0
Why does a hot water bottle feel warm?
Molecules in the hot water bottle are
moving faster than molecules in the skin.
Molecules in the skin are moving faster
than molecules in the hot water bottle.
DONE

Answer:

Average atomic mass of element X is 56.19 amu

Explanation:

Given:

Four isotopes of X:

5.845% of X has a mass of 53.93961 amu.

91.75% of X has a mass of 55.93494 amu.

2.123% of X has a mass of 56.93539 amu.

0.2820% of X has a mass of 57.93328 amu.

To find: average atomic mass of element X

Solution:

Isotopes are variants of a particular chemical element such that they have the same number of protons but different number of neutrons.

Average atomic mass of element X = [tex]\frac{53.93961+55.93494+56.93539+57.93328}{4}=\frac{224.74322}{4}=56.185805\approx 56.19[/tex]

So, the average atomic mass of element X is 56.19 amu.

Answer:

Explanation:

molecular weight of creatinine = 131

1 mg of creatinine = 1 x 10⁻³ / 131 = 7.63 x 10⁻⁶ mole of creatinine.

volume of solution = .1 L

mass of blood solution = .1 x 1025

= 102.5 g

mass of solvent = 102.5 g approximately

= .1025 kg

molality = mole of solute / mass of solvent in kg

= 7.63 x 10⁻⁶ / .1025 kg

= 74.44 x 10⁻⁶ .

Osmotic pressure :---

π V / T = nR     π is  osmotic pressure , V is volume of solution in liter , T is absolute temperature , n is molality .

π x .1 / 298 =  74.44 x 10⁻⁶ x .082

π = 18.19 x 10⁻³ atm

Answer:Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine because the bromine radical is less reactive and therefore more selective.

Explanation: Halogenation occurs when a halogen replaces  one or more hydrogen atoms in an organic compound ie  chlorine or  bromine with the reactivity of the halogens decreasing  in the order of  F2 > Cl2 > Br2 > I2

Since fluorine reacts  explosively making it is difficult to control, and iodine is unreactive. Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine  with Chlorination  ie chlorine radical being more reactive and not selective and the Bromination of alkanes ie bromine radical  occurring similarly but slower and less reactive but  more selective which is due to the fact that a bromine atom is less reactive in  the hydrogen abstraction  than a chlorine atom evidence in the  higher bond energy of H-Cl than H-Br.

Answer:

Check the explanation

Explanation:

1)

Atomic number of Se = 34

So, number of proton = 34

use:

charge = number of proton - number of electron

-2 = 34 - number of electron

number of electron = 36

number of neutron = mass number - atomic number

= 78 - 34

= 44

Answer:

44

34

36

2)

number of proton = mass number - number of neutron

= 65 - 36

= 29

29 is atomic number for Cu

use:

charge = number of proton - number of electron

+1 = 29 - number of electron

number of electron = 28

Answer:

Cu

29

28

3)

Atomic number is 36 for Kr

use:

charge = number of proton - number of electron

= 36 - 36

= 0

use:

mass number = number of proton + number of neutron

= 36 + 42

= 78

Answer:

Kr

78

0

Answer:

1.2 atm

Explanation:

Given data

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

[tex]P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm[/tex]

Answer:

9.9 ml of 0.200M NH₄OH(aq)

Explanation:

3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)

?ml of 0.200M NH₄OH(aq) reacts completely with  12ml of 0.550M FeCl₃(aq)

1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution

1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)

=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters  

The amount of [tex]0.200 M NH_{4} OH[/tex] required to react with [tex]12.0 ml[/tex] of [tex]0.550 M FeCl_{3}[/tex]would be [tex]9.9 ml.[/tex]

Given that,

Reaction:

[tex]3NH_{4} OH(Iaq) + FeCl_{3} (aq) => NH_{4} Cl(aq) + Fe(OH)_{3} (s)[/tex]

To find,

The amount of [tex]0.200 M NH_{4} OH[/tex]required to react with [tex]12.0 ml[/tex] of [tex]0.550 M FeCl_{3}[/tex] = ?

Procedure:

As we know,

[tex]1[/tex] × molarity of [tex]NH_{4}OH[/tex]× [tex]Volume (Am-OH) Solution(l)[/tex] [tex]= 2[/tex] × molarity of [tex]FeCl_{3}[/tex]× volume of solution [tex]FeCl_{3}[/tex]

By substituting the given values in this formula, we get

⇒ [tex]1(0.200M)[/tex][tex](Vol Am-OH Sol)= 3(0.550M)(0.012L)[/tex]

⇒ [tex]Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M)[/tex]

⇒ [tex]Vol Am-OH Solution = 0.099 liters[/tex]

[tex]= 0.099[/tex] × [tex]1000[/tex]

[tex]=[/tex] [tex]9.9 milliliters[/tex]

Thus, [tex]9.9 ml[/tex] is the correct answer.

Learn more about 'compounds' here:

brainly.com/question/13516179

Answer:

Explanation:

Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10

the partial pressures of the gases in a mixture

= mole fraction x Total pressure

mole fraction = mole of a gas in the mixture  / total mole

partial pressure of Ng = [tex]\frac{7.8}{10} \times 101.3 kPa[/tex]

= 79.014 kPa

partial pressure of O = [tex]\frac{2.1}{10} \times 101.3 kPa[/tex]

= 21.273 kPa .

partial pressure of  Ar = [tex]\frac{.09}{10} \times 101.3 kPa[/tex]

= .9117 kPa .

partial pressure of  Co = [tex]\frac{.01}{10} \times 101.3 kPa[/tex]

= .1013 k Pa .

Answer:

87.6 %

Explanation:

Step 1: Write the balanced equation

LiOH + KCl ⇒ LiCl + KOH

Step 2: Calculate the theoretical yield of LiCl

We will use the following relations:

The theoretical yield of LiCl from 20.0 g of LiOH is:

[tex]20.0gLiOH \times \frac{1molLiOH}{23.95gLiOH} \times \frac{1molLiCl}{1molLiOH} \times \frac{42.39gLiCl}{1molLiCl} = 35.4gLiCl[/tex]

Step 3: Calculate the percent yield of LiCl.

We will use the following expression.

[tex]\%yield = \frac{real\ yield}{theoretical\ yield} \times 100\% = \frac{31.0g}{35.4g} \times 100\% = 87.6 \%[/tex]

Answer:

88.6%

Explanation:

Hello,

In this case, considering the given reaction, we notice a 1:1 molar relationship between lithium hydroxide (molar mass=23.95 g/mol) and lithium chloride (molar mass=42.394 g/mol), for that reason, we are able to compute the theoretical yield of lithium chloride by stoichiometry:

[tex]m_{LiCl}^{theoretical}=20.0gLiOH*\frac{1molLiOH}{23.95gLiOH}*\frac{1molLiCl}{1molLiOH} *\frac{42.394 gLiCl}{1molLiCl}=35.4gLiCl[/tex]

Next, by knowing the actual yield of 31.0 g, we compute the percent yield as:

[tex]Y=\frac{m_{LiCl}^{actual}}{m_{LiCl}^{theoretical}} *100\%=\frac{31.0g}{35.4g}*100\%\\ \\Y=87.6\%[/tex]

Therefore, among the given, the answer should be 88.6%

Best regards.

Answer:positive electrode

Explanation:

Anode can also be referred to as positive electrode in a cell

Answer:

The variables in Gay-Lussac's law are the initial temperature (T1), the initial pressure (P1), the final temperature (T2) and the final pressure (P2)....

Explanation:

Answer:

C. precipitate formation.

Explanation:

options C is correct answer.

Answer:

C. precipitate formation.

Explanation:

Answer:

Specific Immune Response

Explanation:

A specific immune response identifies the pathogen which then allows it to produce antibodies that protect against that SPECIFIC pathogen.

Answer:

Explanation:

Answer:

Explanation:

10 mL = 10⁻² L

1 mL of solution contains .0087 x 10⁻² mole of Cu

15 mL of solution will contain .1305 x 10⁻² mole of Cu

.1305 x 10⁻² mole of copper = .1305 x 63.5 x 10⁻² gm of Cu

= .08286 gm

concentration of copper in the ore sample

= .08286 x 100 / .25

= 33 % approx .

Answer:

Explanation:

N₂       + 3H₂     =     2 NH₃

1 vol                         2 vol

786 liters               1572 liters

786 liters of dinitrogen will result in the production of 1572 liters of ammonia

volume of ammonia V₁ = 1572 liters

temperature T₁ = 222 + 273 = 495 K

pressure = .35 atm

We shall find this volume at NTP

volume V₂ = ?

pressure = 1 atm

temperature T₂ = 273

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

[tex]\frac{.35\times 1572}{495} =\frac{1\times V_2}{ 273 }[/tex]

[tex]V_2 =303.44[/tex] liter .

mol weight of ammonia = 17

At NTP mass of 22.4 liter of ammonia will have mass of 17 gm

mass of 303.44 liter of ammonia will be equal to (303.44 x 17) / 22.4 gm

= 230.28 gm

=.23 kg / sec .

Rate of production of ammonia = .23 kg /s .

Answer:

The hardness is more than 2.5. Hope this helps.

Answer:

The hardness is more than 2.5.

Explanation:

Answer:

The answer is e - Negative, Exothermic

Explanation:

Kono Dio Da!!

Answer:

Compromise

Explanation:

Please give brainliest :-)

Answer:

Compromise

Explanation:

Answer:

I believe it is C.Shelter.

Answer:

C

Explanation:

The butterflies use the trees for shelter, because the trees protect them from the weather and the cold air.

Answer:

grams H₂O produced = 8.7 grams

Explanation:

Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)

               7g           18g                             ?g

Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water

Moles Reactants

moles C₂H₆ = 7g/30g/mol = 0.233mol

moles O₂ = 18g/32g/mol = 0.563mol

Limiting Reactant => (Test for Limiting Reactant)  Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.

moles C₂H₆/2 = 0.233/2 = 0.12

moles O₂/7 = 0.08

Limiting Reactant is O₂

Moles and Grams of H₂O:

Use Limiting Reactant moles (not division value) to calculate moles of H₂O.

moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield

grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O

Answer:

19656J

Explanation:

Step 1:

Data obtained from the question.

Mass (M) = 78g

Initial temperature (T1) = 20°C

Final temperature (T2) = 80°C

Change in temperature (ΔT) = T2 – T1 =

80°C – 20°C = 60°C

Specific heat capacity (C) = 4.2J/g°C

Heat (Q) =...?

Step 2:

Determination of the heat required for the reaction.

Q = MCΔT

Q = 78 x 4.2 x 60

Q = 19656J

Therefore, 19656J of heat is required.

Answer:

q1..no.2 and 4 are aromatic

Answer:

132.5 ATPs

Explanation:

We are Given, gadoleic acid has 20 carbons with one unsaturation at carbon number 9.

And we know that For a saturated fatty acid, one beta oxidation cycle results in 1 acetyl CoA molecule, 1 NADH + H+ and 1FADH2. this cycle occurs in 4 steps:

1. Fatty acyl CoA to trans-enoyl CoA: This step produces 1 FADH2

2. trans-enoyl CoA to beta-hydroxyacyl CoA: No reducing power or ATP is produced, Only hydrolysis of trans alkene takes place.

3. beta-hydroxyacyl CoA to beta-ketoacylCoA: This step produces 1 NADH+ H+

4. Release of one Acetyl CoA and fatty acyl CoA chain short of two carbon atoms.

Now, the cycle of gadoleic acid runs in same way till three acetyl CoA molecules are lost forming three FADH2 and three NADH + H+.

After loss of 3 acetyl CoA molecules, carbon number 7 (of actual chain) becomes acyl CoA and so, isomerase comes into action which converts cis double bond between carbon number 9 and Carbon number 10 to trans bond between Carbon number 8 and Carbon number 9. This isomerization then undergoes hydrolysis (as in step 2 of beta oxidation cycle) and step 3 and 4 take place as usual.

The above changes result in release in one acetyl CoA molecule and 1 NADH + H+ but FADH2 is not formed (because step 1 did not occur)

Remaining fatty acyl CoA containing 12 carbons undergoes 5 cycles of beta oxidation to form 6 acetyl CoA, 5 FADH2 and 5 NADH +H+.

So, a total of 10 acetyl CoA, 8 FADH2 and 9 NADH +H+ are formed in beta oxidation of gadoleic acid.

Now, each acetyl CoA on entering citric acid cycle forms 3 NADH + H+, 1 FADH2 and 1 GTP ( = 1ATP)

So, total 10 acetyl CoA from citric acid cycle will form 30 NADH + H+, 10 FADH2 and 10 GTP ( = 10 ATP)

Overall, complete oxidation of gadoleic acid will form, 39 NADH + H+, 18 FADH2 and 10 GTP ( = 10 ATP)

On ETC, assuming 1NADH + H+ to form 2.5 ATP and 1 FADH2 to form 1.5 ATP,

total ATPs formed will be 97.5 ATP (39 NADH + H+), 27 ATP (18 FADH2) and 10 ATP (10 GTP) = 134.5 ATPs

On the beginning of first cycle of beta oxidation, 2 ATPs are used for activation of fatty acid molecule. (these have to be subtracted)

So, net ATP yield = 134.5 - 2 = 132.5 ATPs

The ATP yield of complete oxidation of Gadoleic acid has been 132.5 ATP.

Beta oxidation of fatty acid has been a catalytic process for breaking of fatty acid molecules into acetyl Co A and NADH and FADH that enters the citric acid cycle for the generation of ATP.

The overall reaction for beta-oxidation can be stated as:

[tex]\rm C_n-acyl\;CoA\;+\;FAD\;+\;NAD^+\;+\;H_2O\;+\;CoA\;\rightarrow\;C_n_-_2acyl\;CoA\;+\;FADH_2\;+\;NADH\;+\;H^+\;+\;acetyl-CoA[/tex]

The complete oxidation of saturated even carbon fatty acid will result in :

ATP yield = 7n -6

Where n is the number of carbon

The complete oxidation of saturated odd carbon fatty acid will result in :

ATP yield = 7n - 19

The unsaturated fatty acid having a double bond at odd carbon results in a less [tex]\rm FADH_2[/tex] molecule production, resulting in the formation of 1.5 ATP less than the saturated fatty acid.

The ATP yield of 20 carbon chain Gadoleic acid :

n = 20

ATP yield = 7n - 6

ATP yield = 7 (20) - 6

ATP yield = 140 - 6

ATP yield = 134

Due to unsaturation at C9, there has been a reduction of 1.5 ATP.

ATP yield = 134 - 1.5

ATP yield = 132.5.

The ATP yield of complete oxidation of Gadoleic acid has been 132.5 ATP.

For more information about beta-oxidation, refer to the link:

https://brainly.com/question/9399547

Answer:

see explanations

Explanation:

              PCl₅  =>     PCl₃     +     Cl₂

C(eq):   [PCl₅]       0.054M        0.34M

a.  Keq = [PCl₃][Cl₂]/[PCl₅]

b.  7.9 = (0.054)(0.34)/[PCl₅] => [PCl₅] = (0.054)(0.34)/(7.9) = 0.0023M

c.  If [PCl₃] = 0.054M; [Cl₂] = 0.34M and [PCl₅] = 0.0023M then the reaction is at equilibrium and will not shift forward or in reverse. In order to determine if reaction is not at equilibrium, a set of concentration values needs to be given in problem, used to calculate Qeq and compared to the given Keq value.  The following defines direction of shift ...

Keq  <  Qeq  =>  rxn shifts left

Keq  =  Qeq  =>  rxn is at equilibrium (no shift)

Keq  >  Qeq  =>  rxn shifts right

NOTE: If Keq is listed first followed by Qeq in the above conditions, the inequality symbol indicates direction of shift.

Answer:

It's probably claim 3

Explanation:

It's not claim 1 because the amount of energy from the sun can't change and claim 2 doesn't really make sense.

Answer:

127 grams of carbon dioxide

Explanation:

We need to determine the chemical equation first. Butane has a chemical formula of [tex]C_4H_{10}[/tex], oxygen is [tex]O_2[/tex], carbon dioxide is [tex]CO_2[/tex], and water is [tex]H_2O[/tex]. The reactants are butane and oxygen and the products are carbon dioxide and water. So we write:

[tex]C_4H_{10}+O_2[/tex] ⇒ [tex]CO_2+H_2O[/tex]

But remember! We need to balance this. Currently, there are 4 carbon atoms (C), 10 hydrogen atoms (H), and 2 oxygen atoms (O) on the left, while there are 1 carbon atom (C), 2 hydrogen atoms (H), and 3 oxygen atoms (O) on the right. Let's place a coefficient of 4 in front of the carbon dioxide and a coefficient of 5 on the water, so that we have equal numbers of carbon and hydrogen atoms on each side:

[tex]C_4H_{10}+O_2[/tex] ⇒ [tex]4CO_2+5H_2O[/tex]

However, we need to ensure that there are equal numbers of O atoms, as well. On the left, we have 2 and on the right we have 13, so let's put a coefficient of 6.5 on the oxygen:

[tex]C_4H_{10}+6.5O_2[/tex] ⇒ [tex]4CO_2+5H_2O[/tex]

Finally, multiply everything by 2 to get whole number coefficients:

[tex]2C_4H_{10}+13O_2[/tex] ⇒ [tex]8CO_2+10H_2O[/tex]

Ah, now we can actually get to the problem!

We need to determine the limiting reactant, so let's convert the 42 g of butane and 150 g of oxygen into moles of any product, say, carbon dioxide. To convert to moles, we need to find the molar mass of each compound.

The molar mass of butane is 4 * 12.01 + 10 * 1.01 = 58.14 g/mol, while the molar mass of oxygen is 2 * 16 = 32 g/mol. We can now set up the equations:

[tex]42 gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}} *\frac{8molCO_2}{2molC_4H_{10}} =2.8896molCO_2[/tex]

[tex]150 gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{13molO_2} =2.8846molCO_2[/tex]

Clearly, we see that 2.8846 < 2.8896, which means that oxygen is the limiting reactant. In other words, the most products can be made when the oxygen is all used up.

Now let's finally convert moles of carbon dioxide into grams by multiplying by its molar mass, which is 12.01 + 2 * 16 = 44.01 g/mol:

[tex]2.8846molCO_2*\frac{44.01gCO_2}{1molCO_2} =127gCO_2[/tex]

Notice that we have 3 significant figures because we had 3 significant figures at the start with 150. grams of oxygen.

~ an aesthetics lover

Answer:

The correct answer is 7.8 percent.

Explanation:

As mentioned in the given question, the absorbance (A) of the sample solution is 1.07. To find the concentration of aspirin, Beer's law is used, that is, A = ebc

Here, e is the extinction coefficient, which is equal to 139.322 M^-1cm^-1 as per the standard value for salicylic acid, b is the pathlength, which is equivalent to 1 cm. Now putting the values we get,  

A = ebc

c = A / (eb)

c = 1.07 / (139.322 × 1)

c = 0.00768 M

Now to determine the percent salicylic acid in the sample, there is a need to compare the value of concentration determined with the concentration of aspirin given initially.  

0.02 grams is the initial concentration of aspirin mentioned in the question. The molar mass of aspirin is 240 g/mol.  

Therefore, the moles of aspirin will be,  

0.02 / 240 = 8.33 × 10^-5 moles  

The final volume of the diluted solution given is 10 ml or 0.01 liters.  

The molarity of aspirin in the diluted solution will be,  

c1 = 8.33 × 10^-5 / 0.01 = 8.33 × 10^-3 M or 0.00833 M

Now, the percent of salicylic acid in the product will be,  

c1 - c / c1 × 100

(0.00833 - 0.00768) / 0.00833 × 100 = 7.8 %

Absorbance is directly proportional to the concentration of the solution. The absorbance can be calculated if the molar absorptivity, path length, and concentration of the absorbing species are known.

The percent of salicylic acid in the solution is 7.8%

Given that:

Absorbance of the solution is = 1.07

Path length = 1 cm.

Applying Beer's Law,

A = ε b c

where,

c = concentration, A = absorbance, ε = constant, and b = path length

Now, putting the values in above equation

c = [tex]\dfrac{\text{A}}{\text {(e b)}}[/tex]

c = [tex]\dfrac{1.07}{139.32 \times 1}[/tex]        ( ε = 139.32)

c = 0.00768 M

Now, to calculate the percent of the salicylic acid in the solution, we will compare the given concentration of the aspirin.

As we know:

Given mass of aspirin = 0.02 g

Molar mass of aspririn = 240

Number of moles of aspirin = 0.02 / 240 = 8.33 x 10⁻⁵

Now, the molarity of aspirin is:

[tex]\text{Molarity}&= \dfrac{8.33 \times 10^{-5}}{0.01}\\\\\text{Molarity}&= 8.33 \times 10^{-5}[/tex]

Now, the percent of the salicylic acid is:

[tex]\dfrac{\text {C}_1 - \text C}{\text {C}_1 \times 100}[/tex]

[tex]\dfrac{(0.00833 - 0.00768)}{0.00833 \times 100}[/tex]

Percent of Salicyclic acid = 7.8%.

Thus, the percentage of the salicylic acid in the given solution is 7.8%.

To know more about Absorbance, refer to the following link:

https://brainly.com/question/17062521

Answer:

The answer is 2

Explanation:

The equation that represent the conservation of charge is Option 2.

The following information should be considered:

Learn more; https://brainly.com/question/11833983?referrer=searchResults

Answer:

1a. Both sides of the decay reaction have the same charge.

b. The number of nucleons on both sides are the same.

2. The binding energy of one mole of the atom is 17.172 × [tex]10^{16}[/tex] J.

Explanation:

1a. Considering the two sides of the decay reaction and with respect to the law of conservation of charge, it can be observed that both sides have the same charge. Charge can not be created or destroyed in the process.

b. The number of nucleons on both sides are equal. No nucleon is created or destroyed in the process.

2. Binding energy is the minimum energy required to separate an atom into its nucleons. From Einstein's energy equation;

             E = Δm[tex]c^{2}[/tex]

Where E is the binding energy of the atom, Δm is the mass defect and c is the speed of light.

Given that: Δm = 1.908 g/mol and c = 3 × [tex]10^{8}[/tex]. So that:

           E = 1.908 × [tex](3*10^{8}) ^{2}[/tex]

              = 1.908 × 9 × [tex]10^{16}[/tex]

              = 17.172 × [tex]10^{16}[/tex] J

The binding energy of one mole of the atom is 17.172 × [tex]10^{16}[/tex] J.