1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.
Answers
Answer:
a) Please find attached the required drawing of light passing through the lens
By the use of similar triangles;
The image distance from the lens = 26 cm
The height of the image = 14 cm
c) The image distance from the lens = 26 cm
The height of the image = 14 cm
Explanation:
Question;
a) Determine the image distance and the height of the image
b) Calculate the image position and height
The given parameters are;
The height of the object, h = 14 cm
The distance of the object from the mirror, u = 26 cm
The focal length of the mirror, f = 13 cm
The location of the object = 2 × The focal length
Therefore, given that the center of curvature ≈ 2 × The focal length, we have;
The location of the object ≈ The center of curvature of the lens
The diagram of the object, lens and image created with MS Visio is attached
From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m
The height of the image = The height of the object - 14 cm
b) The lens equation is used for finding the image distance from the lens as follows;
[tex]\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}[/tex]
Where;
v = The image distance from the lens
We get;
[tex]v = \dfrac{u \times f}{u - f}[/tex]
Therefore;
[tex]v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26[/tex]
The distance of the image from the lens, v = 26 cm
The magnification, M =v/u
∴ M = 26/26 = 1, therefore, the object and the image are the same size
Therefore;
The height of the image = The height of the object = 14 cm.
Related Questions
Courtney wants to practice doing science. Which example best illustrates her
using inquiry?
A. Courtney decides to drop several different objects off her
apartment's porch to see which falls the fastest.
B. Courtney pays close attention in her physical science class to see
if her teacher explains the speed of falling objects.
C. Courtney reads about the history of the study of gravity and learns
about why scientists first studied falling objects.
D. Courtney finds a calculation that explains the speed of falling
objects. She tries to understand the calculation by writing it down.
Answers
Answer:
A
Explanation:
because she wants to practice science and A is the practical option.
A student has connected two generator/motors together. The student turns the crank 20 times and noticed the other crank only turns 12 times. What happened to the "missing" energy?
Answers
Answer:
eu não consigo entender essa situação o Fim dessa história só pode ter confusão dos iguais com cabeças diferentes a invés de amigas são concorrentes
You can do only number 1 only
Answers
For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C
t = Q / I
From question:
Q = 100C
I = 0.1A
Therefore, time, t = 100 / 0.1 = 1000 s
What is the frequency of a wave that passes a given point 412 times in 4.0
seconds?
O A. 0.0097 s
OB. 103 Hz
O C. 408 S
O D. 1650 Hz
SUBMIT
Answers
Answer: A.0,0097s
Mas a unidade aí deveria ser Hertz (Hz)
Explanation:
Answer:
103 hz
Explanation:
A person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person.
Answers
Answer:
Pressure = 39200 N/m²
Explanation:
Given the following data;
Mass = 60 kg
Area = 150 cm²
Conversion:
1 centimeter square = 0.0001 meter square
150 centimeter square = 150 * 0.0001 = 0.015 m²
To find the pressure exerted on the ground by the person;
Mathematically, pressure is given by the formula;
[tex] Pressure = \frac {Force}{area} [/tex]
First of all, we would determine the force exerted by the person.
Force = mass * acceleration due to gravity.
We know that acceleration due to gravity is equal to 9.8 m/s².
Substituting into the formula, we have;
Force = 60 * 9.8
Force = 588 Newton
Next, find the pressure;
[tex] Pressure = \frac {Force}{area} [/tex]
Substituting into the formula, we have;
[tex] Pressure = \frac {588}{0.015} [/tex]
Pressure = 39200 N/m²
Calculate the force that is applied on this 0.25 kg ball, as it goes down to hit the ground.
(given gravity= 9.8 m/s2).
Answers
Answer:
F = 2.45 N
Explanation:
m = 0.25 kg
a = 9.8 m/s^2
F = ma
F = (0.25)(9.8)
F = 2.45 N
A rock from the top of a hill is falling from rest.
Object name?
Starting energy form?
Conversion?
Final energy form?
Non usable form of energy?
Answers
Object name:- Rock
Starting energy:- Kinetic energy
Conversion:- Potential to kinetic energy
Final energy form:- Potential energy
Non usable form if energy:- Nil [ As it has potential & kinetic both]
Scientists today use satellites as well as telescopes to observe the universe. Suggest one way
that developments in equipment have changed the information scientists collect about
planets.
Answers
Answer:
Rovers, unmanned space probes, modern instruments,
Explanation:
how do icebergs form
Answers
Answer:
They break off large ice sheets found at the North and South poles.
Answer:
The answer is D
Explanation:
They break off large ice sheets found at the poles.
Your friends sit in a sled in the snow. If you apply a force of 95N to them they have an acceleration of 0.8 m/s2. What is their mass
Answers
A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to friction?
Answers
Answer:
the kinetic energy lost due to friction is 22.5 J
Explanation:
Given;
mass of the block, m = 0.2 kg
initial velocity of the block, u = 25 m/s
final velocity of the block, v = 20 m/s
The kinetic energy lost due to friction is calculated as;
[tex]\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 - \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J[/tex]
Therefore, the kinetic energy lost due to friction is 22.5 J
Answer:
22.5 J
Explanation:
It loses the difference in kinetic energy between the starting and ending speeds and that is (1/2)(M)(V1)^2 - (1/2)(M)(V2)^2 = (1/2)(M)((V1)^2 -(V2)^2) = (1/2)(0.2 kg)((25)^2 - (20)^2) = 22.5 Joules.
Explique cómo es que las estrellas emiten una radiación, específicamente qué es lo que sucede a nivel atómico
Answers
Answer:
Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella
A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella
Explanation:
A steel railroad track has a length of 79 when the temperature is 2◦C. What is the increase in the length of the rail on a hot day when the temperature is 35◦C? The linear expansion coefficient of steel is 11 × 10−6 (◦C)−1.
Answers
Answer:
We know that the length is 79 (there are no units of length in the question, so i will leave it as it is written, without units) when the temperature is 2°C.
We want to find the increase in length when the temperature is 35°C, knowing that the linear expansion coefficient is 11*10^(-6) °C^-1
The change in length is just given by the equation:
[tex]\Delta L = \alpha*L_0* (T_1 - T_0)[/tex]
where:
α = 11*10^(-6) °C^-1
T₀ is the initial temperature, so T₀ = 2°C
T₁ is the final temperature, so T₁ = 35°C
L₀ is the initial length, so L₀ = 79
Replacing these in the equation we get:
ΔL = ( 11*10^(-6) °C^-1)*79*(35°C - 2°C)
= 0.28677
So the length of the railroad will increase by 0.28677
Mrs. Botts applies brakes on a car help it to decelerate at the rate of -0.80m/s2. What distance is required to stop the car when it is moving 17 m/s.
Answers
Answer:
Explanation:
vf=0
vi = 17
a = -0.8
Δx = ?
vf^2 = vi^2 + 2 a Δx
Δx = (vf^2 - vi^2) / 2a
Δx = (0-17^2) / 2 (-0.8)
Δx = 180.625 m
CAN SOMEONE PLS HELP ME ILL GIVE YOU BRAINLIEST!!!!
A 7000 N braking force is used to slow a car down. The car was traveling at 25 m/s before the
brakes were applied and was traveling at 5 m/s after 6 seconds. What is the mass of the car? (ANS:
2100 kg)
Answers
Answer:
the answer is already there lol
Explanation:
Answer:
answer is there you can see from there lol
Explanation:
Alexis is a scientist who is studying solid-state physics. Which activity would she most likely do as a part of this research? O identifying the optimal vessel for containing carbon dioxide O studying the atomic structure of solid carbon dioxide O determining the effect of pressure on the volume of carbon dioxide O observing the natural state of carbon dioxide
Answers
Answer:
pretty sure its studying the atomic structure of a solid carbon dioxide. so c
Explanation:
Answer:
B. Studying the atomic structure of solid carbon dioxide
Explanation:
This is known as crystallography, the study of the arrangement of atoms in a solid, and it is a popular branch of solid-state physics.
Hope this helps :)
A certain AM radio wave has a frequency of 24Hz. Given that radio waves travel at 3 m/s, what is the wavelength of this radio wave?
Answers
Answer:
Wavelength of AM radio wave = 0.125 meter
Explanation:
Given:
Frequency of AM radio wave = 24 Hz
Velocity of AM radio wave = 3 m/s
Find:
Wavelength of AM radio wave
Computation:
Wavelength = Velocity / Frequency
Wavelength of AM radio wave = Velocity of AM radio wave / Frequency of AM radio wave
Wavelength of AM radio wave = 3 / 24
Wavelength of AM radio wave = 0.125 meter
The length of an aluminium rod is 1m and the speed of sound along the rod is 5000 m per second .Find the values of f1 ad f2
Answers
Answer:
i. 2.5 kHz ii. 5 kHz
Explanation:
The frequency of the wave in the rod is given by f = nv/2L where n = harmonic, v = speed of sound in rod = 5000 m/s and L = length of rod = 1 m
i. f1
For f1, n = 1
f1 = 1 × v/2L
= v/2L
Substituting the values of the variables into the equation, we have
= 5000 m/s ÷ (2 × 1 m)
= 5000 m/s ÷ 2 m
= 2500 /s
= 2500 Hz
= 2.5 kHz
ii. f2
For f2, n = 2
f2 = 2 × v/2L
= v/L
Substituting the values of the variables into the equation, we have
= 5000 m/s ÷ 1 m
= 5000 /s
= 5000 Hz
= 5 kHz
Do only number 3 and thank
Answers
Charge = 0.2 Ah is the correct answer...
Every day, every hour, every second one of the most important events in life is going on in your body—cells are dividing. When cells divide, they make new cells. A single cell divides to make two cells and these two cells then divide to make four cells, and so on. We call this process "cell division" and "cell reproduction," because new cells are formed when old cells divide. The ability of cells to divide is unique for living organisms. 3.A) _________ is a type of cell division which results in the formation of gametes. *
Answers
Answer:
the answer to the question is mitosis
Pls help it’s really late <3
Answers
Answer:
22.4%
Explanation:
The plane is 300000 kg
It is 11000 meters about the earth's surface.
g = 9.81
PE = mgh
PE = 300000 * 9.81 * 11000
PE = 3.24* 10^10
The Kinetic Energy
KE = 1/2 m * v^2
m = 300000
v = 250 m/s
KE = 1/2 300000 * (250 m/s)^2
KE = 9.375 * 10^9
Total Energy = 3.24 * 10^10 + 9.375 * 10^9
Total Energy = 4.17 * 10^10
9.375 * 10^9
=========== * 100 % = 22.44 %
4.17 * 10^10
Most ozone is found in a region of Earth’s
atmosphere between 10 and 20 miles above
Earth’s surface. This temperature zone of the
atmosphere is known as the
(1) thermosphere (3) stratosphere
(2) mesosphere (4) troposphere
Answers
Answer:
It’s stratosphere
Explanation:
Most ozone is found in a region of Earth’s atmosphere between 10 and 20 miles above Earth’s surface. This temperature zone of the atmosphere is known as the stratosphere.
What is ozone?Ozone is an allotrope of oxygen. It is blue in color and it is found in Earth's atmosphere. It protects the Earth from ultraviolet rays from the Sun.
Most ozone is found in the following layer of the Earth's atmosphere:The ozone subcaste is centered at an altitude between 10-15 country miles (15-25 km). Close to 90% of the ozone found in the atmosphere is in the stratosphere. Ozone that is found in this region is about 10 parts per million by volume (ppmv) to the troposphere's 0.04 ppmv.
Therefore, we have determined that Most ozone is found in a region of Earth’s atmosphere between 10 and 20 miles above Earth’s surface. This temperature zone of the atmosphere is known as the stratosphere.
Learn more about ozone here: https://brainly.com/question/26254261
#SPJ2
Can someone help me :)
Answers
Answer:
undergone a chemical change
Explanation:
Answer:
undergone a chemical change
can someone please help me with this question... thank u ❤️
Answers
Answer:
Which of the following... : constant velocity horizontal motion
A ball is thrown at certain... : 0 m/s
when two capacitors are connected in series, the effective capacitance is 2.4muF and when connected in parallel, the effective capacitance is 10muF. calculate the individual capacitances.
Answers
Answer:
let one capacitor be x and other be y
[tex]in \: parallel \: connection : \\ \frac{x + y}{xy} = 10 \times {10}^{ - 6} - - - (a) \\ in \: series \: connection : \\ x + y = 2.4 \times {10}^{ - 6} - - - (b) \\ in \: (a) : \\ \frac{2.4 \times {10}^{ - 6} }{xy} = 10 \times {10}^{ - 6} \\ xy = 0.24 - - - (c) \\ from \: (b) : \\ y = (2.4 \times {10}^{ - 6} ) - x \\ \therefore \: in \: (c) : \\ x(2.4 \times {10}^{ - 6} - x) = 0.24 \\ 2.4 \times {10}^{ - 6} x - {x}^{2} = 0.24 \\ {x}^{2} - 2.4 \times {10}^{ - 6} x - 0.24 = 0 \\ x = 0.5 \\ 0.5y = 0.24 \\ y = 0.48 \\ { \boxed{ C _{1} = 0.5 \: farads}} \\ { \boxed{C _{2} = 0.48 \: farads}}[/tex]
Determine the force exerted by two particles that have a charge of +0.35 Coulombs each and are 1 meter apart
Answers
The electric force between two charges is:
F = (9 x 10⁹) Q₁ Q₂ / D²
F is the force, in Newtons
Q₁ and Q₂ are the two charges, in Coulombs
D is the distance between them, in meters
For these two particles:
F = (9 x 10⁹) (0.35) (0.35) / (1)²
F = (9 x 0.35 x 0.35 x 10⁹) / (1)
F = 1.10 x 10⁹ Newtons
Thatsa lotta force . . . like 124 thousand tons !
The reason it's so big is because the charges in this question are so big ... 0.35 Coulombs each. 1 Coulomb is a huge amount of charge.
Each of the particles feels the same force, pushing it away from the other particle. (The electric force between two charges is always the same in both directions, just like the gravitational force between two masses.)
Acc. to columb's law;
F = k × Q1Q2/r²Clearly, from the question you have:
Charge on both particles = +0.35 columbsDistance between them = 1 meter = 1 × 10-¹⁰ ÅNow just put them up in the formula:
F = k × Q1Q2/r²
F = 9 × 10⁹ × 0.35 × 0.35/1 × 10-¹⁰
F = 9 × 10⁹ × 35 × 35/ 10-¹⁰ × 100 × 100
F = 9 × 10⁹ × 35 × 35/ 10-¹⁰ × 10⁴
F = 9 × 10⁹ × 35 × 35/ 10-⁶
F = 9 × 10⁹+⁶ × 1225
F = 11025 × 10¹⁵
A first aid provider is trained to do the following except:
A) diagnose the victims condition
B) recognize, asses and prioritize the need for first aid
C) seek professional medical assistance when necessary
D) provide appropriate first aid care
Answers
They’re supposed to help the person and cannot diagnose them as that is the job of a doctor
If the satellite weighs 1000g, orbits the Earth at an energy of 9.8 × 10 ^ 9j, what is the speed of the satellite?
Answers
Answer:
1.4×10⁵ m/s
Explanation:
Applying,
K = mv²/2............. Equation 1
Where K = Energy of the satellite, m = mass of the satellite, v = speed of the satellite.
make v the subject of the equation
v = √(2K/m)............ Equation 2
From the question,
Given: K = 9.8×10⁹ J, m = 1000 g = 1 kg
Substitute these values into equation 2
v = √(2×9.8×10⁹/1)
v = √(1.96×10¹⁰)
v = 1.4×10⁵ m/s
50N force accelerated a body at a rateof 8 metres per second square. Calculate the mass of the body
Answers
Answer:
m=6.25kg
Explanation:
Force= mass × acceleration
50=m×8
make m subject of the formula...
m=50/8
m=6.25kg
Answer:
[tex]\boxed {\boxed {\sf 6.25 \ kilograms}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F= m \times a[/tex]
We know the force is 50 Newtons and the acceleration is 8 meters per second squared. Let's convert the units to make the problem and unit cancellation easier.
1 Newton is equal to 1 kilogram meter per square second (1 kg*m/s²), so the force of 50 N is equal to 50 kg*m/s².
Now we know 2 values:
F= 50 kg*m/s²a= 8 m/s²Substitute the values into the formula.
[tex]50 \ kg *m/s^2= m \times 8 \ m/s^2[/tex]
Since we are solving for the mass, we must isolate the variable, m. It is being multiplied by 8 meters per square second and the inverse of multiplication is division. Divide both sides by 8 m/s².
[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= \frac{m \times 8 \ m/s^2}{8 \ m/s^2}[/tex]
[tex]\frac {50 \ kg *m/s^2}{8 \ m/s^2}= m[/tex]
The units of meters per square second (m/s²) cancel.
[tex]\frac {50 \ kg }{8 }=m[/tex]
[tex]6.25 \ kg =m[/tex]
The mass is 6.25 kilograms.
Craig is modeling the discovery of electromagnetism. Which procedure should he use?
A. moving a magnet into a coil of wire in a closed circuit
B. moving a magnet into a coil of wire in an open circuit
C. bringing a compass near a wire that has no electric current
D. bringing a compass near a wire that has an electric current
Answers
Answer:
A
Explanation:
moving a magnet into a coil of wire in a closed circuit
Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism. Option A is correct.
What is electromagnetism ?The physical interplay of electric charges, magnetic moments, and the electromagnetic field is known as electromagnetism.
The electromagnetic field can be static, moving slowly, or forming waves.
Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism.
Hence, option A is correct.
To learn more about the electromagnetism, refer to the link;
https://brainly.com/question/3427992
#SPJ2
