determine the element's temperature as density within the star. The spectral line may also be used to display the star's electric flux. The width of the line may be used to gauge how rapidly the material is moving. We can learn something about stellar winds from this.
How are elements recognized by spectral lines?Dark bands in a broad band can be used to identify components, and it can also reveal an object's temperature: The spectrum has more green, blue, and violet hues as the temperature rises. The spectrum of relatively cool objects is dominated by deep red or red and yellow.
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show an example of the method described above. ii. why might your calculated value for the half-life of barium-137 from this method differ from the accepted value?
By monitoring a sample's activity as it decays, Ba-137m can be calculated. Utilizing AktivLab, the radioisotope Ba-137half-life, m's which was isolated from Cs-137, is found.
How is the experiment's half-life determined?After that, the half-life is calculated using the basic concept of activity, which is the sum of the radionuclide decay constant,, and the number of radioactive atoms present, N. By using the formula = ln2/T1/2, one may solve for and obtain the half-life.
Describe half-life in detail.?A half-life is the duration needed for something to reduce in quantity by half. The phrase is most frequently used in reference to radioactive decay, which takes place when unstable atomic particles shed energy. There are 29 elements that can travel through this, according to known facts.
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