1 by 6 of a construction work is finished in the first year, 1 by 8 part in the second year and 1 by 12 in the third year how much work is finished in 3 year

Answer:

x=19.86

Step-by-step explanation:

use cosine,

cos 19°=x/21

x=cos 19° * 21

x=19.86

Answer:

Me = no it doesn't....

you = why tho

me = becoz function not given .....

so lame joke ik...

Answer: a = -8

Step-by-step explanation:

Given

-8a - 5 = -7a + 3

Subtract 3 on both sides

-8a - 5 - 3 = -7a + 3 - 3

-8a - 8 = -7a

Add 8a on both sides

-8a - 8 + 8a = -7a + 8a

a = -8

Hope this helps!! :)

Please let me know if you have any questions

Answer:

a = -8

Step-by-step explanation:

-8a-5=-7a+3                    Add 5 to both sides.

- 8a = - 7a + 3 + 5           Combine

-8a = - 7a + 8                  Add 7a to both sides

-8a + 7a = 8                    Combine

-a = 8                              Multiply by - 1

a = - 8                          

When you get a weird number like this, you should check it.

LHS = -8(-8) - 5

LHS = 64 - 5

LHS = 59

RHS = -(7*-8) + 3

RHS = -(-56) + 3

RHS = 56 + 3

RHS = 59

So a = - 8 must be right.

Answer:

1.

= Here,

Narasimha invest = 120,000

Madhu 135,000

pavan =

Answer:

definition of perpendicular lines

Answer:

Step-by-step explanation:

होय साहेब!!!!!!!!!!

0.7% percent is the answer

Answer:

The answer is the last one, (X^2-2)/3!

Step-by-step explanation:

To get the inverse of a function, you switch the variables and solve for y. Doing this produces the last choice.

Answer:

[tex] \rm \displaystyle x \approx \bigg \{ {59.3}^{ \circ} + \frac{n\pi}{2} , - {14.3}^{ \circ} + \frac{n\pi}{2} \bigg \}[/tex]

Step-by-step explanation:

we would like to solve the following trigonometric equation:

[tex] \rm \displaystyle \sin(x) \cos(3x) + \cos(x) \sin(3x) = \tan( {140}^{ \circ} ) [/tex]

the left hand side can be rewritten using angle sum indentity of sin which is given by:

[tex] \rm \displaystyle \sin( \alpha + \beta ) = \sin( \alpha ) \cos( \beta ) + \cos( \alpha ) \sin( \beta ) [/tex]

therefore Let

Thus substitute:

[tex] \rm \displaystyle \sin(x + 3x) = \tan( {140}^{ \circ} ) [/tex]

simplify addition:

[tex] \rm \displaystyle \sin(4x) = \tan( {140}^{ \circ} ) [/tex]

keep in mind that sin(t)=sin(π-t) saying that there're two equation to solve:

[tex] \begin{cases} \rm \displaystyle \sin(4x) = \tan( {140}^{ \circ} ) \\ \\ \displaystyle \sin(\pi - 4x) = \tan( {140}^{ \circ} ) \end{cases}[/tex]

take inverse trig and that yields:

[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) \\ \\ \displaystyle \pi - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) \end{cases}[/tex]

add π to both sides of the second equation and that yields:

[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) \\ \\ \displaystyle - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi\end{cases}[/tex]

sin function has a period of 2nπ thus add the period:

[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) + 2n\pi\\ \\ \displaystyle - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi + 2n\pi\end{cases}[/tex]

divide I equation by 4 and II by -4 which yields:

[tex] \begin{cases} \rm \displaystyle x= \frac{ { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) }{4} + \frac{n\pi}{2} \\ \\ \displaystyle x = - \frac{{ \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi}{4} - \frac{n\pi}{2} \end{cases}[/tex]

recall that,-½(nπ)=½(nπ) therefore,

[tex] \begin{cases} \rm \displaystyle x= \frac{ { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) }{4} + \frac{n\pi}{2} \\ \\ \displaystyle x = - \frac{{ \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi}{4} + \frac{n\pi}{2} \end{cases}[/tex]

by using a calculator we acquire:

[tex] \begin{cases} \rm \displaystyle x \approx - {14.3}^{ \circ} + \frac{n\pi}{2} \\ \\ \displaystyle x \approx {59.3}^{ \circ} + \frac{n\pi}{2} \end{cases}[/tex]

hence,

the general solution for: for the trig equation are

[tex] \rm \displaystyle x \approx \bigg \{ {59.3}^{ \circ} + \frac{n\pi}{2} , - {14.3}^{ \circ} + \frac{n\pi}{2} \bigg \}[/tex]

Answer:

88 ft^3

Step-by-step explanation:

First find the volume of the rectangular prism on the left

V = l*w*h = 2*(4)*8 = 2*4*8= 64 ft^3

Then find the volume of the rectangular prism on the bottom

The base is not 5 but 5-2 since we used 2 on the left side

V = l*w*h = (5-2) *4*2 = 3*4*2 = 24 ft^3

Add them together

64+24=88

Answer:

x = 65 degrees

Step-by-step explanation:

x° + x° + 50° = 180°

2x + 50° = 180°

2x = 180° - 50°

2x = 130°

x = 130°/2

x = 65°

Answer:

Sequence number is a list of numbers that are linked by rule.

Answer:

f(5) = -2

Step-by-step explanation:

f (x) = -x + 3

Let x = 5

f(5) = -5+3

f(5) = -2

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{f(x) = -x + 3}\\\huge\boxed{\rightarrow}\huge\text{ f(x) = -5 + 3}\\\huge\boxed{\rightarrow}\huge\text{ y = -5 + 3}\\\huge\boxed{\rightarrow}\text{ y = -2}\\\\\\\boxed{\boxed{\huge\text{Answer: \bf f(x) = -2}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

Option B, $2020.00

Step-by-step explanation:

Volume of the pool,

12×5×14.5+4×5×7

= 1010 ft³

each cubit foot costs $2, so 1010 ft³ will cost,

1010×$2

= $2020

Answer:

Step-by-step explanation:

This is classic right triangle trig. If you're solving for x, which you are, you have to consider how the given sides relate to that angle. The side with a length of 50 is opposite the angle x, while the side of length 36 is adjacent to angle x. The trig ratio that utilizes the sides opposite and adjacent is tangent; HOWEVER, we are looking for a missing angle. Finding missing angles on your calculator requires the 2nd button. To find the missing angle x, you are looking for the angle that has a tangent ratio of 50 over 36 (opposite over adjacent...Toa in SohCahToa). Hit the 2nd button on your calculator and then the tangent button (in degree mode, not radian mode) and you will see this on your screen:

[tex]tan^{-1}([/tex]

After the parenthesis, enter the fraction and then hit the enter button to get the angle measure in degrees:

[tex]tan^{-1}(\frac{50}{36})=54.2[/tex] degrees.

It's very important that you learn how to use your calculator to find the trig identities that give you the ratio in decimal form and how to find the missing angles. Missing angles always use the 2nd button along with whatever trig identity you are using.

Answer:

B

Step-by-step explanation:

Area of shaded region + Area of unshaded region = Area of circle

Area of the unshaded sector=256*pi-32*pi=224*pi

Answer:

radius Is 16

total area becomes pi r ^ 2 = 16^2 pi = 256pi

remaining area becomes

256 pi - 32 pi = 224 pi option b

brainliest pls

the value of 4 tenths x hundreds.

4000

Answer:

40

Step-by-step explanation:

4/10 x 100 = 40

Answer:

Rate of change, is also another word for slope.

Slope --> y2 - y1 / (x2-x1)

Assuming the table is already in xy, the cords are in xy form too.

1) (8,8)

2) (11,10)

Plug points into slope eq

--> 10 - 8 = 2

----> 11 - 8 = 3

2/3 Is the slope/rate of change.

Answer:

Step-by-step explanation:

16x^2 = (4x)^2

49 = 7^2

16x^2 - 49 = (4x)^2 - (7)^2

===========================================================

Explanation:

Refer to the diagram below.

There's a lot of info given to us that we don't need (and won't use).

The only key piece of info we'll really use is the fact that angle XZY is 27 degrees.

Draw in segments RU and RT to form quadrilateral TRUZ

Focusing solely on this quadrilateral, we see that the angles T and U are 90 degrees each (since the tangents are perpendicular to the radii at the point of tangency). Furthermore, we see that angle Z is 27 while angle R is x

For any quadrilateral, the four angles always add to 360 degrees

T+R+U+Z = 360

90+x+90+27 = 360

x+207 = 360

x = 360-207

x = 153

That means angle R of quadrilateral TRUZ is 153 degrees.

Furthermore, it means angle TRU is 153 degrees.

By extension, it indicates that minor arc TU is 153 degrees.

That makes arc TSU = 360 - (minor arc TU) = 360 - 153 = 207 degrees

By Joining TR and UR we got 2 right angles and a Quadrilateral

now

In a Quadrilateral sum of angles=360°

[tex]\\ \large\sf\longmapsto x+90+90+27=360[/tex]

[tex]\\ \large\sf\longmapsto x+180+27=360[/tex]

[tex]\\ \large\sf\longmapsto x+207=360[/tex]

[tex]\\ \large\sf\longmapsto x=360-207[/tex]

[tex]\\ \large\sf\longmapsto x=153°[/tex]

Answer:

40 degrees

Step-by-step explanation:

The formula for calculating the sum of interior angles is ( n − 2 ) × 180 (n = Number of sides)

in this scenario you have 9 sides so put it in the equation.

(9 - 2) ×180 = 1260

1260 is the sum of all the interior angles so we must divide this number by the number of sides to get the angle of one individual interior angle.

1260/9 = 140

180-140 = 40 degrees

Answer:

x=5

y=2

w= -5

Step-by-step explanation:

We have that the two matrix are equal, so all corresponding elements are equal.

X-Y=3

From the second row and second column, we have y=2

so x-2=3

x=5

From the third row and the first column, we have w= - 5

Answer:

x=10, y=24

[tex]\left(34-y\right)^2+y^2=676[/tex]

Step-by-step explanation:

Answer:

x = 10 and y = 24

Step-by-step explanation:

Perimeter of triangle = sum of the 3 sides of the triangle

:. x + y + 26 = 60

x + y = 60 - 26

x + y = 34 ---- (1)

From Pythagoras theorem,

x² + y² = 26²

x² + y² = 676 ---- (2)

From equation (1): y = 34 - x

:. x² + (34 - x)² = 676

x² + 1,156 - 68x + x² = 676

x² + x² - 68x + 1,156 - 676 = 0

2x² - 68x + 480 = 0

x² - 34x + 240 = 0

(x² - 24x) - (10x + 240) = 0

x(x - 24) -10(x - 24) = 0

(x - 24)(x - 10) = 0

x = 24 or 10

y = 34 - x

y = 34 - 10 = 24

:. x = 10 and y = 24

Answer:

B

Step-by-step explanation:

the decay will cause loss so it's the function B

Answer:

B

Step-by-step explanation:

trust

Answer:

SA = 112

Step-by-step explanation:

A = 2wl + 2lh + 2hw

length = 8 km

width = 2 km

height = 4 km

SA = 112 km

[tex]\\ \sf \longmapsto 39+4+q=-14[/tex]

[tex]\\ \sf \longmapsto q+43=-14[/tex]

[tex]\\ \sf \longmapsto q=-14-43[/tex]

[tex]\\ \sf \longmapsto q=-57[/tex]

Area = Side^2

Area =( 4x + 2 )^2

Area = (4x)^2 + 2(4x)(2) + (2)^2

Area = 16x^2 + 16x + 4

Thus the correct answer is option B .

From my knowledge:

²−2−15=0

x=5

x=-3