1-5. Graph MU (line MU) for M(-1, 1). (Look at the bottom of the pic)

Answer:

1.  (12 - 2x)(11 - 2x)x

2. 4(11 - 2x)²(x + 1)

3. π(x³ + 15x² + 63x + 81)

Step-by-step explanation:

1. Write the polynomial function that models the given situation.

A rectangle has a length of 12 units and a width of 11 units. Squares of x by x units are cut out of each corner, and then the sides are folded up to create an open box. Express the volume V of the box as a polynomial function in terms of x.

Since the length of the rectangle is 12 units and its width 11 units and squares of x by x units are cut from its corners, it implies that a length x is cut from each side. So, the length of the open box is L = 12 - 2x and its width is w = 11 - 2x.

Since the cut corners of the rectangle are folded, the side x which is cut represents the height of the open box, h. so, h = x

So, the volume of the open box V = LWh = (12 - 2x)(11 - 2x)x

2. Write the polynomial function that models the given situation. A square has sides of 24 units. Squares x + 1 by x + 1 units are cut out of each corner, and then the sides are folded up to create an open box. Express the volume V of the box as a function in terms of x.

Since the square has sides of 24 units and squares of x + 1 by x + 1 units are cut from its corners, it implies that a length x + 1 is cut from each corner and the length 2(x + 1) is cut from each side. So, the length of side open box is L = 24 - 2(x + 1) = 24 - 2x - 2 = 24 - 2 - 2x = 22 - 2x = 2(11  - x)

Since the cut corners of the square are folded, the side x + 1 which is cut represents the height of the open box, h. so, h = x + 1

Since the area of the base of the pen box is a square, its area is L² = [2(11 - 2x)]²

So, the volume of the open box V = L²h = [2(11 - 2x)]²(x + 1) = 4(11 - 2x)²(x + 1)

3. Write the polynomial function that models the given situation. A cylinder has a radius of x + 6 units and a height 3 units more than the radius. Express the volume V of the cylinder as a polynomial function in terms of x.

The volume of a cylinder is V = πr²h where r = radius and h = height of cylinder.

Given that r = x + 6 and h is 3 units more than r, h = r + 3 = x + 6 + 3 = x + 9

So, V = πr²h

V = π(x + 3)²(x + 9)

V = π(x² + 6x + 9)(x + 9)

V = π(x³ + 6x² + 9x + 9x² + 54x + 81)

V = π(x³ + 15x² + 63x + 81)

Answer:

13200 ft

Step-by-step explanation:

1 mi = 5280 ft

5280 ft x 2.5 = 13200 ft

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Using Pythagorean Theorem

[tex]\\ \sf\longmapsto H^2=P^2+B^2[/tex]

[tex]\\ \sf\longmapsto H^2=8^2+15^2[/tex]

[tex]\\ \sf\longmapsto H^2=64+225[/tex]

[tex]\\ \sf\longmapsto H^2=289[/tex]

[tex]\\ \sf\longmapsto H=\sqrt{289}[/tex]

[tex]\\ \sf\longmapsto H=17[/tex]

Answer:

8.4

Step-by-step explanation:

jjdijendjndoendidnie

Answer:

0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.  

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniform distribution between 15 and 20 minutes.

This means that [tex]a = 15, b = 20[/tex]

What is the probability that a randomly selected application from this distribution took less than 18 minutes?

[tex]P(X < 18) = \frac{18 - 15}{20 - 15} = 0.6[/tex]

0.6 = 60% probability that a randomly selected application from this distribution took less than 18 minutes.

Answer:

A) 4x^2+20x+25=(2x)^2+2*(2x)*5+5^2=(2x+5)^2

Area=(side)^2, side=sqrt(area)=sqrt((2x+5)^2)=2x+5

B) 4x^2-9y^2=(2x-3y)(2x+3y), these are the dimensions of the rectangle

A) The length of each side of the square is (2x + 5).

B) The dimensions of the rectangle are (2x - 3y) and (2x + 3y).

Used the concept of a quadratic equation that states,

An algebraic equation with the second degree of the variable is called a Quadratic equation.

Given that,

Part A: The area of a square is [tex](4x^2 + 20x + 25)[/tex] square units.

Part B: The area of a rectangle is [tex](4x^2 - 9y^2)[/tex] square units.

A) Now the length of each side of the square is calculated by factoring the area expression completely,

[tex](4x^2 + 20x + 25)[/tex]

[tex]4x^2 + (10 + 10)x + 25[/tex]

[tex]4x^2 + 10x + 10x + 25[/tex]

[tex]2x (x + 5) + 5(2x + 5)[/tex]

[tex](2x + 5) (2x+5)[/tex]

Hence the length of each side of the square is (2x + 5).

B) the dimensions of the rectangle are calculated by factoring the area expression completely,

[tex](4x^2 - 9y^2)[/tex]

[tex](2x)^2 - (3y)^2[/tex]

[tex](2x - 3y) (2x + 3y)[/tex]

Therefore, the dimensions of the rectangle are (2x - 3y) and (2x + 3y).

To learn more about the rectangle visit:

https://brainly.com/question/2607596

#SPJ4

Answer:

-78

Step-by-step explanation:

Zinc group :

Mean, x1 = 3328

σ1 = 640

Sample size, n1 = 28

Placebo group :

Mean, x2 = 3406

σ2 = 851

Sample size, n2 = 31

The point estimate for the true difference between the population means is obtained as :

Mean difference between population :

x1 - x2 = 3328 - 3406 = - 78

Answer:

so 3 people both read their books and watched films.

Step-by-step explanation:

n(U) = 50

n(A) = 18 ( read books)

n(B) = 28 ( watched films)

n(A U B) with a line at the top = 7

so

Finding n(AUB)

n( A U B) with a line at the top = n(A) + n(B) - n( A n B)

7 = 50-n(A U B)

or, n( A U B) = 50 - 7

so, n(A U B) = 43

Then

n( A U B) = n(A)+n(B)-n(A n B)

43 = 18 + 28 - n( A n B)

or, 43 = 46 - n(A n B)

or, n(A n B) = 46 - 43

so, n(A n B) = 3

Answer:

Destiny will be able to create 12 identical snack bags.

Step-by-step explanation:

Given that a snack bag will be 1 chocolate candy bar, and 1 cookie, we have to subtract 1 chocolate for every cookie she has, and that will leave us with 6 chocolate bars left. The equation for this is 18 - 12 = 6.

Answer:

6

Step-by-step explanation:

21-20 = 1

20-18 =2

18 -15 = 3

15-11 = 4

We are subtracting 1 more each time

11-5 = 6

Answer: Hello the table related to your question is attached below

answer:

a) attached below

b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )

Step-by-step explanation:

a) p-chart for 95% confidence

std = 1.96

Total defects = ∑ number of defective items in the sample = 10

number of samples = 10

sample size ( n ) = 15

The P value for the process is calculated as :

Total defects / ( number of sample * sample size )

= 10 / ( 15 * 10 ) = 10 / 150 = 0.067

standard deviation ( σ ) = [tex]\sqrt{\frac{p(1-p)}{n } } = \sqrt{\frac{0.067(1-0.067)}{15} }[/tex]  =  0.065

next we determine the limits ( i.e. upper and lower )

UCL = p + zSp = 0.067 + 1.96(0.065 ) = 0.194

LCL = p - zSp = 0.067 - 1.96(0.065) = -0.060 ≈ 0 ( because LCL ≠ negative)

attached below is the required p-chart

b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )

Step 1: Solve for one variable

---I will be using the first equation and solving for a.

a + c = 405

a = 405 - c

Step 2: Substitute into the other equation

---Now that we have a value for a, we can substitute that value into the second equation. Then, we can solve for c.

12a + 5c = 3950

12(405 - c) + 5c = 3950

4860 - 12c + 5c = 3950

-12c + 5c = -910

-7c = -910

c = 130

Step 3: Plug back into the first equation

---We now know one variable, which means we can plug back into our first equation and solve for the other.

a = 405 - c

a = 405 - 130

a = 275

Answer: 275 adults, 130 children

Hope this helps!

Answer:

6.22 sec

Step-by-step explanation:

h(t) = 105t-16t^2

For values of t for which height will be 34 feet can be obtained by substituting 34 in place of h(t) and solving for t

34=105t-16t^2, using quadratic formula we have t=1/32*(105±sqrt(8849)) which translates to - 0.34sec and 6.22sec but as time can't be negative, time is 6.22sec

Based on the fact that you asked this three times and got the same answer three times, I suspect the interpretation made by the users that posted those answers was incorrect, and that you meant to ask about dividing in base 2.

We have

111001₂ = 1×2⁵ + 1×2⁴ + 1×2³ + 1×2⁰ = 57

1101₂ = 1×2³ + 1×2² + 1×2⁰ = 13

and 57/13 = (4×13 + 5)/13 = 4 + 5/13.

4 = 2² is already a power of 2, so we have

111001₂/1101₂ = 1×2² + 5/13

we just need to convert 5/13. To do this, we look for consecutive negative powers of 2 that 5/13 falls between, then expand 5/13 as the sum of the smaller power of 2 and some remainder term. For instance,

• 1/4 < 5/13 < 1/2, and

5/13 - 1/4 = (20 - 13)/52= 7/52

so that

5/13 = 1/4 + 7/52

or

5/13 = 1×2 ⁻² + 7/52

Then a partial conversion into base 2 gives us

111001₂/1101₂ = 1×2² + 1×2 ⁻² + 7/52

111001₂/1101₂ = 100.01₂ + 7/52

Continuing in this fashion, we find

• 1/8 < 7/52 < 1/4, and

7/52 = 1/8 + 1/104

==>   111001₂/1101₂ = 100.011₂ + 1/104

• 1/128 < 1/104 < 1/64, and

1/104 = 1/128 + 3/1664

==>   111001₂/1101₂ = 100.0110001₂ + 3/1664

• 1/1024 < 3/1664 < 1/512, and

3/1664 = 1/1024 + 11/13312

==>   111001₂/1101₂ = 100.0110001001₂ + 11/13312

• 1/2048 < 11/13312 < 1/1024, and

11/13312 = 1/2048 + 9/26624

==>   111001₂/1101₂ = 100.01100010011₂ + 9/26624

• 1/4096 < 9/26624 < 1/2048, and

9/26624 = 1/4096 + 5/53248

==>   111001₂/1101₂ = 100.011000100111₂ + 5/53248

and so on.

It turns out that this pattern repeats, so that

[tex]\displaystyle \frac{111001_2}{1101_2} = 100.\overline{011000100111}_2[/tex]

Answer:

y=-\frac{2}{3}\approx -0.666666667

Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.88}{2} = 0.06[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.06 = 0.94[/tex], so Z = 1.555.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that [tex]n = 300[/tex]

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]15 = 1.555\frac{300}{\sqrt{n}}[/tex]

[tex]15\sqrt{n} = 300*1.555[/tex]

Dividing both sides by 15

[tex]\sqrt{n} = 20*1.555[/tex]

[tex](\sqrt{n})^2 = (20*1.555)^2[/tex]

[tex]n = 967.2[/tex]

Rounding up:

The administrator should sample 968 students.

Answer:

This statement would be true.

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

because 5•9=45 so yeah that's the answer

This differential equation is separable:

(1 + y²) dx + (1 + x²) dy = 0

(1 + y²) dx = - (1 + x²) dy

dy/(1 + y²) = -dx/(1 + x²)

Integrating both sides gives

arctan(y) = -arctan(x) + C

and solving for y gives (over an appropriate domain)

y = tan(C - arctan(x))

(the domain being -1 ≤ y ≤ 1).

Answer:

u^2- 18u +81 = (u-9)^2

Step-by-step explanation:

u^2- 18u +

Take the u coefficient

-18

Divide by 2

-18/2 = -9

Square it

(-9)^2 = 81

u^2- 18u +81 = (u-9)^2

Answer:

The blank should contain 81

Step-by-step explanation:

E = u^2 - 18u + (-18/2)^2

E = (u^2 - 18u + 9^2)

E = (u - 9)^2

To be perfectly correct what you have there is a perfect square, but you need to subtract out (9/2)^2 to make it a valid statement.

E = (u - 9)^2 - 81

Answer:

8/9

Step-by-step explanation:

Let the geometric series have the first term=a and common ratio=r. ATQ, ar^3=8 and ar^6=216. r^3=27. r=3. a=8/3^3=8/27. t2=ar=8/9

Answer:

6x10^4

Step-by-step explanation:

Answer:

A: the standard error of the mean

Step-by-step explanation:

The most frequently used measure to determine how much difference there is between population mean and sample mean is by calculating the standard deviation of the sampling distribution of the mean. This standard deviation is also referred to as the sew Station.

Answer:18

Step-by-step explanation:

Answer:

re send it

Step-by-step explanation:

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