(1,-1) (5,-7 find the slope

Answers

Answer 1

Answer:

m=-2

Step-by-step explanation:

m=-8/5-(1)

m=-8/4

divided -8 by 4

m=-2

Answer 2

Answer:

m=-2

Step-by-step explanation:


Related Questions

a number of students are standing in a circle. they are evenly spaced and the fith student is directly opposite the eleventh student. how many students are there all together

Answers

Answer:

There would be 12

Step-by-step explanation:

How many 2 digit numbers have unit digit 6 but are not perfect squares

Answers

9514 1404 393

Answer:

  7

Step-by-step explanation:

Of the 9 2-digit numbers ending in 6, only 2 are perfect squares: 16 and 36. The other 7 are not perfect squares.

A two digit number is four times the sum and three times the product of its digit. Find the number.​

Answers

10 × 2 + 4 = 24. Hence, the required number is 24


Consider this function.
h(x) = (x - 2)^2+3

Which of the following domain restrictions would enable h(x) to have an inverse function?
a. x < 1
b. x >5
c. x < 3
d. x > 4

(Ps: all four answer and larger equal then or smaller equal then

Answers

Answer:

No inverse function:  (a), (b), (c)

Inverse function exists:  (d)

Step-by-step explanation:

The graph of h(x) = (x - 2)^2 + 3 is a parabola that opens upward and has vertex at (2, 3).  If the entire graph is drawn, and the horizontal line test then applied, h(x) would not have an inverse, because the horizontal line would intersect the  parabolic graph twice.

Note that if we restricted the domain to x ≥ 2, the resulting graph would pass the horizontal line test.  This would also be true for x ≥ 3, x ≥ 4, and so on.  Not so for (a) x < 1.  False for x > -5.  True for x < 3.  True for x > 4.

No inverse function:  (a), (b), (c)

Inverse function exists:  (d)

Please help. ASAP. Work out, giving your answer in its simplest form:


3 1/2 divided by 2 3/5

Answers

Answer:

26/35

Step-by-step explanation:

1. First to divide the 3 1/2 by 2 3/5 you have to turn them both into improper fractions

First take 3 1/2. You have to multiply the whole number (3) by the denominator (2) and you would get 6. Then you would add then you add the product (6) to the numerator (1) and get 7.

You keep the denominator the same so the improper fraction is 7/2

Do the same thing to 2 3/5 and the improper fraction is 13/5

2. Now we can divide 13/5 by 7/2 using "keep, change, flip"

Keep: 13/5

Change: division to multiplcation

Flip: 7/2 to make 2/7

Your new equation is 13/5 × 2/7. Multiplcation is easy so you just have to multiply staight across: 13 × 2 and 5 × 7 giving you 26/35

If you divide 35 by 26 you will get 1.34 and a bunch of other numbers but I usually stop at two decimal places

hope this helps :)

Please help this is my fifth time asking this question please answer it correctly with explanation

Answers

Step-by-step explanation:

There are two attachments to this post. The first attachment shows the numbered angles formed through the intersection of the transversal, t, into the parallel lines, m and n, which will be used to determine how each angle relates to other angles.

First attachment:

The corresponding angles in the first attachment are:

∠1 and  ∠5

∠2 and ∠6

∠3 and ∠7

∠4 and ∠8

Corresponding angles have the same measure.

The same-side exterior angles are the pair of angles that are outside the parallel lines, and on the same side of the transversal.  In the first attachment, the same-side exterior angles are:

∠1  and ∠8

∠2 and ∠7

These angles are supplements of each other, meaning that the sum of their measure equal 180°.

Second Attachment:

Given parallel lines, m and n that are cut by a transversal, t.

The angle that has a measure of  ∠(10x + 5)° is a supplement of ∠(5x + 25)°.  In order to solve for the value of x, we must establish the following equation:

m∠(10x + 5)° + m∠(5x + 25)° = 180°

10x° + 5° + 5x° + 25° = 180°

Combine like terms:

15x° + 30° = 180°

Subtract 30 from both sides:

15x° + 30° - 30° = 180° - 30°

15x° =  150°

Divide both sides by 15:

15x°/15 = 150°/15

x = 10°

Verify whether we have correct value for x by substituting its value into the established equation:

m∠(10x + 5)° + m∠(5x + 25)° = 180°

10(10)° + 5° + 5(10)° + 25° = 180°

100° + 5° + 50° + 25° = 180°

180° = 180° (True statement).

Therefore, we have the correct value for x = 10°.

m∠(10x + 5)°  = 105°

m∠(5x + 25)° = 75°

A car traveled 35 miles per hour. In how many hours did it travel 280 miles?

Answers

Answer:

8

Step-by-step explanation:

280/35=8

Answer:

8 hours.

Step-by-step explanation:

280/35 = 8

How many solutions can be found for the system of linear equations represented on the graph?
A) no solution
B) one solution
C) two solutions
D) infinitely many solutions

Answers

Answer:

A) No solution

Step-by-step explanation:

Given the systems of linear equations, y = 2x + 1 and y = 2x - 1:

Both equations in the system have the same slope, m = 2, thus forming parallel lines.  Since their lines are parallel from each other, then it means that their lines will never intersect.

Therefore, the given systems of linear equation is an inconsistent system that has no solution.

The greatest possible number whose digits are all even numbers from 1 to 9

Answers

Answer:

8642

Step-by-step explanation:

Our even numbers from 1-9 are:

2,4,6,8

The largest possible number using the even numbers once is 8642.

Hoped this helped

Write the equation of the line with x-intercept 3 and passing through the point (5.4)

Answers

Answer: y=(1/5)m+3

Step-by-step explanation:

Start with the standard form of an equation of a straight line:  y=mx+b, whre m is the slope and b the y-intercept (the value of y when x=0).

y=mx+b

We know b (3), so:

y=mx + 3

To find the slope, m, we can use the one given point, (5,4):

y=mx + 3 for (5,4) would be:

4 = m*5+3

1 = 5m

m = (1/5)

y=(1/5)m+3

(2x+y)2-y2 if x=-3 y=4 and z=-5

Answers

Answer:
-12
Hope this helps!
So your equation it (2x+y)2-y2 so then you will substitute meaning your equation will now be 2(-3)+4*2-(4)2 and I assume it’s squared and there is a lot of things missing but I get -6+8-16 all together it would be 14 that’s what I get at least

Identify the vertex of the parabola represented by the equation y=−2x2+8x−1.


(−4, −65)

(4, −1)

(2, 7)

(−2, −25)

Answers

Answer:

it is correct but -65 is not correct

Today everything at a store is on sale the store offers a 20
% discount the regualr price of a t shirt is 18 what is the discount price

Answers

Answer:

$14.40 is the discount price.

Step-by-step explanation:

0.2 x 18 = 3.6

18 - 3.6 = 14.4

When determining domain it is important to work from

Answers

Answer:

use graphs

Step-by-step explanation:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

Determine the rate of change between the points (-1,-1) and (1,-1).

Answers

Answer:

[tex]\displaystyle m = 0[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Coordinate Planes

Coordinates (x, y)Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Step-by-step explanation:

*Note:

Rate of change is slope.

Step 1: Define

Identify.

Point (-1, -1)

Point (1, -1)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m.

Substitute in points [Slope Formula]:                                                              [tex]\displaystyle m = \frac{-1 + 1}{1 + 1}[/tex][Order of Operations] Simplify:                                                                        [tex]\displaystyle m = \frac{0}{2}[/tex]Simplify:                                                                                                             [tex]\displaystyle m = 0[/tex]

Write a linear inequality for each graph (back page)

Answers

Answer:

I can't read that...........

Z=3 evaluar -[z-(-z)+z]Por favor alguien que me ayude

Answers

Sorry yo no hablar mucho español

in triangle abc it is given that AB =9 cm Bc=6cm and Ca = 7.5 cm also
triangle def is given that ef =8 cm and triangle def similar to triangle abc then perimeter of triangle def is ​

Answers

Answer:

Make me as brain liest plz

The perimeter of triangle DEF is; 30 cm

Similar Triangles

We are given dimensions of Triangle ABC as;

AB = 9 cmBC = 6 cmCA = 7.5 cm

Thus;

Perimeter of Triangle ABC = 9 + 6 + 7.5 = 22.5 cm

We are told that Triangle DEF is similar to Triangle ABC.

This means that the ratio of corresponding sides must be equal to the ratio of their perimeter.

Side EF corresponds to side BC. Thus;

Perimeter of Triangle DEF/22.5 = 8/6

Cross multiply to get;

Perimeter of Triangle DEF = (22.5 × 8)/6

Perimeter of Triangle DEF = 30 cm

Read more on similar triangles at; https://brainly.com/question/14285697

Andrew shovels snow for 4 %2 hours and makes
$27. How much did he make per hour?
And how much does he earn in 8 hours?

Answers

He got paid $54! :)

2. A house costs $30,000. A buyer is given a 1/10 discount. How much money does the buyer save?

Answers

Answer:

3000

Step-by-step explanation:

FInd the value of T - triangle measerments

Answers

JK=JH

[tex]\\ \sf\longmapsto 10t=7t+15[/tex]

[tex]\\ \sf\longmapsto 10t-7t=15[/tex]

[tex]\\ \sf\longmapsto 3t=15[/tex]

[tex]\\ \sf\longmapsto t=15/3=5[/tex]

-x+3y=0
x+3y=12

System of linear equation by elimination

Answers

Answer:

x=6

y=2

Step-by-step explanation:

-x+3y=0 (1)

x+3y=12 (2)

(1)+(2)<=> 6y=12

Please Help!! Asap!!

A local club team is holding tryouts for six spots on the soccer team. Since there is not much time before a very important tournament they need to select the best players. Which method would be the best to ensure they select the "most talented" soccer players?


A. They watch the players during tryouts and then put them on a list in order from the most skilled to the least skilled and then select the top six from the list.


B. The first day of tryouts they select the first six that show up as they figure those are the most eager for a spot.


C. They place all of the names of the people trying out in a hat and then select six out of the hat. Those are the ones that are chosen.


D. They watch the players during tryouts and then put them on a list in order from the most skilled to the least skilled and then select the top three and the bottom three from the list.

Answers

Answer:

A because it's most likely to be like that at tryouts

Plsss help It due tmr plsss

Answers

Answer: 50

Step-by-step explanation:

exterior angles are supplement of interior angle therefore the 110 thing must be 70, also youre given 60 so 70+60=130

50 is missing from 180

Help me this question is so hard i fried up my brain yesterday working on it for so long!!!!

Answers

Hello there! (:

The answer is 9.

3^4=3*3*3*3 (81)

3^2=9

81:9=9

So the answer is 9.

Hope it helps! If you have any question or query, feel free to ask! (:

~An excited gal

[tex]SparklingFlower[/tex]

(20pts) I need to know who is incorect and why

Answers

Answer:

i thig it is hj

Step-by-step explanation:

jk

Can someone help plz

Answers

Here’s ur help The answer is 571

does anyones know these ?

Answers

No I don't know your thing

help me please !!!!

Answers

Answer:

graph X only

Step-by-step explanation:

because with the rate of change it makes a straight line

(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme​

Answers

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]

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